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請設計一程式,使用者輸入一個正整數N,程式會輸出相對應的費氏數列第N項。

sample input:

10

sample output:

55
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 16957 - Available when: Unlimited - Due to: Unlimited
| 3.4k views

26 Answers

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Hidden content!
#include<stdio.h>

#include<stdlib.h>

int plus11(int num)

{
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answered by (-188 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>



int main()

{
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}
answered by (-264 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int sumNfiS(int num)

{
**** * ***** * ** * ** i, num1 = 1, num2 = 1, sum = 0;
* ** * **** ********** * ((num == 1) || (num == 2))
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}



int main()

{
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*** ** *** ** *** * * = sumNfiS(num);
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}
answered by (-214 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
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}
answered by (-90 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int sumNfiS(num)

{
*** * **** ** ** ** i, num1 = 1, num2 = 1, sum = 0;
****** ** * * ** * * **** ((num == 1) || (num == 2))
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}



int main()

{
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*** * ** * ** ** = sumNfiS(num);
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** * *** * **** ** *** * 0;

}
answered by (-214 points)
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Hidden content!
#include<stdio.h>
** * * * * * *

#include<math.h>

int main()

{
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}
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}
answered by (-190 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



void Fibonacci(int x)

{
*** * * * ** ** k, num1, num2, i;
* **** * *** * * * = 1;
* * * *** *** = 1;
* ** * *** ** * * == 1 || x == 2)
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}

int main()

{
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* * *** * *** *** *** * * * * **** ** &x);
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** *** * **** * * * 0;

}
answered by (-188 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

int fas(int N)

{
** * * ** * * * * i,sum=0;
** * ** ***** * * * * *** x=1,y=1;

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**** * ** ** ** * sum;

}



int main()

{
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* *** * * * ** ***** * * ** *** *
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* * * * ** ** * **** 0;

}
answered by (156 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



void Fibonacci(int x)

{
** *** *** **** *** k, num1, num2, i;
*** ** * * * * * * = 1;
** * ** *** * * **** = 1;
* ** ** ** * == 1 || x == 2)
* ** * ** * * ** ** * ** ** *** ** * **
* ** * * * ** * * *
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** *** *** ***** * * * ********** * = 3;i <= x;i ++)
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}

int main()

{
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** * *** ** ** ** ** 0;

}
answered by (-188 points)
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Hidden content!
#include ***** * ** *

#include * ** * * * *



int printFF(int n);



int main(int argc, char *argv[]){
* * * *** ** * * * * * a,b,sum;
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}



int printFF(int n){
*** ** * * * ** ** * f[10000]={1,1,0},i;
** ** * * * ** ** ** i <= n; i++)
* ** ** ****** * ** * *** * ** ** * * ** * * **** ** * ****** ***
** * * * ** ** ** *** * f[n-1];

}
answered by (-216 points)
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