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請設計一程式,使用者輸入一個正整數N,程式會輸出相對應的費氏數列第N項。

sample input:

10

sample output:

55
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 16957 - Available when: Unlimited - Due to: Unlimited
| 3.4k views

26 Answers

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Hidden content!
#include<stdio.h>

#include<stdlib.h>

int plus11(int num)

{
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answered by (-188 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>



int main()

{
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}
answered by (-264 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int sumNfiS(int num)

{
* * *** ** * * * * i, num1 = 1, num2 = 1, sum = 0;
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}



int main()

{
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* *** * **** ***** ** * *** 0;

}
answered by (-214 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
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}
answered by (-90 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int sumNfiS(num)

{
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}



int main()

{
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* * ** **** ** * * ** * * = sumNfiS(num);
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** ** * ** * * * * * 0;

}
answered by (-214 points)
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Hidden content!
#include<stdio.h>
*** * *** ** * *

#include<math.h>

int main()

{
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}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



void Fibonacci(int x)

{
* * * * * ****** k, num1, num2, i;
* *** ** * * **** * * = 1;
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}

int main()

{
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}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int fas(int N)

{
* ** * * * * **** * *** i,sum=0;
* * ***** ***** * **** * x=1,y=1;

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}



int main()

{
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* * ** ** ** ** * * = fas(a);
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*** ** * * * * * ** * * ** * *
*** ** * * * * * ** 0;

}
answered by (156 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



void Fibonacci(int x)

{
* **** * * * *** * k, num1, num2, i;
*** ** ** * *** = 1;
* * *** * * * ** = 1;
******** ** * *** == 1 || x == 2)
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** ** * *** *** * ** * *** * = 3;i <= x;i ++)
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* * * * * ** * * 0;

}

int main()

{
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** ** * * ** * *** * *** * &x);
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*** ** *** * * ***** * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include ** ** ** ** *

#include *** * ** * *



int printFF(int n);



int main(int argc, char *argv[]){
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}



int printFF(int n){
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* * * *** * * **** * * ** ** * * * * ** *** * * * ** **** * **** ** * ******* * *
* * *** * * ** **** * f[n-1];

}
answered by (-216 points)
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