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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* * * *** ** * * * * * a,b=0;
* * * ** * ** * * * * * * * * ** ** ***
* **** **** ** ** * * ** * * * * ** * = b+a;
* * * * * ** ** ** ** * **** * ** * * ** * *
* * * * * * * * * * ** * * * ** * ** * * *
** * * * ***** * * * * *** **
* * * * ** * ** *** * * *
int main()
{
******* * * *** *** * ** * num;
* * *** ** * * ** * *** * * ** * ** * * *** *
*** * ** * * ***
* * * ** * * * ** * * *
* * ** ** * * * * **
**** ** * * * * * * * * ** * * * ** * **
** *** * * **** ** ** ** * * 0;
** * * *** * * ***
* * ** *** * ** ** *
* * **** * * * * * * * *
* *** * * * * **
* * * * **** * * *** * ** * * * *
** * ***** * * * ** * * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** *** *** * * ** * ** * * * i,n,fi,last1 = 1,last2 = 1;
* ** * * *** *** * ** * * * *
* * * * ** * *** * * ** *** ** * * * * *****
** * * * * * * * * * * ** **
* *** * * * * ** * * * * * == 1||n == 2)
** ** * * * * * * * * ** * * * * *** * ** ** ** * *
* * ** ** * * * * * * ** *
* ** *** ** * * *
* * *** * * ** * ** * **** ** ** = 3;i <= n;i++)
** * * * ** * ** * * * * * ** ** * ** + last2;
* * * * ** ***** *** ** **** * * *** = last1;
* * ** * ** ** ** * * ** * * * * * = fi;};
** * ***** * ** * * *** * * ***** *** ** * * ** * ** *
* * * ** * *** * * *
* * ** ** * * * * * * * ** ** * * * * * * ** * * **
* ** ** ** * * * * * ** * * * ** * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * * * * ** * * * * *** ** *** i, num1 = 1, num2 = 1, sum = 0;
* ** ** * * * ** ** * ((num == 1) || (num == 2))
* * * * * **** * * *
* ** * * * ** * ** * *** ** * *** *** * * * ** * ** * ** * 1;
* * * ** * * ** * *
* * ** * * ** ** ** * **
** * ** * * ** ** **
* * * * * *** * * * * * * * ***** * * (i = 3; i <= num; i++)
* *** **** * ***** **** * * ** * * * * * * *** * **** ***
* * * * * *** ** ** * ** * * * * * * * * * * * * * * * * * * = num1 + num2;
* * * * * * * ** * * * * * ** ** * * ** * * * * * * ** ** * * * * ** = num2;
* ** * ** * *** ** * ** * * *** ** * * * * ** ** ** * ** * ** ** ** * = sum;
** ** * *** * * * * * * ** ** ** * * * * *
* * * * **** * **** * * * ** * * * * * * * * * * sum;
* * * * **
}
int main()
{
* ** *** * ** *** * ** num, sum;
* ** *** ** ******* **** * * * ** * * ** * &num);
* * * ** * ** ** ** * * * ** = sumNfiS(num);
* ** * * * * *** **** * * ** *** * * ** * sum);
* ** * ** * * *** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * * ** * *** ** * ** * * * * int num;
**** *** * ** * ** * *** a,n,b=1,c=1;
** ** * * * ** ***** ** * * * * * **** ** * * ** * * * *
** ** * * * * * * * *** * ** *
{
* * * **** * * *** * * * * ** ** * * * ** *
* * * * * * * ** * ** * ** * * ** * * * * * * * * ** * * * ** * *
}
* * * * ** * ** *** * *
{
* * * * * *** ** *** * * * * * * * * * * * * ** ** ** **
**** *** * ** * * ** * * ** * * * * * ** *
* * * * * * ** * *** * * * ** * *** ** ** * ** * * *** * * * * ****
* ** ***** * ** **** ** * * * **** * *** * ** * * * * * * * ** * *
* * ** * * * ***** * ** * ** *** * * *** ***** ** ** * ** ** *
** ** * * * ** * * * * * * *** ** * * ** * **
** *** * * * * ** ** * * ** * * ** * ** * * *** * * * ** *
}
** * * ** * * * * ** * * * * * * **** * *
*** * ** * **** * ** ** *** 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
** ** * ** * ** * *** ** ** i, num1 = 1, num2 = 1, sum = 0;
* * * * * * * * *** * * * ((num == 1) || (num == 2))
** ** * * * * * * *
* * * * ** * **** * * ** **** * ** ** * * * * * ** ** 1;
* *** ** * * * * **
* * ** ** ** * * * * *
** * * * * ** * * ** ** * **
** * * ** * * * * ***** * * *** ** * ** * * ** (i = 3; i <= num; i++)
**** * * * * * * * * * * ** * ***** * * * ** * ** *
** * * ***** * * ** * ** * * * * ** * * ** ** *** * * * ** *** * ** * = num1 + num2;
* ** * * * *** * * * ** * ** * * ** ** * * ** * * **** * * = num2;
* * ** ** ** * ** * ** * * ** * * * * * * *** * ** ** * * ** * * ** = sum;
** * **** ** * * ** * * *** * * * * * * ** * * * **
** * * * * * * *** * * * * ** * * * *** * * * *** * sum;
* * * * * * * * * *** *
}
int main()
{
** * *** *** ***** *** * ** * num, sum;
** ** * ** * * * ** * **** * * * * * * &num);
*** * * * *** * * = sumNfiS(num);
* * * * * *** ** *** ** ** * * *** * * ** sum);
* * * * * *** * * * * ** * ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* * ** ** ** *
#include<math.h>
int main()
{
** ** * * ** ** i,j,k=0,a=1,b=1;
* * ** * ***** * * **** * **** * * * * * * *
* * * * * * * **** **** * ** || i==1)
** * * * * ** ** * * * * * *
* * * * * ** * *
{
** ** * * * * ** * * * * **** * *** *
{
* ** ** * * ** * ** * * *
* ** * ** *** ** * * * * * *
* ** * * * * * * * * *
}
* * * * * * * * ** ** ** *** * * * * *
}
** *** * * * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * ** * k, num1, num2, i;
* ** * ** * * ** ****** = 1;
* * * * *** * * * * * = 1;
* * * * * ** * * == 1 || x == 2)
** * ** * ****** ** ** ** * *** ** * **** * * * * * * ** ***
*** * ****** * * * * **
* * * ** * * *
** ** ** * ** * * * *** ** **** = 3;i <= x;i ++)
**** * * * * * * ****** * * * * * ***
* * **** ** * * * * ** ** * * *** ** *** * ** * ** * * *** = num1 + num2;
* ** * * * * * *** * ** * * * ** * * * ** * * ** * * *** * = num2;
* ** * * * ** *** * * * * ** **** * *** ** * * * * * * * = k;
* * *** * * *** * * *** * ** *
* ***** * ** * * * * * * * * * ** * ** *** * * ** * * * k);
* * ***
}
int main()
{
* * * * ** * * *** x;
* * * * * ** ** * * ** ** * &x);
* * * * * * * * * * *
* * *** * * * * * * ** 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
**** * *** * * * * ** ** * i,sum=0;
** * * ** * ** * * ** * * x=1,y=1;
** ***** * **** ** ** * * * * * *
* * ** * * * ** * ** * *** * * ** 1;
* * * * ** ** * * * *
** * * * * ** *** ** ** ** * * * ** ** * ***** * * 1;
* ** ** **** ** * ** * **
{
* * * * * ** * * * * ** **** * ** * * ** *** *** * **
* * * ** * * * * ** * * *
* *** * ** **** * * * * * ** ** ** * ** * ** ** *** * ** * * = x+y;
** * * * ** * * * ** *** * * * *** * * * ** ** * = y;
*** *** ** * * * **** ** * * * * *** ** * * *** * * * * = sum;
* * ** *** ** * * * * **** * * * * * *
* *** ** * *** * *
** * * ** * * * * * sum;
}
int main()
{
* *** * **** * * * * * ** ** a,total=0;
** * * * * * * ** *** * * * * * * * ** * ** **
* * * * *** ** * * ** * **** = fas(a);
***** * *** * * ** * * * *
* * * * ** ** ** ** *** * * ** * ** * * ** * *
* ** ** *** * * * * ** * ** *** *** 0;
}
answered
Nov 3, 2016
by
410523043
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * * * ** * *** k, num1, num2, i;
** *** * * ** ****** = 1;
* * * * ** ******* = 1;
* * ** * *** ***** * == 1 || x == 2)
** ** * * * * * * * * *** *** * * * ** * ** **
* ** * * * * *** ** *
* * * * * *** * * *
* ** ** * * * * * * ** * * * * ** *** * * = 3;i <= x;i ++)
* ** * * * ** ** * ** * *
* *** * ** * ** ** * * ****** ** * * ** ** ** * * *** ** *** = num1 + num2;
* * * ** * * * * * * ** * * * * ** * * * * * ** = num2;
** * * * * * * * ** ** * ***** ** * * * *** ** * * ** **** *** = k;
* ** ** * * ** * ** * ** * ** ** ** * ** *
** * * * * * * ** * *** ** ** * ** * * ** * ** ** k);
* * ** * * * ** *
* * * * ** * * * ** 0;
}
int main()
{
* *** * ** * * * ** x;
* ** * * ** ** * ** * * * * &x);
* * * ** **** * **
* * * * * * * * * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * * * * * *** **
#include * * *
int printFF(int n);
int main(int argc, char *argv[]){
*** * * * * * **** * ** a,b,sum;
* * * * * * *** * * *** ** * *** ** * * * **** * * *
* * * **** ** * ** ** = printFF(a);
* * * ** ** * *** *
* * * ** ** * ** ** * * * * * * ** * * ** *** *
* ** ** *** * * ***** ** * * * ** * * * * ** ** * * * * * *
* ** * * * ** *** ** ** * * ** 0;
}
int printFF(int n){
*** * * *** *** ** ** * ** * * ** f[10000]={1,1,0},i;
** * *** * * *** ** * * * * i <= n; i++)
** ** * * * * * * * * *** *** * *** * **** ** ** * * * * ** *** * * **** * * ** * * *
* * * * * *** * * * * *** ** f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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