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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
* ** * ** * * * * * * *** ** * * ** * ** * **** * ***
* * ** ** * * * * ** ** * * * * ** * ** ***** * * **** * * *
if (year%4 == 0)
{
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}
else
days = 365;
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** ** * * * * ** **** * ** * * ** * ** * * * ****
return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
* * * * * * * * * ** * year=0;
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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else
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}
**** * * * ** * * * ** * * 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
** * * * * ** *
* * * * ** ** ** * * ** main()
{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
***** * * * *** * * ** ** year, days;
** * * * * * * * **** * * * **** input year:");
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* ** ** *** * ** ** *** * ** * ** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * * ** * * * ***** year=0;
** * * * *** *** ** *
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}
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Hidden content!#include<stdio.h>
** * ** * *
** * * *** *** * main()
{
* ** * ** *** * * i=0;
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Hidden content!#include ** * * ** * * *
main()
{
* * ** * * * * * year=0;
* *** * ** * ** * * * ** *** &year);
* ** ** * * * ** * * *** && year%100 !=0)
* * ** * * ** ** * * * ** * * year is leap ** ** * * *
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** * * *** * * * * * * * * * ***
}
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Hidden content!#include <stdio.h>
#include * * *** *** *** *
int main()
{
* ** * **** * * * year;
* * * * **** * ******* * * ***** * * put your years:");
* ** ** * ** * * * * * * * * * * * * * **** * ** * * ** ** *
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* * * * * * * * * ** ** * 0;
* * ** * * * * *** * * * ** *** * *
* * * * * * * * * * ** * * * * *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * *** ** * ** ** * * * ** year=0;
** ** ** * ** * * ** * * *
* * ** * ** * * ** ** ** ** ** * * * ** * * * * * ** **
*** * *** ** * *
****** * * * ** * ** * *** ** ** * **
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** ** * *** * * * * **
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** *** * * * ** *** * **** *** * *** ** * year is leap year" , year);
** * * * ** * ** * * **
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* *** * * ** *** ** * * * * ** 0;
* * *** **** * ***
* ** * * * * *** * * * * **
* * *** ** * * * ** ** *
}
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