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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * ** * *** *
#include <ctype.h>
#include <math.h>
#include * ** * ****
int main(){
* *** * * * ** * * * * * * * * h,m;
* ** ** * * ** * * * *** * * * ** * **** ** * * * ***
** * * ** * ** * * * * * *** * arch,arcm,sum=0;
*** * * * * ** * * * * * * * * ** * *
* * * * * ** * ** = m * 6;
* * ** * * *** *** ** ** * * = h * 30 + m * 0.5;
* * ***** * * * ** * * * * * ** * > arch){
* * * * *** * * *** *** * * * ** * * * * ** * * = arcm - arch;
* * * ** * * * * * * ** * *** *** ** * ** ** ** * * *** * * * ** * *
* ** * * * * * * * ***
* * * * **** * ** * * ** < arch){
** * * ** * * * * * ** ** * * * * * **** *** ** = arch - arcm;
* * * ** * *** *** **** *** * * ** * ** ** * * *** * * * **
** * ******* * ** ** *
** * * *** *** ** * * ***** * * ** == arch){
** * ** * * * * ** * ** *** **** * * ** * * * * * * ** * * *
* ** * * * ** * ** * * *
*** *** * * * * *** ** ** 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include *** ** * *** * *
#include ** * ** ** *
#include <ctype.h>
#include <math.h>
int main()
{
* * *** * * * ** * * a,b,c,d,e;
** * ** * * * * * * ** * ** ** ** * * * ** * **
* * * * * ** * ** * ** ** * * * * * *
* * * * * * * **** * ***
* * * * * *** * * * * * * *** *
* *** ** * * * * * *** * * * * * *
***** ** * * * ** (c>=d)
* ** * *** * ** * * *
* * * * * * *** *** * * * * (c<d)
* * * * * * * * * **** *
** * * * ** ** * ** (e>180)
* * *** * * * ** * *** * **
*** * * ** ** * * * * ** ** * * ** * * **
** * * * *** ** * * * **** * *** * * 0;
}
answered
Dec 1, 2016
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410523016
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Hidden content!#include * * * * * ** *
int main()
{
* * * * * ** * * ** * * *** * ** * ,j ,n=0;
* * ** * * * ** *** * i;
** * *** * * ** ** * ** ** * * * * * * * *
* * * *** ** ** * ** = i % 12 ;
* * * ** * ** * *** =( i * 30 )+( j / 2) ;
* ** ****** * ** * * = j * 6 ;
*** * * ** ** ** =k-l ;
if(m < 0)
* * ** * * * * **** * * *
* * * * * *** **** ** ** ** * ** ** = - m;
** * * * * * ** **
** * ** * * if(m > 180)
* ** **** * * *** *
* * ** * * * * *** * ** * ** * * = 360 - m ;
** * * * *** * *
* * ** * *** * * * * *** ** * *** *
** * * * * * ** * *** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * *** * * * h,m;
* * * * *** * * ** * ang1,ang2;
* ** * ** * * * * ** * * * * * * * *
** *** * ** * ((30*h+0.5*m)>6*m)
* * * * * *** * **
* ** * * ** ** * ** * * * * * * * = (30*h+0.5*m) - 6*m;
* * * ** **** * *** * * ** ** * * * * * ** = 360 - ang1;
* * * *** * * * *** * * * * * * * * (ang1 > ang2)
* * * * * * * * ** *** * * * * * * * **** * * * * ** * * **
*** ** * * * * *** ** * * * * **
** ** * * ** * * * * ** ** * ** * * ** ** * * * * ** * * ** ** * **
*** * * * **
* * ** * * * **** **
* * * ** ** * *
* **** **** * * * ** * * * * * * * *** = 6*m - (30*h+0.5*m);
* * ** * ** ** * * * * ***** * ** * *** = 360 - ang1;
**** * * * * * * * * ** * * *** * (ang1 > ang2)
** ** ** * *** ***** * * ** * * * * * * * * ** * ** *
* * * * * * * ** ** * * * * * **
** * * ** * *** * * * **** * * * * * **** * * * ** ** * *** * *
}
* * *** * ** * * * ** 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * * * *
* * * * * ** ***
int *
* * * * * ** ** a ,b ,i;
* * * *** * * * c;
* ** * ** ** ** **** *** ** ** * ** **
* * * * **** ** * * * * * ** * * *
* ** * ** *** != 12)
*** * * ** * *** **** = b*6 - b*0.5- a * 30;
*** * * * * * ** *
** * * * * ** ** = b*6 - b*0.5;
*** *** * * ** * * c * 0 )
* * ** * * ** * * = -c;
* * * * * * * * ** * *** *** ** ** * *** * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include **** * ** *** *
int main()
{
* * * ** ** ** * * m=0,k=0,l=0 ,j ;
* *** ** * ** * *** ** **** i;
*** * * * * * * * * * ** * * * **** * * * ***
* * * * * * * *** * = i % 12 ;
** ** **** ** ** ** ** =( i * 30 )+( j / 2) ;
* * ** * * * * * = j * 6 ;
** * * * ** * * =k-l ;
** * * *** * *** < 0)
*** ****** ** * * * **
* * ** * * ** * * * * * ** ** * = - m;
* *** ** * **
* * ** * * * * ** ** if(m > 180)
* * * **
* ** **** * * * * * * * * * * * * ** = 360 - m ;
* * *** * * *
* * ** * * ***** * ** * ** * *** * **
* * * * * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
*** * * ** * * ** * * * a,b=0;
* * * * ** * * * * * * ** * * * ** c,d=0;
* * * * ** * ** * *** * ** ** * *
* * * * * ** * * ** * * ** *** ** ** ** * *
* ** * * ** ** ** ** ** * *** *
* * ** ** ** * * * ** * * *
* **** * * * * * ** * * * ** *
* * * * * * * **** * *** * *
* * ** * * * * * * * * ** * * * * * * * *** * * ** * *** ** **
}
**** * * * * ** * * * * * *
* * ** * * * * ** ** * * * * * * ** * ** ** * * * * * * * * * * * ** *
}
**** * *** * * * * * * *** **** 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** * * * * *** * hour,min;
* ** * * * * * * * *** d,k,a1,a2;
* * * * * * ** **** *** * * *** *** * * *** *** **
* * * ** * ** * * * ** * (hour==12)
* * * ** *** ** * * * **
* * * ** * *** * * **
* *** ** *** ** * * ** * * ** ***** *
** * ** * * * * * * ** *
* **** * * ** * * * * * * ** * * * *
* * ** * * ** * ***** * ** *
* ** * ** * * * * * *** ***
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* * * * ** * * * * **
* * *** ** * * ** * **** * * * * ** * ** * * * *
* ** * * * ** ****
* **** *** * * ** * * 0;
** *** ** * * ** ***
** * *** *** **** ** ** *
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * * * * ** * * a,b;
* * ** *** ** * * ** ** * * * q,w,e;
***** * * * * * * ** * ** ** * ** * * ** * **** *
* **** * * *** ** ** * * *** ***
{
* * ** * * * ** * * ** * * * * * * * *** * * * ** == 0)
** * ***** * * * * ** * * * ** ** * * ** ** * * = 6*b - b/2;
* * * ** * * * * *** *** * * *** * * * * ***** if(b%2 != 0)
* * **** * ** * *** * *** * * * * *** * ** * * * *** = 6*b - b/2 - 0.5;
* * * * ** ** * * * * * ** ** * * * * * ** * * ** *** ** * * ** * *
** * * * ** * * ** *** * * ** * ****** ** * ** ** * ** * = 360 - q;
* * ** * * ** * ** * * ** * * * ** * if(q<0)
* * * * * * * * * ** ** * * * * * * *** = 360 + q;
}
* *** * ** ** * * * * ** * *
{
* ** * ** * * * * ** ** * * * * ***** * * * == 0)
*** * * * *** * ** * * * * * **** * ** *** = 6*b - b/2 - 30*a;
* ** * * * * * * * **** * * **** * ** * ** * *** * * if(b%2 != 0)
*** * * * * * * ** * * * * ** * * * ** = 6*b - b/2 - 0.5 - 30*a;
* **** *** * * * * * *** ** *** * * * * ** ** * *
** ** ** *** * ** * * *** * * ** * * * ** * **** * ** * * * = 360 - q;
* * * ** * ** * * *** * ** * * * ** * ** ** if(q<0)
*** * ** ** *** * *** * * * ** *** * * * * ** * * * = 360 + q;
}
** *** * * * ** *** *** * ** *** ** * ** * * ** *** * ** * * ** * * * *
* * ** * ** * *** * ** ** ** * * * * * * * * * * * ** *** ** * * * * * * * **** * * * ** * * * ** * **
** * * **** ** * ** * * * * if(w>q)
* ** *** * *** ** * ** ** * * * *** * * * * * *** * * * * * * * ** ** * * * * * *
** ** **** ** * * * *** * * * * * * * **** * ** * ** = b%2;
* *** * * ** * ** * *** ** 0;
}
answered
Dec 1, 2016
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * *** * * * * * a,b=0;
* * ** ** * * * * ** c,d=0;
* * ** * *** ** * * * ** * ** * * * * * * ** ***
* * * * * * ** * * * * *** * * * **** * * * *
* * ** * ** ** *** *** * ** * * * * * *** *
* *** * * ** *** **
* ** ** * * * * * *
* * * * * * * ** * ** *** * *** *** * * * **** * * * * * * ** * ***
* * * * *** *** * *** * * **
** * ** ** ** ** ** * * **
* * * * * ** * * * * * * * * * * * *** ** * * ** * * * **** *
}
* * ** * ** * ** 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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