0 like 0 dislike
3.5k views
時鐘上有時針有分針,分針每一分鐘跳一次,分針每跳一次時針也會前進相對應的角度。請設計一程式,由使用者輸入一個時間,程式會計算出時針與分針間的夾角後輸出。

輸入說明:輸入包含兩個正整數,兩個數之間由一個空白隔開,第一個數字代表時,第二個數字代表分。

輸出說明:請輸出時針與分針間較小的那個夾角。

輸入範例:

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 3.5k views

62 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** ** * * **

#include <ctype.h>

#include <math.h>

#include ***** * *



int main(){
* * * * * * ***** * * h,m;
*** ***** * * * * ** * ** * ** * ** ***** ******
* ****** * * * ** ** arch,arcm,sum=0;
****** **** * * * ** *** **** ****** *
* * * * ** * = m * 6;
* *** ** * ** = h * 30 + m * 0.5;
*** **** *** ** ** * > arch){
* ***** *** * ***** ** * * * * ** **** ** = arcm - arch;
** ** ** * * ** ** * * * ***** ***** ** ***** * ** ** * * * *
** * *** * *** ** *
* ** * * *** * *** * < arch){
**** * ** ** * **** * *** * * * * * * = arch - arcm;
*** * * ****** ** * ** ** * * *** *** ** * * ** ** *** *
***** ** * * * * * *
** * **** ***** * **** * == arch){
******** * ** * *** *** * * ** ** * *** * **** * * * *
** * * * * * * *
* *** * *** * * * ****** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include *** **

#include * ****** * *

#include <ctype.h>

#include <math.h>



int main()

{
* * * * * * **** ** * a,b,c,d,e;


* *** * * * *** *** **** ** ** * ** *
*** **** ** ** ** * ** * ** ** * ** ** **


** * * * **** * ** **
** ** * ** ** * ** * * * ** *


** * ** * ** *** * ***** ** ** ***




** *** * ****** **** (c>=d)
* * ** ** ** *** * ** *
******* * **** *** * * (c<d)
** ** ** * * ** * *


* ** * * * * * ** (e>180)
* ** * **** *** * ** * *




* * *** *** * * ** * * ** * * *
* * ** * * * *** * 0;



}
answered by (-136 points)
0 like 0 dislike
Hidden content!
#include *** * ***



int main()

{
** * *** * * **** * * * * * * * ** * ,j ,n=0;
*** * * * * ** ** i;
** ** * * * ** * * * ** * *** *** *
* * *** ** ** * = i % 12 ;
* *** * *** =( i * 30 )+( j / 2) ;
** * ***** = j * 6 ;
** *** * * * =k-l ;

if(m < 0)
** * *** * * * * **
**** * ** *** *** ****** ** *** * = - m;
** **** ** **
* * * * * * * ** **** if(m > 180)
** * ***** *
*** * *** *** * * * ** * = 360 - m ;
** * * * * *
* ** * ***** ** * ** ***** * ** ***
** * *** * ** * **** * 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** * ***** *** * h,m;
* *** * * * **** ang1,ang2;
********* ** * ** * *** ** * ***** ** * * * *


* * *** * *** * ((30*h+0.5*m)>6*m)
**** **** * ** *
* * * ** ** * * * *** *** = (30*h+0.5*m) - 6*m;
* **** ** *** * * * ** * = 360 - ang1;
*** * ** **** * * ****** * **** * (ang1 > ang2)
*** * **** * *** * * * ** * * * ***** * * * *** *
* * **** * * *** **** * *****
* **** * ** ** *** ** ** * * * * * **** * *** * * * * **
** * ***** **** **
* **** *** * * **
*** ** **
* ** * * ***** * ** ** *** * * * ** * = 6*m - (30*h+0.5*m);
***** ** * ** * *** ****** **** ** * = 360 - ang1;
** ** * * ** * * ** * * * * * (ang1 > ang2)
* *** * ***** ** * ** * ** ****** * * ** * * * * * * **
** ** **** * ** * **** ** * **
** * ** * ******* * ** ** * *** * ** *** * *** * * * ** * **** *

   }
*** * ** *** * 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * *** *** *
*** * ***** * * ***



int * ** *


** * ** * * ** a ,b ,i;
* ** * * ** *** c;


* ** *** * *** * *** ** ** *** **** ***
*** ** ** **** ** * **** ** * ** * ** * *


* * **** * ** * != 12)
** * * ******* ** = b*6 - b*0.5- a * 30;
* ** * *** * **** *
** *** * * = b*6 - b*0.5;


** * ******* * c *** 0 )
** * *** * * = -c;


** ** *** * * * * ** *** ** c);



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * **



int main()

{
* ** * * * **  m=0,k=0,l=0 ,j ;
* **** **** * ** * * i;
**** **** ** **** * * * ** *** * ******* **
* ** ***** = i % 12 ;
* **** ****** =( i * 30 )+( j / 2) ;
* * * * ** * ** * *** = j * 6 ;
* * * **** * =k-l ;
* ** * * ** * * * *** * * < 0)
** ** * ** * ***
* * ** * * * * * *** ** * ** = - m;
** * *** **** ** ** **
* * * *** **** if(m > 180)
** * * * * *
****** * ** **** **** * * * * *** = 360 - m ;
* * ******** * * *
* * ** ** ** **** ** * * * * * * *
* ** *** ** ** ***** ** * 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* *** * * *** * ** * a,b=0;
* * * * * *** * ** *** c,d=0;
*** *** * ****** *** *** *** *** *****
*** * * ** ** * * ** **** * *** *** * * * * *
** ** *** * * ** * ** ** ** ***
*** * ** * * *** ***
** * * * *** * * **** ******
***** * * * ** * * * ***
* ******* ** * * *** **** * *** ** ** * * ** * ** *

    }
* * *** ** * ** *** * *
** ******** * **** ** ** ** * * * * ** ** ** * ****** * *** *

    }
* * * ** * * ** **** ** ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** * ** * ** * * ** ****** hour,min;
**** * * * *** d,k,a1,a2;
** ** *** ** * * **** *** * * ** ******** *** *** ** * *
* ** ** ** * *** *** * (hour==12)
***** ** *** ** ** ** *
** * * **** ** * **
* * *** * * * * *****
* * **** ** * ** ** ** *

    
* * * ** *** ** * *** * ** * ** *
*** * ** *** ** **** ** * * * * * *
* ** ** * * * ***** *
* *** * ** * * ** *** * * ** ** *
***** * * * ***** **
* * *** * * * *

    
* * * * ** *** ****** *
* ** ***** *** * * ****** * * * **** * * * * **
* ** * * ****** ******
* * ** ******* * **** * **** * ** ***
***** ** * ** * * *
**** * * ** ** * ****** 0;

    
* *** ********
** * * **** *
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ***** * **** ** a,b;
* ** * * * ** ** * ** * q,w,e;
** * *** ** *** * * * **** ** * * ***** * ** * ** *
** * *** ** * * * *** ***

    {
** ***** *** ****** * * *** *** * ** * * * * ** ******* == 0)
** ** ** * **** * * * *** * * *** ** *** * = 6*b - b/2;
** * * ** ******* * * * ** **** * * ** * * if(b%2 != 0)
*** ** *** ****** *** * ** ** * **** *** * = 6*b - b/2 - 0.5;
** * * * * ** *** *** *** * * ** ** **** * *****
**** * * ** * ** *** ** ** * *** = 360 - q;
**** *** ** ** * *** * ** * ** * ***** * if(q<0)
*** **** * * * * * * ** ** * * * *** * = 360 + q;

    }
* * * ** **** * **

    {
******* ** * * * * * ** ** * ******** * == 0)
* * * * * * * * *** ********* * ** * = 6*b - b/2 - 30*a;
** * *** ** *** ** ****** ** *** ** ** ** *** if(b%2 != 0)
** **** * * ***** * ****** * * * * **** *** = 6*b - b/2 - 0.5 - 30*a;
* * * * * * ** ** * ** ** ** ** ** * * * *
**** * *********** **** *** * *** * ** = 360 - q;
* * *** ** * ** * * *** ** ** *** * * ***** * * if(q<0)
*** *** ** ** * ** * ** ** **** * * *** * *** = 360 + q;

    }
* * ** ** ** * **** ****** * * *** ** * *
*** *** *** * * * *** ** * * * * * ** * ****** ** * *** * **** *** * *** * * ** *
*** * * ** * ** **** **** *** ** * * ** * if(w>q)
** * *** ** * * * * * * ** ** **** * ***** * * * ** * * ** * ****** *
* ** * *** * ** * ** ***** ** * * * * = b%2;
** *** ** ** * * * *** * * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* * * * * * ** * * * a,b=0;
* *** * ** ** ** ******** c,d=0;
*** *** ** ** * * ** *** * * ***
** ** * ** ********* ** ** ** ** ** *** ***
** * * *** **** ** ** * ****
** * ** * * **** ***** ** * ***
* ** * **** *** ** *** *** * ***
* * * ** * ** * ** *** ** * * * * ** * **** **
*** * *** *** ** * *** ***
** * * ****** ** * * *
* * ******* * * ** * * * *** *** **** ********* * * *** *

    }
* * *** * * * ** ***** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.80
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 2.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users