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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
** * * * * ** * * * * a,b=0;
** ** * ** * * * *** * * * * * ** * ** *
* * * * * * ** * ****** * * * * * ** * ****** = b+a;
* ***** * * * *** * ** * * ** * ** **
* * * ** * * ** * * *** ** * ** *
* * * * * * * * ** * * ** ** ** *
* * * * * * *** *** * *
int main()
{
* * ** ** * * ** * * * num;
* * * ** * * ** * * * ** * * * * ** * * ** * *
** **** ** * *** * * * * ** ** ** **
* * * * * *** * **
**** * *** * * * *
* * * * ** ** * ** * *** * *** * * * *
** ***** * ** * * * ** *** * 0;
* ** * * * * *
* * * * * ** * *** * * *
* * *** * * * ****
** ** * ** * *** ** * * **
* * ** * * * * *** *
* * *** * * * ** * **
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * *** * ** * ** * * * * * i,n,fi,last1 = 1,last2 = 1;
* ** * * ** ** * ** ** * * *
*** * ** ** * * * * ** ** * ** * * * * * ** ** ** * ** * * **
* * ** ** *** * * * * * * * * *
* * * ** ** *** * ** * ** *** == 1||n == 2)
* * ** * ** ** * * ** * ** ** * ** * ** *
** * * * * * * * * ** * * ** * **
* ** * ** ** ** * *** *** ***
* * * * * ** * ** *** * * * = 3;i <= n;i++)
* ** * *** * * * * * * * * * * * + last2;
* ** * * * ** *** * * * *** * * * * = last1;
* *** * * * * * * ** * ** * * * * * = fi;};
** * ** * * * * ** * *** * * * ** * * * * * * * ***
* ** * * * ** * ** *
* ** * * * ** *** * * * * * ** **** * * * ** *
* * * * * * ** ** * * * *** * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * * * * * * * ***** * ** i, num1 = 1, num2 = 1, sum = 0;
* ** ** ** * * * * ** ** ((num == 1) || (num == 2))
* ** ** * * * ** * ** * * *
*** ** * * * * * ***** ** * * ** *** ** ** ** ** * ** **** * * 1;
** * * * * * * * *
* ** * * * * * * * *
* ** ** ** * * *
** * * * * * * ** ** * ** * * ** ** ** ** * (i = 3; i <= num; i++)
* ** ** * * * ** * ** **** ***** * * * *
***** * ** ** * * * * * **** * * * * * * * ** * ****** * * **** = num1 + num2;
* * *** * * ** ** * *** * * * ***** * * * * * * * ** * * * * *** ** * * * = num2;
** **** ** * * **** * * * * **** * * * * * * * * * * ** = sum;
* * * * * * * ** * * ** * ** * * ** * ** * ** * ******
* * * * ***** * * ** ** * ** * * * * ** * sum;
** * * ** * * * * *
}
int main()
{
* * * * **** * * * *** * * * num, sum;
* * * * * * *** *** * ** * ** **** &num);
* * * *** * * * * = sumNfiS(num);
* ** *** * * * * * ** * * ** * * ** * * sum);
* * * * * *** ** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * *** * * int num;
* * * * *** * * * a,n,b=1,c=1;
* * ** * * *** * * * * *** ** * * * ** **** * * * * ** **
* ** * * * * * * ** *
{
* * * * * ** ** * * * * * ** ** ** * * *** * *** * *
* * * **** * * ***** ***** * * * * ** * * *** * * *****
}
* ** ****** * * ** **
{
* *** **** * **** * * * * * * * * ** ** * * * * * * *** * * ** *
** ** * ** * * * * ** **** **** ** * * **
* * * * * * * * ** * * * ** ** ** * * ** * ** * ** * * *** * ** * * ****
* ** * * *** * ** * * ** ** * ** ** ** ** * ** ** ** **** * * * * * *** * * ** *
* * * * * * ** ** * * ** * * * * * * * ** ** ** * ** * * * ** ** **
* * * * * * **** **** ** * * * * * * *** * **
* ***** * * * ** ** ***** * * ***** * * * **** * * ** * * * **
}
** * * * * *** ** ** ** ** *** * **** **** **** *
**** ** * * * * ** * * ** **** 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
***** ** * * ** * * * * * ** * i, num1 = 1, num2 = 1, sum = 0;
* ** * * * * *** * * * * * * * ((num == 1) || (num == 2))
*** ** *** ** * * * * * * *
**** * * ** * * * * * ** ** * * * * * **** * 1;
* * ** * ** * **** **** * *
* * * * ** ** * * ** * *
* * ** ** * * * * ** *** * *
** ** * * **** * * * * * ** ** (i = 3; i <= num; i++)
* ** ** ** ** * * ****** * ** ** ** * * * *
* *** ** *** *** ** *** ** ** * ** * *** * * * ** * ** *** * * * * * ** ** * * = num1 + num2;
* * **** * * * * * *** * * * *** * * * * * ** *** * * * * * * *** ** = num2;
***** * ** * ** *** * * ** ** *** * * * * * * *** * * * * * * * = sum;
** ** * ** * ** * * * * * * * * * * * * * ** *
* * * * * * ** ** ** ** *** ** * ** * * * *** * sum;
** * * *** * ** * * * *
}
int main()
{
** ** *** ** * ** * * * num, sum;
* * ** ***** * * ** **** ** * * * * * &num);
* * * * ** ** ** * * ** = sumNfiS(num);
*** * ** * *** ***** * * * * * ** * ***** * * sum);
* * ** * * * * * ** * * * *** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* ** * * *
#include<math.h>
int main()
{
* ** * * * *** * * i,j,k=0,a=1,b=1;
* * ** * * * * ** **** *** *** * * ** * * * ***
** * * *** * * || i==1)
* ** ** ** * * ***** ** * * * ** * ** ** *
* *** * ** * ** ** **
{
*** **** * * * **** * * * *
{
** * ** ** * *** * * ** * *** *** *
* * * * * ** *** * * * *** *
* * *** * ** * * *
}
* *** ** * * * * *** * *** * *
}
** * ** ** * * ** 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** ** ** * * * * *** * k, num1, num2, i;
** * ** * ** * * ** = 1;
* * * * ** ** * ** * * = 1;
** *** * * ** * * * ** == 1 || x == 2)
* * * * * * * *** * ** ** * * *** ** ** * * * ***
* *** * *** * * * ** * *
* ** * * * * * * *
* * * * * * ***** * * * * * ** * * **** * * * = 3;i <= x;i ++)
** * ** * * * *** * *** * ** * * *
* ** ** *** * * * * * *** *** * **** * * * * * * = num1 + num2;
*** ** ** ** * * *** * * *** * * * * ** * * * = num2;
*** * ** * * *** * * * * * * * ** * **** * * * * = k;
* * ** * *** ** * ** * * * *** * *
*** *** * * *** *** * **** *** ** * ** *** * k);
* * * * * * *******
}
int main()
{
* * * * * * ** * * x;
* ** * * ** * * ** * * * * ** *** * &x);
** ** * * * * * ** *** * * *
* * * * * * * ** * * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * * * * * ** i,sum=0;
* *** * * * * * * ** ** * x=1,y=1;
** * * * * * * ** ** *
*** * * ** * ** * * * * * * ** * * * ** * * 1;
* * * * * * * * * ** * *
* *** * ** ** ** * ** * * * **** * 1;
*** * * ****** ** * * * ** * ***
{
* * * ** * * * * * * * * * ** * * ** * * * *
* * * * * * * ** * ** * **** ** * * *
* * * * * * * ** * ** * * * ** * * * *** ** *** ** * * ** ** * = x+y;
* * * ** *** * ***** *** * * * ** ** * * * ** * ** = y;
* * * * ** ** *** * * * * * *** * **** ** *** * ** **** * = sum;
* ** ** * * * * * * * * * * * ** **** * * *
* ** ** *** * * ** * **
* * ** * * * * ** ** * * ** sum;
}
int main()
{
* * * * ** * * ** * * **** * * a,total=0;
* * * ** ** *** * * * * ** * * * * *
* * * * * * *** *** ** ** = fas(a);
* * * * * ** ** * ** * * * * * * ** * * ** *
** * * * ** * ** * * *** * * ** * * * *** *
* * * * ** * * * * *** ** ** ** 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * **** * * ******* * k, num1, num2, i;
* * ** * * * * = 1;
** ** * *** ** = 1;
* ***** ** * *** * * == 1 || x == 2)
* ** ** * * ** * * * * * ** * * ** ** * * * *
** * * ** ** *
** * ** ** * * *
*** ** *** * * * *** * *** ** * ** * * * = 3;i <= x;i ++)
** * * ** * ** *** * * ** * ** * *
*** ** * * * ** * * * * ** * * * * * ** ** ** * = num1 + num2;
* * ** **** * * * * * *** *** * ** **** * * * *** *** = num2;
** * ** ** ** * * ** * * ** * ** * ** * ** * * * * * * = k;
* * * * * ** * * * **** * *** ** *** *
* * * * * * * ** ** ** ** * * * * ** * * * * ** * * * * * ** k);
* * ****** **** * *
** * ** *** * ** * *** 0;
}
int main()
{
* *** ** * * * ** * * x;
* ** * * * * ** * * ** * ** * * * &x);
* * * ** ** * **** * **** * * *
* * *** * * * * * * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * * * * * * *
#include * * * * **** *
int printFF(int n);
int main(int argc, char *argv[]){
* * * * * * * *** ** * a,b,sum;
** * * * ** * ** * * * * ** ** ** * *
* **** * ** * ** * * * * = printFF(a);
** * * * ** * * **
* * *** * * ** * *** * * ** * ** * * **
* * ** * * * ** * * ** * * * * * * **** * *** ** * * * *
* ** * ** * * * * * * * 0;
}
int printFF(int n){
* * ** ** ** ** * * * ** * * * * ** f[10000]={1,1,0},i;
** * **** * * **** * ** * **** i <= n; i++)
* * ** * ** * * * * ** * * *** * ** ** ** * * ** ** * * * ** * ** * ** * * ** * * *
*** * ** * ** ** * *** * * * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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