11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
18.2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 18.2k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 *** * ** ***  **  *  * i;
**  **   ***   **   *  ** * *  * * j;
*** **  ** *  * *      **  newNum1;
* * *  *  *  **  ** *   *** newNum2;
 *   *     ****** *  *     ** *** gcd;
 *  *  ** **   ******   **   rem;
*  *  ***** * **  ****  ***** num1, num2;

***  * *  *** **  **** ***   *    * *    * *     *** ***    **  *  **  

*  * *  *** * *  *** *  *  
* ****     **  ***  *** *** *

  * *** **   * * *   **     *  * ***  != 0)
  *    ** *  ***  ** ** *
 **  ****  *  * ***  *  *   ** *    * * *  **  **  *      *  **   = j%i;
   * * * **    **** * **        ******   **** **  ***  **  = i;
* *** *   ** * ***   *  * **        ****   **  *    ** * = rem;
 * ***     ****     * ****
   **  **  * * ****  **   *  *** 

* * *  *         *  *  ***  *** *  = num1/gcd;
**   * * * * * ** **    * * ** *   = num2/gcd;

 *   *  ** ***** * * * ** * * == 1)
    {
* * ** *   *  * *** *** ** *  ******** **    * ** * ******** ***  *** ****   ** * *   *
    }

 * *** *  * ***** * **  * ***
    {
* * ***  *  **** ****   ** *   * *  **** *  ****  ***  ***  **        * ****** **  **      *    ** 
*  ** *  *** ****   *     

***  **  **  ** **   ** ****** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
***  *    *  **** *   ** * ** ****  * * **   *  ** ****   *        

     **  *** * ** **  *  * **  * * **  * ***
  **  **    ** ** ****  ** **** ** * * *   ** * ***  **  *  ** *** *    

    else{
* ** ** *    ****  * **  ***  * *  *   * * 
    {
 **    **   ** * **   * *   ** *   *  *  *
 *  **  ** * **  *   * *  * **     * *    *  * *** *  * *  * ***    ** *   *  **     && deno%i==0)
*  *  * *     *** ***** ****  ****  *  *     ***  ***  * *  ****    ** *  ****  ****
 *   ** ** * ** **   ****** *    * *  **** * ** * ** ** ***     ***** *   * **  **  **   *     ** * * **
 * *** **      *   *    **  *** ** *   **    * * ** * * * * **  ** ***      **  *   * *    **    *  *
   * *     *   *  *   ***** *** *   ***** **  ********** ** ***  ** ***
    }

 ** ***** *   *   **    ***   **  ** *     *** 
    {
 ** * ****  *  *     ***   ****    *  *  ** *
*  * ****  *  *** ** **** *****   *    **  **     *  * ***  ** **  *  *    ****     ***** * * && deno%i==0)
 *    *      *******   ***    *    ** ***  *  *  **   * * ** * *** * *   *  **
 * ******  ****  *    **** ** * ** ***  *  * *** *   *****   **   *      * **   **  **       **** ***    *
****  * ** *           * *  ** *  * * * * *  *  *  *   * *  * * * * *   *  **  * **   * *  * *  ******* **  * 
****       ** * *  * *** *  * *   * *     **** ** ** *****   *** **  ** * *  *****   ** 
    }
****       ** * ** ** * *    ** ***  **   * **  *  *

    }




*   *  *  ****  ***  *** ****   ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  ** *  *  ** * 
#include *   **   * *   * *

int gcd(int n, int m)
{
    *      *** *** * **   *  gcd, remainder;

   * **** *   *   * * * ******* (n != 0)
   *****   **    *****      * *
*  *  **  ** *  ****         *** * ***   ***    **** **** ***   = m % n;
 *   **   *  *    *** *      * **   * ****  * *** *  ** = n;
** *** * * * **** * ** *    ****    * **  **** ** * **** = remainder;
 ***  ****  *  *  ****  ***   *

  ***** *  ** *  *  *  = m;

*  *  **  ** **       **      * gcd;
}

int main (int argc, const char * argv[]) {

* **  ***   *    * *** *   * * **  number1, number2;
    * ********** *     *** newNumber1, newNumber2;

** *****  **   **    *****  *     * * * *  *    ****** * * * * * ******* 

 ** * ****  *******  *  ****  * = number1 /   **   * number2);
****  * *** **  *     * *** **** *  = number2 / **** **** number2);

**  **  * * * * *  ***     * **    ****   **** *    **
* ** * *    *      **  * ******* * *   * * **  **  **  * *   *   * **  
    *  *   **  ***** ****  *** *** 
 ******* * ***     * ****  *  * *  *     **   *** 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   **   ** **    *  *
*  **** *    **  ** ** 

int ****** n, int m)
{
* *** ***  *  ** *** int gcd,   * * 

 *    *  * * **   ** ** (n != 0)
  ****  *        {
****** *  *   ***  ** *  * * *** = m % n;
**   * * ***  ****** * ****  **  m = n;
***    *   ***      * * * * * *  n =  * **
  *  *   *** ** }

   ** ****  * gcd = m;

*****    * ** ** *** * gcd;
}

int main (int *** **** char *   {

 * *  *   *  int ** *     
    ** * * **  int * ** **  ** * * 

* **   *     **** ***** ***  *  *** **        ***      **   * * 

** * *  * *  *  * * *   = ***  / **  * **  ***  
** **** * **  ***   ****   = *** *  /  *   *  ***** 

 **** * **    if **       *** *** *
 **   * ***  *** ****     *** *** *  ** **** ****    *
* * ***  *    ** else
 *** **    *  * ** *  **    *     **  *  ***    ****
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 * ** ***   *    *   *     * * i;
* **     ***       *  *      j;
 * * * ****  * ***** * ** * newNum1;
 * ** *  *** * *  ***   *** **** * newNum2;
********  *  *        ** * *    gcd;
  * * **     *  * ** **   * **  ** rem;
 * *******    *  *  *  *** ***** num1, num2;
    
    *    * **    *    * ** * *** *  *  **** * * **** *  * * *   *
** *     *   ** **** 
 **** * * *  ** *      ** **       
   *     **    **   **** **  ***   * 
****** *  * * ***        * *
*** * ****   **  * ***    *     *   != 0)
******* * ** *** * **** ** *
    *  ***   *   *  * * **  * *****   **  ** **** * = j%i;
 **  ** ** *  ****      *     ***   * **  * * *  ***** ** = i;
*  * * ****  * * *  *  *   * ** **  * *  *  * ***  *** **** = rem;
* **  *      * ***   ***  
* *  **  * *   *** **    *
    
  ** * **** ***   *   *** ** *** = num1/gcd;
******     **     ****  * *    *    * = num2/gcd;
    
  *    *  * ******   ** * ***  == 1)
* * * **  * * * *** *****  
**   *   ***** ****** * ***   ***   **   *  * * *   *  *  * *** * ******* 
 * * ***   ***********
    
 ****    **   * * *   **     * 
**   *** * **  *  *   * ** 
* *  **   ** *** ** * * ** *** *  *          *** * *     *  * ** **   * *    ***** *   * 
   * **     *** * * *** ** *** 
    
  ***   ** *    * * * ** * **   * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*  * *    ***     **  **       * i;
 **  ***  * ****    * ***** j;
** ** *** ***      ****** *** * newNum1;
 ****  ** * *** ** *** * ***  newNum2;
 *    *    *      *  ** **  gcd;
   * *****    * * * *********  rem;
   **      ****     **** **   * *  * num1, num2;
    
    **     *   * **   ** * **  **  *  **  * **** **      * **
  * *   * ***** ****  * *  **
*  *   ****   **   *  * * * *
*** ** ****** ** *  *   ***  
* * ** * **  ** * **  * ***
   * **     * * *      *   * * * * * != 0)
**** * *  **   * * * ******* 
 * *  * *      *** * ** *   **  ** *    * *    *       = j%i;
**  ****** *      **   *  *****  **  * * *** *   *  * * = i;
** **  *         * ***       *       *** *  *  *   = rem;
* *   *  *      *  * ** *
  * * ******** *  *  *  ******  
    
* *     ** * * **  *   ***    = num1/gcd;
 * * ****  **  ***  * *    *  = num2/gcd;
    
*  ** ** * ** * ****  *  *    **  * == 1)
   *****  ** ** * * * ***
*** * ****** ***  ** *   ***** *      * * **  *  * * **    *** **  * *  **** * *  
***  * *   * **  ***     **
    
  * ****** *** *    *    *      
*   *  *** ** * *  **   *      * 
 *****   ** **  * *** ** **   *    * *   *   *       *  ** *  ***   * * * ** ********* * *
******** ***** ******     **  *  *
    
 ****    **** *** *  *  **  *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  ** ***** ** *  * * ** ** *  ** * ** **      **    ** *
* * ** **   *  * *  *   *   **    *****     *  * ** *  ** ***   
    {
***  ******  *  *  **   *  *   ** *    *  ******  ** *** ***  
******   *   * ****   ***   * * ** *********     *  * * *      
 * *** *  * ****** *** *  *****  * * *
 ** * **   *   ** **  *  *  * *** **  * * ** 
***   *** *  **** *  ******    * ***   * * ** 

  *** *** **  ***  **** *     ** *  
  *** * * ** * ****** *****  ** *** ** **   **** *   **  * ***  *** ****    ******* **  ** * *****  * *** **  * *
 ** *** **   **     * ** ** **   **  * ** *** ** * * *****  * ** ***     * **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** *  *** ***  ***  *   * a,b,GCD;
**** **   ** *       * *  *    ** *****   *** * ******* *  * *******  
 ** *  *  * * *  * *    *  ** 
    *** *    *  *****    * ****  * 
 *     ***   *  *     ******  ** ***** *    *  * *      *****   **** *  **
 ** ****  * *          **
*  ****   *  **       * ** * **   * ** * * **    *   * * *** * ** *   *** ****** ** 
 ** * ******* * * * **    **   0;
}
  *    ***** **    **    gcd(int a, int b){
 *** *     * * * ** *********** * ***** *   ****** **    (!b) return (a);
  * * *    ** * *** **    *   *      ***  * *    ****   * * *** * gcd(b, a % b);
   **  *   ***  * *****
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *    * * *** * ** *  **
#include   *****          

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** **  *  * * *  *** * *   * *   gcd, remainder;
    * ***** *** * *  * **
**   * ****  **   *  *  * *  (n != 0)
 *  * *****  **   ***  *  **
*      ***   ** ***     *  *   **  *    *** ***  * = m % n;
  * *  *** *  ***   * **  **    **   ** **   *   * **  * = n;
  * *** ** * *     **** ***  **  * * **  * * ****  * ***   = remainder;
**  *   *  * ** **  * * **    ** *
** ** **  *** ** * *  *
*   * * * ****    *  * ** ****** = m;
   **   * ***   **   ***  * *  
*       **  *   **      *  * gcd;
}
int main (int argc, const char * argv[]) {
    ****** * * ***   ** number1, number2;
* *****   ***   *   *    * *  newNumber1, newNumber2;
  *   * * ****   ***     *     
**  * *  **    * * * ** *
***   * *  * * * *** ** * *****    **      *    * ** *  ***** ***    
 **   * *  **  **  * 
* **  *  *     **  *  ******   **** = number1 / gcd(number1, number2);
  **  ****** * *  *** ***  * ***  * = number2 / *   *** number2);
*** *    *** * **  *  * 
   * * ****  **   *  * * 
   ****  * *****  * *  **  ( ** * * *
 * ** * **    *    *         * ** * ** **  *  * **    **   * **  * *     ** * newNumber1);
   *  *    *  * * * *   **    
  *** **  **** * **    * *    *
 ****    ** ****   * *   ** ** *   ***     *   * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 **    * ***    * **  * * *  a,b,c,d,e,f;
 * * **** **** *    *** ***         ******   * **** * * *  ***
     *****       * ******     *  
  * * * *  ** ** *  * *  **        
********  *** *** ******   *   *  *  
    {
** *  ** *   **   *** ** **  ** *   ****** * *    **  * *   
** **   ** *  *      **     *** * *      * ** *     * **   
 ***  * ***  *** *  *  *  ***  **     ****  *  **  **
    }
   *** ****** **  ** ** **  *** *** *  
    {
*  *   *** *   *** ***** * **   * *  * * ** ** ** ****** *
 **   **  *   * ***  ** * *  ** **  *  *** *   * ***** **   * ** **  * *  * ***
     **** *   **   **  *  *  * *   *   * * **** *    
*   *****   *   * **  * *  *****  **********   **  ***    * *  *  * *** * *
    }
 * ****** *      * *  * ***  * **
    {
* ***     * ** ***  **    *   *  **  ******  *   * *  * *  
* **  *   * **** ****  *   * * ***  ***    *  ***  *  *  **  *** *  **
* ** *   * *   * **      **    ******  ***  *******   *
   * ****** ** **   ***  * * ****  * *  * ** ****  * *  *****  *  *  * ***
    }
** ****  * **   **  *   *  * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 18.1k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17.9k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 23.9k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 18.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users