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Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

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86 Answers

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Hidden content!
#include * * * *

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}
answered
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
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** * *** * * * ** * passed,failed;
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}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
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}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
**** ** * ** **** * * * * a,b;
* **** ** * ** * * *** passed,failed;
**** * ** ** * total;
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****** * *** *** **** * = a+b;
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*** * ** * ***** ** ** **** * ** ** * passed);
** * *** **** * * ** ** * ** * ** **
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* ****** **** ** ** *** *** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** * * *** ** **

int main()
{
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** ** ** * *** * ** * * * * * * ** ***

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* * * * * ******* ** * * Ratio: * * * * * * ** *

*** ** * ** * * * *** * 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * ** ** ***** *
int main()
{
** *** *** *** * ** ***** a,b;
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* ** * * **** * ** * **** * *** * ** * Ratio: ***** * ** * ** *
*** * * * ** * ** * ** *** ***** Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
****** * ** **
int main(void)
{
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*** * * *** * * **** * 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* *** ** ** *** * * **** a,b;
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*** * ** * ** * * * * * ***** Ratio: * * *** * * * ****
* ** ** *** ** Ratio: * * * * * * *

** * * ** ** ** ** * ** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
*** ** * *****
int main()
{
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}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * * ** * *
int main()
  {
*** ** * ** * ** * ** *** a,b;
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}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
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