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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* * * * * * * * ** * * a,b=0;
* * * * * * * * * * * ** ** ** **** ** ** * ** * *
* ** **** * * ** * ** *** * * ** * * = b+a;
* * * * ** ** ** ** *** * * ** ****** * *
** ***** * * * * * * ** * * * ** * *** * **
* * * ** ** *** ** * * * ** ****
* * * *** ** * *** * * ****** * ***
int main()
{
** * * * **** * * * * num;
** * * * * * * * ** ** * * * * * * * * ** **
*** * *** * ** *** **** * * * * * * * **
* * * * ** * * ** * * *
* * * * * * ***** * **
* * ** * ** * * * * *** *** **** * * * ** * * * * *
** * * * * ** ** * * *** * * ** * 0;
* ** ** * * **** ** * *** *
** ** *** ** *** * * * *
* * * * ** * * ** **** * **
* * ** **** * * *** ** * * *
* ** * ** * * * * *
* * ** * * *** *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * ** * ** * * * * ** * i,n,fi,last1 = 1,last2 = 1;
* **** * * * * * ** * * * * *
* ***** ** * *** * * * * * ** * **** ** *
* * *** *** * ** * ***
** ** * * * ** ** * * * ** * == 1||n == 2)
* ** * * * *** * *** * * * * *** * * ** ** * *** **
* ** ** *** * *** * * *** * * ***
* ** * * ** ** * * *** *** * * **
* ** * * * * ** ** * ** * ** * = 3;i <= n;i++)
* ** * ** * ** * ** * * * * ** * ** ** + last2;
* ***** * ** * * *** * ** * * * ** = last1;
* *** * * * * ** ** * * * * * * * *** = fi;};
* * * ** * * ** * ** * ** ** * * * * * * * * *
** * * * * **** ** ** ** * * ** *
* * * ** * * ** ** * * * * ** ** * * * * ** * * * *
* *** * ** ** ** ** ** ** * *** ***** 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* ** * * * *** * * * i, num1 = 1, num2 = 1, sum = 0;
* ** * *** ** * ** ** ((num == 1) || (num == 2))
* * * * ** * * * * * **
* ** * * * * ** * ** * * * * * * * * * * 1;
* * ** * ** *** ** *
* *** * * * * * * ****
** * ** ** * * * * *
* * * **** ** **** ** * * * *** * **** * * * ** (i = 3; i <= num; i++)
* * ** * * ** * * * * ** * ** ** * * * * * *
* * * **** ** **** * *** ** * ** * * * * * * *** ** ** * ** * *** ** * * ** * **** * *** = num1 + num2;
* * ** * ** ** * * * * * * * * * * * * *** * * * * * ** ** **** * *** = num2;
** * * * ** * * * * ** * *** ***** * * * * * *** ** * * **** * * * *** * * = sum;
* * * ** * ** * *** ** * *** * * **** ** * * * **
* * ** ** * ** * * *** * * * * * ****** *** **** * * sum;
* * ** * *** * ** * * *
}
int main()
{
** * ** * * *** * * * num, sum;
* * * * * ** ** * ** * * ** * ** * * * * &num);
** ** * * ** *** * *** * ** * * = sumNfiS(num);
** * * * * ** ** ** * ** * * * ** * * * sum);
* * * * ** * * * *** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* *** * ** ** * * ** * ** * int num;
** * * * * ** ** * ** * a,n,b=1,c=1;
**** ** * * ******** * * * ***** * * * * * ** ** *
*** * **** ** * * * ** * ** *
{
* * * * * ** * * ** ** * **** * * *
* * ** *** * * * **** * * * ** * * * *** * * * * ** **
}
** ** ******* ** * ** ** * * *
{
* * * **** * ** * * * *** * * * * * * ** ** *** ** *** * ** * * *
* * * *** ** * * * * **** * ** ** * * *** * * ** *
* * * * ** ** * * *** * * * * * *** * ** * * ** ** ** ****** * * * ** ** **
* * * * * ** **** * * * ** * * * ** * * * * * * * * * ** * * ** *
* ** ** * ** * *** * * * * * * * * * * * * * * *
* *** ** * * ** *** * *** * * ** ** *** * * ** * * * **
* * ** * * * * * *** * ** * *** * * * ** ** * * * * *** ***
}
* * ** * * * * * * * * * * * ** * * * * *
* * * * ** * * ** * * * * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* ** * * * * * ** ** *** i, num1 = 1, num2 = 1, sum = 0;
**** * * * **** * * ((num == 1) || (num == 2))
** * **** **** ** * * *
* * * *** ** ** * * * **** * * * * * *** * ** * 1;
* * ** * * * * ** ** ** **
*** * * * * * *** ** * * *
* * ** *** *** * *** *
* * * * * *** * * * * * * ** * * * * (i = 3; i <= num; i++)
** * * * * ** * ** * ** * * * * ** * * ** *** *** ** * ***
* * * * *** * * ** * ** * * * * * * * *** * * * * * * * * * * = num1 + num2;
* *** * ** * * * * * * * * ** * ** ** ** * * ** ** * * * * * * * = num2;
* * * **** * ** * ** * * * * * *** * * * * * * * * * **** *** ** * * * * = sum;
* * * * * * * ** * * *** * **** * ** * *
* *** * * *** * ** ** * * * * * ** ** * * sum;
** * * *** ** *
}
int main()
{
* * * * * * * * * * **** num, sum;
* ** *** * ** * * * * * *** **** ** **** * &num);
* * *** * * ** ** ** = sumNfiS(num);
* * * * * * * * * * **** *** * * ** sum);
* ** ** * *** * * * * ** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
** ***** * * * * *
#include<math.h>
int main()
{
** * ** *** * * ** i,j,k=0,a=1,b=1;
* ** * *** ** * * **** * * * * * * ** *
* **** * * ** ** * * || i==1)
* ** * * * ** * * * * * ** ** *
* * *** * * * ** * ***
{
* * ** * * *** ** *** * **
{
*** * * ** * ** * * ** * *
*** * * * * * *
** * ** * * *** * ** * ** *
}
** *** * * ** *** * * ** * * ** *
}
* * * ** * * * *** * 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * ** * * * * k, num1, num2, i;
** **** **** ** *** * = 1;
* * ** * * * * = 1;
** * *** * * * * * * * == 1 || x == 2)
* ** ** * ** * * * *** **** * * ** * * **** * * * *
* ** * * ** ** **
* * * *** ** * *** *
* * ** * * * * * * ** * * * *** = 3;i <= x;i ++)
** * * * * ** ** * * * * ** * ***
* ** ** * ** * ** ** * * * * * * * ** * * ** * = num1 + num2;
** *** * * * ****** ** * * * *** * ** ** ** * * * ** ****** = num2;
* * * * ** * * * * ** * ** * ** * * * * * * ** ** * = k;
* * ** *** * * * **** *** * ** *
* * * ** * * * * * *** * *** *** * * * * * * ** * k);
* * ** *** * *
}
int main()
{
* ** ** * * * x;
**** * ** * * * * * ** * * * * &x);
* * * * * * * * ** * **
* * * * *** ** * **** 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* ** * * * * ** * ** i,sum=0;
*** * ** * * * ** * * * x=1,y=1;
* *** * * * ** * * * * *
* * *** * ** ** * ** * * * * * * 1;
* * * * * * ** * * *
** * * ** * ** * * * * *** ** * ** * * * * * ** 1;
* ** * ** * * * *** * **
{
** * ** ** * * * * * ** ** * * * * * * * ** ** ** **
* * * ** * * ** * ** * * * * ** * *
**** ** ** ** * * ** ** * * *** * * * ** * * * * * *** * * = x+y;
** ** *** *** * * * ** * * * * * * ** ** * * * * * * * * *** * * * = y;
* ** *** * * * * **** ** ***** * * * * * ** * ** *** * * = sum;
** *** * *** **** * * * * ** ** *** * * **
* * ** * * * ** ** *
** * * * ** * *** * * * * sum;
}
int main()
{
* *** *** ** * ***** ** a,total=0;
* * * ** * **** ** ** *** * *** ** * * * * * *
** ** * * ** * * * * * = fas(a);
** ** **** * * ** ** ** ** *** * * ** * * * * *
* * * * ** * * * ** ** * * *** * * * * * **
* * * * * * ** * 0;
}
answered
Nov 3, 2016
by
410523043
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * ** * * ** * *** k, num1, num2, i;
* ** * * * * * * * * = 1;
* ** * ** * *** = 1;
* * * * * *** * == 1 || x == 2)
* * **** * *** * * * * ** ** * * * * * * *** ******* *
*** * * * * *** * * * *
* * ** ** ** * ** *
* * ** * * * ** ** * ** * ** ** * = 3;i <= x;i ++)
* * ** * * ** * * * * * * * * *** **
* * ** * * ** * ** ** ** * * * * * *** ** * * * ** * * * * ** = num1 + num2;
* * * ** * * * * * * ** * * *** * * * * * * ** ** * ** = num2;
* * ** * * ** ** * * * ** * * * ** * * * * * * ** = k;
* **** * ** * * * ** *** * * * *
* ** ** * *** ** ** * * * * * * ** *** * * *** * * * * k);
** * *
*** * * ** ** * ** * 0;
}
int main()
{
* * **** * ** * **** x;
* * *** * ** * * * * *** **** *** * * * ** &x);
** * * * * ** **
* ** * * * * ** * * * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include ** * * * * *
#include * ** * * *
int printFF(int n);
int main(int argc, char *argv[]){
** * * * * *** ** ** * * ***** * a,b,sum;
* ** * * ** ** * * * * * ** ** ** ** * ** * *
* ** * * *** * * * * * * = printFF(a);
* * * * * ** * ****
* ** *** ** ** *** ** * ** * * * * ***
** * ** * ** * * ** * * * * ** * * * * ** **** * * ** * ** ** ** * **
** **** * ** * ** * * ** ** * * 0;
}
int printFF(int n){
* ** ** * * ** * ******* f[10000]={1,1,0},i;
* * * ** * * * * * ** * * i <= n; i++)
* * * * * * * ** * * * * * * * * ** * ***** * ***** * * * * * ** * * * * *** * *
* * * ** * *** * * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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