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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
** * * ** * * **** * * *** * * * * * * * * * *** * ** * ***
** * * *** * * ** ** * * * ** * * ** * * *
if (year%4 == 0)
{
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else
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
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}
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楊傑宇
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Hidden content!#include<stdio.h>
* ** ** ** ** * *
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{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * ** * ** * * year, days;
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* * * * * * * * * * * *** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * * * * * * * year=0;
* * ** ** * *** *
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}
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Hidden content!#include<stdio.h>
* * * * * * * * *
* * * * * ** * * * main()
{
** * * * * * ** i=0;
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Hidden content!#include ** ** * ** *
main()
{
** ** * * **** * year=0;
* ** ** * * * ** * * * * **** * * &year);
* * * * *** ** * * * && year%100 !=0)
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* * * *** * * * **** ** * ** *
}
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Hidden content!#include <stdio.h>
#include ** * * *****
int main()
{
* *** ** * ** ** ** * year;
* * * * ** * * **** * * ** * put your years:");
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* * * * * * * * * * * * ** * is not leap year");
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* * * * * * * ** * if(year%400!=0)
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* * * * ** *** * **** *** *
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* * * * ** * * * **** * * * * **** 0;
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*** ** * * * * * ** * ** * * ****
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * * * ** * *** * * * year=0;
* * * ** * * * ** * *
* * ** * * *** * ** ** ** ** ** * ** * * ** *** * *
** * * * *** * **
** * ** * ** *** ** **** * *
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* * * * * ** ** *
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* * * ** * * ** * * *
* * * * * * * **** * ** *
*** ** *** **** * ***** * ** * *
}
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