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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* ***** * * *** * * * a,b=0;
** ** * * * ** * * * * ** **** ***
* * ** * * * * * ** * * * * = b+a;
* * ** * * * *** ** *** * * * * * * * * * *** ***
* ** * **** * * ** * * * * * *** ** * * * * *
* * * * * * ** * * *
** ** * * **** * * * *
int main()
{
** * * * * ** * *** *** * num;
* * * * * ** * ** * **** * * * * * * * * * * * ** * *
* * * * * * * ** * *** **** * *
* * * * * *** * * * *** * *
* * * * * * ** * * * * **
* * **** **** ** ** * * ****** * * * *
* * ** * * * *** * * * ** 0;
** * ** * * * * * *
* ** ** * * ** * * ** * * *
** * ** * * * *** * * *
* ** * * ** * * * * *
*** * ** ** ** * * **** * * *
* * * * * * * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * *** * ** * * * * i,n,fi,last1 = 1,last2 = 1;
* * * ** * * * * * *
* * * * * * * * * ** * **** *** * * * *** * * * *
* * * ** ** * * * *** * **** * ** *
*** * * ***** *** ** * * * ** * == 1||n == 2)
** * * * * * * * ** * ** * * ** ** ** ** * * * * * * **
* * * * **** *** * * * * * * *
* * * * * * * * * * ** **
* ** ** **** * * ** * * * ** * = 3;i <= n;i++)
* *** * ** ** * ** * ***** * * ** * + last2;
** ** ** ** *** * * * * * ** *** * ** ** * = last1;
** * * *** *** ** * * * * ** * * = fi;};
* * ** **** *** * ** * *** *** ** * *** * * ** *
* ** ** * * * * * * *** * * ** **
** * * * * * * * * * ** ****
* * * * ** ** * * ** ** * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
*** ** ** * * * i, num1 = 1, num2 = 1, sum = 0;
* ** * * ** * * * * **** * * ((num == 1) || (num == 2))
** ** * * *** * * * * *
* *** * **** ** ** * * *** ** **** *** * ** * 1;
* * * * * * * *
* * ** ** * ** * * **
***** ** ** * * * **
* ** * ** * * ** * * ** * ** * * * * * **** * * (i = 3; i <= num; i++)
* *** * * * **** * ** * * * * * * * ** * * **
* ***** ****** ** * * * * * * ** * * * * * * ** *** * *** * * * *** ** * *** * * ** * * * * = num1 + num2;
** * * ** ** * * ** * * * * ** ***** * * * * * **** ***** *** * * * ** * = num2;
** ** * * * * * * * * * * * * * ** * * ** * * * * * * * * * *** = sum;
* ** * * * ** * ** * * * * * * *** *** * *
*** * ** * * ** * * ** ***** * * * **** * * * * sum;
** * * * * * **** * * *
}
int main()
{
* ** * * * ** * * *** * * num, sum;
* *** * * **** ** * **** ** * * &num);
* * * ** * * *** * * * *** = sumNfiS(num);
** * * *** **** * ** * * **** * * ** sum);
* * * * * * * ** *** ** * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** * * * * * ** * int num;
** * * * * * * *** ** * a,n,b=1,c=1;
* * * * * * ** * * * ** *** ** * *
* * *** * * * * ** * *** ** * *
{
* * * ** * * * ***** *** * * * ** * *
**** * * * * * *** ** * ** * *** * * * * ** ** * * *** * * * ** *
}
* * ** * * * ** *** * * * *
{
** * * ** ** * * * * ** * * * * * * * * ** *** * * * *********
* * * * * * * * **** * * * ** * *
** ** ** *** * ** ** * * * ** * ** * * ** * * *** ** * *** * * * * * *
* ** * * * ** * * ** * *** * * * * ** * ** * * * ** ** * * * ** ** * ** *
* * * * * * * *** * * * * * * * * * ** ** * * ***** * **
* *** * * ** ** * * * *** **** **** ** *
** ** * ** **** ** ** ** * * ** * ** * * * ** * * * ** * * * * **
}
** * * * * * * *** * ** * ** **
** *** * * **** ** ** * * * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
** * ** *** *** * * * * * i, num1 = 1, num2 = 1, sum = 0;
* ** * * ** ** * * * * ((num == 1) || (num == 2))
* * * * ** *** ** * *
* * * * *** ** ** *** * * * * ** ** * * * **** * * * 1;
** * * **** ** *** ** **
*** ** ** ** * * * * * *
*** * * * * * * * * * * * ***
* * * *** * * *** * * * * ***** * * * * * *** (i = 3; i <= num; i++)
** * *** * * *** * * ** * * * * ** * * ** ** * * * **
***** ** ** ** ** * * ** * ** * *** * *** * * * * * * ** * * *** * ** = num1 + num2;
** * ** **** * * *** * ** * * * * * * * * ***** * * * * ** * ** = num2;
*** ** ** ** * * * ****** * * * * ** * * ** * * * ** * ** ** * * ** ** = sum;
* * **** * * * *** ** * ** **** * ** *** * ** ** * * ** *
* * ** * * ** *** * * * * * ** * ** ** * * sum;
* ** * * *** * *** **** ****
}
int main()
{
* ** ** * * * * * ** * num, sum;
* * * ** *** ***** * * ** * * ** * ** &num);
* * * * * ** * ** *** * * * * = sumNfiS(num);
*** * * * * ** * ** * ** * **** * sum);
***** * * ** * * ** * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* ** *** ** * * * * ** ***
#include<math.h>
int main()
{
* ** * * ** * ** * i,j,k=0,a=1,b=1;
* ** * * ** * * ** * * * * * * ** * *
* ** * * * **** ** * * || i==1)
* * ***** ** * * * * ** ** * ** *** *
** ******* * * *** * * ***
{
** * ***** * * ** * * ** ** * * *
{
* * * * * * * **** * **
* * *** * * * *** * *
* * * * * * * *** *** ** *
}
* * ** ** * **** * * ** ** *
}
** *** * ** ** * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
**** * * ** * * * **** k, num1, num2, i;
* * ** *** ** = 1;
** * ** * * * * ** **** * = 1;
* * * ** ** * * * * == 1 || x == 2)
* * * * * * * ***** * ** ** ** *** ** ** * *** * *
* ** * ** **
** * *** *
** * * * ** * ** * * ** * ***** ** * * = 3;i <= x;i ++)
* ** * ** * * **** * * ** * * ** * ** *
* ** ** * *** * * ** * * * * * * * *** * * * *** *** = num1 + num2;
** * * * * *** * * * * **** ** * * * ** **** * ***** * * * * * * * = num2;
* * ** * ** * ** * * *** * * ** * ** ** * ** * * * ** *** = k;
** * ** ** * ** * * * ** ** **
* * ** * * *** *** * * ** * * *** * * * * * ** * k);
*** * * ** *** * * **
}
int main()
{
* ** * * * ** * * x;
* * * * ** * ** * **** * * * * &x);
* * * *** ** *** ** * *
* ** * * * ** * * * ** 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * * *** * ** * * ** i,sum=0;
** ** * * * * * * * x=1,y=1;
* * * * * * * ** * * * *
* * ** ** * * * * * ** **** * * ** *** ** ** * 1;
* ** * * ** * * * * * ** * ** * *
*** * *** * * *** * * * * * * ** ** ** ** * * * ** 1;
* * * * * * * * ** *
{
* * * ** * * * ** * * * * *** * * ** * * * ** * *
*** *** *** ** * * * ** * * * ** * *
* * * ****** * *** * * * * * * * * * * ** * * ** * * * * * * * * * * = x+y;
* ** * * * * * * ** * * * * * * *** * * ** **** * * * ** * * = y;
** * * * * *** * * * * * *** ** ** * ** * * **** ** ** ** * * ** * = sum;
*** * * * * *** * * ** ** * ***** ** ** **
* * * ** * * *** * ***
** **** * * * ** *** *** ** * * * sum;
}
int main()
{
* * * * * ** * * *** a,total=0;
* * *** * * ** * * * * ** * * * * * *
* * * ** * * * **** * * * ** = fas(a);
* * * ** * * ** ** *** ** ** ** * * * * * * **
** ** ** * *** * ** * * * * ** ** * **
*** * *** ** *** *** * * ** 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * *** * ** *** k, num1, num2, i;
* * * * * * * * * * = 1;
* ** * * * * *** * * ** = 1;
* * **** * ** * * == 1 || x == 2)
* *** * ** * *** * * * * * *** * * ** ** * * ***
**** *** * * ******
* ** ** * * ** ** **
* * * * ** * * ** *** * * * * ** = 3;i <= x;i ++)
* ** * * * * * ** * ** * * * **
* * * ** * ** ** * * * ** ** ** * ** * * * * * * * * * ** = num1 + num2;
** ** * * * * ** *** * ** * * ** * * * * * = num2;
** ** ** * * * *** * ** ** *** * * ** * * ** * = k;
* * * * * * * * * ** * * *
* * *** * * * *** * * * * ** * * * **** ** * ** * *** * k);
* * ** * * ** *** * * *
* * * ** * **** 0;
}
int main()
{
* * * ** * * *** * x;
** *** ** ** **** * ** * ** * * * &x);
** * * * * ** ** * * ** * * * * *
* * * * * * *** * *** * * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include * * *
#include ****** ** ** * *
int printFF(int n);
int main(int argc, char *argv[]){
* * * * * * * * a,b,sum;
* * ** * * * * ** ** * * * * *** **** * * * * * * ***
** * ** ***** * * * * * ** = printFF(a);
** * * * ** * ** * * *
* * * * * * ** * ** * ** * ** * ** * **** * **
* ** ** * * * **** * *** *** * * * * ** **** * * * * *
* * * * * **** ** * ** * 0;
}
int printFF(int n){
* * ** **** * * * * ** f[10000]={1,1,0},i;
* *** ** ** ** ** ***** i <= n; i++)
* * ** * * * * * ** ** * * *** ** ** * *** ** * * * * * ** * ** * * * ** ****
* * * * * * * * * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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