3 like 0 dislike
12.3k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 12.3k views

86 Answers

0 like 0 dislike
Hidden content!
#include ** * * * **

int main(){
* * * * * * *** * a,b;
***** **** **** * * ** passed,failed;
* * * ** * ** * ***** * total;
* ***** ******** * * ***
**** ** ** * **** ** *** * *** * *** ****
* **** * *** ******* = a+b;
** * ** * * * * ****** = (float)a/total*100;
* * * * ** * * * * * *** = (float)b/total*100;
* * * * **** ** *** *
** ** * ** * *** ***** * *** * Ratio: %d%%\n", passed);
* *** * ** * * **** * * **** Ratio: ** ** *
* ** ** * * ***
* ***** **** ****** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* * * *** ** ** *** *** a,b;
* * **** ** **** ** *** * * passed,failed;
* * * *** * *** ** *** total;
** ** ***** * * *** * ** **
** * **** *** * ** * ** * * * * **** * * * * **
*** * * * * ******* ** * = a+b;
*** * ** * *** *** ** = (float)a/total*100;
* *** * * ******* = (float)b/total*100;
*** * * *** * **** * * *
** * * ** ** **** ** ** * ** * ** * *** passed);
***** * **** ** ******** *** ** ** * * ** ** ** *
*** ** ** * * ***
**** * ** * * ** *** * ** * ** 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
******* * * **** * ** ** * a,b;
*** * ****** * ** * * passed,failed;
* * *** * * *** * * total;
**** ** * * * *** **
* ** ** * ** *** *** *** ** *** * * *
* *** * * * * ****** * *** = a+b;
** ** ** ** * * ** *** = (float)a/total*100;
** * *** ** * ** * * * = (float)b/total*100;
** * **** ** **
** * * * * * * * ***** * * * ** ***** * * * ** * passed);
* ** ***** * *** ** ** *** ******** ** *** * * **
* ******** * ** ***
* * * * * * ***** * ***** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** ** *** * * * ** * * a,b;
** ** * ****** * * * ** ** ** passed,failed;
* * * ** **** ** * * total;
** * * * * **** ***** **
* ***** * * * ** * *** ** * * *** * * * *
**** **** * * ******* = a+b;
* ** ** ** * * ** * = (float)a/total*100;
* * ** * **** ***** * = (float)b/total*100;
********** * ***
* ** **** **** * **** * *** * * passed);
* * ** ** ** ******** *** * ******* * * * *
*** ****** * * *******
* ** * * * * *** * * * *** * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** ** **** * *

int main()
{
* * * **** * * * * * * pass,fail;

*** ** *** ** * * * * * * * * ** ** * * ***

* * * * *** ** * **** ***** * *** *** * Ratio: * *** * **** ** * ***
* * * ***** * *** *** * ** * Ratio: ***** *** ** * ***

* * * **** * ** * **** ** **** 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* *** * ** ** ** *
int main()
{
** ********* ** ** * ** a,b;
* * * ** ** * * *** * ** * **** * **
**** **** ***** * * ** * ** Ratio: * **** * ** *
* * * * *** * *** ******* * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * ** * * ****
int main(void)
{
** * ********** * a, b,success, fail ;
* ** *** * * ** **** ****** ** * * *** ** ****
* ** * ***** *** ** * ** *** *
***** ** **** ****** *** ** *
* * ***** * * **** *** **** *** Ratio: %g%%\nFail Ratio: * * *** success, fail);
** **** * ******** ***** ** 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* ***** * *** * * * a,b;
*** * * ****** * * * * *** *** ** ** ** * * *** ****

***** * *** ** ** * **** **** Ratio: **** ** * * * **
* * * * * *** **** **** ** **** * * Ratio: *** * ** * *** *

** *** * * * * ** ** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** ****** *
int main()
{
* ***** * * * ** ****** ** a,b;
* * * * * ** ** * * * * *** ** *** * ** * * ** **
* *** ***** * * ** ** * ** * Ratio: *** ** **** *****
** ** ** * ** ** * * Ratio: %g%%",100*(b/(a+b)));
** * * * * * * ** **** * 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** **** * *
int main()
  {
* * * * * **** *** *** a,b;
** *** * *** * * * * * ** * ** * * * **
** **** *** ** * ** * * * ** * ** * **** Ratio: ******* ** * * *
* ** * * ** ** ** *** ** *** * Ratio: * * * * * ***
* * ** * * ** *** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.117
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users