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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
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Dec 1, 2016
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Hidden content!#include <stdio.h>
#include * * ** **
#include <ctype.h>
#include <math.h>
#include * ** ** * * *
int main(){
* * * * ***** * * * * ***** * h,m;
* * *** * * * * * ** * * * ****** *** * * ** *
* * * * * * * * * *** ** ** * * ** arch,arcm,sum=0;
* * * * * **** * * * * * * ** * ***
** ** * * * * * *** * * ** = m * 6;
** * ** * ** *** * ** * * = h * 30 + m * 0.5;
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* * ** ** ** * * * ** * * * * * * * ** ** ** = arcm - arch;
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* ** * *** * * * ** * * * ** * * ** *** ** * ** = arch - arcm;
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* **** * * * ** *** * * ** * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include ** * * * *
#include * ** * *
#include <ctype.h>
#include <math.h>
int main()
{
** * *** ** * * ** * * a,b,c,d,e;
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}
answered
Dec 1, 2016
by
410523016
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Hidden content!#include * * ** * * *
int main()
{
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* ** * ** * ** * * i;
** ** * * * * * ** * * * * ** * * * ** * * * *
* ** ** * * *** = i % 12 ;
* * ** * ** ** * =( i * 30 )+( j / 2) ;
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* *** * ** ** * * =k-l ;
if(m < 0)
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*** * * ** ** * * * *
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** * * * * * ** * * * **** * = 360 - m ;
*** * * * * **
* * * *** * * * *** ** ** * ** * ** ****
** * * * ** * **** * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * *** * *** * h,m;
* * * ** * * *** * ** * ang1,ang2;
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}
* ***** **** * ** ** * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * ** **
*** * ** ** ** **
int * * ** * *
*** * * ** * ** *** ** a ,b ,i;
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* * * ** ** * * * * c **** 0 )
* * * ** *** *** * * = -c;
*** * * * *** * * * * * * * * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include ** * ** ** * ***
int main()
{
* * * * * * * * * * * * m=0,k=0,l=0 ,j ;
* * * * * ** ** i;
* * * ** * * * * * *** * * * * ** * * ** ** * * *
** * *** * ** * = i % 12 ;
* * * ** * * * * =( i * 30 )+( j / 2) ;
* * ** ** * = j * 6 ;
* * * * ** =k-l ;
* * *** ** * * < 0)
** * ****** * * * *
** * **** * *** ** ** * * ** * ** * * * = - m;
* * * * ** * * ** * *
* ** *** ** ** * * * if(m > 180)
* * *** * *** ** * **
** * * * ** * * * ** *** * = 360 - m ;
* * ** * * * ** * **
* * * * **** * * ** * ** * *
* * * * ** * * * * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
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* * * * * * ** * * * * * * c,d=0;
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}
** ** * ** * ** * * * * *** * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * ** * * *** * * * hour,min;
* * * * * ** * * * *** d,k,a1,a2;
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* * * * ** *** * ** *
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answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * **** ****** * ** a,b;
*** * * * ** **** * * * * q,w,e;
** * * * *** * ** * ** * ** ** * ** * * * * * * *
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{
* * * ** * *** * * ** * * * * ** ** ** * * * ** * == 0)
* ** ** * * *** * * * * * *** * **** * * ** * * * * = 6*b - b/2;
* * *** * ** * * ** * * * * ** ** **** * * * ** if(b%2 != 0)
* ** * * ** * * * * * * ** * * *** ** = 6*b - b/2 - 0.5;
* ** * * * *** *** * ** ** * * ***** ** ** * * ** *** * *
* * * * * ** * * * *** * * ** * * * = 360 - q;
* ** ** * ** *** ** * * * ** * * * ** * * ** *** if(q<0)
*** * ** *** *** ** ** * * * * * * * ** * * *** = 360 + q;
}
** * ** * ** * ***** *** * *
{
* ****** * * * * * * ** * *** * * *** **** ** == 0)
* * *** ** ** * *** * * * * * *** * * = 6*b - b/2 - 30*a;
* * * * ** * ** * * * ** * * ** * ***** * * * * * if(b%2 != 0)
* * ** *** *** ** * ** * * ** ** * * = 6*b - b/2 - 0.5 - 30*a;
**** * * * * ** * ** * * * ** * ** * ** * ** ** * * * *
** *** * ** * * * * * * * * * **** * * * ****** = 360 - q;
* ** * * * * ** * * * * ** * ** * * ** * * *** *** * if(q<0)
** ** * *** * * ** * *** ** *** ** ** ** *** = 360 + q;
}
** **** * * * * ** * * * ** * ** * ** * *** * * * * * *
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* ** * ** * * * *** * *** * ** * * * * * **** * = b%2;
* * *** * *** *** *** * *** 0;
}
answered
Dec 1, 2016
by
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
** * * * *** ** * * *** * * * * a,b=0;
***** * * * * * * * * * * c,d=0;
* * **** ** ** ** * * ** * *** ** * * * * ** * **
* **** ** ** * * *** * * * ** * * * * ** * * **
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* * * * * * ** ** *
** * *** * ** * *
* * * * ***** * * ** * ** ** * * * ** * ** *** * *** * * * * *
}
* * * * * ** * * *** * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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