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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
** * * * * ** * * * ** ** *** a,b=0;
* * ** * * * * * ** * * * *** * *
* * * * * * * ** ** ** * * * * ** * * * ***** = b+a;
** * *** * ** * * ** ** *** ** * * **
* * ** ** * ** * * * * * * * ** ** ** * * * * * * *
* * * *** * ** * *** * * ****** *
*** * * * ** * * * *
int main()
{
* ** * ** * * * * * * * *** num;
* * ** * * *** * ** * * ** * * * * *** * *** **
*** ** *** *** *** * *** *
* * ** * * ** *** * * *
** * * * * * * *** * *
* * * *** * * * * ** * * * * * * * ** * * **
** ** * ** * ** ** * * ** 0;
* * ***** *** * *** * *
** * * ** * ** *** * * *
** * * * * * * *** * *
**** ** * * * * * ** ** *
*** ** * *** * *** *
* * * * * * * * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** * * * * * * * * ** i,n,fi,last1 = 1,last2 = 1;
*** * ** *** ****** ** *
* * *** * * * * * * * * * *** *** *** * * ***
* * * * ** * * * *** * * * *
**** ** ** * * * *** * ***** * * == 1||n == 2)
* * * * ** * ** * * ** *** * * *
* * * ** * ** * *
* * ** * * * ** ** ** **
* ** * * ***** *** * * * * * = 3;i <= n;i++)
* * ** ** * * * * ** * ** * + last2;
* ** * ** *** * ** * * ** * *** * * * ** * ** * = last1;
** ** * * * * * *** ** * * * ** * * ** * * * = fi;};
**** * * * * ** ** * *** ** ** * * * * * ** * * * * *** *
* * ** * * ** * *** ** *
** ** * * ** ** *** * * * * * * * * * * *
* * * ** * * ** * * * * ***** * * ** * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* *** * ** * * * *** i, num1 = 1, num2 = 1, sum = 0;
* * *** * * * * ** *** ((num == 1) || (num == 2))
* * * **** * * * * ** * * **
*** * *** ** * * * * * * * * ** * * 1;
* **** * * * * * **
* * * * ** * * * * ** * *
* ** * * * * * *** *
* * * ** * ** * * ** ** * ** * *** * ** * (i = 3; i <= num; i++)
* ** *** ** ** * * ** * * ** * * **** * ** *
* * * * * * * * * * * ** ** ** * * * * * * *** ** * **** ** * * ** ** * * * ** *** = num1 + num2;
* * * * * * * ** * * ** * * **** * * * * * *** * * *** * ** = num2;
* * * ***** ** * ** * *** * * * ** * * * ** *** * * ** * * * * *** *** = sum;
* * * * ****** * * * * * * * * ** * ** * * ** * * * *
* *** ** ** * * * * * * * **** *** ** *** * * * * * * * * * * sum;
* * * * ** ** * ** * ***
}
int main()
{
*** *** * ** * ** * *** num, sum;
* ** ** ** * * * ** * * * ** &num);
* * * ** ** ** *** * ** *** * = sumNfiS(num);
** *** * * * ** * * * * * * **** * sum);
* ** * **** * * * * * * ** 0;
}
answered
Nov 3, 2016
by
410314217
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-214
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** *** ** ** * ** * * int num;
* ***** * ** ** * * * *** * * a,n,b=1,c=1;
** * * * * ** * **** * ** * ** *** * * * * * ***
* * * ** * * * * * **** ** * *
{
* * * ** * * * * *** * ** ** ** **** * * ** * * ** * *
* ** * * **** * * * *** * * *** * * * ***** * * * *
}
* ** * * * ** ** * * * *
{
* ** * * * ** * * * ** *** * ** * * * * * ** * * * * ** * ** *
** * ** * * * * * * ** * * * * ** * ** **** *
****** *** ** ** * *** * * * * *** * * ** * * * ** * * ** *
* * * * ** * * * ** * ** * * * *** * * * * * * * * ** ** * ** * **** * ** **
* * * * * * *** * ** ** * * * ** * * * * * * * *** ** *
* * * * ** * * * * * * * * * * * * * * ** ***
* * * * * * **** * * ** ** * * * * * ** * ** * * * * * ***** * * *
}
* ** * * * * ** * * ** * **** * *
* * * * * * * * * * * ** * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
*** ** * * * * * ** * * * i, num1 = 1, num2 = 1, sum = 0;
* * * * ** * * *** * * * * * * ((num == 1) || (num == 2))
* * ** * * * *** * ** *****
*** * * ** * * ** * * * ** * ** ** * ** * * 1;
* * * ** * * * *** ******
*** * * ** * *
* * * * * * * ** *
** * * * * ** * * * * *** ** *** * ** ** * * ***** * * * * (i = 3; i <= num; i++)
* * * * ** * ***** ** * *** * * * * ** * ***
* ** * * ** * * * * *** * * * * * * ** ** * * * *** ** ** * * * ** * * * = num1 + num2;
* **** ** ****** * * **** * * * *** * * * * ** * ** ** ** * * * ** * * * * * = num2;
* * * * ** *** * ** * * * * * * *** ***** * * *** * ** * * ** ***** ** = sum;
**** ** * * * * * * * * ** *** ** * ** * * *
** ** * * ** * * * ** * * * * * * * * *** * * ** * sum;
* * * ** * * *** ** ** **
}
int main()
{
* * * **** * **** * * * * num, sum;
* * *** * * * * * * * * ** * * * ** * &num);
* * * * * * * ** * * * = sumNfiS(num);
* * *** * * * * * * * * * ** * * *** *** sum);
* * * ** **** * * ** *** ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* * * ** * * ** ******
#include<math.h>
int main()
{
** **** ** ** ** * * i,j,k=0,a=1,b=1;
* * * **** * * ** ** * ** ** * * * * * ** * *
** * ** ** * * * *** * || i==1)
** ** * * * * * ** * * *** * * *
* * * ** * ** * *
{
* ** * * * * * * * ** * ** * * ** * **
{
*** ** ** * ***** * * * *
* * ** * ** * * * * * * *
****** * **** * ** *
}
* ** * * * * * * * * * * **
}
* * ** * * * *** 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * * * *** * k, num1, num2, i;
** * **** * ** * **** * ** = 1;
* *** * ** ** * ** ** = 1;
* ** * * * *** ** * ** == 1 || x == 2)
* * * * * ** * * * * * * * * * ** * *
**** * * ** * * ***
** * * * ** **
* * **** * * * ** ** * ** * * * = 3;i <= x;i ++)
* * * * ** * * * ** **
* ** *** * ** * * ** * * ** ** * * * = num1 + num2;
* * **** * *** *** * ** * * * * **** ** * * * ** * * * ** = num2;
** * * * * * ** * ** ** *** * * * * * * * * * * ** * * = k;
* * ** * * * *** ** * **** * * *
* * * ** * ** * * ** * * ** ** * * * * **** * ** * * k);
** * ** * * * * **
}
int main()
{
* * * * ** * ** * * * * * * x;
* ** * ** * *** ** ** * *** * * &x);
* * ** **** * ** ** ** *
* * **** * * * * ** 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * ** *** ** * ** i,sum=0;
* * *** ** * * * *** x=1,y=1;
* ** * ** * * ***** *** *
*** * * * ** ** * ** * * * ** ** ** 1;
** ** ** * * * * * ** ** * *
* * * * * * * ** ** * * * * * ** * * * 1;
* * *** * *** * * * * *
{
* * * * * ** ** ** ** * * *** * *** * ** * * **** *
* * * * **** * * * * * * ** * *
* * **** * * * * * ** * * * * * ** * * * **** * ** **** ** ** ** * ** = x+y;
** ** * * * * * * ** * * ** * * * * * * ******* * = y;
*** *** * * ** * * **** * * ** * ** ** ** * * ** = sum;
* * * ** *** *** * * * * ** *** *** * * *** *
* ** *** ** ** * * * *
** ** *** * ** * * * * * * sum;
}
int main()
{
* **** ** * * * ** * * * * a,total=0;
* * * *** ** ** * * ** * ** * *** * * * * * * * * * *
* *** ** * ** ** ** ** * = fas(a);
* * * * * * ** * * * * ** *** * * ***
* * *** *** * * * * * * ** * * **** * * *
**** * * * * *** * * * * * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * ** k, num1, num2, i;
* * * ** * * ** * = 1;
* ** * ** ** ** ** * ** = 1;
* ** * * *** * ** * == 1 || x == 2)
** ** *** * * * * * * * * * * * * * * * * * *
**** * * * * * * * *
* ** * * ** * *
** * ** * * * * ****** * * * * * * * *** * = 3;i <= x;i ++)
* * * * ***** * * * * * ** * ** ** * * **
** * ** ** * * ** ** * * * ** * * * * * * ***** = num1 + num2;
* * * ** *** * * * ** *** ** * * * * * * * ** * ** * * * = num2;
** * * * * ** * * ** * ** ** *** * * * * * * = k;
* * ** ** * * * ** * * * **
* * * * * * * ** ** * ** * ** ** * * * *** *** ** ** * * * * * k);
* ** *** *** * ** *
* *** * ** *** * 0;
}
int main()
{
** * * ** * * * * x;
* *** * *** * * * * * *** * &x);
* * * * * * * * *
* ** * * * *** * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include * *** * * *
#include ** * * * *
int printFF(int n);
int main(int argc, char *argv[]){
******* * * * * * * ** * a,b,sum;
* * **** * ** ** * * * ** ** ** * * ** * *
* * * * * * ** ****** * * ** * * = printFF(a);
*** ** ** * * * *
* * * * * * * * * ** * *** ** **** *
* * * * ** * ** * * ***** ** ** * * * * ** * * * * * ******* * *
*** ** * * * * * * * *** 0;
}
int printFF(int n){
** * * *** * ** ** f[10000]={1,1,0},i;
*** * * * * * ** **** * * * i <= n; i++)
* **** ** * * * ***** * ** * * * ** * * *** * * * * ** ***** *** ** * * * * * *
* * ** *** * * * * ** f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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