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Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

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86 Answers

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Hidden content!
#include * ** * ** *

int main(){
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**** *** *** * * **** passed,failed;
** ** * * * *** ******* total;
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** *** ** * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
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}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
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}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* ** * * ********** a,b;
* **** **** ** * ***** ** passed,failed;
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** * ** ** * *** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * * * *

int main()
{
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* * *** ** * * *** * * * *** * * * * * ** * **** ** * *

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* * *** * ** ** * * * ** * *** ** Ratio: * * * **** * ** ** * ****

*** * ** * ** ** * * * * * ** 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
******* **** **
int main()
{
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** ** ** * * **** * * *** * * ** * Ratio: **** ******** ***** ***
*** *** * ** *** * ***** * ** * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* *** * * * **
int main(void)
{
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}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
** ** * * *** *** a,b;
* **** * * * ** ****** * *** * * **** * *

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* ** ** * * ** ** ** *** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
***** * ***** * * *****
int main()
{
* ** * *** *** ** * ****** a,b;
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** ***** ** ** *** ** *** ** 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** ** ***** * *
int main()
  {
** ** *** *** *** *** *** * a,b;
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}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
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