2 like 0 dislike

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 2k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* *** *** ** * * *** * * i;
* * *** *** * * * * *** j;
** ** * ** ***** * * newNum1;
* ** ** * * * ** * ** newNum2;
***** * * *** * * * gcd;
*** *** **** * *** * * **** rem;
*** * **** * * ** * * * * num1, num2;

* ** * ** *** **** * **** * * * * * * ***** * * * ***

** ** * * ***** * * *
*** * ** *** *** * ** * ** *

*** * * ****** * * ** ** != 0)
** ***** * **
* ** ** * * ** ***** ** ***** * * * ** ** * * = j%i;
* * *** * * ** * ************ * * * *** * ** = i;
** * ****** *** *** *** ** * ** * ** *** * * * * = rem;
** *** ** * * *** *
****** * ** * *** *

* *** * * * * * * *** = num1/gcd;
* *** * * ** **** * * * * * = num2/gcd;

* * ** * * * * ***** * ** * * == 1)
    {
*** ** * * * * ** * ** ** * ** * * * * * * *****
    }

* * ** **** **
    {
* * * ** **** * * * * * ********* * * ** * ** * * ****
* * * **** ** **

* ****** ** **** * * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * * * **** * ** ******** * * * ** ***** * ***

* * ** * * ** *** ** * * *
**** ** *** *** * * ** * ** * *** ******* * * **** *** ** *

    else{
* ** *** * ** *** * * * * *
    {
** * ** * ***** ** **** * *** **
** * * * ** * *** * * * * * * * * ****** *** ** ** * *** ** ** && deno%i==0)
**** ** ** * *** * * * * * * * * *** *** ** * * * ** ** ** ****
* ****** * ******** * * * * ** *** * ** * ** * ** *** * * ** * * * * *
**** *** * * ** *** ** * * **** * * ** * * * *** * ******* * * ***** * ** ** *** ****
* **** * * ** ** ** ** * *** *** ** *** * **** ****** ****** *
    }

** **** * * *** *** ** ****
    {
* ** ** * * * ** ** * *** ***
* **** * ** *** * * *** *** ** * * ** *** * * **** ** * * **** *** * * && deno%i==0)
*** * **** * * *** * *** * * * * * * * * * * ***** * ** * * * *
** * * ** * **** * *** * * * *** ** **** **** ** * * *** * * * * ** * **** *
**** **** **** * * ** * ** ** ** * * **** * * * * ** ** * ***** ***
** ** * ** * * ** * ** **** ** * * * ******
    }
** ** * **** ** * ** * ***** * * **** *

    }




*** * ***** **** ** *** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * *
#include **** * ***

int gcd(int n, int m)
{
** * * ** * ***** * * gcd, remainder;

** *** ***** * ** *** * (n != 0)
**** * ********** ***
** * *** * * ** * ** * ** * * **** * * * ** * = m % n;
* * *** ** ** * ** ** * * * * = n;
** * *** ** *** *** * *** * ****** ** * = remainder;
* * ** * **** * * **

* ** ** * * * * = m;

***** * ** **** *** * gcd;
}

int main (int argc, const char * argv[]) {

** **** *** * * * **** * number1, number2;
** * *** *** * ** * newNumber1, newNumber2;

********** ** ** * * *** ** ** *** * * * * ** * ** ** *** *

* * *** *** ** * * = number1 / * ** * number2);
* ** * *** *** ** * ** * *** ** = number2 / * number2);

* ** **** * **** * * **** * * ****
* *** **** ** * ** * * * * * * *
** * * * ** ******
*** * * * ** * * ***** * * ** *** * * * * *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* ** * ** *** * *
* * * * * **

int ** * n, int m)
{
* * * ****** int gcd, * * *

* ** * * * (n != 0)
*** * ** {
*** * * **** ** *** * *** *** ** = m % n;
** * ** * * * * * * m = n;
* **** * *** * ****** ***** * n = ****
*** ** * * }

* * * * ** gcd = m;

* ** ** * ** * * gcd;
}

int main (int * char * * ** {

* * * * * * int ****
** **** *** * int ***** * * * *

* *** **** *** ** ***** * * ** * * * * * ** * ***

* * * * ** * = * / ** * **
*** * * **** ** * = *** / *** ** ** *

** ** *** if *** * * * * ** **** * *
* * * * * ** *** ** ****** * ** * **** *** *
* * ** *** else
*** ** ** ** ** *** * ***** * ** ** ***** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** *** * ********** i;
**** * * ** * * ** **** j;
* *** * ** **** * * * * newNum1;
*********** * * ** * * * newNum2;
* ** **** ** ***** * * gcd;
** *** *** **** * * *** * rem;
* * *** ******* ** * num1, num2;
    
* * * ** * *** * * * * *** *** *** * * ** * ** ** *** *
* **** *** ** *
**** * * * * * * ** **
*** * *** * **** **
* **** * ** ***** ** ** **
* ** ** ** * ** ** * ** != 0)
** * * ******* * *
** * *** * * * * * ** * *** ***** ** * ** * * = j%i;
* * * * * * * ***** **** *** * * * * = i;
**** * *** ** ** *** * ** * * ** ** * * = rem;
* * ** * * *** *** * **
* *** ** * ** * ******
    
** ** * ** ** * ** * = num1/gcd;
*** ** * * * * ** * * *** = num2/gcd;
    
* * ******** * **** * * * * * ** * == 1)
* * ** ***** * * *
*** * ** * ** ** * * ** ** * * * ** ********* ** * *** ***** * *
* * * * ** * *
    
* ** *** *** ** ** * *
* * * ** *** *** *******
* * ** ** * * *** ****** ***** * * ** * * * * * * **** * * * ** * * ***
* * ** ** *
    
** ** *** * * **** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * ** * * * * ** ** i;
* * * **** * * ** ** ** j;
* * ***** ** ** * ** * *** newNum1;
***** **** * * *** * * * newNum2;
* * *** *** * * * gcd;
* * ** ** *** * *** rem;
* *** * * *** ** * num1, num2;
    
* * **** * * * * * ** ** * * **** ** * * ** * ****
** ** **** *** ** * **
* ***** ****** ** ** *
** **** *** * **** ****
* ** ** * * *** *****
** ***** * * ** * *** * != 0)
*** * * ** * **** *
* * * ** ** * * **** **** * * ** * * = j%i;
* ******* **** * * *** * ** * * * ***** ** **** ** * = i;
* * * ** *** * * ***** * ****** * **** *** * = rem;
* * ****** *** ** * *
*** * * *** * * * * **
    
** **** * * * * ** = num1/gcd;
*** * * *** * * **** ** * = num2/gcd;
    
** ******* ** *** * * * ** ** == 1)
* * **** **** ** ** * *
** ****** *** * ** * * ** * * * *** *** * * * ** **
*** *** *** ****
    
* ** ** ** ** * **
* *** ***** **** ** ** **
* ****** * **** ** ****** **** * *** * ** * ** ** ***** ** * ** *** ** **
*** ** **** * *** ****
    
* * * * * * ** ***** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**** * * * ** ****** *** *** * * * ** ********** * *
* ** ** * ** * * *** * ** ** * * * **** * * **
    {
* ** *** ** * ** **** *** * ** *** * ** * ***** * ****
* * * * * ** * ** *** ** ** **** ** ** * * * * * **
*** * * *** * *** ** * * **** ** *
* ** * ** * ** ***** * ** * * * ** **
****** * * * * * *** *

**** * * ** ** * *** ***
* * ** *** * ***** *** * * *** ** ****** * ** * **** * *** ** * ** ** * *** ** *
* ** * ***** * **** *** * ***** * * * *** * * ** ** ** * ** * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** * ** ** * ** * * * a,b,GCD;
* ********* ** ** *********** * *** * *** *** * *
* *** * * * * ** * ** * * ***
**** * * **** * **** * *
********* * *** * ** **** ** * *** **** * * * * * ***
* *** * * * ***
** * * ** * **** * ** * *** * * * * ** * *** ** ** * ** *
**** *** * *** ******* 0;
}
*** ********** * ** **** gcd(int a, int b){
******* * **** ** * ** * *** * * *** ** (!b) return (a);
* ** * * * ******** * * **** * *** * ** * ** gcd(b, a % b);
** ** ** * ***** ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** ** *** * * *
#include * ** * ** * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
****** * ******** * *** * gcd, remainder;
*** ** * **** * ** **
****** ** * *** * **** (n != 0)
** *** **** * * * * * * ** *
* * * **** ** **** * * * * * ** ****** = m % n;
* * ***** * ** * * **** *** * *** ** **** = n;
* ** * *** **** ***** ** * * * *** ** * * = remainder;
* * * * * *** *
* ** * * ** * * *
*** ***** ****** ** * * = m;
*** **** * ** *** ***
* * ** ** * *** * * * * gcd;
}
int main (int argc, const char * argv[]) {
* * ** ** * * ** ** * number1, number2;
***** * * *** * ** * newNumber1, newNumber2;
* ** ** * * ** * ** **
* ** * ***** * **** *
* * **** ** ****** * *** * * * ** ** * ** ***** *
**** * * *** * * **
***** * * * ** ** * * ******* = number1 / gcd(number1, number2);
** * ** * * **** * ** * *** ** * = number2 / * number2);
* * ** ** ***** * * *
** ** ** * ** * ** *
* * * * *** * * ** * * ( **** *
* * *** * ** * * * * **** * * ** * * ****** * ***** newNumber1);
*** **** *** ** *
* * * ** *** ** * * *
* * *** * ** * * *** * * * * ** * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ***** **** *** * * ** * * * a,b,c,d,e,f;
** * ****** * * * ** * ** * ***** *** * ** ** ****
* ****** ** ** *** ***
** * * ******* *
* ** * * * * * ** * * *
    {
* * * **** ** ** * * * * **** * **
**** * ** ** ** * * ** ** ** * * ***** ***
** **** ** * ** **** * * * * * **
    }
***** ** * * * ** ** ** **
    {
** ** * ** * ** * *** * * * *** ** * **
* * ***** *** ** ***** * * *** * * *** ** **** * ** *
*** ** **** * * * * ** ** * *** * ** * **** ******* **
******* * * * ***** * * ** *** **** * ** *** * * ** *
    }
**** * * *** * ** * *
    {
** **** * ** ** ** * ** ** * * * ** * *
*** * ** * * * * ** * ** ** *** ******* *** ***** * *** * *
* *** *** **** * * ***** ** ******* ** *** * *
** ** ** **** * * *** *** ** * ** ** * * *** * *** * ** *
    }
*** * ** * * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.110.198
©2016-2022

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 2.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 2k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 2.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 2k views
13,413 questions
202,739 answers
183,587 comments
4,966 users