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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
* * ** * * * * * * * ** * * * * * * ** * *** ** *** * **
* ** * * * * * * * * * * * ** ** * * * * * * * **
if (year%4 == 0)
{
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}
else
days = 365;
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
* * * * * * * * ** * * * year=0;
* * *** * *** * * * * * * * ** * * ** * * * input year:");
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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else
* ** * * * * ** * * * * * ** ** * year is not leap year",i);
}
**** * * * * * ** ** * * 0;
}
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Hidden content!#include<stdio.h>
* * * * ** * * * *
* ** * * * * * * * main()
{
* ** * *** * i=0;
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * ** * * * ** * year, days;
* *** * ** ** **** * **** ** * * * ** * input year:");
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** * * * * * ** * *** * *
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* ** * * * * * *** * *** *
*** * * * * * * *** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * *** ** * ** *** * ** year=0;
* ** * *** * *** *
** ** * * * * * * * **** * * * * * * * ** ** *
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** * * * * ** * ** * *
* ** * * * * * **
* * ** * * * ** ***
}
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Hidden content!#include<stdio.h>
*** * * *
** * * * * * ** main()
{
*** * * * * ***** i=0;
* * ** * * *** ** * * ** * * * * * *
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Hidden content!#include * * ** * **
main()
{
* ** * * * * * * * * year=0;
* * ** * ** * *** * * * * * * * * &year);
* ** * ** * * * * * && year%100 !=0)
* *** * * * * * **** year is leap **** * * * *
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** * * ***** *** * * * * * ** * * *
}
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Hidden content!#include <stdio.h>
#include * ** ** * **
int main()
{
**** ** * ** *** ** * ** * * year;
** * ** * * ** * * * * ** * *** put your years:");
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* ** ** * **** * * *** * * * * *** * *** 0;
*** * * * ** * * * ** ***
* ** * * * * * *** ** ** * *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * * * * * *** ** * year=0;
* **** * * * * ******** * * * *
* * * * ** * * * *** ** * * * * * * * * * * *** *
* ** ** * * ** **** *
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**** * ** * *** * * * * ** *
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* * * ** * * * * * * * * 0;
* ** * * * * * * *
* * * * * * * * *
* *** * * * * * * * *
}
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