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Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 12.3k views

86 Answers

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Hidden content!
#include *** ** ***

int main(){
** * *** ** * * * ** ** a,b;
* *** * ** ** * **** passed,failed;
* *** * ** ** total;
* * ** * * * *** *
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** * * * * ** **
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* *** ** *** ** * * * * * * * Ratio: ** ** *
* *** ** * ** ********* *
* * ** ***** **** * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
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* *** *** **** * ** **** * * * passed,failed;
***** * ** *** **** total;
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*** ** * **** * * * * ** * * * * * * * **
* *** ** * * *** ** * **
** **** * ** * ** * * * * 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** ** * *** * *** ** * * a,b;
*** * * * * * **** *** * passed,failed;
** ********* * * * * total;
* * * * * * *
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** ** ***** * *** * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** ** * **** * *** * * a,b;
* * * * ** * **** * ** * passed,failed;
* * * ******** ****** total;
** * * **
* *** *** ** *** ** * ** * ** * **** * ** ** * * *
******* ** *** *** = a+b;
***** * ** ** *** *** ** = (float)a/total*100;
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** *** ***** * * ****** *
** ******* ** * ******* * * * ** * * passed);
* ** *** ******* * **** * * * * * *** * *
** ***** * * **
** *** ** * * * ** ******** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** ** ** * *

int main()
{
* ** **** ****** *** * * * pass,fail;

** * ** *** ** *** * * **** * * * **** *** ****

*** * ** ******* ** * ** *** ** Ratio: *** * **** ** ** *
** ***** * * ** * * Ratio: *** ** ** ** * *** **

** **** ** * ** ** **** 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** ** * ** ****
int main()
{
* * * ** ** * * *** a,b;
* ******* * * * ** * * ** * * * * * *
* * ***** * **** * *** ** ***** *** * Ratio: ****** ** *** * *** * *
***** ** **** *** * *** ** *** * * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* *** * * *
int main(void)
{
* ** * * * **** ***** * ** a, b,success, fail ;
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*** * ** * * ** 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* **** * * ** *** *** a,b;
* * ** *** * ** ***** * ** ** * *** ** * * ** ** * * **

* **** * * * * *** *** *** *** * Ratio: * * * ** ** * *
**** * * **** ****** ** * * Ratio: ** * * ***

** ** * **** * ** **** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
*** ** ** ** ** * *
int main()
{
** ** * * * * *** *** a,b;
******* ** * ** *** * * **** * ** **** * **
* *** * * * **** ** * *** * * **** Ratio: **** * **** ** * *
* * * *** ** ******** * * **** Ratio: %g%%",100*(b/(a+b)));
** * * * * * ** *** * 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * *****
int main()
  {
* * * * *** * * * ****** *** a,b;
* * **** ** * * *** * ** *** * ** * * *** *** ** ** ** *
* * * * * **** ** * * * * * * Ratio: *** * * **** * *
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* ** ** ** *** * * ** *** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
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