11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
14.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 14.4k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

    *   *****  **   ***** **   i;
* *       * *** *  **   * **** j;
  ** *  ***  **  *       * * newNum1;
  ****** ** ***** *****  *  newNum2;
**  **** ***  **   ** *   * *  gcd;
 **** **  * * ** ** * **     rem;
  *** *** ******* * * *     * num1, num2;

 * * * * * * *  * * * *  * **    **  *** * *** **   *     **    

* * *  ** ***    *  * *  ** *
* *     *  *        *** **** **  *  

 ** **    ** **   *  ** *  * ** != 0)
 *  ***      *  ***   *** * *
  ******* ** * **    *   * **    *    **  ** **** * ** = j%i;
  *** *** *  *  ** * * * *    *  * *   *   *  = i;
**** **** *         ** * *****  *** ****  *** *** * **** = rem;
**  * * * *  ***   *     * *   
* * ******* ***   *   * * *** 

*  ****  *  *   * * *    *  ** = num1/gcd;
 * * **  **   *  ***  *   *  * ***   **  = num2/gcd;

* **  * **  *  *** *    ** * ***  * ***  == 1)
    {
** ******* *   **  * * *  *       *   *  **  * * **   *  ***  **    *** * * * ***** 
    }

 *  *** * * **  * *   *   *   
    {
*  * ***   **     *   ******* ** * * ** * * **  *  ***** *******   * * * **  **** ** *  ** 
    *** ***   * * * * *** *

*  **    * **  ***** ** * ***** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 ****      **      * * *   *** *  *   * ** **  * ****    ***   ****  **   *

** *  ** * * * **  **  * ***** *  * ***  *
**  *   * ***    ***  *     *  ******** * * ***** * **  *****    * ** * **  *  * **

    else{
 **       * ** *  * ** ** *   *** * * * ****** *
    {
**  *   *  ** *  ** *  * *****  ** *** * * *     
   *   *  *  ***  * * *** * **  ****     * **** * * **** *   * *      ** * ****** *  *     && deno%i==0)
   *  *  * *** * * ** ** *  ***  ***     *    ** * *** * **   ***  * **** **  *   
*   * ** * * *** *  *** ** *** **  **  *  *   * **     **  ** *** ** * *   *    *  *    * **   **       
***     ** * **    * *** **   * ***  **  *  *     ** ***    ***  *** ******   *  * * * ** ** * *   *
*   ** * *** * *  * *   *  * ** * *  ****** *  * ***  *    *** ****** * *  ** *     **
    }

* * *      * **** * *  *** ** ***  **  * 
    {
**  *  ****   *  *  **** ***** *** ***   ****
******  * * * * * ** ***** ***  ***** ** * ** *****  *  * *** * *      ** *******     *  *****   && deno%i==0)
*** ****** ** *  * *  **** *  ** * *** **** **    ******  *** **  **   **  *****
***   *    *  *****  ** *  **        * * ** ** * * *** *    *    ****  ** **** **  *  *  **     * **
 ***  * ** * ** ** ** * **   *     *   *     *   **** **  ***  * *  * *** * *  *   ****  *  * * 
*      *  **    *  ****   *  ***  **  *  ****    ****** ** * * *  **   *****
    }
* *  * * *  ***      **  **    *  ***  *  * *   * *

    }




 **  *     * **   * * *   ** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *****  **   
#include  *  *       ***

int gcd(int n, int m)
{
**  ** **** **    * *** *     * gcd, remainder;

*****  * * * **** * **  **  *   (n != 0)
* * **            * ** 
  * *   * *****  *  *** **  *  ***     * *****  *  *  *** * = m % n;
      ***  *    * ***** *    ****     ******* ** = n;
 *  *     *  *** *   *** **  * * *  * * **   *   = remainder;
*   *  * * * *    *  **    * **** 

******* *  ** * ** ***** * * *   *  = m;

* *******  *     ****** *  *  *   gcd;
}

int main (int argc, const char * argv[]) {

** * ** **      **     * number1, number2;
* *** **  **** *** * * newNumber1, newNumber2;

  *** ** *      ** *  ** *  ******* * ***   ***  * *   **** *        *

** *  *  *** * *** *   ***   **   = number1 /  *     ***  number2);
  ** *    ** ***  **  * ** **** *      = number2 / *  ***  number2);

 *** **** **   ** *** ** ** * *  *   *  * * **    * ***
*   ******   ****    * ****     * *    *       *     ***     *
  *  * ***  *   ** **  *    * 
 ** *** ** * **** ***  * *    **** * *   *  * *    
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *   * ** *  * ** ** * **
**   *  *** * *  * *

int **  n, int m)
{
* **  * *       *  int gcd,   **  

      * *  ****** *    (n != 0)
   *  *   ** ****  {
*  *  **      * * *** ***  **   ** * = m % n;
** * ***   *  ***  * ***   ****  m = n;
 * *     *** * *   * **  * *****  n =      **
***  * *  * *  }

    ***   * *  *** gcd = m;

** ***   * ***     gcd;
}

int main (int   *  *    char *  ***** {

*    * **  *   *  int  **     * * 
   * **    * int ** * ***    ****

***   **  *  * ***  * ***   **  * *  *  *** *  ** **  *** ** **  *

*    * ** **      =   * * /  * *  *  *   *  *
    * *  **    * *  *   * =   ** / *     ***    * 

 *  * * ** * * if *     * ** *  * * *  *
 * * *        * **  **   **  ** ***** **   *   **** ** * * * 
* *  **       else
** *** * *    * * * ******    ***  * *     *  *   
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*  *  *   *    ** *  **  *  *    *   i;
 **   ** * ** *  * * * **  j;
  ** * **        *    * *   * **** newNum1;
*** *    ** *   * newNum2;
 ** *  *   *    ******  * gcd;
*    *******   * *    *    * ***  rem;
**    *   **  **  *** *  ** num1, num2;
    
     *  * *  ** *   ***    *  * ***       ** **  * ****  * * *    *
**   * * *     * * *** **     
*  ******* * ** *** *****  *
*   **     *  * * ** **** *****
    **** *  **   ****
   **  * *   ****      ** *    *  != 0)
 * **  ****   ***  **   
   * *     *** * ** ***  * ****** ***** *** * = j%i;
*  * * ***  *  ** **  ****  ** **     *     * * * *    = i;
*  ** * * *** * ***  ****   *** * *     **  * ***    *** *  = rem;
 ***** *   * * * *** *  **
 * ** * *** *   * * *** ** *******
    
  *    *  * * ***  *****  = num1/gcd;
  ***  * * **    ***  ** *** = num2/gcd;
    
 *** **   *    **  ** **     **  *   == 1)
*  * ***** ***    * * ***
**   * ***** ** *   **** ***  * ** *   *  *      *  *** **  **  *     ** *** 
****   * ******  *  * **
    
 **  * * **  *** * *** **  *  
*   **** *   ** **  **     *   
*   ** ** * * ****  ** *  *  *  ***  * * *   * * *  ** ***  *  *  ***  **  ***  **  *  *   **
  ******      **   ****  **
    
**  *** * *  **  ** *      ** *   0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
     *  *  ** * * ** ** *****   i;
*  ** * *   * *  *    **     j;
   *   **    * * ***** * ** *  newNum1;
*** * **** *   * * ** ***  *  newNum2;
     *  *  * *  * ** *** * ** gcd;
  ***  * *   ****  * ** ** * rem;
 *  *****  **   * * * ** num1, num2;
    
*   *  *  ***  * * ** *   *********  ***   *    * * *  ****  *  * *     *
   * * *  * *   *   *      * 
         *** ****** ** * **   **  *
*  * *** * * ** **   ** ***   
* *  ***** **   * ****** *****
** ** * * * ** *  *****  *  *  != 0)
 **   *  *    * *  * **  *
**  ****    ** **   **  ***** **** * ** ** *  * = j%i;
* **** *  * *   ****  ***    *  *** ***  * *  * ****** = i;
**   *   * * ***** ** * *    *  *    * ***** * * ** ** *   = rem;
    ******* * *  ****  **** 
******* * *   *     *** **  * *  **
    
     **        * ******  *    **     = num1/gcd;
 *      *  **   *****  ** **  *  * * = num2/gcd;
    
 ** * **  * **  * **** * *** == 1)
 ** * *  *  * *    ** *  *   
* *  **   * * ****  * * **  * * ****    *  *  *******  ** **    *   * **     **** **  
* * ******  *   **   * *  **
    
 *  * ** * **** *** * *    * * 
 **   * * ***    * ***** ** *  
***    * * *    *  *** * *  *   * ** * **  * *    ****  * ***  *    ** *    **   *  * *** ** **
*  *      ** **  **     ** *  
    
  *         *** * *  **** *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 *     *  * *     *** **** * ***  **   *** *  ** ** **  ** * *
* *   * ** ** *  **  *   ***      *    * * **  *     * **
    {
  *** ** * **  * *  ** * **     ****** * * *  **** ***   *     ***
**** * ********  * * **** * *****   *     ***    **       *
 * *  *   *****  *  **  *   * *  * ****  
*   *****   *  **   **  *     * * **** * ** *
*  * *       *** *******   ****** *  ** ***   **** 

* * *** ***  *   *  *** * **   *  * 
** ****** *  *  * *** ** ** * **   * ** **  *** **  ***  ***   *   * *  ** ** **  *   * ** *   ****  ** ** 
***  ** **           **  ***  *  *   *** *   **** *  * ***   *  *   ***  *  * *    


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*  *  **    **** **  * ** **** a,b,GCD;
 *  **  *  ***  ***     **  *    *  **** ** *** ** ****  *  **   *
*  *** **  * * *   * * **  ******   
*****    ****        ***     **   **
*  ****     * **  ****      **** * ** ***  * **    *  ** *** *  ** 
 *****    *  *  *  **  ** * *
  *** *** * ***  *  ***     * * *** **  ****** ** ** ***  **   ***  ***    *     * 
*  ** *   ****      **         *  0;
}
   *  ** * ****  * *  * ** * *  gcd(int a, int b){
* * * ***  **  * *  ** ***  *** * ***   *  * * ** * * (!b) return (a);
  **       *****   *    ******* * * * ****  *  gcd(b, a % b);
   *   * *   *  * *  **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** *    *  ***** 
#include    * *   * ** *** 

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
  **     **  *   ***  * ** *  gcd, remainder;
  * **   *     * *** *
*    ** ** * ** * *       * * *      * (n != 0)
  ** * * **     ** **   * **   *
 **  ***  *** *  *** **    *** ***   *      ** **  **   ** *  = m % n;
** **      * * * ** * * *   ** ******  * *  ************** = n;
 *  * ********* * ***** *   * * ** *   *  *  **     * *  = remainder;
        *  ******** * *  *
    *     *  **        *
******   ******** * * * * ***  * * = m;
  **    * *   **    * *
*   *   ** **  ****  *  *****  gcd;
}
int main (int argc, const char * argv[]) {
   *******        *   *   number1, number2;
**   ** * ** **  * **  * newNumber1, newNumber2;
*  ** *  ****  ** ** **** 
   ****   * ***    ** *
  ***** * * **** * *        ** *  **  * * *     **    *  * *    * ** * *  
 ** ***  ***  * *   ***   **
*    * *   *   *** * ****** * = number1 / gcd(number1, number2);
  * *  ******  * **  ***  *  **       *  = number2 / ***** * number2);
*   *  *   *   * *** ** 
   * ***  ** * * * * * * * *
 * *** * *****  * ** **  *  *  ( * *     **
 *   * ***   * * *  * *   * **  * *  **  **  * *  * *** *  * *  * ** *****  newNumber1);
*** *** * ****   ****  ***  * ** **
** * * *** ****    ** ****  *  *
****    ** * ** * **    ** **    * **      * ***     newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
***  ****  ** *   **** **** * *  a,b,c,d,e,f;
** *  * *** **     *    * ***      * * ***      * ** *   *
 * *  *** * ** * * **  **   *
* *    * ** *** **   *    
******   * ** ***  **** ******
    {
 * **   *    * ** *** *  ***   * ****   **   **** *
**   **        * * *   ***** *     *  **** **     ***  
     ** ***** **** **  ** *    *** **  * * *   * * 
    }
* ** *   * *****     *    *   * ** 
    {
*** ** * **   **** *** * *** * * * ** **  ** *** ***   ****  **
 ****      **** * ***** *  ** * *  **   * * **   * **    ** **   *  * ** **
** ** *****  **   *** *    ******  *    * * *  *** **    *
***       ** * *** ***   ** *   * * **   * ***   *    ****  *  *  **      * * 
    }
** * **   *     ** *    **  *   
    {
* *     *   * * ***   *  * *    **** *   **  ******** *  *** * 
* *  **       ***** ****   * * *  ** * *        *   ** * ** *   *****   ** *** * * 
  * **   * ***     *** * ** *  ****    *  ***     *  *****
* ***  ****  *    * ** *  *  ** * ***** ** ***  *   ***  **** *       ***  **   * *  
    }
**      *** * *    ***  ** *** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.97
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 14.6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.4k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 18.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 14.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users