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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * * * * * * year = 0 ;
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}
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Hidden content!#include <stdio.h>
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}
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410511226
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Hidden content!#include <stdio.h>
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Hidden content!#include <stdio.h>
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Hidden content!#include <stdio.h>
#include <stdlib.h>
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{
* *** * ** * ** * * x=0;
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}
answered
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Hidden content!int main(void) {
int y;
printf("input the year:\n");
while(1)
{
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}
return EXIT_SUCCESS;
}
answered
Dec 1, 2016
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410421238
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Hidden content!int main(void) {
int y;
printf("input the year:\n");
while(1)
{
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}
return EXIT_SUCCESS;
}
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410421238
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Hidden content!int main(void) {
* * * ** * * * * * * ** y;
** * * * * *** **** * ** * * * * * * * the year:\n");
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}
* * * * * * **** * * * ** printf("%d year is not leap year.",y);
* * * *** * ** EXIT_SUCCESS;
}
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Hidden content!int main(void) {
int y;
** * *** *** ** * * * ** * *** * * the year:\n");
* * * *** * ****** * *** * * * * * * * ** ** * **** *** *
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{
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** *** * *** ** * * * **
* *** * ***** ** ** * * * * **** * * **** * * * * * printf("%d is a leap year.",y);
}
* * * * * ** * *** * * printf("%d is not a leap year.",y);
* * * * * * * ** * ** * * * * ** EXIT_SUCCESS;
}
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Hidden content!int main(void) {
* * *** * *** * * * * y;
* * * * * ** ** * ** ** the year:\n");
** * * * * ** * * * * *** * *** ** * * * * *
* ** * * ** * * *
* * * * * *** * * *
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*** ** * * * * ** * * * ** **** ** ** * ** * * ** * * ** ** * * * *
* * * * * * * ** * * * * * **** ** * * ** **** * ** ** * ** printf("%d is not a leap year.",y);
** ** * *** * ** *** *** * ** ** ** ***** * *
* ** * ** * * * *** * * * ** *** * * printf("%d is a leap year.",y);
}
* * ** *** * ** ** * * printf("%d is not a leap year.",y);
** * * * * * * * **** * EXIT_SUCCESS;
}
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