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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* * * * * * * * ** * * * * a,b=0;
** * * ** ** ** ** * *** ***
*** * *** **** ** * ****** **** ** ***** * * * * * = b+a;
** * * * ** * * ** * ** * * *** * * ** *
* * **** ** ** ** ** *** ** * *** * *** * * *
* * * * * * * *** * ** *** ** *
* * ** * * * ** ** * ** * *
int main()
{
** * ** *** * * * * *** * num;
** * ** * * * * * ** * * ** * * * * * * * * * *** *
*** * ****** * * ** ** * * ** * * *
* ** * ** * **** * ** * * * * *
* * * * * * * * ** * * **
* * * ** ** * ** * * * * ** * ** * * * * ** * *
** * ** ** * ** ** ** * * ***** 0;
* * * * **** * * * *
* * * ** * ** ** **
* * * * * * * * * ****
* * * * * *
*** *** * ***** **** ** * *
* * * * * * * **
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * ** * * *** **** * *** i,n,fi,last1 = 1,last2 = 1;
* * * * * ** * * ** * * *
* * * * * * * ** * * * * * * ** * * * * ** * *
** * * ** * ** ** ** * ** * *
** * * * * * * * * * == 1||n == 2)
* * ** ** * *** * * * ** ** * * ** * ** * * ** *
** * * * ** *** * *** * * ** * * *****
* * ** * * * *** * ** * **
** ** ** * ****** *** ** * ** ** * * * ** = 3;i <= n;i++)
* * ** * * * * * *** ** *** * * ** + last2;
* * ** ** ** ** **** *** * ** * = last1;
* * ** * * ** * * * * ** * ** * ** * * * **** * * = fi;};
* * ** * * ***** * * * *** * *** * ** * * ** ** * * * *
** * * *** * ** *** * *** * * ** *
* ***** * * * * * ** * ** * *
* * * * * * * *** ** * * * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* ** ** ** ** * ** **** ** ** i, num1 = 1, num2 = 1, sum = 0;
** ****** * ** ** * * ((num == 1) || (num == 2))
* * ** ** * ** ** * *
* * * * * * ** * ** *** * ** * * * *** * * ** ** * * * ** 1;
* * ** ** * * *** ** * * *
** * ** ** * * * * * **
* * *** * * * * * *
* ** *** * * * * * * * * ** * * ** * (i = 3; i <= num; i++)
* * ** * **** * ** * *** *** ** * **** ** ** * *** * **
* * * * * * * ****** * * * * * * * ** * ** * ** * * ** * * * = num1 + num2;
* * * * ****** * * * * * * *** * * * *** * * * * **** ** ** * * ** * ** ** = num2;
* * * * * ***** * ** ** ** * ** * ** ** ** * * * * * **** * * * * * *** = sum;
** ** *** ** * * ** * **** * * ** * * * ***
* * *** * * * *** * * * * ** * ** * ** ** *** sum;
** *** * * * ** **
}
int main()
{
*** * * * * **** * ** * ** num, sum;
* * * * * * * ** * **** * * * * ** &num);
*** * * ** * ** ** * * * * * ** = sumNfiS(num);
*** * ** ** *** * * * * ** *** * ** * * sum);
** ** * * * * * * * * *** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * **** * ** ** ** ****** int num;
* * ** * ** * * * * a,n,b=1,c=1;
* * * * * * ** * * * * * * * * * * * * * * * * *
* ***** **** * * ** * ***
{
* * *** ** * * * *** * * * ** * * ** **** *
* * ** ** * * * * *** * * * *** * * * * * * * ** * * **
}
*** *** * ** * * **** * * **
{
* ** * * * * * ** * *** *** ** * * *** * * * *** ** * * *** ** ** * * * * ***
**** *** * * *** *** *** * * * * * * *** **
** * * * * * * ** * * ** * * * * ** ** ** * ** * * * ***** * * * * ***
** ** *** * ** * ** * * ****** ** ** ** ** * * * * ** * * ** * ** * * ** *
*** *** * * * * * * *** * ** * *** * ** * ** * ** * * * * * ** * * *
* ** ** * * * * * ** ** ** * * * * * * *** * * * ** **
* * * * * * *** *** *** * * * * * * * * * * ** ** ** * * ** *
}
** * * * * * * * * *** * * *
* ** * * ** ** * *** * * ** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* ** *** ** * * ** * ** i, num1 = 1, num2 = 1, sum = 0;
* * * ** ** * ** ** * *** ((num == 1) || (num == 2))
* * * * ** * * ** **
** * * * * * * *** ** * ** * ** * * * *** * * ** 1;
* ** * * * ** * *
* * * ** * *** *** **** *
** ** ** * * * *
** * ** ** * * * * * * * **** * * * ** * * * * * (i = 3; i <= num; i++)
* * * * * * * * ** ** * ** * * * *** * ** *
* ** **** * * ** *** *** * * * * * * * * * * * ** * * ** * * * * * **** = num1 + num2;
* * * * * * * ** ** ** * * ** * * * * * * * * *** = num2;
* ** ** **** * *** *** * ** * *** * * * ** * **** **** ** * * * * * ** ** = sum;
* * ** *** * *** * * * * * * ** ** * *
* * ** *** *** * * ** * * * ** ** * * * sum;
** * * **** * * * * *
}
int main()
{
*** ** ** * *** * ** * * * num, sum;
* ** * * * ** * * * * ** * * * ** * &num);
* * **** * ** * ** * * * ** = sumNfiS(num);
* * * * ** ** ** * ** * ***** ** ** ** * ** sum);
* * * * *** * ** **** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* * * ** * ** * *
#include<math.h>
int main()
{
*** * ** * ** * * * * * * i,j,k=0,a=1,b=1;
* *** * **** * *** * ** * *** ** ** ** * * * * *
*** * ** * * * || i==1)
* * * * * ** * * *** ** * * * * *
* *** * * *** * ***
{
** * * * * * * * * * *
{
* ** * * * * * * ***
* ** * * ** ** * *
* * * * * * * ** * * ** *
}
* * * ** * * * * * * * * **** **
}
* **** *** *** * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * * *** * * ** ** * k, num1, num2, i;
*** * ** * ** ******* = 1;
* *** *** * * ** * * = 1;
*** * * * ** * * == 1 || x == 2)
*** * ** * * * * * * * * * ** * * * ** * ** * * **
* ** *** ** * * * * *
* * * * * *
* *** * ***** ***** ** * ** ** * * * = 3;i <= x;i ++)
** * * *** * * * * * ** **** ** *
* ** * * * * * * * * * * * * * * * * * * * * * ** * * * * = num1 + num2;
* * * * * * ** * * * * * **** * * * * * * *** = num2;
** * * ***** * * ** * * ** *** ** * ** * * = k;
* *** ***** * * ** ** ** ** * **
* * *** * **** * * * * * ** ** **** * *** ** * * * * ** * k);
* *** * **** ** * * *
}
int main()
{
* * ****** * ** ** * ** x;
* ** ** * * * *** * * * * ** &x);
* * * * ** * * ** *
***** * ** * * * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * * * * * ** * * ** * ** ** i,sum=0;
* * * * * *** * * x=1,y=1;
* * ** ** * * * * * **** * * *
** ** * ** * * ** ** * *** * * * * * ** * * * 1;
* * * ** * ** *** * * **
* * ** ** * * * * * * ** *** * * * 1;
* * * ** * * * ***** *
{
* * * * * * ** * ** * * * * * * *** * * * * *
* * **** * ** * * ** * * * * ** * * ** * * *
* * * * * * * ** *** * *** *** * ** * * *** * ** ** * * * = x+y;
* ** * **** * ** * * ** * * * * * * * *** ** * * * * * * * * * * * * ** = y;
* ** * * * ** *** * * * * * *** * * * ** * ** *** *** ** * = sum;
**** * * ** * * * *** * * ** *** ** * **
* * * * *** * * ** * * * ** *
* * * ** * **** * *** * * sum;
}
int main()
{
* * ** ** * *** *** a,total=0;
**** ** * * * * * * * * ** * ****** * ***
** * ** * * * * * ** **** = fas(a);
* * * * * * * ** **** * * * * * ** * * * *
* * * * ** * * * * * ** * * ** * ** * *
* * * * * * * * ** *** 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * *** * * * * * k, num1, num2, i;
** ** * * ** ** * = 1;
**** ** * * *** = 1;
* * * ** * * * ** == 1 || x == 2)
** * * * **** * * ** * ** * ** *** ** * **** * * * * ***
**** * *** * * * * ***
** ** * * * ** *** *
* * * * * * * ** * * * * *** *** = 3;i <= x;i ++)
* * * ** * * ** * * *** * * ***** ** * *
* * ***** ** * *** ** * * * * * ** *** * * * * ** * = num1 + num2;
* *** * * ** * *** * * * * * ** * * **** ** * * * = num2;
***** ** * * * * ** * * * ***** * *** *** * * * * * * ** = k;
* ****** ** *** * * * * * *
** ** * * * * ** * * * * * * * ** * * *** ** * * k);
* * * * **
* * ** *** *** * *** * 0;
}
int main()
{
*** **** * * * * * * ** x;
** * * * * * * * ** * * * ** * * * ** * * &x);
* ** **** * * * * **** ****
* * ** ** **** *** * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include ** ** * ** *
#include * *
int printFF(int n);
int main(int argc, char *argv[]){
* * * * * *** * * * * ** ** a,b,sum;
**** * * * * ** *** *** * ** ** * * **** * * ** *
* ** * * ** ** *** * * * ** = printFF(a);
* * * * ** * * * * ***
* * ** ** * * * *** * * * ** * ** * *
* ** * * * * * * * * * * * * **** *** *** * * **** * * *
** * * * * * ** * * * 0;
}
int printFF(int n){
* * **** * ** * *** * ***** * f[10000]={1,1,0},i;
** * * * *** * * * *** i <= n; i++)
* * * * * * *** ** * *** ** ** * * ** * * ** **** ** * **** * *
* * * *** * ** * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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