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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
**** ** * **** * * * * * ** * a,b=0;
*** * * * ** * * ** * * * * * *
* * *** ** * ** ** * * ** * * * * * ** ** = b+a;
* **** * **** * * * * * * * *
* * * * * * * * * ** * * ** * * * * * *
* * * ** ** ** * ** ** * *****
* ** * * *** **** * * *** **** *
int main()
{
* ** ** * ** ** * *** *** * * num;
* * * * * * ** *** ** *** ** ** ** * * ** * * *** **
** * * * * * ** ** * * * * ***
* * * ** * * * * * * *
** *** ** * ** * * * * *
* * * ** ** * * * * * * *** ** * **
* * * * * * * * * ** * 0;
* * * * * * ** * ** * *
* ** * * * *** * * * *
** ** *** ** * * * *
* * * * ** * ** * **
* ** * ** * * **
* *** * * * * * * **
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * * * * * * * * * * ** * * ****** ** * i,n,fi,last1 = 1,last2 = 1;
* * * ** ** ** ** * * * * **
* * * * ** * * ** * * * * * *** *** * * ***
* * * * ***** * * ** ** ** * ** *
** * * * * ** * * * * * * * * == 1||n == 2)
* * * * * * * * * * * ** ** ** * ** ** * * * *** * * **
** * * * ** ** * ** * * **
** ** ** * * ** * * *** *
** * * * * ** * * ***** * *** * = 3;i <= n;i++)
* ** ** ** ** ** ** * * * ** * * + last2;
** * * * * ** * * * ***** * = last1;
** * ** * * ** * * * * ** * * = fi;};
* * * * * * * * * ** * *** ** * * **
*** * * * * ** * ** ** ** *
* * ** * * * ** ** * * * * * * * * * ** ** ** ** *
* ** *** ** ** * *** ** * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* ***** * **** ** * ** * i, num1 = 1, num2 = 1, sum = 0;
* ** * * * * * * * ** * ((num == 1) || (num == 2))
* * * * ** **
* * ** ** * * * * * * *** * * * * * * * *** 1;
* * ** *** * * * *
* * ** * * * *** ** ** * *
* * ** * ** ** * ** *
* * * * * * * *** * * * * * * ** *** * (i = 3; i <= num; i++)
* ** * *** * * ** ** * * * * ** * ***** * *** * * **
** * * **** * * ** * * * ** * * ** * **** * **** *** * **** * * ** * * * = num1 + num2;
* * *** ** ** ** ** * ** * * * * * * ** * ** * * ** * * * * = num2;
* ** ** * * * ** * * * * ** * * ** *** * ** * ******* * * *** ** * * * * * * = sum;
* * ** *** * * * * * ** * * * * * ** * * * * *
*** * * ** * ** ***** **** * * * ****** * ** * * * ** * sum;
* * ** ** * * ** * * *
}
int main()
{
* * * * ** * * * * * * ** num, sum;
* * * * * * ***** * * ** ** * * * *** * * &num);
* * * * * *** * * * * * ** = sumNfiS(num);
** ** * *** ** *** * * * ** * * ** * * sum);
* ** * ** * * * ** * ** * * *** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * ** * * ** * *** int num;
* ** * * ** * ** * ***** * a,n,b=1,c=1;
* * ** * * * * * *** * ** *** * ** * *** ** * * * * *
* * * ** ** * * * **
{
* ** * ** * * *** * * * ** * ** * * * * ** ***
* ** * * * * * * * * * ** * * * * ** * * * ** * ** ** * * * ** **
}
* ** * * * * ** * **
{
* * * * *** * * * * * * * ** * * * * ** * * ** * * * * *
** * ** * ** * ** ** ** * * *** * * * * * * ** * *
* * * * * * * * ** * * * * * * * ** * * * * * ***** * **
** * * * * * * * * * ** * ** * * ** * *** ** * * ** * ** * * *
* * * ** ** * * * * ** ** * ****** * ** *** **** * * *** * * * * * *
* *** ** ** ** * ** * ** ** * * * ** ** * ** * * *** **
* ** * * * * * ** * * * * * * ** ***** * * * * ** * * * * * *
}
* * *** ** *** * * ** * ***** * * * * * ** * * *
* * ** ** * * * * *** * ** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
*** * ***** * * * * i, num1 = 1, num2 = 1, sum = 0;
* **** * * ****** ** ** ** * * ((num == 1) || (num == 2))
* * *** * * * *** * * *
** ** * * *** **** * *** * * * * * * **** * *** * * * ** 1;
** *** * * * * **** * * * * *
* * ** * * * * * ** * ***
* * *** * * * ** * ***
* * * * * * ** *** * * ** * *** ** * *** * (i = 3; i <= num; i++)
* * * ** * ** ** * * ** * * ** * * ** * ** * *** *
* ** ** ** * * * * *** * * * ** ** * * * * * * ** *** * * ** ** ** **** ** * ** * = num1 + num2;
* * * ** ** * *** * * **** * ** * * * * * *** * * * * *** ** * * * ** ** * ** = num2;
**** * * ** * * **** * * ***** **** **** * ** * ** ** ** * * * * * ** = sum;
** * * * ** ** * * * * * * * ** * ** * * * *
* ** ** * * ** ** * * * * *** * * ** * * sum;
* ** * * * ** ** *
}
int main()
{
** *** * * ** * ** * * * num, sum;
* ** *** * ** ** ** * * ** **** * * ** * * * ** &num);
* * * * * * * *** * = sumNfiS(num);
* * * ** * * * ******* ** **** * ** * * * sum);
** *** * * ** * * * ** ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
*** * ** * ** ***
#include<math.h>
int main()
{
* * ** * * * * i,j,k=0,a=1,b=1;
* * * * **** ** *** ** * ** *** ** * * *
* * * * * * * ** * || i==1)
*** ** * * * ** * * * ***** * * *
* ** *** * * ** * *
{
* *** * * ** ** *** ** *
{
* * ** * ** * * ** *** *
* **** * * * *** * * ** * * * *
* * * * * * ** * * * **
}
* * * * * * * *** * ** * ** * * * ****
}
** * * **** * * * ** 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
*** * * * *** * * * * * k, num1, num2, i;
* ** ** * ** * * = 1;
* * * * * * * * * = 1;
* *** * * == 1 || x == 2)
* *** * * * * *** * ** * * * * * *** *
* * ** *** * ** * * *
**** * ** * * ** * * *
* *** *** * * *** * * * * * * * * = 3;i <= x;i ++)
* * * * * * ** * * **** * * * **
** * * * * * * * * *** * * * ** *** * * = num1 + num2;
* ** * * * ** * * * * * * * *** ** * * ** ** ** * * * * = num2;
* * * * * * * * ***** *** * ***** * * * * * * * * * ** = k;
* * * *** **** ** * * * *** ** *
** * * * * * * * ** ** * * * *** ** * ** * * * * ** k);
**** * ** ** * ** *
}
int main()
{
* * ** * * ** * * * x;
* *** **** ** * ** *** * **** ** * ** * *** * &x);
* * * ** * * * * * ** *
** * * ** *** ** ** ** * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* *** * * *** * **** * * i,sum=0;
**** * ** **** ** * ***** ** ** x=1,y=1;
** * ** * * * ** * * * * *
* * * ** *** * * * * * * ** ** * ** ** *** ** 1;
* * *** ** * ** ** * * ***
** * * * * * * * * * ** * *** ** * * * 1;
*** * * ******** * * * ** * ** * * **
{
*** *** *** * ** * * * * * * * * * * *** * * ** **
* * * * ** * ** * * * * * * * *** *** *
* * * * *** ** * * * * * ** ** * * * * **** ** * ** * * * * *** = x+y;
* * * * * ** * * **** ** * * * ** * *** ** * * * ** * * *** ** **** = y;
* * * * * * * ** * ** * * * * * * * * * * ** = sum;
* *** * * ** ** * * * ** * *** *** ** ** ** **
* * * * * *
* ** * *** ** ** *** * * * sum;
}
int main()
{
* * ** ** * * ** * a,total=0;
* * * * * * * *** * ** ** ** * *** * * * * *** *
**** * * * * * * * * * ** = fas(a);
* * * * ** ** * *** * ** * * * * * * * ** *
** * * ** * * * * * * * ** * * * * * ***** *
* ** * ** ** * * **** * * * ** 0;
}
answered
Nov 3, 2016
by
410523043
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* *** *** ** * * k, num1, num2, i;
* ***** ** * ** ** * = 1;
** ** *** ** * * * ** = 1;
* * * ** * * ** * * == 1 || x == 2)
* * * * * * * * * * * * * * * * *** * * *
** * ** ** * *
* ** * * *** *
* * * * ** ** * *** * * ** *** ** *** * * * * = 3;i <= x;i ++)
* ** * * * * *** * * * * ***** * *
* * * * * *** ** ***** ** ** * ** ** * * ** * * * = num1 + num2;
* * * ** * ** * ** ** ** ** * * * ** * *** * * * * ** *** * * * = num2;
* ** * * ** ** * * * * * * ** * * ** * * * * ** * * * * = k;
* * **** ** * * * *** ** * * ** * *
* ** ** ** * ** ** * ** * * ** * * * * *** * k);
* * * ** * ****** *
** * * * * *** * * * 0;
}
int main()
{
** * *** ** ** * x;
* * **** ***** * * * * ** * * &x);
* * ** * * * ** ** *** *
* * ** ** * * ** * * ** 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * * **
#include *** ** **** *** **
int printFF(int n);
int main(int argc, char *argv[]){
* * * * * ** * ** ** a,b,sum;
* * * * * ** * ** * **** * ** * * * ***** * * * * * *
** ** ** **** * * * * ** *** ** = printFF(a);
**** * * * ** ** *** *
** * * * * * * * * * * ***** ** ** * * * * ***
* * * * * ** * ** * * * * **** * * ** ** *** ** * * * * * * * *
* * *** ** * *** ** * * 0;
}
int printFF(int n){
** ** ** * * * ** ** * ** * ** * *** f[10000]={1,1,0},i;
* * * *** * *** ** **** * i <= n; i++)
* * * * * * ** * * ** * * * ***** * * *** * * * * ** * * * * ** * * * * * * * * * * *
*** * *** ** * * * * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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