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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * * * ** * * *
#include <ctype.h>
#include <math.h>
#include * * * * * * **
int main(){
* *** * * * * *** * h,m;
* * ** * ** * * ** **** * * * * *** * * * ** * * ** ** * *
* * * * * * ** * ** * **** ** * arch,arcm,sum=0;
* ** *** * * * ** * ** * *** * * ** *
*** * ** * * ** * * ** * = m * 6;
* * * * * * * *** * * ** * * ** = h * 30 + m * 0.5;
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** ** * * ** * * * * **** *** ** ** * * * ******* * * * = arcm - arch;
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* ** ** ** * * ** * * * * *
** * * * * * ** * * ** * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include ** *** * *** *
#include ** ** * **
#include <ctype.h>
#include <math.h>
int main()
{
* * * **** * ** * * ** ** a,b,c,d,e;
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}
answered
Dec 1, 2016
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410523016
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Hidden content!#include *** * * ** *
int main()
{
* * * * * * * ** * ** * * * *** ,j ,n=0;
* * * * *** ** * * * i;
* **** ** ** * *** * * *** * ** * ** * * **
* * * * * ** = i % 12 ;
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* * ***** * * = j * 6 ;
* * * * * * ** * * * =k-l ;
if(m < 0)
*** * * * ** * **
* * * ** * * * ** ** * * * * * * * * * = - m;
* * ** ** * * ***
* * * * ** ** if(m > 180)
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* ** * * * * * * * * * * * ** * ** = 360 - m ;
* * ** **
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** * * * * ** * *** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * *** * h,m;
*** * * ** * * ** * * * ang1,ang2;
* *** * * * * ** * * * * ** ** ** * * ** ** *
** *** * * * * **** ((30*h+0.5*m)>6*m)
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* * * **** * * * * * * * * ** ** = 360 - ang1;
* * * * * ** ** * * * * ** * (ang1 > ang2)
* * * * * ** *** * * *** ** * * * * * ** ** * * ** * * *
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* * *** **** ** * ** * ** * * ** *** * * * (ang1 > ang2)
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** * ***** ** * * * * * * ** * ** * *
* * ** * * * * * ** * * * * * ** *** * ** ** * * ** * ** * *
}
* * * * ** * **** * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * ****** *
***** * * * ** **
int ** ***
** * * * * ** a ,b ,i;
* ** ** * * * *** * * ** c;
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* * ** *** * * * * ** * ** != 12)
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*** * * * ***** * = b*6 - b*0.5;
* ** * * * *** * *** c 0 )
* ** * * * * * * * = -c;
* * * *** ** * * ** * * * * * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include ** * * **
int main()
{
** * ***** ** ** ** * * m=0,k=0,l=0 ,j ;
* * * * * * * ** *** i;
* ** ** * * * ** * * * * *** * ** * ** * * * *
* * * * * ** * *** = i % 12 ;
* ** * * * * =( i * 30 )+( j / 2) ;
** * ** * ** * = j * 6 ;
* ** * * ** ** =k-l ;
*** * * ** * * * * < 0)
* * * ** **** ***
*** * * ** * * * * * * ** *** * = - m;
* * ** ** ** *** *
* *** *** *** * if(m > 180)
* * * **** * ** *
* ** * ** ** * * * * * * * = 360 - m ;
* * * *
* *** * ** * * * * * * ** * ***** ** ** ** *
* * * * * ** * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
*** * * * ** * * * * a,b=0;
* * ** * ** ** ** * * * c,d=0;
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}
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}
** * *** * * * * * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** ** * ** * hour,min;
** * * * * * * * * * * * d,k,a1,a2;
* ** ** ** * * * * * * * * ** * *** * * ** ** * * * * * *
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* ** * * * * * * * * *
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answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * **** *** * ** * a,b;
** **** **** * ** * *** * q,w,e;
** * * * * *** ** * * *** * ** **** *** * ** * **
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{
* * * * ** * * * ** ** * ** ** *** * * * ** * ** == 0)
* * ** *** * * * * ** **** ** * * * * ** * * * = 6*b - b/2;
* * ** * * * * ** * * * * ** * ** * * ** * if(b%2 != 0)
* ** * * * * ** * * *** * ** * * * **** * = 6*b - b/2 - 0.5;
* * ** ** * * *** * *** ** * ** ** * ** * * * * *
** * * * * * ** * * * * * *** * * * ** * * * ** * * = 360 - q;
*** ** * ** * * * * * * * * * ** * * ** * * * * if(q<0)
* * * * * ** * * * * * * *** ** * * * ** * * * * = 360 + q;
}
** * ** ******* * * **** * **
{
* *** * * * * * * ** * ** * * * * * * * * * == 0)
* ** * * ** *** * * * ** * * *** * * *** * * * ** * * * = 6*b - b/2 - 30*a;
** *** * * ** * * ** * * *** * ** * ****** * if(b%2 != 0)
** * ** * ** ** * * * * * ** ** * ** ** * = 6*b - b/2 - 0.5 - 30*a;
* * * * ** * * * ** ** * ** * ***** ** ** * * ** * ** ** * *
* * *** * ** **** * ** * * * * * * * * = 360 - q;
* * * * * * ** * * * * ** ** * ** * ** ** * ** if(q<0)
* * * *** * * *** ** ** ** ** ** ** * * * ** = 360 + q;
}
* ** * ** * ** ** * * * *** * * * * * ** **** * **
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* * * * ** ** ** * * * * * ** * * * * *** ***** ** if(w>q)
** * * *** * * * * * * *** ** ** * * * *** * * ** ***** * ** * * ** * *** * * * * ** * * * * ** * * *
* * ** ** ** * ** * * * * ***** * * ** *** ** * = b%2;
* * * *** ** * * * * * * * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* ** ** * * * ** * * * * * a,b=0;
* * ** * * * ***** * * * c,d=0;
* * * * * ** ** ** * *** * * * * ** * *
* ** ** * * ** * * * * * *** * **** * **
** * * * * ** * * * ** * * ** * * * * * *
* * * * * * * * ** **** * **
*** * * ******** * * * * * * *
*** ** * * * * * * * * * ** * * * * * ** **** * * ** * * * * **** *
*** * *** * ** * * * ***
* ** * * ** * * * * * *
** * *** *** * * * ** * * * * * ** ** ** * * * * * * ** * * **
}
* ** ** ** * * ** * ** *** 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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