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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
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if (year%4 == 0)
{
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else
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
* * * *** * ** * * * * * 0;
}
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Hidden content!#include<stdio.h>
* * ** * * * **
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{
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * *** * ** * * * year, days;
* * * * * * ** * * **** * * ** * ** input year:");
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* * * **** * * * *** * * 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * ** ** * * * ** * * ** year=0;
* * ** ** * * ** * **
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}
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Hidden content!#include<stdio.h>
* ** * * * * *** *** *
** * * * * * ** * * main()
{
* * * * * * * * i=0;
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Hidden content!#include * * * * *
main()
{
* * ** * * * * * * year=0;
* * **** * * * * * * ** * * * * &year);
* * * ** * **** * * && year%100 !=0)
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* * * ** * * * * * * * *** * * * **
}
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Hidden content!#include <stdio.h>
#include * * * * ***
int main()
{
* ** * ** * * * * * * year;
*** * * * * ** * * * * * * * * * ** * put your years:");
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* * * * * * **** * * ** * **
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* ** * * * * * *** * * *** ** *** * * *** * * 0;
* * * * ** * ** **** ** * ** ** * ** ** *
* * ** ** * * * ** * * * **
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * ** * * * * * year=0;
* * * **** *** ** * *
* * ** * * * *** * * ** * * * * ***** *
* * * * ** ** ** * * *
* * * * * ****** * * * * * *
* ** * ** ** ** *** ** *** year is not leap year", year);
* * * * ** *** * ** * * *
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*** ***** * * * * ** **
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* *** ** ** * * ** *** **
* * * * * *** ** **** 0;
* * * * * * ** ** *** *
* *** *** * ****** ***
* ** * * * * * ** *
}
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