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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
** * *** * * ** ** ** ** * **** * ** * * ***** ** ** * ** *
*** * *** ** ** ** *** *** *** * * * * * * * * * * * * ** * * *
if (year%4 == 0)
{
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}
else
days = 365;
*** * * ** * ** * * ** * * * * * * * * * *
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
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}
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楊傑宇
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Hidden content!#include<stdio.h>
* ***** * * * * **
* * * ** * * *** * * * main()
{
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
**** * * ***** * * * *** * year, days;
* ** * ** * ** ** * **** * ** * * ** input year:");
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** * * ** * *** ** * *
* ** ** * * * *** * * * * * *** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * * * * * * *** * * ** year=0;
********** ** * * *
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}
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Hidden content!#include<stdio.h>
* *** * ** * *** **
** * * * * * * ** * main()
{
*** * ** ** * * **** i=0;
* *** * ** * * * * * * ** * * * * ** * * *
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Hidden content!#include * * * *** * * * * *
main()
{
* * * * * * * year=0;
** ** ** * * ** * * * * * * * * * * * &year);
* * * * * * * * * ** ** && year%100 !=0)
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* ** * * * ***** * ** year is not ** **** * ** * **** * * ** ** * * * * ** * * ** * * * * * * **** *
* ** ** ** *** ** * ** * ** * * ** * ** * * * *
}
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Hidden content!#include <stdio.h>
#include * ***
int main()
{
** *** * * ** ** * *** ** year;
* ** ** *** ** ** * * * * * * ** * put your years:");
* * * * * * * ** * * ** * * * * * * * ** * * * *
** ** ** * * * * ** ** *** * * *
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* * * * * ** * * ** * * ** is not leap year");
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**** * ** ** ** * * * ** * ** * is leap year");
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* * * **** * * **** * * * * * * * * * 0;
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* * * * * * * * ** ** * *** * ** *** **
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * ** ** * * * * * year=0;
* **** * * * **** * *
*** ** *** * ** *** * * * ** ** ** * * ** * **** * * *
* * **** *** * * **
* * * * ** * ** ** * * ** * ** * *
** * *** ** * * * * * * ** ** * * year is not leap year", year);
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* * * * ** * * ** *
* **** * * ** * ** ** * * *
* * * * * * ** * * * * **
}
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