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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
**** ** * * * ** * * *** * a,b=0;
* * ** * * ** * * *** * ****** ** ** *
* * ** * * *** * * * * * * ** * * * * * = b+a;
*** * * * * ** ** * * * * ** * * ***** * ** * **** **
* * * **** * ** ** *** * * * * * ** * *
* * *** ** ***** * * * * *
** * * * * ** ** * ** ** ** * *
int main()
{
* ** ** * * * ** * * * * num;
* ** * * * * * * * * * * ** * **
*** * * * *** * ** **** *
* * *** * * **
* * * ** * * * * * * ** **
* * * * ** *** ** ** *** * * * ** * ** ** **
* * * * * ** * * * * * * 0;
* ** ** * * * * *
* *** * * * * * * * * *
* * * *** ** ** **** ** *
* * *** * * * * * * * * *
** * * * *** *** * * * *
** ** ** * * ** *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * * * ** * * * * i,n,fi,last1 = 1,last2 = 1;
* * * * * * * * * * * * * * *
** * * * ** * * * ** * ** * * * ** * * * * * * *
* *** * * * * *** * **** * * * **
* *** ** ** * * * *** * == 1||n == 2)
* * * * * * * * *** ** * *** * * ** * ** * **
* * ** * * * * ** ** ** *
** *** * ** ** ** * * * * * * *
* * * * * **** * *** = 3;i <= n;i++)
* * * ** * *** * ** *** * * * * * + last2;
* * * * ** * * * * ** * * * ** * * * = last1;
** * *** ** ******* ** ** * * * * * * * = fi;};
* * * * ** ** * * * * * * * * * ** * * * * * *
** **** * * * ** * * * * * * ** *
* ** * * *** * ** ** * * * * * * * * * *
** *** * * ** ** * * * * ** * ** ** * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
** * * *** * ** ** ** ** * * * i, num1 = 1, num2 = 1, sum = 0;
*** * * ** ** * **** *** * ((num == 1) || (num == 2))
** * ** ** * * * * *
* * ** * ** * * ** * * * * * * *** *** * * * * * * * 1;
* ** ** ** * * *
* * * * * **** *** ** ***
* * ******* * * *** * * *
* * * * * * * * * * ** * * * * * *** * * ** * ** * (i = 3; i <= num; i++)
** ***** * * * * * *** * ** * * ** ** * * ****
* * * * ** * * * * * ** * * * * ** ***** ** * ** * * * ** ** * * = num1 + num2;
*** * * * * * ** * * * *** * * * ** ** * ** ** *** * * *** * ** ** * * * = num2;
** * * ** * * ** * * * * * * * *** * * * * ** * * * *** * * **** * ** * * = sum;
**** * * * * * *** * *** * * ** * * **** ** * * * *
* * ** * * ** * * *** * ** ** * * * *** ** ** sum;
*** *** * * ** * * *
}
int main()
{
* ** * * * * * * * ** * num, sum;
* * ** * ** * * * * * * ** * ** ** &num);
* * * * * * ** * * *** *** = sumNfiS(num);
* * ** * * * * ** * * * * * * * * sum);
* * * * * ** * ** ** ** * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * * ** * *** ** ** * *** * int num;
* * * ** ***** * * * ** a,n,b=1,c=1;
** * * * ** * * * * *** * * * ** * * * ** *
** ** * ** ** * * * ** * * * *
{
*** *** * * * * * * * * *** * ** * ** * * * * **** *
* ** * * * * ******* *** * * * **** * * * **** ** * * * ** * *
}
** ** * * *** * * * * ** *
{
* * * * ** ** * *** ** * * * * * * ** ** * * *** **
* * * ** * * * * * * * * * * * * * ***
* * * * * * *** * * *** ** * * ** * * ** * * * * * *** * * ** * * * * ***
* *** * * ***** * ** * * ** * * * * * *** * * ** *** ** ** * * ** * * **** *
* * * * * *** * * * * * **** *** * * * * * * * ** * * * * * ** * * *
* ** ** * * *** ** * ** * * ** *** * * * * * * *
* * ** ** * ** ** ** ** * * *** * * * ** ** * * ** * * * * * ***
}
* ** * ** * * * * ** ** * ** * * ** * ** * * * * *
* * * * * * * * * * * * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * ** * ** * * * * i, num1 = 1, num2 = 1, sum = 0;
* * * * * * ** * ((num == 1) || (num == 2))
* * ** * * * * * * * *
** * *** * * * * * * * * * ** * * 1;
* ** * * * * * ** *
*** * * * * * * * * * *
** * * ** ***** * * *
**** * * * * * * * * * * *** * * **** * * * ** *** ** (i = 3; i <= num; i++)
* * * ** * *** *** ***** * * * * * * * ** * *
** * * * * * ** * ** * ** * * * * * * ** * ** * *** ** ** * * ** * ** = num1 + num2;
* * * * *** * * *** * ** * **** * * * * * ** * * * *** ** * * * *** * ** * *** = num2;
* * * * * * * * * * * ** * ** * ** * * * ** ** * * *** * ** **** * *** = sum;
** * *** * * * * ** * *** * * ** *** * * ** * *
* * * ** * * * * ** * * ** * * * *** * *** * * ** * *** ** * sum;
** * ** ** *** * * ** * *
}
int main()
{
* * * *** * *** * ** * ** num, sum;
* * * * * ** * ** * *** ** * ** ** * * * * &num);
* * * * * * * * = sumNfiS(num);
* *** * * * * *** * * * ** ** * * * ** * sum);
* ** ** * * * * * ***** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
***** ** * * ** ** ****
#include<math.h>
int main()
{
* * * * * i,j,k=0,a=1,b=1;
* ** * *** ** * * * * ** * * *
** ** **** * ** ** ** || i==1)
** ** ** * * * * * * * * * **** * * ****
* * * *** *** * * *
{
* * * * * * ** * * * * ** ** * *
{
* ** ******** * * ** ** **** **
* * * * ** *** * ** * *
* ** * * * * * ** * * ** * ** **
}
** * * ** * ** ** * * * * * * * * ** *
}
* * * ** *** * ** ** * 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * ** * ** * * * * k, num1, num2, i;
* ** * * * * ** * = 1;
* * * * * *** * * = 1;
**** * * ** * * *** * == 1 || x == 2)
* ** *** ** * * * * * * * ***** ** * ** * * *** * *
* * ** * ** * *
* *** * * * * *
* *** ** ** * * ** ** ** * ** * ** = 3;i <= x;i ++)
* *** *** ** * *** ** ** * * *
* * * * *** ** * * * **** ** *** * * ** *** * * * = num1 + num2;
** * ** * * * * ** * * * ** * ** * * **** * *** * * * ** * ** * = num2;
* * ** * * ****** * * *** * * * ** ** *** * * ** ** * ** * = k;
* ** * * ** * ** * * * *** * *
** ** * * ** ** ** * ** * * * * * * **** * ** ** ** * * * k);
* * ** * ** * * * ***
}
int main()
{
** ** *** *** ** * x;
** * **** * ***** **** * ** ** * * * &x);
** ** * * * * * ** * * *
** ** * * ** * *** * ** 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * * ** * * ** * * * * i,sum=0;
** * * * * ** ** * * ***** * * x=1,y=1;
** * * * ** * ** ** * ***
* * * * ** * * ** * * * ** ** * * ** * 1;
* * * * ** * *** ** * ** * *
* ** * ** * * * * * * ** * * * 1;
* * * * * * * **** * ** * **
{
** *** * * * * * ***** * * * ** * * * * ** * * ** * *
*** * * **** * * * * * * ** ***** * ** *
** * * *** ** * * * * ** * * ** ** * ** * * * * = x+y;
* * * *** * * * * * * *** * * ** ** * * * * **** ** * **** = y;
** * * ** *** * *** * ***** ** ** ** * ** * * **** ** * = sum;
* * * * ** *** ** ** * * * **** *
** * ** * * ** * *
* * *** * **** * * * * * sum;
}
int main()
{
* * *** *** * *** * ** * * * a,total=0;
** * ** * * * * ** * * ** * * ** * * * * **
* * * * * * * * ***** ** * * = fas(a);
* * * * * * * * *** * *** * **
* * * ** * * * * * * * ** * * * * *
** * * ** ** **** * * ** ** * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* ** * * * * ** * * k, num1, num2, i;
** * ** ** ** * * ** = 1;
** * * * * ** * * **** = 1;
** ** ***** ***** * * * * == 1 || x == 2)
** ** * * ** ** * * * * * ** * * * * * * * ** *
** * * ** ** * * * * **
* * *** * ** * *
* ** ** * * * * * * * * = 3;i <= x;i ++)
* * * * * * * * * **** * * * ***
* * * * * * ** ** * * * * *** * ** * ** * * ** * * * ** * = num1 + num2;
** * * * * *** ** *** ** * * * *** * * * * ** * * * * = num2;
* *** * * * * * ** * * * * * ** ** ** * **** * * ** * * ** * = k;
* *** * *** ** ** * * * * **
** * ** * * * * * * *** * ** * * * **** * **** ** ** k);
* * ** * * * * * *
** ** * *** * * * 0;
}
int main()
{
* ** ** * * * * x;
* * * * * * * * * ** ** ** *** * &x);
* ** * * * * **** * * *
* * * ** * ** * * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * ** * * *
#include * * * *** ** ** *
int printFF(int n);
int main(int argc, char *argv[]){
* * ** * *** * * * a,b,sum;
* * * * ** * * ** ** ** * ** * *** * ** *
* * ** * * *** * * * * ** * = printFF(a);
** * * * * * * * *** *** ** *
* ** ** * * *** ** * * * * **** *
** * ** * ** ** ** * *** * * ** **** ** ** * * * ** * * **
* * * * ** ** * * ** * * * 0;
}
int printFF(int n){
* **** * * * * * ** * ** * * f[10000]={1,1,0},i;
* ** * * * * *** * ** * * i <= n; i++)
* * * * * * * * ***** * ** * * ** ** ** * * ** *** * * * * ** * ** * * * * **** **** * *
* * * ** * * * * * * * ** *** * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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