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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
* * ** ** * * * * * * *** * * *** * ****** * *** * * **
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if (year%4 == 0)
{
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}
else
days = 365;
* * *** **** * * * * * * ** * * ** * * * ** *
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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** * * * * * * ** ** * *** * * input year:");
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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else
* * ** *** * * ** * * ** ** * * ** * ** ** * year is not leap year",i);
}
* * ** * * * * ** ** 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
*** * * * * * ** * * *
* * * * * * * * * **** main()
{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * ** * ** * ** * * * * * ** year, days;
** *** *** ******* * * * ** * ** * ** *** * input year:");
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}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * * *** * year=0;
* * ** * * * ** *
** **** *** ** ** * * ** * ** *** ** * ** * **
* * ** * * * * * * * *
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}
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Hidden content!#include<stdio.h>
* ** ** ** * * *
** * ** ** ** main()
{
** * * * * ** * * i=0;
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Hidden content!#include ** ** * * * *
main()
{
* * * * * * * ** * year=0;
* * * * ** * ** ** * * * * **** ** ** &year);
* * * * * *** * *** * * * * && year%100 !=0)
* * * ** ** * *** *** * ** * * * year is leap ** ** ****** *
* * *** * *** * * ** **
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** ** * ** * * *** * * ** * ** *
}
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Hidden content!#include <stdio.h>
#include * *
int main()
{
* * ** ** * * * * * **** year;
**** * * * *** * *** * * * * * ** * put your years:");
* * * ** * * * ** ** ** * * * * * ** *** *** ***** * * * *
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** * *** * * *** * ** * * * * * * *** ** 0;
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** * *** ** * ** * * * ***** ** *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * ** * *** ** * *** year=0;
* ** * * ** * * ** * * * *
* * * * * * *** * * * * * *** ** * * ******* *
* * ** * * * *
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* ** * ** * * *** * ** * *** * *
** * *** * ** *** *
* * * * * *
}
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