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時鐘上有時針有分針,分針每一分鐘跳一次,分針每跳一次時針也會前進相對應的角度。請設計一程式,由使用者輸入一個時間,程式會計算出時針與分針間的夾角後輸出。

輸入說明:輸入包含兩個正整數,兩個數之間由一個空白隔開,第一個數字代表時,第二個數字代表分。

輸出說明:請輸出時針與分針間較小的那個夾角。

輸入範例:

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 12k views

62 Answers

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Hidden content!
#include <stdio.h>

#include ** ** ***

#include <ctype.h>

#include <math.h>

#include ***** ******* ***



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}
answered by (-216 points)
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Hidden content!
#include * * * * * *

#include ** *** * * *

#include <ctype.h>

#include <math.h>



int main()

{
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}
answered by (-136 points)
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Hidden content!
#include *** * * * *



int main()

{
* **** * ** ** *** ,j ,n=0;
* *** *** ** ** * i;
* ** * * ** ** ** * * * * * ** * ** *
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* * * * * =( i * 30 )+( j / 2) ;
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if(m < 0)
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*** * * *** *** * * * ** * *
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}
answered by (-60 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
*** * * * * h,m;
* *** * * * ** ang1,ang2;
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** * * * ** **
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**** ** ** * * * *** *** ** = 360 - ang1;
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}
answered by (-42 points)
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Hidden content!
#include ** * * * *
** * **** * ***



int ***


***** * * ** * * ** * a ,b ,i;
* * * * * * * c;


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** ******* * * * ** * c ** * 0 )
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* *** ** * ** * c);



return 0;

}
answered by (-122 points)
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Hidden content!
#include * * ** *



int main()

{
* *** * * *  m=0,k=0,l=0 ,j ;
* ** ** * ** * ** i;
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}
answered by (-60 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* * **** * ***** ** **** a,b=0;
*** **** **** **** ** * ** c,d=0;
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    }
*** ** * * * ** * * ** * 0;

}
answered by (-140 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** *** ** ** ** ** hour,min;
* * ** * **** **** * * * * * d,k,a1,a2;
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answered by (-122 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** *** * ** *** * a,b;
* * ** *** * * ** * * q,w,e;
* * ** * ** *** * *** *** ** ** ** **
*** * ** ** ** * * ****

    {
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*** * **** ** ** ** * * * ** * *** ** if(b%2 != 0)
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* ** *** ** *** *** * * *** * ** ****** * ***
* * ** *** * *** **** *** *** ****** ***** = 360 - q;
* * * * ***** ** * * * ***** **** * ** ****** if(q<0)
**** ** * * *** ** * ** *** * * * * * * = 360 + q;

    }
* ** * * * ** * * ***

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* ** ** ** * * ** * ** * * ***** *** ** == 0)
* ** ** * ** * * **** * * * * ** * * * = 6*b - b/2 - 30*a;
**** ********* ** * ** * * * *** * * * * if(b%2 != 0)
***** * * ** * ** **** * *** ***** *** * = 6*b - b/2 - 0.5 - 30*a;
** *** ***** *** *** * *** * * * **** * ** ** ** *** *
* ** * ** * * ** ** ** * **** = 360 - q;
** ** * * ***** * * ** ** * * ** * * ** if(q<0)
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    }
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* * ****** ******* * * *** ** * **** *** = b%2;
*** *** ** **** * ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* *** ** ** ** * * * *** a,b=0;
* * *** ** *** *** ** **** c,d=0;
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    }
* **** * ** * * 0;

}
answered by (-140 points)
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