3 like 0 dislike
13.3k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 13.3k views

86 Answers

0 like 0 dislike
Hidden content!
#include *** * * *

int main(){
* *** * * * ** ** * * * a,b;
* *** ** * ** * passed,failed;
* * * * * ***** ** *** total;
* *** **** ** *
* *** * ** *** * **** *********** ** *
*** ** ** ******** = a+b;
** ** * * ** * * = (float)a/total*100;
** **** ** ** **** ** ******* * = (float)b/total*100;
* * **** ***** * *
* * *** * **** **** * ** *** *** * * Ratio: %d%%\n", passed);
**** *** ** * ** *** ********* * * *** * Ratio: * ** **
* * * * * * * * *
** * *** * ** * * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** * * *** ** * * * ** a,b;
* * ** * ** * * * *** * passed,failed;
** * ** *** * * *** total;
* * ** * ** * *
** *** * ** ** ** ** * * * ** ** **** ** ** ** * *
** * * * * ** *** ** = a+b;
*** * **** *** * * ***** = (float)a/total*100;
* ***** * **** * * * *** = (float)b/total*100;
** * * * ** * * ***
** ** ****** * **** ** * *** *** ** passed);
** ** * *** * ** ** * * * * * * ** ** * * ***
** * * *** ** *** **
* ****** ** * * * ** ** 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* * * ** * *** * * * a,b;
** * ** ** * * * *** * passed,failed;
**** *** ** **** *** * total;
* ** ** * ** * *
* * * ** ** ** ** * **** ** * *** * * ***** ** ** ** *
* * *** ** * * = a+b;
**** * ** * ** * * = (float)a/total*100;
** * ** * *** * * ** = (float)b/total*100;
** * * * *** **
* ** * ** ****** ****** **** ** * ** * * passed);
* * * * ** ** * ***** ***** * ****** *
*** ** * ***** ** ** ***
* ** ********* *** * ** * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** *** ** * ******* * ***** a,b;
** ** ** * * ** ** * ***** * passed,failed;
*** * * ** ** * * * total;
** * * *** ***** **
** * ** * * * * ** * ** * ** ***** * * * ****** **** *
* **** ** * *** ** ** * * = a+b;
***** * * **** * * * = (float)a/total*100;
* ** ** * * ** *** * *** *** = (float)b/total*100;
** * ** * * ** *
* * ** * * * * ****** ** **** * ** passed);
* * * **** * * ** * * ** * ** ** * * *** ***** *
* * *** **** * ** **
*** * ** *** ** * * * * ** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * **

int main()
{
** * ** * ** *** pass,fail;

* * * ** * * * ****** ** **** * * * * * * ** ** *

* * * **** ** * *** ** * * ** ** Ratio: * ** *** * * * **** *
* * * ** * *** ** * * * Ratio: *** ** **** * * ** * *

**** ** * * ** ** ** * 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** *** * *
int main()
{
** *** * * ** a,b;
* *** * * * * ** ** * * * * * ***** * *
**** ****** * * **** * **** **** ** * Ratio: * * * ** **** * * ****
* * ****** * ** * * ** **** ** * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * *** * **
int main(void)
{
*** *** **** ** **** a, b,success, fail ;
* *** *** *** **** * * * **** * *** ** * * **
* * **** ** * ** ** * * ** *** * * * **
*** * ***** * *** * ** **** * * * *
* * **** ** ** * ** * Ratio: %g%%\nFail Ratio: *** success, fail);
* * * *** * **** * 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* ** ** * * * * a,b;
* ** ** **** * *** ** **** ** ** * * ** * *

* * ** * * * * * ** * *** * * *** Ratio: * * ** * ** **
* * * * * *** * ** * *** * Ratio: * * * ** ***

*** ** ** * ***** * * ** ** * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* *** ** * ** * **
int main()
{
* * * ** **** * ** * a,b;
***** * **** *** *** **** * *** ***** ** * ** * **
****** * * * ** * *** **** * * ** * Ratio: * ** * ** * ** * **
*** * * * *** *** ** * *** * ** Ratio: %g%%",100*(b/(a+b)));
*** * * * ** * ** **** * * ** 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
*** *** * * *
int main()
  {
** ** ** * *** * * **** ** a,b;
* **** * * * ** * * ***** * * * * **** * * * ** ****
*** **** *** * * *** * *** *** *** Ratio: * * * *** * ***
** * * * **** ** * * ** *** Ratio: * ** * * * * **
* * ** * * * * * ** **** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.45
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users