11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
2.4k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 2.4k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* ** * * ** * ** * **   *  **   F0,F1,Fn,n,a;
   **        *** ***** **  *        

 * * *   *   ** *  ***** **  ********* ***  *** &a);

 ** *** *** *  * ***   ****** *  *** *** *
  * **   **    *      ** * 
  * **  * **  * ** ***** ********* *** **    **   * *** ** *
* ** **   * ** ** ** *   * ** **    *  *****   * *** *   
*** * *** *  * ***** *  *****  * ****   *  ***  **** *
    }


*  **   * ** ***     * *   *  **  *****   **** * Fn);

* *   * ****   *  *** ** * * * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  * ** ** *
int  *** 
{
int   *    *** *
 *  **** *   *    * ** * 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
 * *   *   ** *   ***     *  *  ** ** * **
 * ****   **  ** *** ***** * ** *  * * ** * **   *  *   = c0+c1;
**  * **  *  ***  * * ** ***   **   *******   *** ** = c1;
**  *  *   **       * ****** ****    **  * *** ***  ** ** = cb;
  ** ** **** ****** *    * 
*   * *  ** * * *   ** ***     * ******    *  ****
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *     **** 

int ** ** *
{

int ** * ***  * 
 *  **** * *** *   * *** ***

if(a==0) printf(0);
else if(a==1)   *  *
else {
     ** ** *   *** *   **  * ** ***  * * *
**      *** *   *  *** ***** * *    **   * * * ****  *** * = c0+c1;
**** **** *  *  *  * *  *    *    ** **   ***  *        ** * = c1;
*****   ***** ** ** *** * *** * * *** * *      ** *** *   **  **   = cb;
* **    ****   * *    **  
  * *  * **    **    *   * * * *** *    **    


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** * **    ** * 

int main(void)
{

int *   ** * *
 **  *   *   ** **   * * * **

if(i==0) *  *     ** **     ** 
else if(i==1) *   ** *   * ** *  * * 
else {
*  ** **** * * *   ** ***   **      *** * ** *
** **  *      * ** *     * *  ** **  ** * * **  *   *** = f0+f1;
* **** ** * *       *** **   * *** * * * ** *   ***  ***  = f1;
*  ***    ** ****  *****  * * *  *** **  **** **** *   **** = fn;
******  ** ** **** **  *** * 
 *   **   **  *******   *** **  *   *    ** **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * ***  * ****  

int  **** * 
{

int *****      *
** **  ***    * *  *    

if(i==0) printf(0);
else if(i==1) ** **  
else {
** **   **** ***** *   *** *** * * ****  
    **  ***  *   ***     **  * * *  ****  * *** ** ** *** ** = f0+f1;
 ***  * *      ***  ***      ** * * ** ****  * ****** = f1;
 **   ******   *******     *  ***** ***   *** **   ***    * * = fn;
  ***  *   *  * * *  * *
  *    **   ***         * ** *       ******  *   *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * ** ***** * **** * * * **** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** **** * *** *** ** * ** ** **** ** **** **** * d;
* *** ** * * ** ***** ** * ** * * (d=2; d<n; d++)
***** * *** * * * * *** ** * ***** *** * *****
* * ** * ** * * ** * * * * * * * **** * (n%d==0)
* *** * ** * ** ** * ** * * * * * ***** ** **** **** *

   }
* * * ** * ***** *** * *** * *** * * * *** *
* ** **** ** ** ** ** * ** * *** ** *
** ** * *** ** * * * * * * * * * * * * ***
** ****** * * * * ** ** * ** * ** **** * ** *
** * *** ** * ** * * *** * ******* * * * * * ** * * **** ***** * * (e==0)
* ** * * * *** ***** ** *** *** ***** * * ** *** ** ** *** * ** ** ** * * *** ** **
** * * ** ******* * * * * ***** ** ** ** ** **** *** ** * ****** ** *
* * * * * * ** * * * ** * ** ** * * * ** * * * * * ** * *** * * * * * * **** * ");
*********** * * ** ** * **** *** * ** * * * **** * * *** * ****** *
* ** ** ** **** *** **** * * *** ** * * ****** * ** ** * ******** ** * * **** * *
**** ** ** *** *** *** **** * ** * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** ** * ** ** ** ****** * * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * * ** ** ** *** ** ****** *** ** d;
* * ** ********* ** *** ** *** ****** * **** * ** (d=2; d<n; d++)
* * ** * * * ** * ** * *** * ** * ** ***** **
* * ** * * * * ** *** ** *** * ******* (n%d==0)
* ** ************* * * * * ** * * ** * * * * ** * * ******* ** * *

   }
* * * * **** *** * ** ** *** ** *** **
**** *** * * * * ** *** * *** *** * ** *
* ** ** * *** *** * *** * ** ** * ** * * *
** * * * * ** **** * ** * ** *** ***
** * *** ** * * * * * ** *** ** * ** ** * * * * * ** *** ** * * ** (e==0)
* * ** **** *** * ** * *** **** ************ ** * * * ** ** * * *** ** * ***
** * ** * ** * * ** ** *** ** * ** * **** * ** ** * **** * *
** * * **** * ** * * * ** * *** * * * * **** *** * * ***** *** ** * *** * ** * ** * ** ");
* ** **** * ** *** * * *** ** * * ***** *** ** ** **
* * *** * *** * *** ** * *** ** * * ** ** ** ***** *** ** *** * ****** ** *** * *** * * * *** *
* **** * * * * * * **** ** * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
**   **   *  *   ***** ** **** * *        *       *** d;
* **   *        **   * *   **  ** *   *  *  ***********  * (d=2; d<n; d++)
* *    *  ***  *    * ******* * ****  * * **  ****  
***  *   *  * *** ***   ** *  * *****   *   * * * (n%d==0)
   * **  *   *  ** ****  **   *  * *  ****  *   * * *     *** **  *    *   *  *   * * *
   }
*****   *    *  *  **  *  **** *** ****** ** *** *    * *  **   ***
 **   ***   *     ** ** **** **   * ** **   ** *  ***   **
*  ** * *   **   *****  ** *  * ** *   ***  *  **** * * 
 ****  **       ** * *  ***  *  *      *  ** ***       **
* *  *   *   ** ***  ***    ***** *** * *** *** *    *    * *  **** ** *  * **  **** **   (e==0)
***** **   *   * ** **     * **  ***   * *  ***      ** **  * ****  ***    ****  **   ** * * ** **  * * ***    
* *   *  **  * *** **  *  * *** **  ****  *** **  *  *  * **  *   ****    *  * * *  
**  *   *** ****** * ***** *  * * ** *** *  * ***  ***  *    *   * *  **** *    *   *   ** *  ****  ***   * * ***** *    ** *   ");
   **  * **   * ** * * **** * *   ****  ** ****  ** *** **** *** ***   
* * **** *    ** **    *    * *  *****   **** * *****  ***  **  **  * ** * *    **    ** **  * ***** *** * 
*** **** *  **    ** **  * *** * * *  ** ** **  *   ***  
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 ***  ***       * *  ** ** * Fn,t1=0,t2=1, n,input;
    ** * * *    ***** * *  *      *   * ****  * *****       *

*** ** ** *  * ***   * *  *   *  * **** *  * ** n++)
*    *** **   **** *  *  *   **
*     ** ****   *    *   *  *  **** * **  ** * ** *  *  ** = t1 + t2;
 ** * *    **** *****  ***   * **   ****** **  ******  *
  *  *    *****  *   *  **** **** *        *  *  **  **   
    }

*** *     * **   *  ***    **  **  **** ** **  * *

**  ***  *****  **   **   ** *    0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
***     *  ** *  * ****  Fn,t1=0,t2=1, n,input;
 **   **** **** *** *   * **    ** * * ***** ***  **    

* *** *  *****  * ***  * * *   ****  ***  n++)
* * **  *  *  **   * * *
***     * * *   * *   ****      * *  *****   * ** *  ** * ** * = t1 + t2;
   ****    **** *   * *        ** ** **** * *****  *  
*  ***  **   * * * * *  * * ** ***  **   *  * ** **    * 
 * * ***  *      *    *** *  * *

 ****** *  *** *** * * **** *** *** *  ** ",Fn);

 *****    ***  *   *  ***      *  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.234
©2016-2024

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 1.7k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.8k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 1.2k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 1.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users