2 like 0 dislike
13.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 13.7k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * * ** * ** ** * ** * i;
* *** *** * * ** * ** * j;
* * *** * *** * newNum1;
** **** * * *** *** newNum2;
** * * *** * ***** * ***** gcd;
** * * ** * * * *** ** * rem;
** * *** *** *** * ** * * num1, num2;

* ** ** * *** * ** ** * * ******* * * *** ** ** * *** * *

* * * ** ** ***
*** * * * *** * * * ** ***

* * ** *** * *** * ** ** != 0)
** * * * * * ** *
** * ** * **** ** * * * *** ** * * = j%i;
****** ** * * * * ** ** * *** * = i;
* * * * * * ** ***** * ** **** ** **** *** = rem;
********** * *** ** *
* * * * **** * ****** *****

** * ** * * *** ** * *** = num1/gcd;
***** ** ** **** **** = num2/gcd;

** * *** * * ** ** ** *** * * == 1)
    {
* * ** *** * * * ** ** * ** * ** * ** **** * * * * * **** ******* **
    }

** *** * * ** * * **
    {
* **** ** ** * *** * *** * **** * * *** * * ** * * * * * *
* ** ***** * * **

* * **** * * ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * * ** * **** **** * * * * *** ** *** *** * * *

**** ** * * ** * * * **
** * * ***** **** *** *** * * ** ***** *** ** ****** *** * *

    else{
* ** * * ****** * ** *** *****
    {
* **** * * *** *** ** * ** ***** * ** * * *
**** *** *** ** * *** * * *** ******** ** **** **** * * * * ** * *** ** && deno%i==0)
**** * * ** * ****** ** *** ****** * * * ** * * ** ** ** ** * * * *
* * ** ***** ** * ** * ** * ** * ** *** * * * * * ** * * *** *** * ***** ** * *
*** * * * * * * ** * * ** * * * * * * ** * * * * ** ***
****** ** ** * * * * *** * * * * * * **** * ** ** * * *** **** **
    }

* * * * * *** *** ** * * **
    {
* ** * ** * ** * * *** * * * ****
* * ** * * ** * ** * * * * ** ** * ** ** * * * * ** * * ** * && deno%i==0)
* * *** * ** * * * *** * * * * * ** * * *** * ** * * * ** ** * *
* * *** ** **** * * *** * * * ** ** * * * ** * ****** * * ** *****
*** * * * * *** *** **** * ** * ***** *** * ** * ** **** * *** ** **** * * * ** ** * * ** *
** ** * * * * ** * * ** *** * * * ** **** ** ** * *
    }
** * * * * * * ** **** ** ** *** *

    }




* * ** ** **** ** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** *
#include *** **** *** *

int gcd(int n, int m)
{
*** * ** **** * ** gcd, remainder;

**** * * ** * ** * * * * **** (n != 0)
** * * * *** ** *** *
* * * * ** ** * * *** ** *** *** ** ** * = m % n;
* *** * ** ** * ***** * * *** * * * ** * = n;
* * *** * * * ** * ** ** ** ** * * * = remainder;
*** * * *** * * * * *

**** ** ***** = m;

** * * ***** * * ***** * * gcd;
}

int main (int argc, const char * argv[]) {

** ** * * ** *** * ** number1, number2;
**** *** * ** * newNumber1, newNumber2;

* ******* * ** * ** ******* * *** ** ** * * *** ** * ** ** *

** * *** *** ** ****** * *** = number1 / *** * number2);
** * * ** *** * ** ** * = number2 / **** number2);

*** ** * *** *** * * ***** ** **
** ** *** * ** * **** * * * ****** ** ***** * * * *** * **
* ** ******* * **** *
* * * * * * * ** ** * ****** * * * * * **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * * * ** * **
* *** ** *** ****

int * n, int m)
{
* **** int gcd, ** *

* ** * (n != 0)
* ***** * ** * {
** * ** *** **** * * * * * ** * * = m % n;
* * ** * * * ** * **** m = n;
*** * ** ***** * ** * * n = * * **
* *** * * * ** }

* * * gcd = m;

**** * * * * * **** gcd;
}

int main (int * * *** char * * *** {

* ***** int * ** ** *
* *** ** ***** ** int **** * ****

** ** * ** ** * ** ** * * **** ** *** * ** * *** *

* **** **** *** = *** * / ** * ** **
* * * * * * = * / ***** * ***

* * *** if ***** * ******* *
** **** ** * ******* * * ** ** * **
* ***** else
** * *** *** *** * ** * ** ** ***** * *** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** * * * * ** *** i;
**** ** * * ** ** *** j;
* ** ***** * *** ** *** * ** ** newNum1;
* ****** *** ** ** * newNum2;
**** ******* ** * **** gcd;
* ** * *** ** * * * * rem;
* * ***** * *** ** * * ** num1, num2;
    
** *** * * *** *** * * ** ** *** ** * **** ** * *
* * ** * * * *
* ** *** * * * ** * * ***
* * * * ** * **** ** **
*** *** *** **** ** ** ***
* ** ** ** ** * * * *** != 0)
** * * * ** ** *** * ** *
***** * * ** ** ** * * *** ** ** * ** = j%i;
* ** * ** * * ******** ** ** * * ** *** = i;
** * * ** ** * ** ** * * * * * * = rem;
* * * * ** * *** * ** ** *
*** ** * * * * * * **
    
** **** ** * * * ************ = num1/gcd;
** * ** ** *** ** * * = num2/gcd;
    
** *** ** * * * ** == 1)
* * *** ** * *** * ***
** * *** * *** ** ** ** ** * * * * * * ** *** * **** **
* ** * * * * * *** ** *
    
* * *********** * * * * *
** *** * *** *
** * * **** ***** ** * ** ** ** * * * ** ** * ** * ***** * ** *****
***** ** * ** * * * ***
    
** ** * * *** * * ** * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * * * ** **** * * i;
**** * ** *** j;
*** ** * * ** * * ** * * ** * newNum1;
* * ** ****** ** ******* newNum2;
* ** * * * * * * ** ** gcd;
**** * * * * * * * * ** rem;
***** ** **** ** ** num1, num2;
    
** * ***** ** ***** * *** ******* ** * ** ******* * ***
* ** *** ** *** * * * **
* * * ** * * *** *** ** ** **
* ** * *** ** ** ** *** * ***
* * * * ** **** * * ***
* *** ** * ** ** * **** ** != 0)
* ** *** * ** * * **
* **** ** * ***** *** * ** * ***** * ** * ** = j%i;
** **** * ** *** * ****** *** * * * * = i;
* ***** **** * * * ** * ** * * ** **** = rem;
** * ** * * *** *
* * * ** * *** ** * * *
    
* ** * *** * * * *** = num1/gcd;
*** ** *** * ** * * = num2/gcd;
    
** * *** ** * ** *** * == 1)
** ** *** ** *** * ******
* * * ** *** ** * * ** *** ***** * * * *** ******* * ** *
* * * ***** * * *** *** * *
    
**** * ** ** ** * ** ** **
* * *** ** ******* *
** * *** ** ** * * * ** ** ** ****** * * * * * * ** *** * * *
*** * * ****** ** *
    
** * **** ***** * * *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* *** * ** ** * * * ** * *** * * ********* * * * * ** * * **
* * * * ** ** * **** * * ** * * ** ****** * **** **
    {
** ******* * * ** * *** * * ** ** ** * ******** **
*** * * * * ** * *** ** * * **** * * * *
* * **** * * ** * * ** ** ** **
* ** ** * ** ** *** * * *
* ** * ** * ** ** * * ** * *** * ** *

**** * * * ** * ******
** **** ** *** ** * * ** ** ** ***** * * * * * * * * * * ** **
*** * ***** ** * ** ** * * ** *** ******** ** * * *** ** ** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** ** **** ** ** a,b,GCD;
* * ** * * ** * ** * * ***** *** * * * ****** * * *
* * * **** *** * * * ** * **
**** **** * * * * * * ** *
* * *** * * ** *** * ** * * * * * * **** ** * * ****** *
* * ** ** * * *
** * ******** ** ** * *** *** * * *** ***** ** * * * * * * *** **
*** * *** * **** *** * 0;
}
** * * * *** *** *** * gcd(int a, int b){
*** ** * ** * ** ******* * * * **** * ** (!b) return (a);
* * ***** * * * * * * * ** *** * ** * * ** ** * * gcd(b, a % b);
* ** ** * ** ** ** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ****** ******
#include * * * * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** * ******** **** * gcd, remainder;
* *** * * * ** * *** *
*** ** * * * * **** *** (n != 0)
* * ** **** *** ** * * *
* **** * ** * * **** ** * * * * * *** * * *** = m % n;
* * * ****** ** ***** * * * ** * * * * = n;
* *** ** * **** ** * ** * *** * * ** = remainder;
** * ** * * **** * **
***** ** * ***** * * *
* * *** * * ** * *** *** = m;
* ** * **** *** ***
*** * * * ** ** * ** * ***** gcd;
}
int main (int argc, const char * argv[]) {
*** * ** ** * ** * * number1, number2;
** ** * *** **** * * *** * * newNumber1, newNumber2;
* * * *** *
* * * *** * * *
****** ** * **** ** * ** * * *** ** ***** *** ** * **** * * ****
******* * * ** * ***** * **
** ** ** * * ** *** * = number1 / gcd(number1, number2);
** ** * * * ** * ** * * ** * ** = number2 / ******* number2);
**** * * ** ***** * **
** ** ** **** * ****
* ** * *** * ** **** ( ** * *** *
* * * * * * **** ***** * ** **** * *** *** ** * ** ** newNumber1);
* * * ** * * * ** ** *
* ** ** * * * * ** *
***** * ***** * * ** * * * *** * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** *** ** * **** * a,b,c,d,e,f;
** *** * * * * * * *** ** * ** * * ** *
* **** *** *** ***
** **** * * *** ** *** ** * *
** * * * ** **** * * *
    {
**** * *** ** ** * * * * ** *** * ** ** *
** * *** ** *** **** *** * * **** * * **
**** *** * *** * * * * **** * **** *** * *
    }
* * * *** * ** *** * * * **
    {
* **** ***** ** * * ***** * ****** ********* * * * **
**** * * * ** * * * * ** * ****** *** ** * * ** * * **
* *** **** * * ** * **** ** *** * * * ****
*** ** ** ** ** * ** *** **** ** * *** ** ******* ** * *** * **** *** *
    }
* ** * * ** *******
    {
* ** ** ***** *** ** ** ** ** **** ** *** **** ***
* *** * * * * *** ** ***** * * * * *** * * ***** *
*** * ** * *** ** ** ** * * ** * ** *
** * ****** ** ***** * * * ***** * ** * * **** * * * *
    }
* * ** ******* *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.21
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.9k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17.6k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 13.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users