11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
18.8k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 18.8k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
   * * **       ***** ***  *** ***  F0,F1,Fn,n,a;
  **    *  *    **  * **  ** **

* *  *   *** **    *   **  *********    * * * **  &a);

*** ** *** * ** *    ****    *** *   *     ** 
 *  **** * *****   ** ** * *   *
   *  *  ****** **  *** **   ********  * ****** *  **** *
**  ***  *  *** **      **        * * * *   **  * *
*  * ****  ****** *   **** ******* **     **   * *    * * *
    }


**  *         *** *  **** * *  ** *  * *   ** Fn);

 * **   * *****    *     ****  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * * *  **
int    **
{
int ***    **  **
  ** * * **   ******* **   * *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
 **   *    * ******* * ** ****  ****  ** *
 ** ** *  *  **    * ** ***   ** ** *  ***  ***** * ** * = c0+c1;
*  ** ****  * * * *  *  * ** ***  ** * * ** ** *  ***   **  = c1;
**  *** ***  **   **** * ** *  ***   *  ********   * *   *  = cb;
 *** *   ****  ***     * ** 
 **  **  *   * ** ***  *    ** *   **   ** *  *** * 
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ******* * * 

int ** *  
{

int * *   **
 ***  ***  *** * *****  **     * 

if(a==0) printf(0);
else if(a==1) * * *  * 
else {
* *  * *   **  **     * ***   ***   * * ***    
* ** **   *  * * ** ** **   *  *  *  ** ** ** **  *** *** = c0+c1;
**** *    **  *  *****   *  * *  **   **** *  ** *    * * = c1;
****   *** ** *  *  *  *** *    * * ***   *     *  * = cb;
* * * * * **  *   ***  *  *
* * ** ***  *  **  * * * ***     **  ** * ** * 


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *  * **** ** *

int main(void)
{

int   *  * ***  * 
  *** ******    *   * *** *  

if(i==0)  ** **********     *  *
else if(i==1) * * * **   *   * 
else {
    *  ** * * *     * *  ***** *** ** * * ***  *
*** *  *** *  *  * **   **    ** ****** **** * * * ** = f0+f1;
*   **    **  ***   ****    ** *  ***  * * **  *  * ***   * = f1;
** **  *** * *  **  * **** ** **   ** * *  ***  *** = fn;
     *** *   ****  *  ****
****  * *  *  ****** * *** * *******  * * ****  * ** 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **     * *    *    *

int   **
{

int     ***  
* *** *  * * ******  *  ** * *   

if(i==0) printf(0);
else if(i==1) ** 
else {
  * ******  *    * **    ***  **   * ** **  *** **
  * **       *** * *  * **   ** **  *****   *       *****  = f0+f1;
* *      * ***** * ****** *** ** ****  *      **  * * **  = f1;
 ** * **     ** ** *  **   * *  *** ***    **  **  ***  *  = fn;
     **    **    *******  **
 *     ****    *****   *    *   *** **    *** *******     
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ******** ***** ******* * * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** * ** * * ** * *** * *** * * * d;
** * * * **** * ** ** * *** * **** * * * (d=2; d<n; d++)
****** ******* *** ** * ** * * ** * *
** ** * * * * *** * ** * * * * * ** ** ***** (n%d==0)
* * * * ** ** * **** ** * * * * *** * *** * * * **

   }
* * ** * ** **** *** ****** *** ** * **** ** *
** * ***** ** * * * * * ** ** * ** ** **
* * ****** * **** *** * * *** * * ** * ** *
** * ** ** *** * * ** * * * *** * * *
* * * * **** * ** ** *** * ** ** * **** * ** * * * * (e==0)
* ** ***** **** * * ** ** * ** * * * * * ** ******* * ** ***** ****** * * * ** * *** * *
* ****** *** * *** ** * * * *** *** * ** ** * * * * *** * *
* * * ** *** ***** *** * ** * ** * * **** ** *** ******** * ** * * * * ***** ***** **** ");
*** ** * **** * ** * *** ** *** *** * * **** *** *** *** * ** **
* ** * * ** * * * * ** ** * ** ** * ***** ** * * ** ** * ********* * **** * **
* * * **** * ** **** ****** ** * ****

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * ** *** * * * *** * * * * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** ** * * * ** * * * ** * * * * ** ** * * * d;
* * * ** *** * * ** * * * * **** * * (d=2; d<n; d++)
** * ***** ****** * **** * * * * ***
*** * * ******* * ** * * ** * * * ** *** (n%d==0)
** * * * ** * * ** *** * * * * * * * *** ** ** * ****** *** * * **

   }
* * * ** * **** * *** ** * * * * * * ** * * **
*** * *** ******* ** * ** **** ** *** * *
* * * * **** ** * ** ** ** **** * ** ****
** * * ** * ** ** * *** ******* * ** ** * ** *
* **** * * ******** * * * **** * ** * * ** * ** ** * * * ** * ** * * *** * * * (e==0)
** * * *** * ** *** *** ** *** ** ** ** ** * * * *** * ** * ** *** * * * * **** * * **
* * ** * * * * * * ** * *** * ******** ** *** * * * ** *
* * * * ** ** ******** ** *** * ** * ********* ** ****** ** * ** ** * * * * * ** ** *** **** ");
** ** * ** **** ** ** * ** ** * * ** **** * * * * * ******* * *** **** * *
**** * ** * * * * *** * * ** *** * * *** * ** ****** * ** ******* **** **
* * ** * ** * ** * **** * * * ** ** ** ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 *     * * ***** ** ***** ****  * ********  * * **** * d;
   *   **    *****   *    *   * * * ********** * **   (d=2; d<n; d++)
* * ********* *  *   ** *   *****  **   *** *  ***** * * 
 ** **   *  *      * *** *  ***  **      ***** *   *  *  *     (n%d==0)
*  *     * * * *  *  *  *   *   ****** * *   *   **         **   *   ***   * *   *** *   *
   }
 ***** *         *      * *     ***  *****   *     *** **
** ***    *** ** *  * **    ****  * ** ** *    *  * *
 *  *  *   *   * * ** * * * **   ** *  *** * *  **** * 
 * ***** * *** * *  **  * * *            *  ** *** 
   ********       * *  * *****  *     **  **  * *  * *     **** * ****  *  *   (e==0)
** ** *****  *   *  ******* *  *   * * *    *       *  **  * ****  ****** *   ** ***** ***    * **** * *
 **    *    ** * ***     * ***   ** *** ********* * * **** *** *** *  ** ** ***** *** ***
*   **  * * **   *   *   *** * **     ****    ***    *  * *** * * * *   **  ***    ** *  ** *** **  *   **  *  *  **** *  *  ");
** *     ** * * * *  *    * *  *** **    **  ** *** *** ****  *** *  *   * 
  ** ***  *   ***    **** * * *   *  ** ******   *  * * ** * **  *   * * * * ****    ** * **    *** *   * 
*** * *** ** **** * * **   ** *    *  ** * *   * **  *    *   *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*   *   ***  **  ***** ***    * * Fn,t1=0,t2=1, n,input;
**  ***** ** **   *    * ******  *   **** ***  **  **  **

*   ***** * ** * * ****  * **** **   *   * ** *  n++)
 ***   ** ** *      ***  * ** *
   * * *      *    * ******  * * *   * *** * ** ** ****     *  = t1 + t2;
**** * * **  *   ** ***    ***   *  ** ****      *     * 
 * **      ** **  **  * *  * *     *  * *  * ***  *** ** **  * *
    }

*  ***   * ** *  ******     * *   * *    *   * *  

 ***     **     ***  *  *   *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 * **   * *     * **    Fn,t1=0,t2=1, n,input;
****** **    ** *   * *** *  *   ***   ***  *     ** ** *** 

**** * *   **** ***  ** *  **** *     ** n++)
* * **  *****   ** 
 * * **   **    *  *  ** * **   * **   **     * **  = t1 + t2;
    * * ***   *  *** *** * *  **     ***  **  ******* *  * ***
   *** **   ** * * ***** **   *** * ****   * ***   ** *
**  *  ** * ** *****  * **  * ** **

** *  *******  * * * *   **  *   *     * ** *    * **  ",Fn);

 ***  *    ** **  *  * *     *  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.7
©2016-2026

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 12.1k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 22.2k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 9.3k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 15.3k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 15.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users