Toggle navigation
Courses
Questions
Tags
Users
AC 20161201 第二次期中考 第二題
0
like
0
dislike
2.7k
views
時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18067 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
by
Shun-Po
|
2.7k
views
comment
Please
log in
or
register
to add a comment.
62
Answers
0
like
0
dislike
Hidden content!#include <stdio.h>
#include * ** ** ** * * *
#include <ctype.h>
#include <math.h>
#include * * *
int main(){
* * * * * **** * * h,m;
*** * **** * * **** * * * * * * * ** * * * *** ** *
* ** * * ** * * * *** ** ** arch,arcm,sum=0;
* * * * * * * **** * * ** ** *
* * ** ** ** ** * * * * ** = m * 6;
* ** * * * ** * * * ** * ** ** = h * 30 + m * 0.5;
* * * *** * * * * * * > arch){
**** *** * * ** * ** * * *** ** * * * * * * * * * * ** * ** * = arcm - arch;
** * * * * ** * ** ** * * **** *** *** ** ** * * * * ** * * * *
* ** * * * * * *** * *
** *** * ** ** * * * *** * * < arch){
*** **** * * * ** * * ** * ** * * * * = arch - arcm;
* * * * * ** * * * ** *** * * * * * * * * ** * * *
* ** * * * * ** ** * * *
* * *** * *** ** * * * ** ** * * * == arch){
*** * ** ** * ** * *** *** * * * * * * * * * ***
* * * ** * ** ** * ** * **
** * * * * * ** ** *** ** * * 0;
}
answered
Dec 1, 2016
by
loyfree0706
(
-216
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include ** *** ******
#include * * * ** *
#include <ctype.h>
#include <math.h>
int main()
{
* * * *** * * * ** * a,b,c,d,e;
**** ** * * * ** * * * ** *** * **** *
** * * ** ** * * *** * * ** * * * * * * ** * **** * *
* * * * * * ***** * **
* * * * * * * * * **** *
** ** * * * * ** * *** * ** * *
* * *** * ** * * * (c>=d)
* * * * * * * ** * ** ** *
* * * * * * * * * (c<d)
* ** * ** * * * * *** * **
** * * *** * ** ** * * ***** * (e>180)
** ** * **** ** * * *** *
* * * * **** *** *** * ** *** * * ** * ** **** * * *
* * ***** * ** * * * * * 0;
}
answered
Dec 1, 2016
by
410523016
(
-136
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include * ***** * * ** **
int main()
{
** * * * * * * * * * **** * * * ,j ,n=0;
** * *** * * * * ** * i;
** *** * ** * * ** * ** * * * * * * * * * *
* ** ** * * * *** * = i % 12 ;
** * * * * ** * * * =( i * 30 )+( j / 2) ;
** ** ** ** * * = j * 6 ;
** ** ** * * * =k-l ;
if(m < 0)
* * * *** * * ***
** * * * * * * * *** * ** * * = - m;
** ** * * * * *
* ** ** * * **** * if(m > 180)
**** *** **
* * ** * * ** * * * * * ** * = 360 - m ;
* * * ** * * ** *
* * * * ** * ** ** * * ** * **** ** ** * *
*** * * ** * **** ** 0;
}
answered
Dec 1, 2016
by
ert5179693
(
-60
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** ** * * * * h,m;
* * ** * * ***** * ** ang1,ang2;
* * * * *** * * * * * ** * * * * ** * * * ** * **
* * ** * * *** ((30*h+0.5*m)>6*m)
* * *** * * * * *
* * * ** * * * * *** * * ** ** ** * = (30*h+0.5*m) - 6*m;
** * * * * * ** *** * * ** * * * ** = 360 - ang1;
* * * * * * ** ** ** ** * (ang1 > ang2)
* * ***** * * * ** ** * * * ** * ** * * * ** ** ** * * * * *
** * ** * * * * *** * *** *** * * **
** * * **** *** * * ***** * *** * * * * *** * * * * * * *
* * * * * * **** *
* * * * * *** * * ***
* * * *** *
* * * ** * * ** * ***** * * * * = 6*m - (30*h+0.5*m);
** *** * ** * * * * * * * * * ** * = 360 - ang1;
* ** * * * * * * *** * * * * *** (ang1 > ang2)
* * ** * ** * * *** * * ** * * * * * * ** ** * *** **** ** **
** * ** * * ** *** * * * *
** **** * * * ** *** * ** * * * * * ** *** *** ** * ** * ** * *
}
*** **** * * * * ** 0;
}
answered
Dec 1, 2016
by
莊長穎
(
-42
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include ** **** * * *
* * * * * * * *** *
int **** *
*** ** * *** ** * * a ,b ,i;
** *** * ** * * * * * * ** c;
* *** * * * * * ** * * * * ** ** * * * *
*** ** * * * * * * ** ** * ** * **
* *** *** *** ** != 12)
* ** **** * * * ** ** = b*6 - b*0.5- a * 30;
* *** * **
* * ** * *** * = b*6 - b*0.5;
* * ** * * * * * * c ** * 0 )
*** ** * * ** **** = -c;
* * * ***** * ** ** ** *** *** * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include ** *** * *
int main()
{
*** ****** * **** ** * * m=0,k=0,l=0 ,j ;
* * **** **** *** ** i;
* * ** * * * * * ** * * ** *** * ** * * * * **
* * * * * ** * = i % 12 ;
* ** **** * ** * =( i * 30 )+( j / 2) ;
* ** * ** * ** * *** = j * 6 ;
** * * * * * * * * ** =k-l ;
*** * * * * ** * * < 0)
* * ** * *
* *** * * * **** * * * * * ** *** ** ***** * = - m;
* * * ** * *
*** * ** *** *** * ** * if(m > 180)
** **** *** * * *
** * * * * * * * * ** * = 360 - m ;
** * * * * *
* * * * * ** * * * * * * **
* * * * ** ** 0;
}
answered
Dec 1, 2016
by
ert5179693
(
-60
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
** * *** * * * ** * * * *** a,b=0;
* ***** ** ** * * * * * c,d=0;
* *** * * * ** ** * * * * *** * ** * *** *
* * * * *** * * * ** * *** ** * *** * *
* * * * * * * ** * * * * * * ** *
* ** ** * **
** * * **** * * * ** * * **
* ** * ** * ** ** * * * * * * * *
* ** * ** * * * * *** * * * * **** * ** * ** **** * *
}
** * * * ** * ** * * *
*** * *** ** * * ** *** * * * * * * *** * * ** * **
}
* *** * * * * * * ** * * * ** ** 0;
}
answered
Dec 1, 2016
by
SRFX
(
-140
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** **** ** * * * * * hour,min;
* ** ** ** *** ** *** * * ** d,k,a1,a2;
* * ** ** * * ** * * * * ** * * * * * * * * * * * * ** * *
* * * * ** * ** * ** (hour==12)
* * * * * * ** * * *
* *** ** * * * * * *
* * *** ** ***** * * ** ** * * * **
* * ** * * * * ** * ** ** * **
* * ** * * * * * * * ****** * * ** *
* ** ** **** * *** ** *** *
** * ** * * * * * * * * *
* * ** * * * * ** * *
* * * *** * * *
* *** * * * *** ** * * ** *
** **** ** **** * * * * * * *
* * * * * *** * * * * * * * ***** * *** **
* ** * * *** * * * * *
* * * * ** * * * * * ** ** ** * * * * * ** * * *
*** * ** * ** ***** * *
* * **** * * * * * 0;
* * * ** **** * * ** ** ** * *
** * * * ** * ******** * *
answered
Dec 1, 2016
by
Gulang
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
*** * * * * * * * ** * a,b;
* * * * * * * * * * ** q,w,e;
* * *** ** * * * * * * * * * * ** *** ** ** * *
* * **** * * * ** ** * * ** *
{
** ** ** * * * * * * * *** * * * * * ** ** * == 0)
*** * * *** ** ** ** ** ** * * *** * ** * ** * = 6*b - b/2;
*** * ** ** **** * * *** * * * * ** ** ** if(b%2 != 0)
** * * * * **** *** *** *** * * ** * *** ** ** * **** ** **** = 6*b - b/2 - 0.5;
* * * * **** ** ** * ** * * *** * ** * ** * * * ** ** * * *
*** ** * * *** * ** * ** ** * * * * * = 360 - q;
* * * * * * ** * ** * * ** ** * * * * * if(q<0)
* * ** ** * ** * ** * * * ** * ** * * **** ** * = 360 + q;
}
* *** * ** * * * ** * * **
{
* ** * * * ** ** * ** * * * **** * * * * * * == 0)
* * ** ** * * * ******** * * ** * ** ** * = 6*b - b/2 - 30*a;
* * *** * * ** * ** * * ******* ** ** * ** ** * * if(b%2 != 0)
* *** ** ** * * * ** ** * * * *** **** ** = 6*b - b/2 - 0.5 - 30*a;
* * * * * * *** * * * ***** * *** ** ** * * * *** * *
* ** * * * * * * **** ** ** * * ** * * * * * = 360 - q;
* * * * * ** * ** * * * * * *** ** ** if(q<0)
* * * * * * * * * ** ** * * **** * * * ** = 360 + q;
}
***** * ** * ** ** * * * * * * * * * ** * ** *
* * * ** * * * ** ** * * * *** * *** * ** * * * * * * * ** * * * * * ***** * ** * ** ** * * * * *
* * * * *** ** * ** * * * * *** * *** if(w>q)
** * * * * * * * ** ** * ** * * ** * * * ** ** * *** ** * * *** * ** * ** ** *** *
* * *** * * * * * * * * * ** * * *** * * * * * * * = b%2;
* ** * * * *** ** ** * 0;
}
answered
Dec 1, 2016
by
410323020
(
-85
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * * ** * * * * * a,b=0;
* * ** * ** * * * c,d=0;
** * *** * * * * * * * * * ***** * * * **** * ****
* *** *** * ** * * * * * ** * * * * * * * * * ***
* * * * * ** * *** ******* *** * **
** * ** ** * * * *** * * * **** *
** * * * * * * ** * * **
* * * ** *** * * * * ** ** * * * * * ** * * * ****** ** * *
* * * * * * * *** * * ** *
* ***** *** * * * * * ** ** * **
* ** * * * *** ** * *** * * * * * * *** * ** * * * *** * ** * *
}
* * * * * ** * * * * * 0;
}
answered
Dec 1, 2016
by
SRFX
(
-140
points)
ask related question
comment
Please
log in
or
register
to add a comment.
Page:
« prev
1
...
3
4
5
6
7
next »
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English
中文
Tiếng Việt
IP:172.69.58.76©2016-2024
Related questions
0
like
0
dislike
16
answers
AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18075 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
|
946
views
0
like
0
dislike
86
answers
AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18071 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
|
3.4k
views
0
like
0
dislike
49
answers
AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18070 -
Available when:
Unlimited
-
Due to:
Unlimited
|
2.1k
views
0
like
0
dislike
21
answers
AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18066 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
|
1.1k
views
0
like
0
dislike
0
answers
AC 20161201 第二次期中考公告
[Resource]
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18085 -
Available when:
Unlimited
-
Due to:
Unlimited
|
10
views
12,783
questions
183,443
answers
172,219
comments
4,824
users