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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* **** ** * * * **** * *** ** a,b=0;
* ** ** * ** ** * * * * * * * ***
* ** * **** * **** * * * * * * * ** * * * *** ** = b+a;
* ** * * * ** ** * * * ** * ** * ** ***
* * * ** ** * * ** * * * **** * * ** **
* * * * * * * ** * * * * * *
* ** * ** * ** ** * ** ** *** *
int main()
{
** * **** * * * * * *** * * * num;
* * * * * ** ** *** ** ** * * ** * * * * * *
* * * * * * * * ** * * ** *
* * * * * * * * * * * *
* * ** ** *** ** * * * * *
**** *** * *** * * ** * * * * *
*** ** * * **** *** ** * * ** 0;
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** * * * * ** * * * *
* * * * * ** * ** * ** *
** * *** ** ** * ** *
* * ** * * * * * * *
* * * *** ** * ** ** ** *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * *** * * ** * * ** i,n,fi,last1 = 1,last2 = 1;
* * ** * * * * * * * ** *
* * * * *** * * * * * ** * * *** * ** ** * * * *
*** * * * ** ** ** *** * *
** ** **** * **** * * * ** * * * == 1||n == 2)
** * ** *** * * **** * * * * * * * ** ** * * *
* * ** ** * * * * ** ** * ***
* * ** * * ** ** * * ** * * *** **
* * *** * * * ** ** ** * = 3;i <= n;i++)
* ** ** * * ** ** **** * ** * ** + last2;
** * * ** ** ** * * * * * * * * * * * = last1;
* ***** * * * * * * **** * ** * * ** = fi;};
* ** * * **** * * * ** * ** * * * * *
* *** * * * * * *
* * * * * * **** * * ** * * * *** *** ** * * * *
** * * * * * *** * * ** ****** **** 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * * ** ** ** * * * * ** i, num1 = 1, num2 = 1, sum = 0;
** * * * ***** ** ** ((num == 1) || (num == 2))
* * * * * * *** ** * **** *
* *** * * * ***** *** ** ** * ** ** * ** * * 1;
* * * * * * * * * ** ***
* * ** * * * ** * * ***** * * **
* * * * * * ***
** * ** *** * ** *** * * ** *** * * * * * * (i = 3; i <= num; i++)
* *** * * ** **** * * * * * * ** * * *
** * ** * * * * * * ** * *** * * * ** * * * ** ** * * * * ** * * *** = num1 + num2;
* ** * * * * *** ** * *** *** * * **** * * * * ******* * *** * * * ****** * * * = num2;
*** * *** * * ** * * ** **** ** **** * ** * ** * * * * **** ** ** * ** * * * * = sum;
* *** * * * * *** * * ** ** * *** * * *
* * * * * * * *** ***** * * * * *** * ** ** * ** * * * * sum;
* **** * * * *
}
int main()
{
* * * num, sum;
* * * ** ******** * * ** ** * ** * * ** &num);
* * ** * * * ** * ** * * = sumNfiS(num);
*** *** ** * * * * ** ** * * * ** * *** ** sum);
* ** * * * * * **** *** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * *** * * ** int num;
* ** ** ** * * * * * * a,n,b=1,c=1;
* * * * ** * * ** * * **** * * * ** ***** * ***** * *
* * * * * ** * * * * * ** ** * ** ***
{
* * * **** **** ** * * * * * * * * *** * * * * *** ***
* * * * * *** *** *** * ** ** ** * * * * ** ** * * * ***
}
* * **** *** ** * * *** ***
{
**** * * * ** * * ** * * * * * ** * ** * * * ** ** * ** *** *
* * * * * ** * * * * * * ** *** * * ** *
* * * ** * ** * * * * * *** * * * * * * * * * ** * * * * * * * * * * *
** * ** * *** * * * * * *** * * ** * * ** **** ** * * *
** ** ** * * * ** * ** ** ** * * * * * * *** ** * * *** * * * * **
* * * * * * * * ** * * ** * * ** * * ** * * * ** *
* * * ** * * ** * * * * * * * * * * ** * * * ** **
}
* * **** *** ** * *** ** *** * ** * * ** *** * *
* * * ** * * * * * * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * * * * * * * * i, num1 = 1, num2 = 1, sum = 0;
*** * * * * * * * ** * * * * ((num == 1) || (num == 2))
* * * ** * ** * * ** * **
* * * *** *** * * ** * * ** * * *** ** * ** *** ** * 1;
* **** * * ** *** * *
*** * * ** * ** *** * **
* * * * * * * * * * *
* ** * *** ** * * ** ** * * ** * * ** **** * (i = 3; i <= num; i++)
** *** ** * * * * ** * ** * ** * * ** *** * * * ****
* * * * * * * ** ** * * ** *** ****** ** * ** * * *** * ** * * * = num1 + num2;
* * * * * *** * * * * * * * ** *** * * *** * * * * * ** * * * = num2;
* * * *** *** * * *** * * * * * *** * ** ** ** ** * * * *** ** * ** * * * * * = sum;
*** * * * * * * * * * * * * ** * * * * ** * ** * * *
** * * ** * * ** * * **** * ***** * * * * * ** sum;
* * * * * ** * ** *
}
int main()
{
* ** ** * * ** * * ** * * num, sum;
* * * *** * * *** * * * ** **** * * * ** * &num);
**** ** * * * * * * * * * * = sumNfiS(num);
** * ** ** * ** * * * ** * * **** * sum);
* *** * * ** * * * * * * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* * ** * * * * * ** *
#include<math.h>
int main()
{
*** * * * ** * * i,j,k=0,a=1,b=1;
* * ** * * * * ** * *** * ** * *** *
* **** ** * ** * ** * * * || i==1)
* * * * * * * * * * ** ** ** * *
* * ** * **** * *
{
* * * * * ** * * * ** ** ** *
{
**** ** * ** * * ** ** * *
* * ** *** ** * * ***** * *
* *** * ** * * * * *** ** *
}
** ** *** * * * * * ** ** ****
}
* * * * *** * *** ** * *** * 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * * * * ** k, num1, num2, i;
* * ** * * * ** * = 1;
** * * ** * * * * = 1;
* * * *** * * * == 1 || x == 2)
* ** * * ** ** * * * * *** * * * *** * * ** * * **** * * * ***
* * ** *** *** * * * *
** * * *** *
** * * * * * * * * ** ** * *** * * * ** = 3;i <= x;i ++)
* * *** * **** * * * ** * ** ** * * *
* ** * * *** *** * * ** ** * * ** * * *** * *** = num1 + num2;
* *** * * * * * * * ** * * * *** * * ** * * * * * = num2;
* ******** * * * * ** * * **** **** ** * * ** ** * * * * ** * *** = k;
* ** ** * ** ** *** * * * * * * *
* * * * ** ** * * * * *** ***** * ** * *** * ** * * ** * k);
* ** ** ** * ** * *
}
int main()
{
* **** ** * x;
*** * * **** * ** * ** * &x);
** * * * *** * * ** ** *
* ** * *** * *** * * * * 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * ** *** * ** * * i,sum=0;
* ** * *** * **** * * ** x=1,y=1;
* * * * * * * * * ** *** **
* * ** * * * * * ** ** * *** * * * * * * ** **** 1;
*** ** * * * * * ** * * **
* * * ** * *** * * * ** *** * * * * * * * * * 1;
*** * * **** * ** ** *
{
* *** ** * * * *** ** * * * * * * * * * *
* ** * * * * * * * ** ** * * * * * *** *
** ** * ** * ** * * * * * *** * * * * *** **** ** ** * = x+y;
* ** * * * * * * ** *** *** ** * * * * * ** *** * * * ** * * = y;
* * * * * * *** * * *** ** ** * *** * * * ** * * * = sum;
** * * * * * * *** * * ** * * * * * *
* * ** * *** * ** ** *
*** ** * * * ** * * * sum;
}
int main()
{
* * * *** * * ** * a,total=0;
* * * * * *** ** *** * * * * * * ** *
** * *** ** * * * *** * * ** * = fas(a);
** *** *** * * * * *** * * * * * * * * ** * **
** * * * * * * * ** * * * * *** * ** *
** * * * *** * * * ** * * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** * * * ** * * k, num1, num2, i;
* ** * * * *** ** * = 1;
* *** * **** ** * * = 1;
* ** ** * ** == 1 || x == 2)
* * * * ** *** * * * ** * ** **** ** * ** * * * * ** **
*** * * ** * * * *
* * * * * * *** * *
* * *** * * ** * * * * * ** * ** * = 3;i <= x;i ++)
* * * * ** * ** **** * * * ** * *
* ** * * * * * * * * * * * * * * * ** * **** = num1 + num2;
** * ** * ** *** * * * * * * * * * ** *** * * * * * * *** * ** * = num2;
** * *** * * * * * *** ** * * * * ** * * ** ** * * ** ** = k;
* * * ** * ** *** * * *
*** * ** ** * * * * * * * ** ** * * ** * ** * * * ** k);
*** *** * * ** * *
** * *** * * * * 0;
}
int main()
{
* * * *** *** * * * x;
* * * * * ** * * * ** * * * ****** &x);
* ** ** * * * * ** * * *
* ** ****** * * * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include **** ** ** *
#include * * * *
int printFF(int n);
int main(int argc, char *argv[]){
* * * ** * * ** * * * * a,b,sum;
** ** * * ** * * * ** * * * * * * * * *** * ** * *** * *
* ** * * * ** * * ** *** = printFF(a);
** * * *** * * * *
**** ** * * ** *** * * ** ***** * * * **
**** ** * * * * *** * * * ** * ** ** *** * *** * ** ** * *
* * ** * * * * ** * * *** 0;
}
int printFF(int n){
* * ** * **** * * **** * * f[10000]={1,1,0},i;
* ** * * * * * ** i <= n; i++)
****** * * * ** * * * * ** * * * * * * * **** * ** * * ** *** * * * * * *** ** ** **** * *
* * * * * * ** f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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