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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
by
Shun-Po
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Hidden content!#include <stdio.h>
#include **** * *
#include <ctype.h>
#include <math.h>
#include ** * * * * * * **
int main(){
* * * ** *** * * **** ** * ** * h,m;
* * * * * * ** * * ** * * * * * *** * * * *
* * ** * * * * * ** * * * * * arch,arcm,sum=0;
** * * * * ** ** * *** * ** *
* ** * * *** * **** * * * * = m * 6;
** ** ** * * * * * * = h * 30 + m * 0.5;
** * * * * ** * * * * * * > arch){
* * * * ** * * * ** * * * * * * * * * = arcm - arch;
** ** * **** * * ********* * * ** * * * ** ** ** * ** * ** ** * * * * * *
* * * * **** * ** * * *
* * ** * * * * ** **** * < arch){
***** ** * ** *** ** * *** ** * **** ** * * * ** * * * = arch - arcm;
* * * * *** ** ** ** * * ** * ** * * *** * * * * *** ** * * **** * **
*** * * * * ** * *
** ** * ** * *** * * ** * * ** * == arch){
* ** * **** * ** * * * **** * * ** ** *** * * **** * * * * ** * ** ** * * ***
* * *** ** ***** * ** ** *
** * * * *** * * * * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include ** *** **** ** * *
#include * * * *
#include <ctype.h>
#include <math.h>
int main()
{
* * * * * * * * * * ** ** a,b,c,d,e;
** ** ** *** * ** * * * * * ** * *** **
* * * *** *** *** ** * * * * * * * * ** * ** **
******* * ** * ** ** *
* ** * * ** * ***
* * * *** ** ** * ** *
*** *** * * * ** ** * * (c>=d)
* * ** * * *** ** * * * * * *
* * ** * ** * * * (c<d)
** ** * * * * ** * * ** * ** **
* * * * * * * * * ** * * (e>180)
* * * ** ** * ** * * * ** * * *
* * * * * * ** * ** * * * ** * ** * *** ** * *
* ** * * *** * * ** **** * 0;
}
answered
Dec 1, 2016
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410523016
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Hidden content!#include * ** * *
int main()
{
* ** * * * * **** * * * ** * ,j ,n=0;
* * * * * * * * i;
* * ** * * * * * * * * ** * ** * * * * * **
** ** * * * * * * = i % 12 ;
** ** * * ** * * * =( i * 30 )+( j / 2) ;
* * * * ** ** * ** = j * 6 ;
* ** ** * * * * *** =k-l ;
if(m < 0)
* ** * * * * *** *
* * * * *** * ** * ** ** * * * * = - m;
* * ** ** * * ** * *
** ** * * * * * * * if(m > 180)
* ** * * * *** *
* **** ** * ** ** ** * * ** * * ** * = 360 - m ;
* * ** *** ** *
* ** * ***** * * * ** ** * *** * * ***
** * * * ** * ** * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * ** h,m;
**** * * * * * * * **** * * ang1,ang2;
** ** * * ** *** * * * * * * * * * * ***
* *** * * * *** * ((30*h+0.5*m)>6*m)
* * * * * ** *
** * * ** *** * ** * * * * *** * * * * ** = (30*h+0.5*m) - 6*m;
* * * * * ** * * * *** ** ** * * * * ** * * = 360 - ang1;
* * * * * ** * ** ****** * * * * * (ang1 > ang2)
* * *** * * * * ** * * * **** * * * **** * **
* *** * * * * ** * * ** * * * **** * * *
** * ****** * * * * * * * * ** * * * * **** * * * ** * ** * * ** *
*** * * ** * ***
* * * * *
* ** * *
* * * * * ** * *** ** * ** * * * * = 6*m - (30*h+0.5*m);
** ** * * * ** **** * ****** = 360 - ang1;
* * * * * ** * * * ** * * *** * * **** *** (ang1 > ang2)
* * ** * * * * * *** ** * ** * ******* * * * * * *** * * * * * *
***** * * * * *** * *** * * * * ** *******
** * * ** * * * * ** ** * *** * ** * *** * * * * * * * * * ** * * *
}
** * * * * *** * * * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include ******* * * *
* * ** * * * * * *
int * * *
* * ** * * * * * ** a ,b ,i;
*** ** * * c;
* * * ** *** * * * * ** * ** *** * * ** * * **
** * ** * ** * * * * ** * * * **
**** * * ** * != 12)
* ** * * * * * = b*6 - b*0.5- a * 30;
** * * * * * * * * * *
* * * * * ** = b*6 - b*0.5;
** * * ** * * * * * c ** ** 0 )
* * ** * * * ** * * = -c;
* * * * * * * * ** ** * * * * * * * * * *** c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * * * * * * * **
int main()
{
* * ** ** * * * *** m=0,k=0,l=0 ,j ;
** * * * * i;
* * * * * * * * * * **** * * ** * * * ** * * *
* * * * * * * = i % 12 ;
* ** **** * * * ** * *** =( i * 30 )+( j / 2) ;
*** * * ** * * * * * = j * 6 ;
* ** ** * * =k-l ;
** * * * * *** * * ** < 0)
*** * * * * * * * *
** * ** ****** * *** * * * ** * * ** ** = - m;
* * * * ** * * ***
** ** * * * * * * if(m > 180)
* ** * * * *
* * * ** * * * * * ** * * = 360 - m ;
* * ** * * ** ** *
* * * * * * *** ** *** * ** * * * * *** * **
* * *** ** * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * * ** * ** *** a,b=0;
* * * * ** * ** ** * * * * c,d=0;
* ** * ** * * ** * * * * * * * * **** * * * *
* *** * *** * * *** * * ** * *** * * * * *** * *
* **** * ** *** * ** * ** ** ** * * *
*** * ** ** ** ** * ** * **
* ** * * * * * * * * * **
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* ** *** ** *** * * * * * * ** * * * * * **
}
* * * ***
** * * ** ** * *** ** * *** * * * * * ** * * * ** ** ** * * *
}
** * * * ** ** *** **** ** * * * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * **** * ** * * *** hour,min;
* * * * *** * * * ** *** d,k,a1,a2;
** ** * * * * * ** * * * ** * ** * * * * ** *
** * ** * * ** * * ** * *** * (hour==12)
* * ** ** * * * * * * * **
*** * * * * ** * * * **
* ** ** * *** *** *** * ***** * ** * **
** * * ** ** ** ** * *** * *
* ** * ** *** ****** * * * **** * **
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* ** * * * * * * ** ***
** ** * ** * * ** ** *** * * 0;
* * * * * * * * * ** *
**** * * * * * * * * *** * **
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* *** * * ***** ** * * * a,b;
* *** ** * * * * ** * *** * q,w,e;
* ***** * ** * * ** * **** * * * * *** ** * * *** * * * * * *
** * * ***** * * ** * * * * * ** *
{
* * * ** * *** * ** * * * **** **** * ** ** **** * * * == 0)
** * * * ****** * * ** * ** * ** ** * *** * = 6*b - b/2;
* * * ** *** * * * * * * *** ** ** ** *** * ** if(b%2 != 0)
* * * * ** * * * ** *** ** ** * * * * ** * * = 6*b - b/2 - 0.5;
* * * * ** * * * * * *** ** * * * * * ** * ** * ** **
* * ** ** *** * ** * * ** ** * * *** ** * * * ** = 360 - q;
* * * * * *** * *** ** * ** * * * *** ** * * * * *** if(q<0)
* * * * * * * * ** * * * * * * ** *** * = 360 + q;
}
* * * ******* * * *
{
* * * *** ** * * ** * * * * *** **** * * * * * * == 0)
******* * * * ** ** * *** * * * * * *** * * * * ** ** = 6*b - b/2 - 30*a;
** * ** * * * ** * * * * ***** * * * * * ** * if(b%2 != 0)
* ** ** * ** ** ** * ** * * * * * ** * ** ** ** * ** * = 6*b - b/2 - 0.5 - 30*a;
**** ** * ** * * * * *** * * * * * * * * * ** * * *
* * ** ** * * ** * ** * * ** ** * = 360 - q;
* * ** * * * *** * ** * * **** * ** * ** **** **** if(q<0)
** * ** * **** ** * * * * * * * ** **** ** * * ** ** = 360 + q;
}
*** * *** * * * * * * * ** * ** * * * * * *
* ** * * * *** * * ** * * ** * ** ** **** * * * * * * *** ** * ** ** *** ** * * *
* ** ** * * * * * ** * * * * * * ** if(w>q)
** * * * *** * * ** * ** * * * * * * * * ** * * * ** * * * * * * * * * ** * * * * ** * * * * *
* ***** ** ***** * * *** ** ** * * ** ** * * * * * = b%2;
* *** ** * * * * * *** * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
** ** * * * * ** * *** a,b=0;
* * ** * ** * **** ** c,d=0;
* * * ** ** ** * * * * * ** * * * * * * **
* **** **** * * ** * * * * * * * * ** * * * *
* * * * **** * * * * * *** **** * **
* ** **** ** * * * ** *
* * * ** ** * * * * ** ** ** * * **
***** * ** * * * * ** * * * * * * * * * *** *** ** * * * * * ** * **
* * * * * * ** ** *
* * * * * * * *
** * ** * **** * * ** * * * * ** * * * * ** *** * * * * * * ** * *
}
*** * * * ** * ** * * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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