2 like 0 dislike

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 1k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

**** * * * * * ** *** * * i;
* *** * ** * * * **** * * j;
***** * * * ** * * * ** newNum1;
* **** ** * **** ** **** newNum2;
* *** * * * * * *** ** * gcd;
* **** *** ***** ****** ** rem;
* * ** *** ** * * num1, num2;

* ** ** **** * * * ** ** * ** ***** * * *** ** ** ***

* ** ** * ** * * * * * *
** *** *** * * * *

* ** **** ** * * * ** ** != 0)
* ** * * ** * ** * ***
* ** ** * * * ** ** * * ***** *** ** * ** * = j%i;
* * ****** * * ** ** **** ** ** * * ** = i;
** * ** ** * *** *** * * ***** * * * *** * * = rem;
*** ** ** **** **** ** *
*** ** ** **** ** **** * **

* ***** *** * ******** ** ** = num1/gcd;
* * *** * ****** * ** * * * = num2/gcd;

* ** * ** ** * ** *** * == 1)
    {
* * ** * * ** * ** ** **** * * * * ** ** * * * * * *
    }

**** * * ** **** ** * *
    {
* ** * ** ** * * ** ** ** ** * * * *** * * ** *** * * * * * * * *
*** * * ****** ***** * *

***** ****** *** *** * * * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * ** ******** * ** * *** **** * * ** * * * ** *

* ****** * **** * ** ***** ***** ** *
* ***** *** **** ******* ** *** *** ** * ** ** *** * * *** ***

    else{
* ** ******* ** * * * * ** *
    {
** * ** ****** * * ** ** * * * ***
*** * * *** * ***** *** * * * * * * * ** * * * * * *** * * * ** * *** && deno%i==0)
*** ***** *** * ****** ** ** ** * ** **** * * * ** *
** * * * * ** * * * ** * * ** * ***** **** *** *** * ** ** * ** *** * *
* **** *** ** ** * * ***** ** * * ****** * * *** ** * ** * * * * **** ** ** ** * * ****
**** * ** *** * * * * * ** ** * ** * * *** * *** *
    }

*** * * * * * *** * * * ***
    {
* ** ** ** *** * *** *** *** * **
** ** *** * * * * *** * ***** * ** * * *** *** ** *** ** * **** * ** ** * && deno%i==0)
***** * *** * * * * * *** * ** ** * * **** ** ****** * * ** * * * **
* * *** ** ***** * * ** *********** ******** * ** * **** * * ** ** *** ** * * *** * * *
* *** ***** ********* * ** * * *** * * * ** **** ** * ** ** * * ** ** ** * * *
* * **** *** * * * * ** ** * * *** ** ***** * ** * ** * *** ******
    }
** ******** * ** *** *** *** * ** ****

    }




* ** * ***** * ** ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ****** * *
#include ***** ** ***

int gcd(int n, int m)
{
* * * ** * * ** * * * ** ** * gcd, remainder;

* ***** ***** *** * **** *** (n != 0)
* * * * * * ** *** * *
***** * * * *** * ** * * * ***** ** ** ** * * **** = m % n;
*** * * **** * * *** * * ** * * * ***** *** = n;
* ** * * ***** * ** **** **** * ** ** * ** *** ** * = remainder;
** *** ** *** ** * * *

** ** **** *** **** * * = m;

*** *** * * ** ** * ** gcd;
}

int main (int argc, const char * argv[]) {

* * * ** *** * * *** * * * number1, number2;
* * * * *** ** * * newNumber1, newNumber2;

* ** * ** ** * * ** *** **** * * *** * ** * ** ** *

**** ** *** * ***** *** * ** = number1 / ** * number2);
*** * * ** ** *** * *** * ** * = number2 / * ** ** number2);

* * **** *** ******* * * ** * ** ** * * *
* * * * * * ** ** **** *** * *** * * * * ****
** ** ** * * * ***
*** * *** *** ** ** * *** ** ** * * ****
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * * ** * ***
* * ** * * ** *

int * n, int m)
{
* * ****** int gcd, ** *

* *** * ** * (n != 0)
* * ** ** ** {
** ** * *** ** * * * * ** * * * = m % n;
* ** * * ** *** ** *** ** * * m = n;
* ** ** * **** ** n = **** **
**** *** * }

** * * * gcd = m;

***** * * * * ** gcd;
}

int main (int * char * * * {

* **** ** * int *** *
* **** int * ** **

** * ** ** * * * * * ** * * ** * *** * *** *

**** * * ** * = *** / * * * * * ***
* ** ** * = * / ****** * **

* * ** if *** ***** * **
**** ** ** * * * * * * * * **
** ** * * ** else
* *** * * *** *** * ****** * * ** *** ** * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** * * ** * ** **** * i;
* * * * ***** * j;
******* ** * * * * newNum1;
* * **** * * *** *** newNum2;
* **** ***** * * * ***** gcd;
***** ** ** ** ** *** * rem;
*** ** * * ** * num1, num2;
    
** * ** * * ** * ******** * ** * * * * ** ** * *
** ****** ** ** ****
* * ** ** *** *** *
*** * * ** **** * * *
* ***** * ** * ** ** ** **
** * * ** * * **** * != 0)
** ** * * ** * * ***
****** * *** * * ** **** *** * *** ** ** ** = j%i;
* **** * * * ** * ** *** *** * * * = i;
** * ** ** * ** * ** *** * * ********* * = rem;
** * * *** *** * ** * **
* * * ** * ** **** * ***
    
* * * *** * * **** ** = num1/gcd;
* * **** * ** *** * * * = num2/gcd;
    
** * * *** *** * *** ** * *** == 1)
* *** * * *** * **** ***
**** *** * **** *** **** * * * **** ** * * * * ** * * * ***
******* * * * * *** *
    
* *** * ** ** * * * ** *
** ** * **** * * * * *
* * ** * * * * *** ***** * * * * * * ** ** * ***** ** **** *** * * ****
* * **** *** * * * **
    
* * * ** * ** ** * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* *** * *** *** * * i;
***** * ** * * ** j;
* *** ** ** * *** ** newNum1;
* * * * * * ** ** * newNum2;
*** * **** *** ** * * gcd;
** ** **** * *** rem;
* * **** ** *** ***** num1, num2;
    
* *** *** ** **** * * ***** ** ** * *** ** ** ** **
******* ***** *** * *
* * * ** **** ** *** *** *
**** * *** ****** * * ** *
* *** ** ** * * *** *
****** * *** **** ** ** != 0)
* *** *** ** *** * *
* * *** * * * *** *** ** *** ** *** ** * = j%i;
** * ** * *** * ** * * * ** * **** ****** = i;
* ** * * * * * ** * ** ** ** **** * = rem;
* ***** * ** *** * ****
* ***** * * **** * * ***
    
** ** ** * ** * ** = num1/gcd;
** * **** * **** ***** * ** ** = num2/gcd;
    
* *** * * * * ** **** * * ** == 1)
* * * ** * ** ** ** **
*** * * * *** *** * **** **** * * * * * * ** * * * ** **** ****
** * *** * * * ** * ** *
    
***** ***** * * * * *
******* * * * ** **** * *
* * * ***** * ***** ** ** * * * **** *** ** ** * ** * * ** * *** * * * *
*** * *** * * * **
    
** ** * * * ** * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** ** *** * **** **** ***** ** * ** * ** * ** **** *
***** *** * ***** ** ** * * * * * *** * *
    {
* * * * * ****** * *** * * ** * ** **** ** **** * *** *
* * * * * * ** * * ** ** **** * * *** * * * **
*** * ** * ****** * ** * *** *
* * * * * ** ****** * * * *** **
*** * ** *** * * * ** * ***** * * *

* ***** **** **** **** **
**** ******* * ** * ** *** ** ** * **** ** **** * * * * * * * ** * * ** * ** * * ** * **
* ** * **** * * * * ** * * ** *** * *** ***** * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** ***** * *** a,b,GCD;
**** ** * * * * * **** ** ** *** ** * * * *** *** ** **
* ** * * ** ** ****** * ** * * *
*** * * * * *** *** * * **
* **** * * ******* ** ** * * * **** * * * * ** ** ** * ***
* **** * *** *** * ** ** * *
* ** * * * ** * * * * * *** *** * **** * ********* *
* * * ** * * ** 0;
}
** **** * ** ** * * * * * ** gcd(int a, int b){
** * * ** * ** * ** * *** * ** * * * * * **** (!b) return (a);
** ** * ***** **** * ** *** * ** * **** * gcd(b, a % b);
* *** * ** ****
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * **** * **
#include **** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* **** *** *** ****** gcd, remainder;
* * * * **** * ** *
** * * * ** * * ** (n != 0)
* ** * * * * *** ****
* ** ** *** *** * ** * * ** ** ** *** *** * ** *** = m % n;
* *** * * *** * ***** * ** ** * ** ** = n;
** ** ***** * * ** * * * * * *** *** = remainder;
* * ** * **** ** *
** *** * * *** *****
* **** ** ** *** * = m;
* * ** ** * ****** *
* **** * * ** ** **** *** * ** gcd;
}
int main (int argc, const char * argv[]) {
** ** *** * ** * ** number1, number2;
* ** ** * ** **** * * ** newNumber1, newNumber2;
* ****** * * * * *** ** **
*** ** *** * * **
* * * *** *** * ***** ****** * * * * * * **** * ** ** ** *
* * * *** ** *** *
** * * * *** ******* * * ****** = number1 / gcd(number1, number2);
* **** * * ** * * * ** * = number2 / ** * number2);
** * * * **** *
* *** * * ***** ***
****** ** * * ***** ***** * ( ** *** *
** ** * ********* * * ** ** **** * * * **** * * ** * newNumber1);
******* ** *** ** * * * *
**** * * *** ** *****
*** ** * *** * * ** ** * * ** * ** * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* **** * * * *** * ** a,b,c,d,e,f;
* * * ** * * * * ** * *** * ****** * ** *** * * *
* *** * **** *** * **** *
*** * ** ** *** * ***** *
* * * **** * * * * **** *** *
    {
* *** * ** ** * **** ** ******** * **** *****
* * *** * ********* **** * * ** ** *** * * **** *****
*** * ** * *** ** * * * ** * **** ** * * **
    }
* *** * ** * * * * ** * * *
    {
* * ** ***** * * * **** **** * ** ** *** *
*** * ** ****** * * * ** ** * ******** ******* * *** *** ** *****
* ** *** * ** ** * * * *** ** * * *** *** **
* * * ** ** *** * ** * ** * *** *** * ***** *** ** **** * * * * **
    }
** *** ** * * * * * * ** *
    {
* ** * * * * ** * * * * ***** * ** ** *
* * ** ** ** ** * * * * **** ****** ** * ** *** * *** **
*** * * ******** * * ** ** ** * * * ** ***
** * * * * ***** ** * ** * * * *** ****** *** ** * *
    }
* ** ** ** * *** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:3.238.204.31
©2016-2021

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 1.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 1.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 1.3k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 1.1k views
12,304 questions
166,965 answers
163,584 comments
4,641 users