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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
* * *** * * * ***** * * * ** * ** * * * *** * * ** ***
* * * ** * * * ** * *** * * ** * * * * *
if (year%4 == 0)
{
* * *** ** ** * * ****** * * * * * *** ** * ** ** * * ** * * ** * *** * * * * ***** * * * * (year%100 == 0 )
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** * ** **** * **** * * *** * * * * * * * *** * ** * * * ***** * ** * * ** ** * * * ** ** ** * * * = 366;
}
else
days = 365;
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
* ** * * ** * ** * * * 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
** * ** ** * ** * *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * * * * ** * * * * year, days;
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** ** * ** *** * * * **** * 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * ** * ** * * * * * * * year=0;
* * * * * * ** * ** *
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}
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Hidden content!#include<stdio.h>
* * * ** * * * **
* * * ** * * ** ** main()
{
* * * ** * * * ** * * * i=0;
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Hidden content!#include ** * ***** *
main()
{
* * * * * year=0;
* ** * * **** *** * ** ** ** * * * * &year);
* * ** ** * * * * * && year%100 !=0)
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* ** * ** * * *** * * ** * * * **
}
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Hidden content!#include <stdio.h>
#include * **** **
int main()
{
***** * *** * ** * *** * *** year;
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * ** * * * * *** year=0;
* ** ** ** * ** ** * * ***
** ** ** * * * * * * * * *** * * * ** * ** ***
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* * ** * * ** * *
**** * * * * ** * **
}
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