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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
* *** * * * * * * * * * * * ** ** * * ** * * * *** *
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if (year%4 == 0)
{
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}
else
days = 365;
* * ** * * * * * * * * ** * * * * * * * ** *
* * * * ** * * * * *** * ** ** * * * * * * **
return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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else
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}
* * ** ** * * ** ***** 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
* * * * ** * ** * *
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{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * *** ** * * ** ** * * * * year, days;
* * * * * * ** *** * * ** ** ** * ** input year:");
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* ** ** *** * * ** * * *
** * **** * * * * * * * 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** * **** * *** * * year=0;
* * * * * * * *** ***
** * * ** *** * ** * * ** * * * ** ** * ***
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* ** * ** ** * * * *******
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}
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Hidden content!#include<stdio.h>
* * * ** ** * * ** **
* * ** * * ** * * main()
{
* ** ** ** * * * * * i=0;
* * ** * * * * * ** * * * * * * * *
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Hidden content!#include * *** * *
main()
{
** * * ** * * ** year=0;
** * * *** ** * * * * * &year);
* * * * *** * * ** * ** && year%100 !=0)
* ** *** ***** * * * * ** ** * year is leap * ** * *
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* * * * * * ** * * * * * * * * ** *
}
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Hidden content!#include <stdio.h>
#include * * ** * *
int main()
{
** ** * ** * *** * * ** * year;
* * ** ** * ** * * * * * * put your years:");
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* ** ** * **** ** * ** * * ** * * **
* ** * * * ** * *** * * ** *** * **
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * ** * * *** * * * ** year=0;
* * * ** **** *** * *
* * * * * ** ** * *** * ** * ** * * *
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** * * * * *
** * * ** * * * *
* *** ** ** * * ** ** * * * * * *
}
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