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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* ** ** * * *** * * ******* ** a,b=0;
* * ** * * ** ** ** * *** * ** * * *
* ** * * ***** * ** * * * ** * * ** *** * = b+a;
* * * * * * * ** * * * * * *** * *** * *
* * ** * ** * * ** * * * * ** * * *
** * *** * * ** * ** *
* ** *** * * * ** * * *** * *** ** *
int main()
{
**** ** * * ** ** * ** * * num;
* * ** * * * * * * * * ** *** * * * * * * * * * *** *
* * *** ** ** * ** * * * * *
** * * * ** * * * ***
**** * * ** ** ** * * * * **
** *** *** * * * ** * * * ** * ** * * *
* * * * * *** ** * ** * ** ** ** 0;
* * * * ** *** * * * * *
* * * * * ** * * * * * *
* *** * * * ** * * *
* * * ** ** * * * * **
* * * * * ** * *
*** * * * *** * ** * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ******** ** * * * * * i,n,fi,last1 = 1,last2 = 1;
** * * * ** * *** * ** * * * *
* * * * ** ** * * * ** * * * * * ** *** *
* ** ** ** ** * * * *
** * *** * * *** * ** ** * * ** ** * * == 1||n == 2)
** * * * * ** * * * * ** * * * * ** * * ** **
* * **** ** * * * ** *** ** *
** * *** **** ** * * **
*** * * * * * * * * * * * ** * * = 3;i <= n;i++)
* * ***** * ** * * * * ** ** * * ** ** + last2;
*** * * * ** * * ** ** * * * ** ** ** * = last1;
* * * * * * ** ** * ***** * * *** * * = fi;};
* * * * * * * * * * * * * * * * * ** *
** * * * * * * * * ** ** * *** ** **
** * * ** * * * * ** ** ** **** * * * * * ** * ** *
* * * * ** * * * * * * * * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * **** * * * * * * * * i, num1 = 1, num2 = 1, sum = 0;
* * * *** * * *** ****** ** * * ((num == 1) || (num == 2))
* * * * * * * * ** * *
**** * * * * * * * * ** * * * * * * * *** * 1;
* **** *** * ** * ** *
* * ** ** * **** * * * *
* **** * ** **
**** * * *** * ** * *** * * ** ** ** * * ** * * (i = 3; i <= num; i++)
* * * * ** * * ** * * * ** * * * * * ** ** *
** * ** * * ** * * * *** * * * * *** * * * * *** ** * * * * ** * * * * ** * = num1 + num2;
* ** *** ** * ** * * * * * *** ** ** ** * * * ** * * * * = num2;
* ** * * * * *** * ** *** * ** ** * * * ** * * * *** * * * *** ** * * ** = sum;
** ** * * * * * * **** * * * * * * * ** * * **
* * * * ** * *** ** * * ** *** ** * *** * * ** sum;
* * * * ** * ** * * *
}
int main()
{
** * * ** *** * ** num, sum;
*** * * **** * * * ** ** **** * ** * * * &num);
* * * ** * * * ** * * * * * ** = sumNfiS(num);
* * ** * *** ** * * * * * * ** * *** * * ** sum);
* * * * *** * * ** * **** ** * 0;
}
answered
Nov 3, 2016
by
410314217
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-214
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * * *** ** ** ** * **** ** * * int num;
* * * **** * * ** * * * * ** * a,n,b=1,c=1;
* * * * * * * * * * * * * * * * * * * *** **
** * *** * * * ** * * * * * *
{
** * * * * * **** **** * * * * ** * *** * ** * *
* ** * * * * * ** * * * * ** * * ** * * *** ** ** * * * * **
}
* * ** * * * * ** * * * ****
{
* * * * ** * * *** ** ** **** * * * **** * * ** * * * ** ***
* * * * * * * * * * ** *** * ** * * * * ** *
**** * ** ** ** * ** * * * ** * **** ** * * *** * * * * * **** *** ** * *
* *** * * ** * * ** * ** * ** * * * * * * * * * ** * **** **
** * * * ** * * ** * * * * *** * ** * * * * ** * * ** * **
* * ** *** * * * ** * * * ** * * * * * **
* * * * * * * * * * ** * * ** * * * * * **** *** * * * * * * *
}
* * * * * * ** * * ** ** * * * * * ** * **
* **** * * * * * * *** * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * * ** * * ** * ** i, num1 = 1, num2 = 1, sum = 0;
* * *** * * * * * * * * * ((num == 1) || (num == 2))
* *** * * * * ** * * * * * **
* * ** *** * * * ** * * * ** * * *** *** ** * ** * 1;
* * * *** * ** * * *
** * *** * * * *
* * *** ** * ** * * * *
** * * * * * * * * * *** * * * * * ** (i = 3; i <= num; i++)
* * *** * * * * *** ** * * **** * ** * **
** * ** ** * * * * ** ** * ** * * * ** * * * * ** * * ** * * * * * * * = num1 + num2;
* * * * ** * ** * * * *** ** * ** * * * * * * ** ** * * * ** * ** ** = num2;
*** * * **** * * * *** ** * * * * * ** * *** * ** ** * * * * * * = sum;
* **** * * * * ***** **** ** ** ** * * * *** * **
* ** * ** *** ** * * * * * * * * * * ** * * * sum;
* ** * *** ** * *** * ** *
}
int main()
{
* * * ** ** ** * * * * * num, sum;
** ** ** * * ** * ** *** * * * ** ** &num);
* * * * *** * ** *** ** ** = sumNfiS(num);
* * * ** * * * * ** * ** * ** * * * *** sum);
*** *** * * * ** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* * * **** * * ** ** **
#include<math.h>
int main()
{
* *** * * * ** * * ** * i,j,k=0,a=1,b=1;
******* * * * * *** * * * ** ** * * *** *
** ** * * * * * * * || i==1)
*** * *** * * ** * ** * **** ** *** **
* * * * ** *** ** **
{
* *** * ******* ** * * * *
{
* * ** ** *** **** * * ***** *
* ** ** *** * * * * ** ** * * *
* * * * * * ** * ** ** * * ****
}
** *** * * ** ** * ** ** * * * *
}
** * * ** * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * ** * ** * ** ** k, num1, num2, i;
* ** ** * * **** * * * * = 1;
* * ** * * * * * *** = 1;
* * * * * * *** * ** == 1 || x == 2)
** ** * * * * ** * ** * * * * * * * * * * * * * ** *
* * * ** ** * * * * ** *
*** * * * * * *
***** *** *** *** * * *** **** * * ** * = 3;i <= x;i ++)
*** * * ** ** * ** *** * * * * ***** *
* * * * ** *** * * * * * * * * * * * * ** * * * ** * * = num1 + num2;
* * ** * * ** ** ** ** *** * * * * * ** * ** * * = num2;
**** ** * ***** *** * * * * ** ** **** ** ** * ** ** ** * * * * ** * = k;
* *** * * * * * * * * ** ** * * * **
* * * * **** * * ** * * * * ** ** ** *** * *** * ** * * k);
* * ** *** * * * ** **
}
int main()
{
*** * * * * * * * * * x;
** * * ** * * * ** * * * * * * * ** * &x);
* * * *** * ** *
* * * * * **** * * * ** * * 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * **** * * * **** * ** i,sum=0;
** ** ** ** * * **** ***** ** * x=1,y=1;
*** ** ** * ** ** ** * ** * *
* * ** * * * * * * * ** * * ** * * ** * * * * 1;
* * * * * * * ** ** * * * * * *
** * * ** * * * * * **** * ** * ** * ** * ** 1;
* **** * * ** * ** *** ** *
{
* * * ** * ** * ** * * *** * * * * *** ** * **** ** *
**** ** * * * * ** * **** * * * * * ** * * *
* *** ** * * * * * * * * * ** * * * * * ** * **** * * = x+y;
* * ** * **** * ** ** * * ** * **** * * * * * ** * * * ** **** = y;
* ** * *** * * * * *** ** * ** * * * ** * **** * **** * * ** = sum;
** * * * * * * * * * ** * * * * **
* ** ** * * * ** * **
*** * * ** * * * * * sum;
}
int main()
{
* * * * * * * ** a,total=0;
* ** * * * * * * * * ** * *** * * * *
** * ** * ** * * ** * * = fas(a);
* * ** * * *** ** ** * ** * * *** * ** * ** * *
** ** * * * * * * * * * * * * * * *
**** * * * * * ** ** ** ** * 0;
}
answered
Nov 3, 2016
by
410523043
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * ** * * * * k, num1, num2, i;
* * * * ** * * ** * ** = 1;
* *** * * ** * * * = 1;
* * *** * * * * * * == 1 || x == 2)
** * **** * * * * * * ** ** * ** ** ** ** * * *
* * * ** * *
* ** * * ** * * * **
* *** ** * * * * * * * * * ** * * = 3;i <= x;i ++)
* * * * * * * *** * * *
* * *** * * * ** * * * * ** ** * ** * ** ** = num1 + num2;
** * * * ** * * ** * *** ** * ** * * ** * * * *** = num2;
* * * ** ** * *** * * * * * * * * * ** * * ** ** * * *** * * = k;
* ** * * * * * * * * * * *** **
** * *** * *** **** * *** ** ** * * ** * ** * * *** ** * k);
* ** * * * * ** *
*** * * * * * ** ** * * 0;
}
int main()
{
** * * **** * * ** * *** x;
** * ** * * ** * ** * ** * * * ** * &x);
** * * ** ** * ** ** * * **
* * ** * ** * ** ** ** 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include *** ** ** * * ***
#include * ** * ***
int printFF(int n);
int main(int argc, char *argv[]){
* ** ** * * * * ** a,b,sum;
*** * * *** ** ** * * * * * ** * ** *** **
* * * ** * ** * * ** * ** * = printFF(a);
* * ** * * * * *
* ** * * * * * ** * * ***** * **** * * ** * *** **
***** ** * *** * * * * * ** * * * * ** * * ** * *
** * * ** ** * * * * * ** * * 0;
}
int printFF(int n){
* **** * * *** * ** *** * * ** f[10000]={1,1,0},i;
* * * * * * * ** ** * * * i <= n; i++)
*** * * * * * ** ** * * **** * *** *** ** * * **** * * * * * ** * ** * **** * *
* **** ** *** * * ** ** * ** * * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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