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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* **** **** * ** ** * a,b=0;
* * * ** * * * * * * ** * * ** * * * *
* * * ** * ** * ** * ** * * * *** *** ** * * = b+a;
* * * *** * * ** * * ** * * *** * * * * *
* ***** ** * * * * * * * ** * * **** * * *
* * ** *** *** * ****** ** * ** * *
* * ** *** ** * * ** ** ** **** ** * *
int main()
{
* ****** * * * * ** ** * * num;
* ** ** ** * * * ** * * ** *** *** * ** * * *
* * * * * * * ** * * * * * * *
* * * ***** * * * * ** *
* ** * ** * * * ** * *
* *** * * * ** ** * * * ** * ** * * * * * * * *
** *** * * * * ** * * * ****** 0;
* * * * * * *** * ****
* * ** * * ** ** * * * * *
* **** * * * * * * * *
* * ** * ** * * * ** * * * * *
* ** ** ** * ****** *
* * *** * * * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
***** * * *** * * ** ** i,n,fi,last1 = 1,last2 = 1;
*** * ** ** *** *** * * **** ** ***
* * * ** * * ** ** ** ** ** * ** ** * * * * * * * * * *
* * **** ** * * * * * * * **
** * * **** * * * * * *** * == 1||n == 2)
* * ** * ** * * ** ** ** * * * * * *
** * * ** ** * ** ***
*** ** ** * * * * * ** * *** ***** ***
* * * * ** **** * * ** *** * ***** * = 3;i <= n;i++)
** * ** * * * ** * ** * * ** * *** * * + last2;
* * *** ** * *** * * * * ** * * * * * = last1;
** * *** ** ** * *** * * ** * * * * * = fi;};
* * * ** ** * * ** * * ** * ** * ** * * * *
* ** * **** * * * * *
* *** * * * * * ** * * ** * * ***** ** * ** *** * * *
* * ** * * * *** * ** ** ** ** * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* ** ** ** ** * * *** * * i, num1 = 1, num2 = 1, sum = 0;
* * * * *** ** * * * ((num == 1) || (num == 2))
* * ** * * ** * * * * * *
** * *** * * * *** * * * * * * * * * *** * ** * * * * 1;
* * ** ****** ** * * ** * *
* * * * * ** * * * * * * ** *
* *** * * * * * ** ** *
* * *** * * ** * * * * * * * *** ** (i = 3; i <= num; i++)
**** * * * ** **** * * ***** * * ** * * * * * * * *
** * ******* * ** * ** * ** * *** ** * *** * * * * * * * * * ** *** *** * * * * ** = num1 + num2;
** ** * ** *** ** * * *** * * * * * *** ** ** **** *** * * * * = num2;
** * * * * *** ** * * * * ** * ** ** ** * * ** ** ** ** * * * * = sum;
** * *** * * * * ** * ** ** * * ** * * * * ** *
* * * *** * * * * * * * * * * *** * * * * * * ** * * * sum;
*** * * * * * *
}
int main()
{
* * * * * ** * * * ** ** * * * * ** num, sum;
*** ** ** * * * ** ** * * * * * * ** * * &num);
* * * ** ** ** ** ** * * * = sumNfiS(num);
* *** * ** * *** ** * * * * * * *** * * * * * sum);
*** ** * * * ** * *** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * ** * * * * * * ** int num;
* * ** * ** * * a,n,b=1,c=1;
* * * * ** * * *** * ** ** * * * * *
* * * ** * * * * *** * ** * * ** *
{
* *** * * * * ** ** * * ** * * * ** * * ******
** ** ** * ** * * * * * * * * * * * * * * **** * ** ** * ** **
}
* * * * * * * * * *
{
* ** **** * *** ** * *** * * * **** * * * ** * * ** * * ** * * * * ** *
* * * * * * * ** * * * ** ** *** * ** ** *** **
* * ** * * * * * * * * * * * * * * * ** *** * ** * ** * *** * * ** * *
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***** *** **** * ** * * * ** * * ** * * * * * ** * * ** * *
* ** * * *** * * ** ** * * * * ** ** **** **
** * ** * ** * * * * * * * **** *** * * ** **** ** ** * ** * * * ****
}
* ** * * * * * * * * ** * * * * *
** * * * * * ** * * **** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* ** *** * * * ** * * * * * i, num1 = 1, num2 = 1, sum = 0;
* * *** ** * ** * ((num == 1) || (num == 2))
* * * * ** * * **
* * * * * * ** ** ** * * * * * * * * * *** 1;
* *** * * ** *** * * *** * **
* * * ** **** * * * *
* ** * * * ** * * * *
* * * * ** ** * * * ** * * * ** * * * * (i = 3; i <= num; i++)
* * * * * * ** ** ** * * * * *** * * ** * * * *
* *** * * * * * * * ** *** * ** ** * * * * * * * * * ** = num1 + num2;
* ** * ** **** * * * ** * * * * * *** * *** * ** * ** * ** * * * * * * ** = num2;
** ** *** * * * ** * *** ***** * ** ** ** * ** * **** * * * * ** * * ** = sum;
** *** * * ** * * * **** * * **** * * * * * * *
** * **** * * ** * * * ** ** * **** * sum;
* ** ***** **** * *** *
}
int main()
{
* *** ** * * ** * ** * num, sum;
* * * * ** * ** * * * * * * * * *** &num);
* * **** * * * * * ** * = sumNfiS(num);
** * * ** ** * *** ** * * ** * * * * * * sum);
* * * ** * **** ** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
** * * ** ** * * *
#include<math.h>
int main()
{
*** *** * ** * * * * ** i,j,k=0,a=1,b=1;
** * * * ** ** * ** * *** * * * * *
* * * **** * * * || i==1)
* * * * * * **** * ** * ** * * * *
* * ** * * * * *
{
* ** * *** * * *** * * *
{
* * * ** * ** ** * * ** *
* * * * ** ***** *** * ** * * ***
* * * ** *** ** * ** * * *
}
* * *** ** * * * * * ** ** ** *
}
* * * * * * * * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * ********* * * k, num1, num2, i;
* * ** * * = 1;
*** ** **** * * * * = 1;
** * * *** ** * * * ** == 1 || x == 2)
** ** ** * * **** * * * * **** ** * ** ** *** *
** ** * **** ** * * *
** * * * ** **** *
* ** * * * ** ** * * *** ** ** * * * * * * *** = 3;i <= x;i ++)
* ** *** * * *** * ** * ** * * *** ** * * * *
** * *** * *** * *** * * *** * * * * *** *** ** ** * = num1 + num2;
* * ** * ** * * *** * **** * * * * * **** * * *** * = num2;
** * *** *** * * * * ** * * * ** ** * * * *** * * * **** = k;
* * * * **** * ** * * *** *** ** ** *
*** * ** * * * ** * * * ** ** *** *** * * * * k);
* * *** * * ***
}
int main()
{
* * * * * *** * x;
* *** * * * ** * * * ** * * * * &x);
* *** *** * ** * **
* ** * * ** * ** *** 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
** * * * * * * *** * ** i,sum=0;
** * * * * * ** * * * * **** x=1,y=1;
* * * * * *** * * * * * ***
* * * * * * * * * ** * ** * *** * * * * * 1;
** ** * * * *** ** * * *
* ** ** * * * * ** * * * ** * * ** * ** *** * * * ** 1;
* * * ** * **** ** * * *
{
* * ** * ****** ** *** * *** * * * ** * ** * * *** ** ** **
* * * * * * * ** ** * * *** * * *
* * ***** * *** * * ***** * * * * * * * * ** * * ** = x+y;
** * ** * * * * *** * * * * * ** ** ** * * * ** * * = y;
** ***** *** * ** * * ** ******* * * ** * * * ** * * * * * * * * * = sum;
* ** * *** ** * * ****** * * * * * * *
* **** * ******* * * ** ***
* * ** ***** * * * ** ** ** *** sum;
}
int main()
{
** * ***** * ** * *** ** ** a,total=0;
** *** * ** * * * * * * * * * * * * * * *
** * * * * ***** * * * * *** * * = fas(a);
* * * *** ** * * * * * ** ** * * ** *
* * ** * * * * * * * * ** * *** *** ** ** ** **
* * * * * * * ** ** ** * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* *** *** * * * k, num1, num2, i;
* * * * ** * * * * = 1;
*** * * * * *** * * ** ** = 1;
* * * * * * * ** * * == 1 || x == 2)
*** * * ** * * * * * * * * ** * * * * ** * * * * * * * *
** * * * ** * **
* * ** ** * * * *
* ** *** ****** * *** * * * *** * * ** ** = 3;i <= x;i ++)
** ** * ** * * * ** * ** * *
** ***** ** ** ** * ** ** * * * * * * * * * ***** * = num1 + num2;
* ** ** ** *** *** * ** ** * * * * * * *** *** * * = num2;
** **** ** * * ** * * * * ** * * * *** * ** * ** = k;
* ** * * * * **** ** ** * * * * *
* ** * * * * ** * * * * * * *** * * * ** ** * *** k);
* * * ** * * **
* **** * * * ** * ** 0;
}
int main()
{
* ** * *** * ** * * x;
**** * *** * * * * * * * ** * * **** &x);
* ** *** * * * ** * * * *
* * *** ** * ** * * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * *** ** ** ** * *
#include * * ** * * * * ***
int printFF(int n);
int main(int argc, char *argv[]){
* *** * ** * * * * ** *** a,b,sum;
****** * * * ** *** * ** ** **** * ** * * **
* ****** **** * * * ** ** = printFF(a);
** * * * * ** * * ***
* * * * * * * ** * ** * ** ** *** ** * ** * ** * *
* * ** ** * ****** *** * * *** * * * ** * **** * ** * * * * * * **
* * * * *** * * * * ** *** * 0;
}
int printFF(int n){
** * ** * ** ** * * f[10000]={1,1,0},i;
** * * * * * * *** ** * * * * * * i <= n; i++)
**** * ** * * ** *** **** * * * *** * * ** * * *** ** * ***** ** * * * ** * *** ** * * ** * ** **** ** * *
* * * **** *** ** *** * * * * * ** f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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