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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
** * * * * ** * * ** * * * ** * ** * ** * ** * * * * ** *
* * * ** ** ** **** ** ** ***** * * * ** ** * *** ***** * *
if (year%4 == 0)
{
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* * * * ** * ** * * * ** * * * * * * * ** * * * * * * ** * * * ** ** * * * **
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}
else
days = 365;
* ** ** ** * * * * *** * * ** * **** * * * **
** * * ** * * * * * * ** * ** ** ** * * *** * * *
return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
** * ** *** ** **** * * * year=0;
* * * * **** * ** *** * * ** * * ** * ** input year:");
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
*** ** * *** * * * * * * * 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
* *** ** * ** *****
* * * ** * * main()
{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * * * * * year, days;
* ** ** ** * * * * ** ** ** * input year:");
* * *** * * * *** * ** * *** &year);
* * ** * * * * ** * (year % 4 != 0)
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** ** * * ** ** ** * ** *** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * * * * * year=0;
* * *** **** * *** * *
* * * * * * * * * * *** * * * ** * * * * * **
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*** ** ** * ** ** **
* * * * * * * * * * **
}
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Hidden content!#include<stdio.h>
* * * ** *** * *
* * * * * ** ** * main()
{
* * * * ** * * i=0;
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Hidden content!#include * * * * ****** **
main()
{
** * * * * * year=0;
* * * * * *** * * * ** ** * &year);
* * * * ** **** && year%100 !=0)
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* * * *** * * ** * * * ** * ***** * * * *
}
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Hidden content!#include <stdio.h>
#include * * * * *
int main()
{
** * * * * ** * * ** * * year;
* ** * ** * *** ** ** * * ** * * ** *** put your years:");
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* * * * ** * *** * * * * * * ** 0;
* * * * ** * ****** * * * ** *** *
* **** * * * * **** * * ** * * * * *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * ** * * * * year=0;
* * * * * * * * **
** * * * * *** * * **** **** * * * * ** **
** ** ** * * * * *
* ** * * * * ** * * * * **
*** * ** * ** ** * * ** **** * * * ** * year is not leap year", year);
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** * * * * * * ** *
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*** * * * * * * * ** * ****
** * ** * * * * * * ** * *
* * * * ** * *** * *
}
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