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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
** ** * * * * * * * **** a,b=0;
** * * * * * ** * * ** * * *
* * ** * * *** * * * * *** *** * * ** * * * * * * ** = b+a;
* * * ** ** ** * * *** **** * * * * * * ** *
* * * * ** * * * * * * ***** ** * * ** **
** * * * *** * ** **** ** *
* ** * *** * ** * ** * ** *
int main()
{
* * * *** ** * * * * num;
** * * *** ** * ** * * * * ** ** * * ** *** * * *
* * * * * * * * * * **
* * * * * ** *** * *
* * * * ** * * * ** *** *
*** * ** * * * * * * * * * * * * *** * ** ** *
* ** ** * ** * ** ** **** 0;
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* **** * ** * * ** * * ** * *
** **** * * * * * ** *** *
* ** * * *** *** *** ** *
* * ** ** * * * *
** * * *** *** * * **
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* *** * * * * * * *** * i,n,fi,last1 = 1,last2 = 1;
* **** *** * * * * * * * * ** *** * *
**** * * * * * ** ** * * ** *** * ** * * *** * ** * *
* * * * * * ** ** *** ***
*** * * ** * * ** ** * * * ** * * ** == 1||n == 2)
* * ** ** **** * * * * ** * * * * * * * ** * * *
* * * * * * ** ***** ** *
* * ** * ** ** *** ** * * * * ** *
* * ** ** * * * * * ** * * * * = 3;i <= n;i++)
* * *** * * * * * * * * * * * * * * + last2;
* ** *** ** *** * * * * * *** * * = last1;
** ** * *** * ** * *** * * *** * ** * * * * = fi;};
* * * * * *** **** *** **** ** * * * * * *
* * ** * * ** * * * * ** * ** **
* * * * * * ** ** * ** * ** *** * ***** * * * *
* * * * ** ** * ** * * ***** * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
*** * *** ** * * * * * * i, num1 = 1, num2 = 1, sum = 0;
** ** *** * *** ** * * * ((num == 1) || (num == 2))
** * * * * * ** * * *
* *** ***** *** * * *** * ** * * * *** ** * * * *** *** 1;
* * * * * ** * * *
** * ** ** *** * * * ** * ****
* * ** * * * * * * *** * *
** * * * ** ** * * * *** * * * ** * * * *** * ** * (i = 3; i <= num; i++)
* * * ** ** ** ** * * * * * * * * * **** * *
* * ** ** * * * * * *** **** ** * ** * ** * ****** ** * *** ** * * **** = num1 + num2;
* * ** *** *** *** ** ** * * * * * ** * * * * * * * * *** = num2;
* * ** **** * ** * * * * **** * ** * * * * * ** * * * * * ** * * *** = sum;
** * *** ** * * ** * * ** ** * * * ** * * * * * *
** ** ** * * * *** * * * * * ** * * ** * * * **** * * sum;
* ** * * * ** ** ** * *
}
int main()
{
** * * * *** *** * num, sum;
* * * * **** * * * * * ** * * * * * &num);
* * ** * * * ** ** ** = sumNfiS(num);
* * * *** **** * *** * ** * * *** * * * * sum);
* * ** * *** *** * ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * ** * **** * ** ** * * * int num;
** * * *** * * ** a,n,b=1,c=1;
*** * * ** * * * * *** * * * * * * **** * *** ** * * *
** *** * ** * * * ** * * * * *** * *
{
* * *** * * * * *** *** * * * * * * * * * * ** * *
*** ** **** * * ** * ** * **** * * * * ** * *** ** ** ** * * * * *
}
* ** ** ** * * * ** * * **
{
* * * * * **** * * ** * * ** ** * * ** *** * * *** ** * * *
* * ***** * * * **** ** ** * * * ** * **** ****
* * ****** ** ** * ** * *** * **** * * * ** ** * * * * * * * * * * * * * * **
** * * * * * * ** * * * * *** *** ** * ** * * * ** *** **** *** * * **
** ** ** * * ** * *** * *** ** * * * * * * ** ** * *** ** * * * **
****** ** * * *** ** * * * ** ** * **
* *** * * * *** * * **** * * * ** ** ** ** * * ** ** * ** ** ***
}
* ** * * ** * * * ** * * ** **** ** * ** ***
* *** * * *** * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
** * * * * * ** *** * * ** ** i, num1 = 1, num2 = 1, sum = 0;
*** * ** ** * * * ** ((num == 1) || (num == 2))
** * * ** * * **
** *** ** * * * * ** * * ** * *** * * * * * * * * * 1;
** * * * * * * *
* * * * * * * * * * *
* * * * * * * * *
* * * * * * ** * * ** * ** ** * * * * (i = 3; i <= num; i++)
* * *** * * ** * * * * * ** * * * * * *** ** *
*** * * * * * * * * * ** *** * * * * * * * * * ** ** * * * * * * * *** ** = num1 + num2;
* ** * * * * ** * **** * ** ** **** ** ** ** * ** * * * ** **** * = num2;
* * * ** ** * ** ** * * * ** ** * ** ****** * ** * * * * ** * * * = sum;
* ** * ** ** ** ** * * *** * * * ** * * * *
* ** * * ** * * * *** * * * * * **** * **** * * ***** sum;
* *** * * * * * * * *
}
int main()
{
* * * * ** * ** * * * * * * num, sum;
*** ** * * ** * ** ** * * * * * * * * * &num);
* * * ** * ** ** ** * = sumNfiS(num);
* * * * * ** * * * * **** * sum);
* * * * * * * ** ** * ** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
** * *** ** *
#include<math.h>
int main()
{
* * **** ** i,j,k=0,a=1,b=1;
* * * * ** * * * ** * * * * ** **** * * *
** * * **** * || i==1)
*** * * * * ** * * * * * * * **** * **
*** ** * * ***
{
*** * *** * * * *** *
{
* * * * * * * * *
** ** * * * ** * ** *
* ** * * * *** ***** ** *
}
** * * * **** * * *** * * ***
}
* * * * * *** * * ** 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** ** * * * *** * * k, num1, num2, i;
* * * * * * ** = 1;
** ** * * * * * * * * * ** = 1;
** * * * *** ** *** * * == 1 || x == 2)
** **** * * * ** * * * * * * ***** * ** ** * * *
* * * ** * ** * * *
* *** ** ** *
** * ** * * * **** * * * * * *** ** = 3;i <= x;i ++)
** * * * * * *** * * * *** * * *
* * * * * * ** * ** * * * * * * * *** = num1 + num2;
** **** * ** ** * * * * * * * * * * * ** ** * * = num2;
* ** * * * ** * ** * * ** * * * * * * * ** * * = k;
*** * *** *** * * * * * * * *
** * * * * * * * * ** * ** * * * * ** * ** * * k);
** ** * ** * * * *
}
int main()
{
** **** * *** * * x;
* * ** * * * * **** ** * ** * &x);
* ** *** *** * * ** * ** *
* * * * * ***** 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* ** * ** ** * ** * i,sum=0;
* * * * ***** * * * ** * x=1,y=1;
* * ** * * * *** * *** * * **
* *** * ** * * **** * ** * * *** **** **** * * * 1;
* * * * * ** * * * * * *
* * * **** * * * ** **** ** * *** *** * 1;
* * * * * ** * * * * * ** **
{
* * * * * * * * * ** ** * * * * ** * **** ** * * *
** * ** ** * ** * * * * * ** ****** * * ** **
* * * * * *** * *** * ** * * * * ** * ** ** * * *** * = x+y;
** * * * ** * * * * * * * * * * * * *** *** * * * * = y;
* ** * * * ** * ** * * *** * * * ****** * * * *** ** * = sum;
* ** * **** * * * * ** * * * * **** * ** *
** * ** * * ** * **
* * ** * * * *** * * * * ** *** sum;
}
int main()
{
* ** * ** ** * ** ** **** a,total=0;
* ** * * ** * ** ** * * *** * ** * * *** * * * *** *
*** * * *** ** * ** = fas(a);
* ** * * ** * * * ** ** * * * * * *
* * * ** * * * ** * * * ** *** * * * *** ** *
*** *** * * * * * * ** * ** *** 0;
}
answered
Nov 3, 2016
by
410523043
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
******* * * ** * * * k, num1, num2, i;
* * * ** * * ** = 1;
* ** *** * ** * * ** = 1;
* * ** ** ** ** == 1 || x == 2)
*** * *** * * * ** * * * * ** * * * * ** ** ** * * ** * *
* * * * ** * * *
** ******* ** * ** * *
** ** * * * * ** * * * * * * ** * * ** **** = 3;i <= x;i ++)
* ** ** *** * * * * * *** * ** ** **
** * ** ** * * ** * * * ** ** * * * * *** * * = num1 + num2;
***** *** * ** * * * ** * * * * ** * * ** *** * * *** * ** * * = num2;
* * * * * * * ** * * * *** * * * * * ** * ** ** * ** * = k;
* * ** * * * * * ** * * * * *
* * * **** * * * * * ** ** * **** * * * * k);
* * * **** * *
* *** * * * ** *** * 0;
}
int main()
{
* * * * * * * ** x;
* * * * * * * ** ** ** * *** * * * * * * * * &x);
** ** * ** * ** ** * ** ** * **
*** * *** * *** * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * * * * *
#include * * * ** ** ** **
int printFF(int n);
int main(int argc, char *argv[]){
* * * * * ** * * * * a,b,sum;
* ** *** *** * * * * ** *** ** ***** ** * * * **
* * * * ** ** ** * * * = printFF(a);
* * * * *** * * * ** *
* * * * * * *** * * ** ** ** * * ** * * ** *
* * ** * * * *** * * * * ** **** ** * ** * * * * *
** * ** * * * * ** *** * * 0;
}
int printFF(int n){
* * * * * ** * * * f[10000]={1,1,0},i;
* * * * ** ** * ** * *** **** i <= n; i++)
* ** * * * * * ***** * * * * * * * * * * * * * * ** * * * * * ** ** * * * * * *** **
* * * * * ** * * **** * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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