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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include ** ** * * *
#include <ctype.h>
#include <math.h>
#include ****** * * *** * *
int main(){
** * * ** *** * * * * * h,m;
* * ** * * ** * **** * * * * * ***** ** * * * ** *
* ** *** * * *** ** ***** * arch,arcm,sum=0;
* ** **** ***** * *** ** * * * * * * *
* * * * * * ** * ** * * * * ** = m * 6;
* * * ** * **** ** * * * ** = h * 30 + m * 0.5;
** * * * * ** ** * * * > arch){
* ** *** * ** * * * * * * * ** = arcm - arch;
* * * * * * * * * ** ** * * * * * ** * ** *** * * * *** * ** * ***** ** **
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** * ********* * * * * * * * < arch){
* *** ** * ** * * * * * * * *** * * ** * *** * * = arch - arcm;
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** ** * * ** * * ** *
** * ** * ** ** * * * ** ** ** * * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * ** * * * * *
#include *** * ** *
#include <ctype.h>
#include <math.h>
int main()
{
* * ** * * * * * ** * * *** a,b,c,d,e;
* * * ** *** ** * ** * * * **** ** * * ** * *
* * ** ** * * ** ** * *** ** * * * ** * * ** * *
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}
answered
Dec 1, 2016
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410523016
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Hidden content!#include * * * * * ***
int main()
{
** * * ** * * * ** * * ** ** * * * * ,j ,n=0;
** * * * * * ** i;
* ** ** * * * * ** * * * * * ** * * * * * ** *
* ** * * ** = i % 12 ;
* * * * * * ** =( i * 30 )+( j / 2) ;
* * * * * * * ** = j * 6 ;
** * *** ** *** * * * =k-l ;
if(m < 0)
* *** * ** * *
* * * * * ** * * * * * * * * * * * = - m;
** * * * ** * ***
* * *** * * * * if(m > 180)
** * * * ** ** * *
** * * * * *** **** * * * * ** * * = 360 - m ;
* * * * ** * * * * **
* * ** * ** * *** ** ** * ** *
* * *** ** * * * ** * * * ** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * ** *** * * * * * h,m;
* ** *** ** * ang1,ang2;
*** * * * ** * * * * * ** ** ** * ** *** **** ** ** *
* ** * * * * * * * ((30*h+0.5*m)>6*m)
* * * * ** * * **
* * * * **** **** * * * ** *** ** *** = (30*h+0.5*m) - 6*m;
* ** * * *** * *** * * * * * ** ** * = 360 - ang1;
* * * * * * * ** ** * * *** * *** * * ** (ang1 > ang2)
* * * * * * **** *** * * * * * * * * * * * * * * * * * *
* **** *** * * * * * * * * *
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* * * ** ** * *
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* * * * * * * ***
*** * * *** *** ** * * * * *** * * = 6*m - (30*h+0.5*m);
** * * * ** * **** * * * * * * * ** = 360 - ang1;
* *** * * * ** * * * * * * ** ** * (ang1 > ang2)
** * * * * * * **** * * * * *** ** * * *** * ** * *** * * *
* * * **** ** * * * * * * **
** * * * ** * * ** * *** * * * * ** * * * * * * * * * *** *
}
* ** * *** * * ** 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include *** * * *
* * * * * * *
int *** *
* * * ** ** * *** ** ** **** a ,b ,i;
* ** ** *** * * * * * c;
* ** * * * * * * ** *** * ***** * * ** *
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* * * * * * ** * ** != 12)
* ** * ** * *** * * = b*6 - b*0.5- a * 30;
* * * * * ** ** ***
*** * * * * * = b*6 - b*0.5;
* ** * * * * * ** * c * ** 0 )
** ** * * * * ** * = -c;
* *** * * ** ****** * ** * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * * ** * * * *
int main()
{
** ** ** * * * * * m=0,k=0,l=0 ,j ;
* * * * *** * ** * * i;
* * * *** *** * * * * * * * * * * ** * * ** *
* ** * * * * ** *** = i % 12 ;
** * * * * ** =( i * 30 )+( j / 2) ;
* ** * * * * * * * * = j * 6 ;
* * * * ** * * * =k-l ;
*** ** * * * ** ** * < 0)
*** *** ** * *
* * ***** * * * ** ** * ** * *** ** * * = - m;
** * * * ** * * * ** *
* **** ** * * **** if(m > 180)
* * ** ** *
* * * * *** * ** *** * * * * * = 360 - m ;
* * * * * * * * * *
* * ** * * *** ** ** ** ** * ***
* ** * ** * * **** *** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
** * * * ** ** ** * * a,b=0;
** *** * ** *** * * * * ** c,d=0;
* * * ** * * * ** * * * *** * * ** * **** **
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}
** * ** ** **** * **** * *
* * ** * * * ** * * * ** ** * * * ** * * ** ** * * ***
}
** * * ** * * * * ** * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** ** * * * * ** * * * * ** * hour,min;
*** * * ** * * * * d,k,a1,a2;
* * * * * * * ** * * * * * * ***** ** * *** * * * * * * **
* * * ** ** ** * * ** *** (hour==12)
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** * * ***** *
** * * * * * * **** ** 0;
* * * * * * *** ** *
** * * * * ** *
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * **** ** ** *** * a,b;
* * ** * * * * * ** * * *** q,w,e;
* ** * * ** *** ** * **** * * ** ** * * **** ** ** ** ***
* * ** ** * * * * ***
{
* ** ** *** * ** ** * ***** * **** * * ** * ** * * * ** * ** * == 0)
* ** * * * * ** *** ** ** ** *** ** *** * ** **** = 6*b - b/2;
** * * * * * * * ** ** * * * * ** * ** *** * if(b%2 != 0)
* * * * * * * * * * * * * * * * * * * ** * * * ** * *** * = 6*b - b/2 - 0.5;
** * * * * * * * * * * *** ** * * ** * * * **
* ** * *** **** * * * ** * ** * * * * * ** * **** * = 360 - q;
* * * * ** * * ** * * * ** * * * * * ** * * * if(q<0)
* *** ** * ** *** ** ** *** * *** * * * * ** * * = 360 + q;
}
* * ***** ** * * * * * ** *
{
* * * * * * ** * * * ** * * **** * * * * ** ** ** *** == 0)
* **** * *** * ** * * * * ** * * * ** = 6*b - b/2 - 30*a;
* ** * * * *** * ** * * *** * * ** ***** ** * * if(b%2 != 0)
* * ** * * ** * * ** ** * * * * * *** ** * * * = 6*b - b/2 - 0.5 - 30*a;
** *** * * **** * ** * ** * * *** ** **** ** * * * * * *** * * **
* * * * * * * ** * * * * * * * * * ** = 360 - q;
** ** * * * * * *** * * ** * ***** ***** ** * * if(q<0)
* * * ** * ** * ** * ** * ** * *** ** *** = 360 + q;
}
** * * ** ** * * * * * *** * *** ** ** * *** * *** * * *
* * * * ** * * ** * * * * * * *** * **** * **** **** ** * * **** * ** * * * **** * ** *
* ** * * * * ** * * ** * * * * ** *** if(w>q)
* * * * * * * * * * * ** ** * * * * ** * * *** * * * * * ** ** ** * * **** ** ** *
* * * *** ** ** * *** * * * * * * ** * * * = b%2;
* ** * *** * * ** * * * * * * ** 0;
}
answered
Dec 1, 2016
by
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * ***** * *** * ** *** * a,b=0;
* ** *** ** ** * *** * * *** c,d=0;
* * * * * *** ** *** * ** ** * * * ** * *
**** * * *** * ** * * * * *** *** * * * * * * * **
* * * * ** *** * ** * * *
* * * * * * * *** * ** *
* * * * * ** * *** * * ** *****
* ** *** * * * * ** * * * * * * * * *
** * * * *** ** * ** ****
** ** * * * * * * * *
* ** * * * ** ** * *** ** * ** * ** **** *** * * * * * *
}
** *** * *** * *** ** ** * ** 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
points)
ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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