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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
** **** * ** ******* * * * * * a,b=0;
* * * * * ** * ** * ** * * * **
* * * * * * ** *** * * ** **** * * * * * = b+a;
** * *** * ** * ** * * ** * * *
* * * ** * ** * * * * ** * * ** * * * * *
* * * * * * ** ** *** ** * *
** *** * * * * * * ** * ** *
int main()
{
* * * ** * ** * * * **** num;
* * * * * * * * * * * * * * * * *
* * **** * * *** * ** * **
* * * * * * **** * **
** * * ** * * * **** ***
* * * * * * * * * * * * * * ** * * * * * ** * **
* * ** * *** * * * ***** * 0;
* **** * *** * **** * * *
*** * ** ** * * * ** *
** *** * * ** ** * * * * ** **
* * * * * * * ***
* * * ***
* * ** ** ** ** **** *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * *** * * ** * * ** *** * * i,n,fi,last1 = 1,last2 = 1;
** * * * *** ** * **** *** * * * *** *
* * * * * *** ** * * * * * * * * * ** * * * *
* * * * ** * *** * * * *** *
** ** * ** ** *** * * * ** * == 1||n == 2)
* * * *** *** * ** * * ** *** * * * * * * * ** **** * *
* **** ** * ********* *
** *** * * * ** ** * * * ** * * *
* ** * * ** * * *** * ** = 3;i <= n;i++)
** * ** * ** * * ** * * * ** *** * * * + last2;
* * *** *** ** * * * * ** * * * * * *** * = last1;
* * * * * * *** * ** ** * ** * * ** = fi;};
* * * * * * * * * * * ** ** ** ** *
* * * ** * * * * ** ** ***** ***
** ** * * * * * * ** * * * * * **** * * * * ** * * * **
** * * ** ** ***** * * * * *** * ** *** 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
** * ** * ** * *** * * i, num1 = 1, num2 = 1, sum = 0;
* ** ** * * *** * * * **** ((num == 1) || (num == 2))
** ** * ** *** * ** **
* ** * * * ******* ** *** * * ** * * ** *** ** ** * * 1;
* * ** * ** * * * ** *****
** * * * * * **** * * * * *
**** *** ** * ** * ** *
* ** *** * **** * * * * * * * * *** * ** * * (i = 3; i <= num; i++)
* ** * * * * ** * * * * * * ** * * * ** * * ***** * * ** *
**** * * ** * * ** * * ** * * * ** * * * * * ** *** *** * ** * * * * = num1 + num2;
** ** * * ** * ** * * * * * ** * * ** ** * * * *** * * * * *** **** **** * = num2;
* * * * * *** * * * ** * * * ** ** * * * * ** ** * **** * ** * ** * * ** * = sum;
* ** * ** * * * ** ** * * ** * * * * * *
*** * * ** * * ** ** ** * * * * ** * * sum;
* * * * **** ** ** * ** * *
}
int main()
{
**** *** * * * * * ** * * num, sum;
* ** ** * ** ** * ***** ** * * ** **** * &num);
** *** ** * * ** * * * *** = sumNfiS(num);
** * *** * * ** * ** * * * * * * ** * * sum);
*** * * * * ** * **** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* *** ** ** * * * * * ** * int num;
** ** * * ** * * ** **** a,n,b=1,c=1;
* ** * * * ** ***** ** ** * ** * * **** * ** * * *
*** ** ** * * * * * ** * * * * * * *
{
* ** * * * ** * * ** ** * ** * * * * ** * *
* * * ** * * ** * ** * * * * * * * * * * * * ** * * * * * * ** **
}
** * * * * * *** *
{
* * **** * * *** ** * ** * **** * * ** * ** * *** *
* * * * ** * * * *** * *** * * * *** * ** * ** * *
* ** * *** * * ** *** ** * * * * * * * * ** * * ** * * * * ** * ** * ** * * ** *
* * *** * ** *** *** ** *** * *** * * ** ** ** * * * ** * ** * ** *
** * **** * ** ** * * **** * ** * * * * ***** * * * ** * *** * * ** *
* * ***** *** * * ** * * *** * ** * * * ** *** * **
* * * * * * ** * *** *** ** * * ** * * * *** ** * * * * ** * ***
}
* *** * ***** ** * ** ** ** * ** * ** * * *
* * *** * ***** **** * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * * * ** * * i, num1 = 1, num2 = 1, sum = 0;
** ** *** * *** ** * ** ((num == 1) || (num == 2))
***** ** * * ** * * * * *
* * * * * * * * * *** * * * * * * * * **** ** * ** *** 1;
* ** * * * ** * **
* * * * * ** * * * *** * * **
** * ** * * * * * * * *
* ** ** *** * * * * * * * * * * * * (i = 3; i <= num; i++)
** * * ** * *** ** * *** ***** * ** ** *
* * *** * * * ** *** * ** * * * * *** * * * * ** * * * * ** **** * = num1 + num2;
* * ** ** * * *** * ** ** * * * * *** * * * * * * ** * = num2;
*** ** * * * * ** * * * *** * * ** ** * * * * * * * * ** *** * ** * ** * = sum;
* * * * ** * **** * * **** * * * ** ** * ** *** ** ** **
* * * * * * * * *** ** * * * * ** ** * * ** sum;
* * * * * * * * * * *
}
int main()
{
*** ** ** ** * ** * * num, sum;
**** * * *** ** * * * * * * * * &num);
* * * *** * ** * * * = sumNfiS(num);
* ** *** * ** ** ** ** * * ** * * * ** sum);
** ** * * * ** * * ********* * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* *** * * *** *
#include<math.h>
int main()
{
* * * * * * * * * * i,j,k=0,a=1,b=1;
* ** * * ***** ** * * * * ** ** ** * *
* * * ** * * * *** * || i==1)
* * *** * ** * ** ** * **
* * * ** * **** * * *
{
** ** * **** ** * * * *
{
* ** * ** * ****** * **
* * * * *** * * * * *
* * * * * * * * * * *
}
* *** * * * * **** * ** **** * * *
}
** *** * * * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * * *** * * ** k, num1, num2, i;
** ** * * * ** * ** = 1;
** * * *** * * ** ** = 1;
** * * * ** * ** * == 1 || x == 2)
* * * * ** * * * * * * * * ** * * * *** * * ***
** * **** * * ** *** *
* ** ** ** * * *
* * ** * ** * **** * * ** ** ** * * ** * * = 3;i <= x;i ++)
** * *** * * ** ** ** * * ***
* ** * * *** * * * * * * ** **** * * ** * ** ** * * ** = num1 + num2;
* * **** * * * * *** * * * * ** * * * * * * * * * ** * *** = num2;
** * *** * *** ** * ** * * *** * ** * ** ** * = k;
* * * ** * * * ** * * * ** * *
***** * * * * * ** * * ** ** * ** * * ** * * * ** * * k);
* * * ** *** ** * ** *
}
int main()
{
** * ** * ** ** ** x;
* * * **** ** ***** * * *** ** * * ** ** ** * * &x);
** * * * * * * * * * * * * *
* * * * * ** *** * * 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* *** *** ** **** *** ** * * i,sum=0;
* * * ** ** * ** ** * * * *** * x=1,y=1;
* ** ** **** * * *** * *
* ** * * * **** * * ** * ** * * * ** * * * * 1;
** * * ** *** ** **** * * *
* ** * *** ** *** * **** * * ** ** * * ** ** * * 1;
*** * * * * * * ** ***
{
** * * **** * * * * * *** * * * * ** * * **
* ** ** * * * *** * * * * * * ** * *** ** **** *
** * ** * *** * * * ** ** * * ** * *** * * ** ** * *** * *** = x+y;
** * * * * ** *** * *** ** **** * * * *** * ** * * * * * * * = y;
* * * * * * * * * * * * * * ** ** * * ** *** ** * * ** ** * * = sum;
* * ** **** * * * * * *** ** * *** *
** * * ** ** ** * *****
* * ** * * * * ** *** sum;
}
int main()
{
**** * * ** ** * * ** * * * * a,total=0;
** *** * * * * * * * * * * * * ** * *** *
* * ** * ** * ** * **** * * * = fas(a);
* * * ** * * * * ** * * * * **
* * * **** ** * * * * ** *** * ** * * * *
* * *** *** * * * * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * ** * * * k, num1, num2, i;
* * * * * * * * * ** * ** = 1;
* * * * *** * * = 1;
* * * ** * * ***** * * == 1 || x == 2)
* ** * * ** * * ** * * * * * *** *** * * * *
*** ** * * * * *** *
* * * ** * ** * * *
* * * * * * * * * ** ** * * ** * * * * *** = 3;i <= x;i ++)
** * * * * * * * * ** *** *
* * * * *** * * * * * * ** ** ** * * * * = num1 + num2;
** ** ** ** * ** * * * * * *** * * * ** ** * *** *** * = num2;
* * * * * * * * * *** ** * * * * ** * ** * * * = k;
* * * * * ** * * * * *
**** * ** * * * ** ** * ** * * * * * * * * * * *** * * k);
* * * * ** * * * * *
* * * * ** ** * 0;
}
int main()
{
*** * ** * * ** * * x;
* * * * * * * ** ** * ** &x);
** * * ** * * * * **
** *** ** ** *** * ** 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * * * ** * *
#include * * * *** * ** *
int printFF(int n);
int main(int argc, char *argv[]){
** * * * ** * * ** a,b,sum;
** * * **** * * * * * *** * * * * * **
* * **** ** ** = printFF(a);
* * ** * * * * * * **
* ** * * * * * * ** * * * * * * *
*** * * * * * ** *** * * * * *** * * * * *** * * *
** * * *** * *** * *** * * ** 0;
}
int printFF(int n){
* * * ** * * * *** * f[10000]={1,1,0},i;
* * ** * * *** * * * * ** * ** *** i <= n; i++)
**** * * *** * **** * ** * ** * *** * * * ** * ** * * * * * * * ** * * * * * ** * * * ** *
* * *** **** * ** * ** * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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