3 like 0 dislike
18.2k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 18.2k views

86 Answers

0 like 0 dislike
Hidden content!
#include * ***** **

int main(){
* * * * * *** * a,b;
** ** **** ***** ***** passed,failed;
* ** **** * *** total;
* ****** * * * ** ***
* ****** ** * **** *** * *** ** ** * *** * * *
** * ** * * ***** **** = a+b;
** * *** * * ** *** *** *** = (float)a/total*100;
* **** ** * * ** ** ** = (float)b/total*100;
* ** * * ** ** **
** *** ***** *** * * **** *** * **** * *** Ratio: %d%%\n", passed);
**** ******* ** * * * * * *** * * * Ratio: * * *** *** ****
* * * * ** *
* * * * * *** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
***** * *** * * * a,b;
* *** * * * * * * * passed,failed;
** * ******** *** ** total;
*** ***** * * * **** ** ** **
** ** * **** * **** * ** ***** * * *** * * * * *
** * * * ** * *** = a+b;
* * * * ** ** *** * *** *** = (float)a/total*100;
* *** * ** * ** * * *** *** = (float)b/total*100;
* * * *** **** ***
***** * * * ** ** ** ** *** * *** * ** passed);
** ** ** * **** **** *** * ** * ******** * **
** * ** * ** * ** ***
***** * * **** ** * * 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** **** * **** *** **** a,b;
**** ** * * * * ******* passed,failed;
*** * * * *** *** ** * * ** total;
* * ** ******* * **
** *** *** *** ** ** ** * * ****** *** * * * ** ** *
* * ** ****** ***** ** ** = a+b;
* * ** * ** * *** *** = (float)a/total*100;
*** *** ****** ** ** * = (float)b/total*100;
***** * **** * ** * *
** * * * * * ** ** * * * ** **** ** passed);
** ** * * * **** **** ** * * ** ** * **
* * * ** *** * * * *
** * * * **** * ** * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** *** * **** ** a,b;
**** *** ** * ***** passed,failed;
* * ** ** ** * total;
* ***** * * ***
******** *** ** ** * * * ** * ** * * *********** * ** *** *
* *** *** ** * * *** * * = a+b;
** * * * * *** * ** = (float)a/total*100;
* * * ***** * * * = (float)b/total*100;
* * * **
* * * * ** * * * ** * * ** *** * passed);
* ** ** ** *** *** **** ** * ****** * *
*** *** * * ** * ** *
* * * * * ** * *** ****** **** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** ** *

int main()
{
* *** * * *** ** * * pass,fail;

* * *** * * ** *** ** *** ** * * * ** * ** * * ***** * ** *

* * *** *** * ** ***** * ** Ratio: ** * *** **** * **
* * * * * ***** * * *** * * *** ** Ratio: * * ** * * **** *

* * *** *** *** 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** * * * ** *** *
int main()
{
* **** * ** * * a,b;
** * * *** * ** ** ** **** * * * * ***** ** * *
* ** ** * ** *** ****** ***** * *** Ratio: * * * * * **** * ***
**** ** *** * * ******* ** * * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** *** * **
int main(void)
{
** * *** *** ** * ** a, b,success, fail ;
* *** * **** * * * **** *** **** * * * **
* ** * ***** ** ** *** **** * ** **** ***
**** ** * * * ******* ** ** **** *
* *** * * * * *** *** * ** * *** Ratio: %g%%\nFail Ratio: * ** success, fail);
* * ** * ** ** * *** 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
*** * **** * ** *** a,b;
*** ***** ** * ** * ***** ** **** *** * *** ** **** *

* *** * * **** * ******* * * ****** Ratio: ****** **** ****
*** ***** ** ** *** ** * ** Ratio: **** ** * * *** * *

** *** * * * * **** * * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** * * * ******
int main()
{
* * ** * * ** * ******** a,b;
* * ******* *** ******* * * * *** * * * ** ** * * **
*** * ********** * *** * * * * * *** * Ratio: * * ** * * **
*** * * *** * *** * * ** ** * * **** Ratio: %g%%",100*(b/(a+b)));
* *** ** * ** ** * ** * 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * * ** * * **
int main()
  {
** * ** *** * *** * a,b;
* **** **** * ***** *** * * * * ** * ** ****
*** * *** ** * * ** ** **** ** Ratio: * ** * *** * *
* ** * ****** * * * *** * Ratio: ** * * * ** * *
** ** * ***** **** * * * 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.24
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users