3 like 0 dislike
19k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 19k views

86 Answers

0 like 0 dislike
Hidden content!
#include ** * * *

int main(){
* ** * * * ** * **** ** * * * a,b;
** * *** * ** * passed,failed;
* ** * *** *** *** total;
* ** * ** ** *
* ** * * ** ** * * **** **** ** ** ** *** ** *****
* *** ** * ** * *** = a+b;
** * * * ******* **** ***** = (float)a/total*100;
* * * * * ** ***** * * ** = (float)b/total*100;
*** * ** * ** ****
* *** ** ** * * * ** ** * *** * Ratio: %d%%\n", passed);
** ** * * ***** * ***** * ** * Ratio: ** * *** **
** ** ** ** * ***********
** ** * *** *** *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** **** * ** *** * * * * a,b;
*** * ** ** * ****** * * * passed,failed;
* ** * *** * * total;
* ** * ********* *** *
* ** **** ***** ********* ** * *** * * **** ***** * *
** * * * *** * ***** * = a+b;
* ** ** * * * * * * * * ** = (float)a/total*100;
******* **** *** * ** ** ** * = (float)b/total*100;
* ** * *** ** *** ** *****
* * *** * * ** **** ** ******* * ** *** * passed);
** * * *** * * * * ** ******* ****** **** * * *
** ** ** ** * * ** ***** *
***** ** * * ** * ** * *** 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* *** * ** *** ** ***** a,b;
** ** *** * * * *** passed,failed;
* * ***** ** ***** total;
** ** * * * * ***
* * ** ** * ** * * ***** **** * * * * * * ** ****
** *** **** **** * * * = a+b;
* * * ** * ** * * *** = (float)a/total*100;
* * ** * * *** ** ** = (float)b/total*100;
** * * * ** * *** **
* *** *** * * * ** ***** * *** * * passed);
* ** ** **** *** * ***** ****** ** ** ** *
* ** * ***** ****** *
* *** ** *** * * ***** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* ** * * **** * * ** a,b;
** ** ** *** * ** ** passed,failed;
* *** * **** *** ** total;
* * ** * *** * **** ***
* **** ** * ** ** * ** * * ** * ** **** * * ** ** ***** *
** * ** ** * *** = a+b;
** * * *** ** ** ** * ** = (float)a/total*100;
* ** * * * ** = (float)b/total*100;
* *** * * **** *****
*** ** ** * * * ** *** * ** ** * * **** passed);
* *** * *** * ******** ******* ** * *
* *** * * * * * * *** *** **
* *** * * ** * * ******** *** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * ****** * *

int main()
{
* ******* **** *** pass,fail;

*** *** *** ***** ** * ** * ** ** ** * *** ** *** ***

* * ** * ** ********* ** ** *** Ratio: *** *** *** * * * **** **
* ******* ** * ** **** *** * Ratio: * * * *** *** **

** * * ** *** ** * 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
**** * * ** ** * ** **
int main()
{
** ** *** ** *** * *** a,b;
* **** * ** * * * ** * *** ** ** *** ** * **
** * ** * **** * ** * ** Ratio: ** ** * **
** * ** * * * *** *** * * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** * * *** * ***
int main(void)
{
* *** ******** * * * * a, b,success, fail ;
***** * * **** * * * * * * ** **** ******* ** * * *
* *** * * * ****** * * *** ** * ** *
* * **** * *** ** * *** * ** **
* * *** * ****** * * * ** Ratio: %g%%\nFail Ratio: * * * success, fail);
* ** * * * ** * ** * * 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
**** * ******* *** *** a,b;
* * ***** ** ** ** * ** * ***** * *** * ***** **

* ** ** * * *** * * ** Ratio: * * **
* **** **** **** *** **** ** * Ratio: * ** ***** *

* ** * ***** * ** * * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
***** * * **** * *
int main()
{
* * *** ** ** ** * *** a,b;
* * * * * ** * * ** * * ************** ** ** * * *
*** * ** ** * **** **** ********* * Ratio: * * * *** *
*** * * * ** * * ****** ** *** ** * Ratio: %g%%",100*(b/(a+b)));
* ** * ***** *** * ** * * *** 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** ** ** * * ** ***
int main()
  {
** * * * * * * * * *** a,b;
* * * * *** * **** *** ** *** * ** ** * ** ** *
*** * *** ** * **** **** *** ****** * Ratio: * *** * ** * * *
*** ** * * ** ** ** * * * **** * Ratio: * * * *
** ***** *** * * ** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users