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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
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Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
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Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * * * * *
#include <ctype.h>
#include <math.h>
#include ** * ** ** * ***
int main(){
* * * * * ** * * * h,m;
* * * * ** * * * ** * *** ** * * * * ** *
*** * * * * *** * * ** * ** * arch,arcm,sum=0;
****** ** * * * ** * ** ** * ** **
** ** * ** *** ** * * ** ** = m * 6;
* * * ** * * * * * * * = h * 30 + m * 0.5;
* ** * * ** * * ** *** * * > arch){
* * * ** * * * * * * * ** * ** *** * * * * * * = arcm - arch;
**** * * * * * * * * * * * * * * ** ** * * * * * * * * * ** *
* ***** ** * * *
* * ** * ** * * * * ** * * < arch){
* * ** * * * ** * * * ** * ***** * * * * * * * = arch - arcm;
* ** * * *** ** * * * * ** * * * * * * * ** *** *** * ** * **
* * ** * ** * * ** *
* * ** * *** ** * * * * == arch){
** * * ** * * * * * * *** * * ** ** *** * *** * *** * * * * * * *
** * **** ** *** * *
**** **** * * * * ** * * * ** 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * *** * ** * *
#include ** ** * ** *
#include <ctype.h>
#include <math.h>
int main()
{
** ** * ** * * ** * * * * a,b,c,d,e;
*** * * ** * **** * * ** * ** *** * * **** * * * *
** * * * *** * * ** * * * * ** * ** **
* ** *** * * ** * * * ** **
* * **** * ** * * * **
* *** *** **** * * *
** ** *** * * * * ***** * * (c>=d)
* * ** * * * ** * * * **
** * ** * *** * ** * * ** * (c<d)
* ** * * * * * * * ** * *
* ** ** * * * * ** **** (e>180)
* * * * ** * ** ** * * **
** * * * * * * * * ** * ** * ***
*** * ** * * * ** *** * ** * 0;
}
answered
Dec 1, 2016
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410523016
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Hidden content!#include * * ** *
int main()
{
* ** ***** * * ** *** *** * * * * ,j ,n=0;
* * * ** * * ** * ** *** * ** i;
* * ** ** * *** * ***** * * ** * * * * * ** ***
** ****** * * * ** = i % 12 ;
** ** * * * *** * =( i * 30 )+( j / 2) ;
* * * * * ** * ** * = j * 6 ;
* * * *** * * ** ** =k-l ;
if(m < 0)
* * * * * ** * * *
** * * * * * * * * * **** *** = - m;
* ** * ** * * *
* * * *** ** * ** * * if(m > 180)
* ** * * * * ** * *
* * * ** * * ** * * * * * * ** ** = 360 - m ;
* * * * *
* * * * * * * ** * * * * * * * * ***
* * *** ** * * ** * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** * * ** ** *** ** h,m;
**** * * * ** * ** * ang1,ang2;
** * * * * ***** * ** **** * ** * * ** * ** * ** **
* * * * * ** * *** * * ((30*h+0.5*m)>6*m)
* *** * * * * ** * **
* * * * * ** * **** * * *** * ** **** * * = (30*h+0.5*m) - 6*m;
** ** * * * ** * ** * * * * *** = 360 - ang1;
* *** * * ** ** * * * * * ****** * ** * * *** (ang1 > ang2)
* * * ** * * * * ** * * * ** * * * * * * * * * * * * * * * * * ** *
* * * * * ** * ** * * * ** ** ** * *
* ** * **** * * ** * * * ** * * ** *** * ** * ** * ** * * ** *** * * * *
** * * * * *
*** * * ** * *
**** *** * * * * ** * *
** ** * * * * ** ** *** * ** *** = 6*m - (30*h+0.5*m);
** * * ** * **** * * ** * * * * * = 360 - ang1;
* *** * * * * * * ** ** * * ** * (ang1 > ang2)
* **** * * * * * ** ** ***** * *** * * * * * * ** *** * * * *
*** * ** *** * ** * * ** ** * * ** * *
* * * ** * * ** ** * *** * ** ** * * * * ** * ** * * * * * *** * *
}
* * * * ** * * * * * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * * * * *
* ** *** * *
int * ** *
* ** * * ** ** * a ,b ,i;
* * * * * * * * * c;
** ** *** * * * ** * * * * * * ** * * **
** * ** * * *** * * * ** * * *** * * * ***
* * * ** * ** ** ** != 12)
* * * ***** * * * = b*6 - b*0.5- a * 30;
* * ** * * ** * * *
**** * ** ** * * = b*6 - b*0.5;
* * *** * c * * 0 )
* * * ** * * * * * ** ** = -c;
* * * * * * ** ** * ** * ** * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * * *
int main()
{
** * * ** * * * * * * m=0,k=0,l=0 ,j ;
* ** * * * * * ** * i;
* **** ** *** ** * * * ** * * *** * * ** * * * * * ** *
* * * ** * ** * * * = i % 12 ;
* *** * * * * * * * ** =( i * 30 )+( j / 2) ;
* * ** * * ** = j * 6 ;
* * *** * *** * * * =k-l ;
* * * * * * ** < 0)
* * * * *** * *
* *** * * * * ** ** ** * * ** * * * = - m;
* * * ** ** * ** * ****
** * *** ** *** if(m > 180)
* * * * * ** * * * *
* * **** * *** * * * * * ** * ** = 360 - m ;
** ** ** ** * * **
** * * ** * * * * ** **** * *
*** * * * * * *** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * *** * * * * * * * * *** * a,b=0;
* * * * * *** * ** ** * ** * c,d=0;
*** ** *** * ** **** * *** * * * * * * * ***
* ** ** * ** ** * * ** * * ** * * * * * * **** * ****
* * * * ** * * * * * ** * *
* ** ** ******* * ** * * *
* *** * ** *** * ** * * * *** * * *
** * * * * ** * *** * ** * *** *
** * * ** * ** * * * ** **** *** * ** * **** * * * ** * * ** * *
}
* ** * * * * * ** * * ** * * * *
* * * *** * * * *** ** ** * * ** * * ** * *** ** *** * * *** * * * *
}
*** *** * ** * * ** * * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** ** * * ** * ** * ** * *** hour,min;
*** * * * * * * ** * * d,k,a1,a2;
* * ***** * * * * * ** * *** * * * * * * * ** * ** ** * ** * *** *
* * * * ** * * * ** (hour==12)
** *** * * * ** ** * ** *** *
* * * * * * ** *
** * * ** ** ** *** * * ** * * * *
* *** ** * * ** ***** * ** * * * **
* * * * * * ** ***** * * * *
** * * **** ** * * * ** * * * * **
* * * *** * * **
** * * ******* * * * * * * ** **
* * * * * *** * * **** *
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* * **** * * * *** * * * * * * * * ** *** ** * ** ** *
* * * * ** * * * * *
* ** * ** *** ** * * * * ** * * **
* ** * * *** ** * * *** * **
** * * * * * ** ** 0;
* * *** * * **
* * ** * * * * * * * **
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * * *** ** * * ** * a,b;
* * * *** ** * * ** * * * * * q,w,e;
** ** *** * *** ** * * ** **** * * ** *** ** * * * * * * * *** *
* * ** * ** * * * **
{
** * * ** * * ** * * ** * * *** ** ** == 0)
* * * * * * * * ** *** *** * *** ** * * * * = 6*b - b/2;
* * ** * ** * * *** *** * * ** * **** ** ** if(b%2 != 0)
* * * * * * ** ** ** * **** **** * * * * * ** ** * * *** = 6*b - b/2 - 0.5;
* * ** ** * * ** * * * ***** * * * ** * ** ** * *
* * * ** * * * * ** ** * *** * * * * * * * * = 360 - q;
* * * * * *** * * ** ** * ** * ** * * if(q<0)
* * ** * * * **** **** * * * ** * * * * * *** = 360 + q;
}
* * * * * * ** * * *** ***
{
* * * *** ** * *** ***** * * * * *** * ** * ** * * ** ** * ** == 0)
* * * * * * ** * * ** * * ** * ** * ** ** * * * = 6*b - b/2 - 30*a;
* * * * ** * *** * * * * * ** * * * * * * if(b%2 != 0)
*** ** **** * * * * ** ** ** * * * * * * * = 6*b - b/2 - 0.5 - 30*a;
* * * * *** ** ** * * * * * * * * * ** * * * ** * ** **
** * * ** ** * * * * * * * ** ** * ** * * *** = 360 - q;
* * * ** ** * * ** * ** * * *** * * ** ** * if(q<0)
* ** * * * ** * * ** * * * ** ** ** * * * * = 360 + q;
}
*** * * ** * * ** * ** ** * * * * * ** * * * * *
* * * ** ** ** * * * ** * * * * * * ** * * ** * * ** **** *** * * *** * * * * * * * * * * **
* * * * * * * * ** ** ** * * ** * if(w>q)
* * * ** ** ** * * * * * ** ** * * * * * ** * * * * * * * * * ** * * * * * ** *
**** * * ** * * ** * * ** * ** ** ** * * = b%2;
** * ** * * * * * * * ** 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
** ** ** * * * a,b=0;
**** *** * ** * * * ** * c,d=0;
* * * **** * * * ** * * * * * ** ** ** *** **
* * ** * * * * ** * * ** * * * * * * * ****** *
** * * * * * * ** * * *** ** ** *
* ** *** ** * ** ***
* * ** * * * ** * * ** ** *
* * * * * * ** * * * * * * * * ** * ** * ** ** * * * * *** ** ** ***
***** ** * * * ******
* * * * * ** * * * * * * **
* * ** * * * * * * * *** ** ** ** * * * * * ****** ** * * ** * *
}
* * * * * *** * ** *** * ** 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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