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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
by
Shun-Po
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Hidden content!#include <stdio.h>
#include **
#include <ctype.h>
#include <math.h>
#include * * * * *
int main(){
***** * ** * * ** h,m;
* * * * ** * * *** ** ** * ** * *** * ** * * * * *
** ** * ** * * * * * arch,arcm,sum=0;
* ** *** ** * ** * ** * * ** * ** * ** ** **
** * * * * * ***** *** * ***** ***** = m * 6;
* ** * * * * * ** = h * 30 + m * 0.5;
* ** ** * * ** ** ** * * > arch){
** * ** * * * * ** * * * *** * *** * ** * * *** ** * = arcm - arch;
** * * ** ** * ** *** ***** * ** * * * * * * ** ** * * ** * * * * * * ** *
* * * * * ** * ** *
** * * * * * * * * < arch){
* * * *** **** * * * * * *** ****** * * ** * ** = arch - arcm;
** * * * ** ** * ** ** * ** ** * * * * * * *** * *** * * ** * ** **
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* * * * *** ** *** ** **** * * * ** * * * * * * * * * * * * * * ** * *
* * * ** * * * *
** *** ** * * * * * ** ** * ** * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * * ** * *
#include * ** * * ** *
#include <ctype.h>
#include <math.h>
int main()
{
* * **** ** * ** ** ** * * * a,b,c,d,e;
* *** * * * * * * ** * * * * * **
* ** * * * * * * * ** * *** * * * * * ** **
*** *** * * *** * ** ** ** *
*** * * * * * * ** * * * * ***
* * * *** ****** * ** * * *
* * * ** * *** * * * * (c>=d)
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** * * *** ** *** * * *** * * ** * 0;
}
answered
Dec 1, 2016
by
410523016
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Hidden content!#include *** * * *
int main()
{
* * * * * * * ** ** * ** *** *** * * ,j ,n=0;
* ** ** * * * * * ** * i;
* * * * * * * * * ** ** * * ** * * ** * ** ** * * *
* * * ** * * ** * = i % 12 ;
* * * * * * ** * =( i * 30 )+( j / 2) ;
** * * * * ** * = j * 6 ;
* * * **** * * =k-l ;
if(m < 0)
* * * * * ** * **
* * * *** *** * * * * * * ** * * * * * * * *** = - m;
* ** ** * * * *
** * * * * * ** * * if(m > 180)
* * *** * * **
* * * * * * * * * * * ** * ** * = 360 - m ;
* * * * * * * * *
* ** ** * * ** * * ** *** * * * * * *
** * * ***** * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** ** * * * * * h,m;
* * ** * * * *** * * * ang1,ang2;
* * * * * * * * ** *** * ** ** * * * * * *
* ** ** * ** * ** ((30*h+0.5*m)>6*m)
** * * ** * * * *
* * ** * * * ** ** * * * * ** = (30*h+0.5*m) - 6*m;
* * ** ** * * * * * * * ** * = 360 - ang1;
* * * * ** * ** * ** * * * * * * (ang1 > ang2)
* * *** * * * * ** *** * * * * * * * ** ** * *** * * *** * * **
* ******* ** ** * * * * * * * **
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** * * *** * * **
** * * * * ** *
* * * *** * **
** ** * ** ** * ** *** * *** ** * * * *** = 6*m - (30*h+0.5*m);
* * * ** * * * ** ** ** *** * * * * * = 360 - ang1;
* * *** * ** * * ** * * * * * * * (ang1 > ang2)
** * * * ** * * * * * * * *** * * ** * * * ** * * ** ***
*** *** *** *** *** * * * * * * ** * * * *
* *** ** ** ** * ***** **** ** * * *** ** * * *** * ** * * *
}
* * * * * * * * * * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include ** ** * **
*** * ** *** ** * *
int *
* * * * * * * * * a ,b ,i;
* * * * * * ** ** * c;
*** ** * * * ** ** *** * * * *** * * ***
* * * * ** ** * * * * * * * * * *
* * * * ** * * * * != 12)
** * * * ** * ** * = b*6 - b*0.5- a * 30;
* * ** * * **
** * * ** * = b*6 - b*0.5;
* * * * * *** * * * c ** * 0 )
*** * * * **** * = -c;
** * * * ** ** * ** * * * * ** * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * * * * ** * *
int main()
{
* ***** ** * * **** * m=0,k=0,l=0 ,j ;
* * * ** * * * ** i;
* * * * * * *** * * *** * * * * *** * * * * **
** * * ** * = i % 12 ;
* ** * * * * * * ** * =( i * 30 )+( j / 2) ;
* ** ** * * * ***** * = j * 6 ;
** * * * * * ** *** =k-l ;
** *** ** ** * < 0)
** * *** * ** * ** *
** * * ** * * * * ** ** *** * * * * * * = - m;
* * ***** * *
******* * * ** * * * **** if(m > 180)
***** ***** * *
* ** * * * * ** * * * * * ** ** = 360 - m ;
* ** *** *** ** *** *
* * ** ** *** * * **** * * * * ** * **
* * ** * ** * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * *** * ** ** *** * * * * ** a,b=0;
**** ** * * * * ** * * ***** * ** *** c,d=0;
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* ** * * ** * * ****** * * ** ** * * * ** * ** ** * * ** *
}
* ** * ** * * * *** *
* ** * * * * ** **** ** * * ** * * * * * ** *** * ** *** * * * * * * ***
}
** * * ** * * * ** * ** * * ** 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** ** * * * * * ** hour,min;
* * * * * * * * * * * * d,k,a1,a2;
*** ** * * ** * * ** * * * ** * * ** * **** ** * * ** * * * * *
* *** ***** ** * * * * (hour==12)
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* ** * * * * * * * 0;
** ** * * * * * *
* * * ** ** * * * ** * *
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
*** * * * *** * * ** ** a,b;
* ** * * **** * * * *** * * q,w,e;
* * ** * * * * * * * * * * * * * * **** * * * * * ** * ** *
* * ***** * * * * ** * * *
{
* * ** * * * * * * * * *** * *** ** ** * * * == 0)
* * * *** ** * *** * *** * ** ** * ** * * ** * * * = 6*b - b/2;
** ** ** ** ** ** * * ** * ** ** *** if(b%2 != 0)
*** * ** ** * ** * ** * * * **** * * * ** * = 6*b - b/2 - 0.5;
* * * * * ** ** ** * * * * * *** ** * * * * * * * *
* * ** *** * * ** ** * * * ** * * ** ** * *** * * * * ** * = 360 - q;
* * * * * ** ** * *** * ** * * * * * * ** * ** if(q<0)
** * * * **** * ** * ** * * * * * ** ** = 360 + q;
}
** **** * * * * * *
{
** * * * * * **** **** *** ** ** * * * * * * ** ** *** == 0)
** * *** * * * * * * * ** * * * ** * * * ** ** * = 6*b - b/2 - 30*a;
*** * * * * ** ** ** * * ** * * * ** * ** ** if(b%2 != 0)
* ** * ** ** * * * * ** * * * * * * * = 6*b - b/2 - 0.5 - 30*a;
** * * * *** * * * * * * * ** **** * * * * * * * * ** * **
* * * ** ** * * * * ** * ** * * * * ** * = 360 - q;
* * * * ** * * * ** * * *** * **** * * *** * ** * * if(q<0)
* ** * * ** *** ** * * ** ** ** * * * **** * * * * = 360 + q;
}
* * * *** * *** *** ** *** * ** * * *** * ** * ** * * **
* * **** ** * ** * * * * * * * ** *** * **** * * * ** * * ***** * * ** * * ** * * * **
* * * * * ** * **** ** ***** * *** ** * * *** if(w>q)
* * * ** * * * * **** ** ** * *** * * *** * *** * * * * * ** * * * ** * *** * ** ** * * * *
* * * * * * * * * ** * * * ** ***** * * ** ** = b%2;
* * ** ** ** ** ** * * ** * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* ** * ** ** **** * * **** a,b=0;
** * * ** * * * ** * * c,d=0;
* ** * * ** ** * ** ** * * * * ** * * *** ** *** * *
* ** * ** * * *** * * * *** *** * * ***
* * * * * ** ** ** * * *** * *
* * *** * *** * ** * *
* * ***** * **** * ** * ** *
* * * * * * **** ** ** * *** ** * * * * * * * ** ** * * * * * * * * * * ** *
* *** ** * **** * ** *
** * *** ** * ** ** * * *
* *** * * * * **** * ** * * * * * * * * * * * * * * * * * * ** ** *
}
*** ** * *** **** * ***** * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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