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時鐘上有時針有分針,分針每一分鐘跳一次,分針每跳一次時針也會前進相對應的角度。請設計一程式,由使用者輸入一個時間,程式會計算出時針與分針間的夾角後輸出。

輸入說明:輸入包含兩個正整數,兩個數之間由一個空白隔開,第一個數字代表時,第二個數字代表分。

輸出說明:請輸出時針與分針間較小的那個夾角。

輸入範例:

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 10.9k views

62 Answers

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Hidden content!
#include <stdio.h>

#include * * ** *

#include <ctype.h>

#include <math.h>

#include *** ** ** ****



int main(){
**** * *** * ** **** * h,m;
* *** *** **** ** * ** * *** **** ***
**** * ** * * * * ** * arch,arcm,sum=0;
**** ** ** ** ** ** * ** ****
** * * * ** * ** * * ** = m * 6;
* * ***** ** * * ** ** * = h * 30 + m * 0.5;
** ** * *** **** * * > arch){
* ** * * ** *** * * ** * ******** ** = arcm - arch;
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}
answered by (-216 points)
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Hidden content!
#include * * * * **

#include * * ** * **

#include <ctype.h>

#include <math.h>



int main()

{
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* ** ** ** ** ** (e>180)
***** * ** ** ** **** *




*** ***** * * *** * * * ****** **** *
*** *** * ** * ** *** **** 0;



}
answered by (-136 points)
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Hidden content!
#include * ** * * ****



int main()

{
***** ** * * * * * ** ** ,j ,n=0;
* * **** * * ***** * i;
*** * * * * **** ** ** ** ** ** ***** * *** ** **
**** * *** * * = i % 12 ;
** **** *** *** =( i * 30 )+( j / 2) ;
** * **** * ** = j * 6 ;
**** *** * ***** =k-l ;

if(m < 0)
* * * * * **** * *
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* *** * * *** **
* * * ******* *** * * if(m > 180)
** ** * ** * * * *
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* * * ********* * *
* * **** ** * * ** *** * * * ** * *
** * * *** ** * *** * 0;

}
answered by (-60 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
**** * * * h,m;
* * * ** * ***** ang1,ang2;
** * ** *** ** *** * * * ******* *** * * * *


* ** *** * * ((30*h+0.5*m)>6*m)
* * * *** **** *
******** *** * ** * **** * ** * * ** **** = (30*h+0.5*m) - 6*m;
*** ** ** * *** * * * * *** ** * = 360 - ang1;
* * * **** ***** * * ** * (ang1 > ang2)
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**** **** * *** *
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** * ** **** *
* * * * *** ** * * *** ** * * = 6*m - (30*h+0.5*m);
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**** ** * * *** ** * ** * **** *
* ** ** * *** *** *** * * * ** **** * ** * * *** ** * **

   }
** * * ** ****** 0;

}
answered by (-42 points)
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Hidden content!
#include ** * ** ***
* * **** * * *



int * *


* *** ** * a ,b ,i;
**** ** ** * ** * c;


**** * *** *** * * * * * * *** ** *
** * *** ***** ** ** * * **** *** * ** * *


* * * ***** **** * * * != 12)
*** *** * * * = b*6 - b*0.5- a * 30;
* * * * *** ** *
** ** * * *** * *** = b*6 - b*0.5;


** **** ********* c * ** * 0 )
*** * ** * ** ** * * = -c;


** * **** ** ** ** *** * * c);



return 0;

}
answered by (-122 points)
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Hidden content!
#include ***** * * *



int main()

{
* ** ** * * ***  m=0,k=0,l=0 ,j ;
** ** **** * *** i;
* * ** * * ** ****** ** *** ** * *** **
****** ***** *** = i % 12 ;
** *** * * ***** =( i * 30 )+( j / 2) ;
* *** * **** * = j * 6 ;
* ** * * * *** =k-l ;
* ** ** * **** < 0)
*** * ** * **
* ** * * *** ** * *** **** * * * * = - m;
** **** ** * *
*** * ** ** * ** * * if(m > 180)
*** *** * * * **
* ** * ******* *** **** ********* = 360 - m ;
** * * * **
** *** ** ****** ** *****
** * * *** * *** 0;

}
answered by (-60 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* ***** * * * ****** * * a,b=0;
** **** * * * * ** * c,d=0;
******* * * * * *** ** ** * * * ** * * *
*** ***** * ***** * ** * * *** * ****** ****** * *
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* ****** *** ** * ** **
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    }
** ** ** * * * **** *** * ****
*** *** ****** ***** *** ** ** * ** * **** ** ** ** *** * * ***

    }
* *** * *** * *** 0;

}
answered by (-140 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** * * ** ** **** **** ** * * hour,min;
* ***** ** * * ** ** ** d,k,a1,a2;
**** **** * ** * * * * * *** ** * ** * * ***
** * ***** **** ** *** * (hour==12)
**** *** * ** * * * ** *** *** *
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*** * **** *** *** ** *** ** *** * *
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* * * *** ***
* *** * * ******** ***** 0;

    
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answered by (-122 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * ** ****** ** **** ** * a,b;
********** ** ** * * *** * * * * q,w,e;
*** ** * * * * ** *** * ** ***** * * * ** **
***** ********** ** *** ** * *

    {
* * * * ** ** ** * * ** * * ** * * ** == 0)
* * * ** ****** *** * ** *** ** * * = 6*b - b/2;
* * ****** ** * * ** * * ** ** * *** ** if(b%2 != 0)
* ** ** ** ** * * ** * * * * **** * * * * ** = 6*b - b/2 - 0.5;
*** * * ** * ** * * ** ** *** ****** * ***
* ** * * * ** ** * * **** *** *** * * ** * * = 360 - q;
**** * * * *** ** *** ** * **** * * * *** if(q<0)
***** ** * ** * * **** * *** * * ** ** ** * = 360 + q;

    }
***** **** ** * *** * ** *

    {
*** * * *** ******* * ** ** * ******* *** * ** * == 0)
*** * * * *** * ** **** **** * *** = 6*b - b/2 - 30*a;
* * * **** * ******* ** * *** **** ** if(b%2 != 0)
** * * ****** ****** ** ** * ** ** **** = 6*b - b/2 - 0.5 - 30*a;
**** * * * ** * * ** ** ** * * ** * ** ***** * *
** * **** *** * ** * **** ***** ** ** *** * = 360 - q;
* * * ** * * ** ** * ** *** *** * *** *** ** * if(q<0)
* **** * * * * * **** **** * * **** * * *** = 360 + q;

    }
* ** *** * ** *** * * * * * ** *** * ** * ** *** * *
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** * * *** * * * ** * ***** ***** if(w>q)
** ** ** * ****** *** * * * ** * * * * * * * * *** * ** * **** * * * ***
*** * * ** * **** **** * * **** ** ** ** ** = b%2;
* * * * ***** ** * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* * ** * **** **** a,b=0;
* ** * * * ** ******* * c,d=0;
* ** * * ********** *** ****** * * * * *** * * *
** *** * ***** ** ****** ** ** * * ** *** * * *
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*** * ** ** * ** *** * ** ** ** ** * *

    }
* * * * ** ** 0;

}
answered by (-140 points)
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