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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
** ** * * * ** * ** * ** * a,b=0;
* * * ** ** * ** **** ** *** ** *** ** * * ***
* * * * * * * * * ** * * * * ** ** * * ** * ** * = b+a;
*** *** * * * ** *** * * ** * * * * *
* * * * * * * ** * * * **** ** ** * * * *
* * * * ** * ** * * * * * **
* ** *** * ** * ** * *** *
int main()
{
* ** * * * * *** * * * * num;
* * ** * * * * *** ** *** * * * ** * ** * * ** * * * * **
* ** * * ** *** * ** * ** **
* * * * ** ** * ** * * * * *
* * ** * ** * *
** * * * * * *** * * * * *** * * ***
* *** ** ** * * ** * 0;
* * ** * * ** * **** * ** ****
**** ** ** * * * * * * **
* * ** * *** * ** * *
* * *** * * ** * * * * * *
* * ** ** * * ** ** * * * *
* * * * * * * * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * **** * ** * * * * i,n,fi,last1 = 1,last2 = 1;
* ** *** * * * ** ** * * * * **
* * * * * *** * ** ** * * ** ** ** ** * * * * * *** * *** ** *
* * ** *** * *** * * * *
* * ** * * *** ** * * * ** ** * * ** == 1||n == 2)
*** * * * ** * * * * * * ** * * * * * * * * *
*** * ** * * * ** * ** ** * *
* * * * *** * * * * * * * * **
** *** * ** ** *** ** ** * * = 3;i <= n;i++)
* ** ** ** * * * * * ** + last2;
* * * * * * * * **** * * * * * = last1;
** ** * * * * *** * * * * * ** * * *** * * = fi;};
* * ** * * * * * ** ** ** ** *** * * ** * **
*** * * * ** * * * * * * *
*** * ** *** *** ** * * * * * * * ** ** ** * ** ** *
** ** ** * * ** * * * * ** * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * * * * * * * * **** i, num1 = 1, num2 = 1, sum = 0;
* * * ** * * * * ** * **** ((num == 1) || (num == 2))
* ** * ** * * *
* * * * * * * ** * ** ** * * * * * * * * * * 1;
* * **** * * * * ** *** **
** * ** * * ** * * * * * *
* *** *** * * * ** * *
* * ** ** * * ** ** *** * * * * * * * (i = 3; i <= num; i++)
* *** ** * * ** * * * * * * * * ** * * * * *
* ** ** *** ** **** * ** * *** ** * ** * ** * * * * * * ** *** ** *** * * * = num1 + num2;
* * * ** ** * * ** * ** * * * * * ** * * ** *** * ** ** * * ** * * ** ** * = num2;
** * ** **** * * ** * * ** * *** * * ** * * * * * * ** * ** * * * * * ** ** * * = sum;
** *** ** * * * * * ** ** * * * * ** ** * * *** * *
* * * ** * * **** * *** * ******* * * * * ** ** sum;
* * * * * * * * * ** *
}
int main()
{
* ** *** * * * *** * ** * *** * num, sum;
** * * * * * ** **** * * * ** * * * * &num);
* * * * * * * = sumNfiS(num);
* * * *** * ** ** * * * * * ** * * * * sum);
* * * ** * * ** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
*** ** ** ** *** * ** * * * * *** int num;
* * * * * * **** ** ** * * a,n,b=1,c=1;
*** * * * * * * ** * * * * ** * * * * ** * * **
* * * * ** * *** * * * *** * * ***
{
* * * * * * *** * ** * * * ** * *
*** ** ** * ** **** * * *** ** * * * * * * * ** * * * **** * * *
}
** * * * ** * * *** *
{
* ** * ** ** * * * * ** * * * * * ** * ** * * *
* *** * * * ** * *** * * * * *** * ** * * * * * * * *
* * ** * * * * * * * * * * * ** ** ** * ** * * * * *** * * ** * ** ** * *
** * ** * * * * * * ** * * * ** *** * * * * * ** ** *** * ** * ** * **
* * * * ** * ** * ** * ** * * * *** * * * * * *** * * * ** * * ** *
** * * ** * * * ** * ** * * * ** * * * *
* * * *** * * *** * * * * ***** *** * * * ** * * * * * * * *** ** ** * ***
}
* ** * * **** * * * * * * ** * *
* ** * * ** * * * * ** * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * *** * * *** * * i, num1 = 1, num2 = 1, sum = 0;
* **** * * * *** *** ((num == 1) || (num == 2))
* * * * ** * *
* * *** ** * * * * * * * *** * ** * * * * * * 1;
** * **** * * * * *
* * * * * **** * *
* * * ** * **** *** * **
* * * * * * * * * * *** * * * * **** ** * (i = 3; i <= num; i++)
* * * *** * ** *** *** ** * * ** ** ** * * * *
* * * * * * ** * * *** * ** * * * * * ***** * * ** * * * ** * * * * ** * = num1 + num2;
**** * * ** ** * * * ** * * * * * * * * * * ** * * ** * ****** = num2;
** ** ** **** * * * * * * * * * * **** * * * ** *** * ** * ** ** * * ***** = sum;
* * * * * * *** * *** * ** * * * ** ** * ****
* * **** * * * * *** *** *** * * * ** * * ** * ** **** sum;
* ** * * * * * * * * *
}
int main()
{
* ** * * **** * *** num, sum;
** *** ** * * * * * ** * * * ** * * * **** &num);
** * ** * * *** * ** = sumNfiS(num);
* ** **** *** * * * * * **** ** * * * sum);
* ** *** * ** * * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* * * * ** * * * ***** *
#include<math.h>
int main()
{
** * * * * *** * * * i,j,k=0,a=1,b=1;
** * ** ** *** * * ** * * * * * * * ** * *
* * ** *** ** * * *** || i==1)
* * * ** * ** ** * ** * * * * * *
* * ** * * * * * * *
{
* * * * ** * ** * * ** * ** * *
{
* * ** ** * * * * *** *** **
*** ** * ** * ** ** * * *
* * ** *** ** * ** ** * **
}
* * * ** * ** * ** ** *** ** * ** * * * **
}
* ** * *** * * * * ** ** 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * * * * ** k, num1, num2, i;
** * *** ** * = 1;
* ** * * * * * * * = 1;
** * * * ** ** * * * * == 1 || x == 2)
* * * * * *** * * * * ** ** * * * * *** * * * ** **
* * * * * * * * * *
* * * ** * ** *
* * * * * * * * * * * *** * * **** * = 3;i <= x;i ++)
* * * ** ** * * ** * *** ** ** *
* * * *** * ** *** ** * ** * * ** * * * ** *** * = num1 + num2;
** *** * *** * * ** * * ** * * * *** * * * ** ** ** * * *** ** * = num2;
* * ** ** * *** * * * * ** * **** ** * **** * ** * *** = k;
* ** * ** *** **** ** ** * * * * **** ** *
* * * * * * *** *** * * * * * ** * ** * * *** * * k);
*** **** ** *
}
int main()
{
* * * ***** *** * *** ** x;
* * * * ***** * * * ******* ** * * * &x);
* * * * * *** *** ** *** * *
** *** * ***** ** ** 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* ***** ** * ** ** **** * * * ** i,sum=0;
** ** * * * ***** * * *** x=1,y=1;
* * * * * ** *** ** * * **
* * *** ** * * * *** * * * * * * * * * ** * * * 1;
* * * ***** * ** * * * **** ** **
* * ** * * **** * ** * * ** ** * * ** * * 1;
* ** ** ** * * * * * * **
{
* * ** * * * * ***** * ** * ** * * ** * * ** **
* * * ** * ** * ** * ** * * *
* * ** * *** * * * * * ** * * * * ** * * ** ** * *** = x+y;
* ** ** * ** * ** * * ** * ** ***** * ** * ** *** * = y;
* * * **** * * * * *** * * * * * ** * ** * * ** * = sum;
*** * * ** ** ** * * * ** * * * ** *
** **** ** * * **** *
* * * * * * *** ** * * * * sum;
}
int main()
{
* ** ** * * * * a,total=0;
* * * * * ** * * *** * ** * * * *** **** **** * ***
* *** ** * * * ** * * * * = fas(a);
** * * *** * ***** * * * **** ** ** *
* * ** * * * * * ** * * *** ** ****
*** ** * * * * * ** 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
*** * * * * * ** * ** k, num1, num2, i;
** * * *** * * * * ** * = 1;
** *** * * * * ** = 1;
** * * ** ** * * ** * * == 1 || x == 2)
** * * * * ** * ** * *** * * *** ** ** * *
* ** * * * ** * * ** **
* * * * ** * * *
* * ** * * * * * * * * * * * *** * ** * * = 3;i <= x;i ++)
** * ** ** * * ** * * ** * *
* * * * *** ** * * *** * ** * ** * * * * * * * * * * = num1 + num2;
** ** ** * * * ** * * * ** ** ** * * ** * * * ** *** = num2;
* * * ** * * * * * * * * *** * *** * * * * * = k;
* * ** ** * ** * *** ** * * * ** * * *
** ** * * * ** * * ** *** **** ** * ** **** * * * k);
* * * * * * * * * * *
* ** **** * * * * 0;
}
int main()
{
* * * ** *** * * * * ** * x;
* * * * ** ** * * ** * ***** ****** &x);
* * * ***** * * * **
* * * * ** ** * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * * * *
#include * * * * **
int printFF(int n);
int main(int argc, char *argv[]){
* ** ** * *** *** a,b,sum;
* ** ** **** *** * * * * *** *** *** * **** ** * ** * *
* * * * * * ** * ** * = printFF(a);
** * * * * * * ***** * *
* ** * * * *** * * ** *** * * * **** ** *
* *** *** * ** * * * * * * * ** * * * * * * * * * * * * * * * *
* * * * *** *** * * * * * *** 0;
}
int printFF(int n){
* * *** * * * *** * * * f[10000]={1,1,0},i;
* * * * * * ** * * *** i <= n; i++)
* * * * * * * **** *** * * ** * * * **** * * * * ** *** * * * * * * ** * * * * * * * ** ** **
* * * *** * * * ** * ** ** ** * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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