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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
* * * * **** * * * * * ***** * ** * ** *** * * * ** * *
* * ** ** * ** * * * ** * * * * * * * * * * * * * * * ***
if (year%4 == 0)
{
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}
else
days = 365;
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
* * * * *** * * ** * ** * * 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
* *** * * ** * *
** ** * ** * * ** ** main()
{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** * * * * * * year, days;
* * * * * *** *** * * * * ** * * * ** * ** input year:");
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* ** * * ** * * * * * * * 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * * year=0;
* ** ** * * * ** **
* *** ** * * *** * ** * * * * * ** ** ** ** ***
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* * * ** ** * * ** * * *
}
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Hidden content!#include<stdio.h>
* * * * ** * * ** *
* * ** * * * * * ** ** main()
{
* ** * *** ** * * * * i=0;
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Hidden content!#include ** ** * * * *
main()
{
* * * * ** * *** * year=0;
** * *** * * * * * ** * * * * ** * * ** &year);
** ** ** *** ** * * ***** && year%100 !=0)
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* **** ** * * * *** * * * ** * **
}
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Hidden content!#include <stdio.h>
#include * * * * *
int main()
{
* **** * * * ** **** * **** * year;
*** * * ** ** ** * ** * * * * ** ** * * * * **** put your years:");
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* * ***** * **** **** **** * * ** **
* * ** * * * * *** ** ** * ** * * * 0;
* * ** * * ** * * ** * * * *
* ** * * ** * * * ** ** ** * *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** * * * ** * ** year=0;
**** * * * * * ***
* ** * * *** ** * * * * * * * * * * ** * * ** * *
* * * * *** *
* * ** * ** * ** * *** ** **
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* ** *** * * * * ***
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** * * ** * ** * * **
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* * * * ** *** * * * * 0;
* ** * * * ***
* * * * *** * * * ***
* ** ** ** * * ** ***
}
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