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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
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if (year%4 == 0)
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}
else
days = 365;
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
* ** * *** * * ** ** ** * * 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
* ** * ** * * *
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{
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ********* * * ** * * year, days;
* ** * **** *** *** * ** * ***** * * * * input year:");
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* * * * ** * * *** * ** * * * 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * * * ******* * * * year=0;
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}
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Hidden content!#include<stdio.h>
* ** * * * ** * **
** * * * * * * * *** ** main()
{
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Hidden content!#include ** * *** * *
main()
{
* ** * ** * ** ** year=0;
* ** * ** * * * * ** *** &year);
* * * * *** * *** * * * && year%100 !=0)
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* * * * ** * * * **** * ** * ****
}
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Hidden content!#include <stdio.h>
#include ** * * * * * * *
int main()
{
* ** ** ** ** * * * ** year;
* * ** *** * ** ** * * * ** * * ** *** put your years:");
* * ** * ** ** *** ** * ** * * * * * ** ** * *
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* * * * * ** * (year%4!=0)
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* ** * * ** ** ** * ** ** * * * * * * * * 0;
**** ** ** * * ** * *** * *** * **
* ** * ** * ** *** *** * * ** * * **** *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** ** * * * **** *** * ** * year=0;
** * *** * * ** * ** ** *
** *** * * * * * * ** *** ** ** ** * *****
* * ** ** * * * * ** * * * *
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* * * ** ** * * * *
}
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