11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
2.4k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 2.4k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*  *  *******   * * **    **  * F0,F1,Fn,n,a;
 * * * **** *  * ******* *  

* *   ***   *    * *   **  **  *** *  * * **    * *  &a);

 **  ** * **   *  *** * *      * *****  *  *    
 *** **** ******    *  * *    *
  ** * ****   * *   ***  **** **   *  **  * *  *  * * *  * 
**  *    *  ***** *     * ***  **** ****  ** ** ***  **  **  * 
  ******** ** ***   ***  *   ***  **** **** ******* *** 
    }


**  *** ****** ****    **    ** **  **   Fn);

* ***  *    **** ***    *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** *  ** ****
int ** *** 
{
int *  ** ***   
  **  * * * ***  *  *** * ***
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*    * *   *      **    *   *    * **   *  ** 
*     ***   **  *  * *** **   * ***  **        **      **  ** = c0+c1;
 *  ***     *  * **  *  * **    **** *   ** *  *** = c1;
*** *******  * *****  * ** *  *  **  *  **   *** *  = cb;
  *  ** **  * *     * ** *    
 *    ** *  *** ***  *** *** *  * **   * ***  **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** * * ***   

int    ***** *
{

int *  ** ** ** 
****  *   ****   *** ** **

if(a==0) printf(0);
else if(a==1)    *  
else {
     *  *   * *  *   ***  **********  ***  
** *  **  *** ** *  ** *   ** * ***** *  * **** **  = c0+c1;
*  ****    ****  *****  *  * * ***** *****  *  ***  **  = c1;
** ****  **   *     **    * * * ** ***   * * *  ***** **    = cb;
**  **  ** * **** ** *  *   * 
  ***  *****  * * *** **   **   **       **** ***  **


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** ** ****  ***

int main(void)
{

int  * *  *** * **
  ****  * ** **  * ** * ****

if(i==0)      * **   *  ****
else if(i==1)  ***** **** * **   **
else {
 **  *******  * **   *   *       * ** **   *
   **** *  ** * ****  **    ****   *     * **  *  *  = f0+f1;
*  *   *  * * ** *   **** **  * *  ** ** ***   *    *  = f1;
*  **  ** * * ***  * * * **    * *    *  * **   ** * ** ***** * = fn;
***    *  *  *   ***  ***    
  ***       *  *  * **  **  ***  ** * *    ** * 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *     ***** *  

int * *  
{

int * ** **  **
  ** *  * **** ***  * ** 

if(i==0) printf(0);
else if(i==1) **** 
else {
*     *  ** ****    * *  ***    *     **  ***** 
  * **  * * *  ** *    *   * *  * ** **** *  *    * *  ****   = f0+f1;
*  **   **   * ** * *   *  **   * ** *  * * ** ** **  = f1;
** *  * *  * ******* **** ***** * *  *  *   * ** * * *   * *   = fn;
   *  *   *  *** *  *  *** *
*    * *  ** ****** * ****** ** ****** ** **** ******
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* *** **** * * ** * ** * * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** * * * ** ** * * * * * * *** * ***** * *** d;
** * * * *** ** **** ** ** ** *** * * *** (d=2; d<n; d++)
**** * * * ** * ** * * ***** ** * * * * ****
* * * * ** ** ** * * * * **** * ** * ***** (n%d==0)
** * * * * ** ** * * * ** ** * * * ** ** * ** * ** **

   }
* ** * * * * * * * * **** ** * * * ***** * * ****
* ** * * *** * * ** ** ** ** ** * ***
* ** ** * ** * * ***** * **** ** * * *** *
** ** * ***** * ** * ***** * * *
** * ********* *** * * * * * * * *** * * ** * **** ** ***** * * ***** * (e==0)
* * *** * * ** * * * **** ** * * ** ** * ***** * * * * * ** ** **** * *** *** ***** *** *
** * * ** ** * **** * * *** ** ** ** * * **** * * ****
** * * ****** *** **** * * *** ** ** *** *** * **** * ** * ** * * * *** * *** *** * * * **** * * * * *** * ");
* ** ** *** * * *** * * * * * ** *** * * * ** * *** **
* * * ***** * ** * ** *** ******** * *** * * * ** *** ** *
**** * **** **** ** ***** * ****** **** ******** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
***** ** *** ***** ** * **** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** * ** ** *** * *** * * * * ** * *** ** d;
**** *** ********* ** ** ***** ** *** *** *** * * (d=2; d<n; d++)
** ****** * *** ***** *** * * * ** * ** **
* * ** * * * * * ** ******* * * * * * ****** (n%d==0)
* * *** ** * * *** *** * * ** ** ** ** * * * ** * ** *** * * ****

   }
** ** ** * ** * **** * * * ** * * * * **** *
** * ***** * * ** * ****** * ** * *
* * * ******** ** * ** *** * ** *
* *** * **** *** ****** ** * * * *** * ****
** **** * * ** ** * * * * * * * ** ** ***** * * * * *** (e==0)
** * * ** ** **** * * ****** * * * *** * ** * ****** * ** ** * ***** ** ** ***
*** ** *** *** * *** *** * * * * * ** ** ** ** * ** ***
* * ** * * * **** ** * ***** * *** * * * * * *** *** * ** * ** **** * ** ");
* ** * ** ** ******* * *** * ** ** ** ****** ** ** * ** * * * **
** * ** * ** * * ** ** ** * * * * * * ** *** **** ***** ** * **** * ***
** ** * * *** * *** * *** * ** *** * ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 ***  * **** ** * ** *** *****  ** ***    ***** * *   *     d;
* * ** * *******       *** * * **  *   **      **   *** *    * (d=2; d<n; d++)
* * ** **  **  ***     ******* *   *      ******* * **  ***
**** ** **   ******* *** **     *    **  **        *  *  (n%d==0)
 *** ** * * * *** * *** *  ** * ****   *   * *** *     *  ** * *** **    ** ** 
   }
 *  *            ** **   * *    * *    ***  ***   * ***    ** ***   **
        *     ** **    *  * ** * *  ******  **
* *  * * ** ** *   *  **  *  *  **      ** * * *  * ** * *    *
***  ***  * *****  **** ****  *  ** * **********     * *
  *  * * * *   * **   **  *     * *   *  * *  **     *   * * * *** ***     *** **  * * (e==0)
*  ****   *  *   *******  * * *   *  *****   ****   * *  *  ****** *   * ***  *      ***  ***   * ********
 ***** ********* * * *   *** ***    *   *  *   *  **  **    **  *  * ***      *  **
**  *** *** ** *  *  *  **    ** *  ***   *    **   *     **** ****  ***     *   ****     * * *   *** **** ");
  ******   **  **   **  *  **  ** ****  *     **** * ** **  *  *   * **   **   
   *   * ******** *    *   **** *     *      *  * *****  * *****  **  ***   * *** *******          **
*    ***    ** * *** *** **  **** *     *     *    * 
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
**  *  *    *** * ** * * * Fn,t1=0,t2=1, n,input;
 ***  *  *** **  * *   ** ** * * ** **  * *  * *** * ** 

****  * * * *   *  ******* * * **  * ** n++)
   * * ** ** * * *   * * *  ****
*** *    *** *    ***        **   **  *  **  ** * ** ** *   = t1 + t2;
 * **     ***  ** *****  * *****  *  * ***  *  **  **  *** 
* ** ** *  ** *** *   ** ***  * *  ***  ***  ***** *   
    }

** * ***  **     *** ** *      * * *  *    ** *

    ** * *  *****  *   *   ** *   0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
  *  ******** *  * **** ** ** * Fn,t1=0,t2=1, n,input;
*  ** ***  ** * **** *  *  **  **  * ***   **  ** * **    

***     ***  *  ** *  *  **  ** **  ** n++)
***     **  * *** * *   ** *** *   
**    **   * *** * * * *   ** *****  *** *  *  = t1 + t2;
*** * *      *    ***  * *  ***** **  **  *   * * * **
  * *    * ** * *  ** *** * * ** *** **** * * *   ** **  
**  *** *** ****  *** ***  *

 ** **      * **   ***     **  **  ",Fn);

***** * ****   *  * **** * * ******  * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.155
©2016-2024

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 1.7k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.9k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 1.3k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users