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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
* ** ** * *** ** * * * ** * ** * * * * ** ** **** * * * * * *
* * * * * * * * ** * ** * ** *** * ** * * *
if (year%4 == 0)
{
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}
else
days = 365;
* ** * ****** * * * **** **** * * * * ** * ** * * *
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
* * ** * **** *** * * * 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
** *** * ** ** *****
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{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * **** *** * ** * *** ***** * year, days;
* ** *** * * **** ** * ** ** * ** * * input year:");
* * * * ** * * ** * * * * ** * * *** &year);
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* * * ** * ** * ** * * *
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* * * * * ** * ** ** * * * ** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** ** ***** * * * * * * * year=0;
*** * * * * ** ** * * * *
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}
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Hidden content!#include<stdio.h>
* * * * * ***
* * ** ** ** * *** * ** * * main()
{
** * * * * * ** * i=0;
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* ** * ** *
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Hidden content!#include *** * * *
main()
{
* * * * * ***** year=0;
* * * ** ** * * ** * * * * * * * * &year);
* * * * * * * * *** * * && year%100 !=0)
** ** ** * * ** *** ** ** ** year is leap * * *
* ** **** * *** **
** * ** * * * * * * *** year is not ** * * ** ** * * ** ** * ** ** ** *** ** * * ** ** ** * * * *** * * * ** * ***
* * * * * *** * * *** * * ** ** * *
}
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Hidden content!#include <stdio.h>
#include ** **** * ** *** *
int main()
{
* * *** * * * * * ** * year;
* * * * ** *** * * * * * * ** * * * put your years:");
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** * * * * ** * * ** * * ** * * ** *
* ** * * * * * * * * * ** ** *** * (year%4!=0)
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* * * ** ** * * * * * * ** *
* * * ** ** * ** * * ** * ** * * * * **
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * * * * ** * * * year=0;
* *** ** * * * * *** * **
* * * * * *** *** * * *** ** * * ** *****
* ** * ** * * * * * *
* * * ** * * * ** **
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*** ***** * * * * ***
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* * * * * * ** * ** * * ** ** * * year is leap year" , year);
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* * * * ** * * ** * *
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*** * * * * ** * * * * ** 0;
* * * * ** ** * *
* **** * * * * * * ** * *** *
* * * ** * ** * **** *
}
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