0 like 0 dislike
4.3k views
時鐘上有時針有分針,分針每一分鐘跳一次,分針每跳一次時針也會前進相對應的角度。請設計一程式,由使用者輸入一個時間,程式會計算出時針與分針間的夾角後輸出。

輸入說明:輸入包含兩個正整數,兩個數之間由一個空白隔開,第一個數字代表時,第二個數字代表分。

輸出說明:請輸出時針與分針間較小的那個夾角。

輸入範例:

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 4.3k views

62 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** * **

#include <ctype.h>

#include <math.h>

#include * ** ** **



int main(){
****** * * *** ** h,m;
***** **** ** * * * ** *** ** ** ****
* * * * * * ** ** *** ***** arch,arcm,sum=0;
* * * * ** *** ***** *** **
** ***** ** ** * * * = m * 6;
* * * ****** ** *** * ** * * = h * 30 + m * 0.5;
* * * * * **** * * ** > arch){
*** * * ** * *** * ****** * * * ** * ** * *** * = arcm - arch;
**** * *** * * * * ** *** ** ** ** * * ** **** * ** ** ** *
** ** ** ***** * * **
* * * ** * * * * *** *** * < arch){
***** * * * * * * * *** * ** ** * = arch - arcm;
*** * * * ** * **** *** * * * * * ***** * ** ** * * ***** *
*** ** * *** * * ** **
** * **** ** ***** *** == arch){
* ** * * ** * **** ** * *** * * * ** *** ** ** * * * * *** *
** ** * * ** *** * * **
* * **** * ** ********* ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include * * * * **

#include * ** * ****** *

#include <ctype.h>

#include <math.h>



int main()

{
* * * * ** ** * * ** * * a,b,c,d,e;


* * ** ** ** *** ** * *** *** *** *** ** **
*** ** ** * ** * ** * * * * *


** **** * * ** *** ** *
*** * * * ** * ** ** * ***


* ** * **** * *** ******** *




* ***** *** * * ****** * (c>=d)
* **** * *** *** * *
** *** ** ***** *** * * (c<d)
***** ** * * ** * ***


*** * ** ** ** (e>180)
* ** ** *** *** ** ********




* ** *** * ** * * * ** ** ** * * ***
** * *********** * *** *** 0;



}
answered by (-136 points)
0 like 0 dislike
Hidden content!
#include * *** *** *



int main()

{
* ** **** ****** * ,j ,n=0;
** ** * * * * i;
*** ** * ** ** *** * * ** * * * * *
**** ** * * = i % 12 ;
***** *** * * * * =( i * 30 )+( j / 2) ;
** * * * * * * * = j * 6 ;
** ** ** * *** *** =k-l ;

if(m < 0)
*** * * ** *
** ** ** **** ** * ** ** * = - m;
** * * * ** ******
* ** * * *** * ** if(m > 180)
**** ** * ***
* * ****** * *** *** * * ** * = 360 - m ;
* *** * * * * *
* **** ** ** ** *** * * ** ***** **
* ** *** * **** * 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* *** ** * *** * h,m;
* ******** * *** * ang1,ang2;
** ** ** ** ** * * * * * **** * **** * **


** * ** * * * ((30*h+0.5*m)>6*m)
** * * *** ** *** *
* * *** **** * * ***** * *** * *** = (30*h+0.5*m) - 6*m;
* * * * * * * **** **** ** = 360 - ang1;
* *** * ** * * ** * * (ang1 > ang2)
** * * * * * * ** * * * ** ** *** ** *** * ** **** *
* ** * * *** * *** * ** *** *** * * ** **
* * * ** *** *** * * ** **** * * *** *** * * * * * * **** ** *** * *
* **** ** ** *******
*** *** ** * ****** *
* * ** ** * ****
* *** ** * * * *** ** * * = 6*m - (30*h+0.5*m);
*** ** *** *** ** **** * ** * = 360 - ang1;
** ***** * ****** *** * ** (ang1 > ang2)
********** * *** *** * **** * * * * *** ** * **
*** *** ** * * ***** * **** *** ** *
* ********* * * * *** * * * ** ** *** ** * * ******* * * ** *

   }
* * * * **** * *** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * * * *** **
* * * ** * *



int ** *


** ** * * ** **** * a ,b ,i;
* *********** ** c;


* ********* * **** * ** * ** **** * ***
**** ** * * ***** * * ** *** **


* *** ** *** != 12)
** *** * ****** = b*6 - b*0.5- a * 30;
* ** **** ** ***** **
* ** * * * ** * = b*6 - b*0.5;


* *** * c * ** 0 )
********* * * = -c;


** * *** * ** ** * ** * * ** * * * c);



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** *** * **



int main()

{
* * ** ** ** **  m=0,k=0,l=0 ,j ;
* * ** * *** *** i;
*** * ** * ** ** *** * ** * ** ** * * * *
*** **** ** * = i % 12 ;
** * * ** * =( i * 30 )+( j / 2) ;
** ** * *** * ** * = j * 6 ;
** ** * * ** * *** =k-l ;
* * * ** ******** ** < 0)
** ** *** * *
** * * * *** ** * ** ** **** = - m;
* * ** * * **
* * * *** * * if(m > 180)
* * **** * * * *
* * ***** ***** * *** *** * ***** = 360 - m ;
** ** * **** ***** **
** * ** ** ** **** ****** * * ****
** *** * * ** *** * * * 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* ** * * * * ** ** * * a,b=0;
* * * * ***** * ** * * * c,d=0;
* * * * *** ** ** * ** *** ***** * *
****** ** ** ** *** *** * * * *** * ** * * *******
**** * * * ** * * * ** ***
* * * * ** ** * * * *
** * * ** *** *** * * ** ***
**** ** * ** **** **
* **** * **** * * ** * ** ** * * ** * * ** *** ***** * * *

    }
***** *** ******* ** * *
* ** * *** * ** * * *** * ** * * * *** * * * **** * ** * ** **

    }
* * * **** ** * * *** * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * * * * * *** ** ** * hour,min;
* * ** *** * ** d,k,a1,a2;
*** * *** * * *** *** * * * *** ** * * * *** *** * * * *
* * *** *** ** * * * (hour==12)
** * ******* * *** *****
* ** * ********** *** *
**** ** * * * ** * * * **
*** ** * ** **

    
*** *** * ******* ****** ** *
* * **** * ** * * * * * *** * *
** * * * * ****
* ** ** ** **** *** ** * ******
* *** * *** *** * *
* *** * *** ** * ** *

    
** * * ***** * ** * * *** *
* * ** * ** * *** * ****** *** * * *** ** ** *
*** ** *** **** * *** *
** * ** * ** *** ** ** ** * ** * ** * ** *
** * * * * **** *
* * *** * * * *** * * * 0;

    
* ** * * * * * **
** ** ***** * * ** *** * *
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** * *** * *** * * a,b;
* *** * *** q,w,e;
* *** ***** *** ******* * * * ** * *** ** *** *
** * * *** ***

    {
***** **** * * *** ***** * * * * **** ** * * == 0)
*** * * ** ** ***** * *** * ****** * * * *** = 6*b - b/2;
****** ** ** **** * ** * * * **** * ** * * ** if(b%2 != 0)
** **** **** ** **** ** * ** *** * * * * ** = 6*b - b/2 - 0.5;
* * * * * ** *** * * ** *** * * * ** **** ** *** *
* * *** *** ** * * * ** * * ** * * = 360 - q;
* ** *** ********** *** **** **** * ** * * if(q<0)
* * ******* ** * **** ** * ** * ** ******* * * = 360 + q;

    }
** *** * **

    {
* * ** * * ** ** * *** ** ** * * * == 0)
* * * * *** ** *** * *** ** * * ** = 6*b - b/2 - 30*a;
* ***** *** ** * * * ******** *** * * * * if(b%2 != 0)
** *** ** ** *** * * * ** * * * * ** ** = 6*b - b/2 - 0.5 - 30*a;
** * **** * * * * ** * ** * *** ** * ***
* *** *** * ** *** * * *** * ** * * **** ***** = 360 - q;
* * * *** **** ***** ** * *** * ** ** if(q<0)
** ** * ***** * * **** * **** * * ** * * ** = 360 + q;

    }
* * ** * * * * * * ** ** **** * * * ** * * * ***
** * ** ******** *** * **** * * *** ** *** ** ** ** *** * * ** ************ *** * * *
* * **** *** *** * * * *** * * * **** * * * * * if(w>q)
** ** * ** ** **** * ******* * * *** * ** * * * ** * * * ** * * * ** * ** **
**** ** ** * ** ****** * ***** ******** ** * * ** = b%2;
*** * * *** **** * *** * * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* * * ****** ** * ** * * **** a,b=0;
* * * *** * * ** * c,d=0;
* * *** * ** ** ** ** * * ****** *** ** *****
** * ** * * * ** * ***** * ** **
* * ** ** ** ** *** * ** * ***** * * *
* ** * **** ** * * **** *
* * * ** ** ** ****** **
** ****** *** **** * * * * * * ** * *** * * ****** * ** * ***** * ** ***
* ****** * * * * *
** * * * * * ** ** * *
**** *** * * ** *** * * *** * * *** ** *** * ** ** ** ******** **

    }
** ** * ** * * * * 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.117
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.8k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.5k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 3.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users