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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* ** * * ** * * * * * ** * * a,b=0;
* *** ** * * **** ** * ** * * * * * *
* ** * * * * * * ****** ** * * * * = b+a;
** * * ** * ** * ** * * * * ** * ** **** * * * * *
* ** * * ** ** * * * * * * * * * *
* * * * * * * ** ** * * ***
* * * ** * *** ** ** * * *
int main()
{
** * ** ******* * * ** * * num;
** * * * * * * **** * * * * ** * *** * *** ** **
*** * ** * ** * ** *** * * * * * * * *
* * * * * ** * ** * ***** * *
** * * * * * * ** * ** ***
*** * *** ** * ** * * * *** * ** * *
* ** ** * ** *** * * ** ** * 0;
** *** * * * * ** *
*** * * * * * * * * **
* * * * * ** * * *****
*** ** * * * ** * * * ***
* *** * * * * * * ****
* * ** ** * * ******
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * *** * * **** * *** i,n,fi,last1 = 1,last2 = 1;
* ** * * * * *** * *** * *** * *
* * ** ** *** ** * * * * * * * * * ** ** ** * *
* * * * * **** * * ** ** *
** * * * * ** * * * * * * * * == 1||n == 2)
* * *** ** * ** * ****** ** *** * * * * * * ** ** **
** * ** * *** ** ** * * * * * ** *
* **** * * * ** * * *
*** *** * ** ** * ** * ** *** * * * ** = 3;i <= n;i++)
** * ** * * * * *** * * ** * * * + last2;
* * ** * * * ** ***** ** ** ** * * = last1;
* ** * * * * * * ** * * ** * ** = fi;};
* **** ****** * * ** * * * ** * * * ** ** * * ** * * *
* * ** *** * ** * * * * * *
* * * ** * * * * **** * **** * ** * ** * * ** ** *
* * ** ** ***** ** ** * * *** * * * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * * * * * * * * * ** * i, num1 = 1, num2 = 1, sum = 0;
* * * ****** * * * * * * ((num == 1) || (num == 2))
* * * * * ** * ******
** * * * ** * **** * * * * * * ** * * ** * * *** *** * 1;
* * * * ** * * **
* * ** * * ** * * * **
* * * * * ** * * * **
**** * * * * ** * * *** *** * ** ** *** * * * * (i = 3; i <= num; i++)
* ** * * * * * * * * * * * * * **** * *
* * ** * ** ** ** * * ** ** * * * * * * * ** * *** * ***** * * ** * ** * ** * * * = num1 + num2;
* ** * * * * * * * ** * * * * * * ** *** ***** * * * *** * *** **** = num2;
* * * * * * * * * * * * * ** * * * ** * * * ** ** * * ** * * * * * * = sum;
* * * * ** * * ** * * * * *** ** * ** * * *
** * * * * * ** * **** ** ** * * **** * * *** * * ** * * sum;
** ** * * ** * ** **
}
int main()
{
*** * * ** * ** ***** num, sum;
** * ** ** *** * ** **** * * * * * * &num);
* ** * ** * *** * ** ** * = sumNfiS(num);
* ** * * ** * ** * *** ** * ** ****** ** * sum);
* *** * * ** * * ** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* **** * * * * * * * ** * int num;
* * * * * * * a,n,b=1,c=1;
* * ** ** *** * * * ** *** **** * ** * * * * * * * *
* *** * * * * * *** ***** * ** * ** * * *
{
** * *** * * * * * ** * * * *** * *
* * ** * * * *** * ** * *** * * * * * * * * * * * ** * ** * **** *
}
* * *** * * * * * ** * **
{
** ** * * * * * * * * * * * * *** * ** * * * * * ** * *
*** * * ** ** ** ** * * **** * ** * * * ** ***
* ** * ** *** ** * * * * *** * ** * * * ** * * * ** * * * *** **** * ** * * *
** * * * * * * ** ** * * * * ** * ** * ** * ** ** **** ** * *** *** * **
*** * *** ** *** ** * * ** * * ** * *** ** * ** * * *** ** ** * * *
* * ** * * * ** * * *** * * * **** *** ** * * *
* * * * * ** ** ** *** * * * ** * * * * * * ** * ** * * **
}
** * ***** ** * * * **** * ** * * * * * * ***
**** * * ** * * ** * * * *** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* ** ** * ** * ** * *** * * i, num1 = 1, num2 = 1, sum = 0;
** * * ** * * ** ((num == 1) || (num == 2))
* * ** * *** * * ** * * *
*** * * *** * * * * *** * * * * * *** * ** * ** ** 1;
* * * ** * * ** ** * * * *
* * * * * ** ** ** *
*** * * ** * * * * * **
* * * * ***** * * * * **** *** * ****** ** ** (i = 3; i <= num; i++)
* * * * * ** *** ** * ** *** * * ** *****
** ** **** * * * * * *** ** * * ** * ** ** ** * ** ** * * * * * * ** * * = num1 + num2;
* * * * *** * * * * * * *** ***** * ** * * * * * * * * * * ** * * * * = num2;
* **** *** * * * * **** * ** * * * ** * * ** * ** * * * **** ** * ** = sum;
* * ** * * *** ** * * * ** ** * ** * * *
** * ** * * * * * * ** * * * ** * ** * * * * sum;
** ** * ** * ** * * * **
}
int main()
{
** *** * ** ** * *** num, sum;
* * * * * ** * * *** * *** * * * * * ** &num);
** * ** * * *** * ** ** * * * = sumNfiS(num);
* * *** * ** * ** * * * * * ** * **** * * sum);
* ** * * * * * *** * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
*** * *** * * * * ** *
#include<math.h>
int main()
{
* * ** *** ** * * * i,j,k=0,a=1,b=1;
** * * * * * * * * * * * * *
* ** * * * ** * *** * * || i==1)
** ** * * ** * ** *** ** *
** * * *** * * ** * **
{
** * * ** * * * * * * **
{
* *** * * * * * ** * ** *
** * * * ** * * * ** * ***
* * ** * * *** *** ** ** ** *
}
* **** * * * * * * ** ** *** * ** * * *
}
** * * * * * * * **** 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** * ** * * ** * * * k, num1, num2, i;
* ** * **** * ** * * = 1;
* * * * ** ** * ** = 1;
** * * * *** ** * * **** * == 1 || x == 2)
* ** ** ** * ** * * * * **** * *** ** * ** * * * ** *** * * *
* *** ** * * * * * **
* * ** * * *** * *
* **** *** ** ** * *** * ** * ** * * = 3;i <= x;i ++)
* ** * * * * * ** ** ** * * **
** * * ** * ***** * * *** * * * * ** * *** * * ** * = num1 + num2;
* * ** *** ** * * * * * **** * ** * * * ** * ** * ** * * * = num2;
* * * * * ** * ** *** ** * *** * * * * ** ** ** * * * * * * **** = k;
* * * * ** ** *** *** * *** ** ** *** ** *
* * * *** * ** ** * *** ** * * * *** ** ** * *** **** k);
* * * ** ** * * *
}
int main()
{
* ** * * *** * x;
*** * * * * ** * * ** * * ** * * * * &x);
* * * ** * **** ***
* * * ** * * **** * * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* ***** * * * * * *** i,sum=0;
* ** * * ** * * * * x=1,y=1;
* * * ** * * * ** * **
** * ** * * ** * ***** * * * ** * **** 1;
** *** ** * * * * * * * * *
* * ** * * * ** * * ** ** * * *** * * ** * * 1;
* * ** ****** ** * * ** **
{
** * * * ** * * * * * * * * * * *** * *
* * ***** * * ** **** * *** * * ** *** * *
* * ** * ** ** ** *** * ** * **** * ** * *** * ** ** ** ** = x+y;
* * ** ** ** **** * * * **** ** ** ** * * * ******* * * * * = y;
* * ** *** * * * ** ** *** * * * * * * * * ***** * * * ** = sum;
** * * *** * ****** * * * * * * * *
* * ** ** * * * * *** * *
* * ** * * ** * *** ** * sum;
}
int main()
{
* * * * * * * * ** * * * a,total=0;
* * * ** ** ** * * *** * * ** * * ** * ** * *
*** * * * * ** **** **** * * * * = fas(a);
* * * ** ** * * ** *** * * ** * * *
* * * * * ** ****** * * * ** * ** * **
* ** * **** * *** * * ** * 0;
}
answered
Nov 3, 2016
by
410523043
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * ** * * * * k, num1, num2, i;
* * * * ** * * = 1;
* * * * * * ** * * * = 1;
*** * * ** * * * * == 1 || x == 2)
** * * ** ** * ** * * * * ** * * * * * * * * ** ** ****
* * * ** ** * * * **
** *** * * * * ** ****
*** *** * * ** * * * *** * * = 3;i <= x;i ++)
** * ** * ** * * * ** ** ** *
** * * *** ** * * * * *** * * ** * *** * * ** = num1 + num2;
* * ** ** ** * * * * * * ** *** *** * * * * * * *** *** *** ** = num2;
** * ** * ** * ** * * * ** * * * * *** = k;
** *** ***** * *** * * * * ** * * * *
** * * ** * * * ** * * ** * ** * ** * * * k);
* *** * * **** ** * **
** * * * ** ** ** * 0;
}
int main()
{
* * * *** * * * *** x;
* ** * *** * * * ** ** * * &x);
** * * * ** ** * * *** * *
** ** *** ** * * ***** ** 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include ** * ** *
#include * *** * * * *****
int printFF(int n);
int main(int argc, char *argv[]){
* * * * * * * *** ** ** a,b,sum;
* ** * * * * *** * * * * ** * * * **
*** * * * * * ** * = printFF(a);
* * ** * * * * * ** **
** * ** * * * * * * * * ** *** * * ** * ***** * **
* * *** * * * * * * * * * * ** ** * * * * *
**** ** *** * * * * *** 0;
}
int printFF(int n){
* * * * * * ** ** ** ** f[10000]={1,1,0},i;
*** * * * ** * * * * i <= n; i++)
* ** ** * * * * *** ** ** * * * * * * * * ** *** * * **** * * * * *** *** * * * *
* * ** * * * * *** * ** * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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