3 like 0 dislike
14.1k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 14.1k views

86 Answers

0 like 0 dislike
Hidden content!
#include * * *

int main(){
* * ** ** * ** * * ** a,b;
* * *** * ** * * *** * * passed,failed;
** * ***** ** ** total;
* *** ** *
********* * * * *** * * * * * *** * * ** ** *
** * ** * * * ** * * * = a+b;
* *** ** * ** * * * ** = (float)a/total*100;
** * * * ** * * ** * *** *** = (float)b/total*100;
*** * * * * * **
** * *** * ** * ** **** ** * * ******* Ratio: %d%%\n", passed);
** * * ******** * **** ***** * Ratio: ** *
* * ** * ***
* **** * **** **** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* * ** ** *** * **** **** a,b;
** * ** **** * ****** * passed,failed;
* ** ** ** * ** ** * ** total;
* ******* * * * ***
***** ** * ** * ****** * *** * ** * ******* ****
** *** * ** *** * *** = a+b;
* ******* ** ***** ** ** ** * = (float)a/total*100;
* ** * ******* * * * * = (float)b/total*100;
** * * *** *** ***
* * ***** *** * * ** *** * * * *** ** passed);
**** * * * *** * *** * * **** * * ***** *** *
* * * **** * *****
**** * * * **** * * 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
******* * ** * * * * ** * a,b;
** * **** * ***** * * passed,failed;
** * * ** * ***** * total;
***** ******** ** * * * *** **
** * * **** * * * *** * * * ***** *** *** ** ***** * * *
** * *** * ** * * * * ***** = a+b;
* * *** ******* ** * *** = (float)a/total*100;
**** * **** ** ** ** = (float)b/total*100;
* **** *** * * * *
* ** *** ** * ** * * ******* ****** *** * passed);
******* ** **** * * **** ** ** ** * ***** ****
**** * * * ** *
** ** ** * *** ** ** * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* * *** * * * **** * ** * a,b;
** * ** * * *** ** *** passed,failed;
** * *** *** * * total;
* *** * ** * * ***
***** * * *** * *** * * * ** * * ** * *** ** * * **
*** * * ** *** * * ** * * * = a+b;
* * * *** * *** * * = (float)a/total*100;
* * * * * ** * ** * * = (float)b/total*100;
*** * * ** *** *** **
*** **** * * * ** ** ** *** ***** *** * * passed);
** *** *** * * * *** *** * *** * ** *** **
* ** * * * ** * ** ** *
* * ** *** * **** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * **** * *

int main()
{
* **** ** ***** pass,fail;

* **** * **** *** ** *** **** * ** ** ** * **

* **** * *** *** * * ** * * ** * * Ratio: * *** * * * *****
** *** * ** *** ** ** * * Ratio: * * * ** * * *

** ** *** * ** * * ** * * 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** * ******** *
int main()
{
*** * ** ** * * ** a,b;
* * *** ** * **** * ** * ** ** **** * ** * * ******
*** * ** * ** ** ********* ** ** Ratio: *** * * *****
* ** * ** *** ***** * * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * * *** * * *
int main(void)
{
**** * **** * * ** *** a, b,success, fail ;
****** *** ** * ** ** ** * * * * ** * ** ** **
* * * *** *** * * * ****** ** * * * *
* * **** * * ** * * * *** ** * *** *
** * * * ** ** **** * ****** * ** * Ratio: %g%%\nFail Ratio: ** * ** * success, fail);
*** * ** * * **** * ** 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* * ** *** * ** *** * a,b;
** * ** ** ** * * * ** *** *** *** *** * *** *

*** * * ** * *********** **** * * * Ratio: * * * **** * ** *
** * ** * ******** **** * * *** Ratio: * **** ** * * ** *

* * * * * * * * * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * *** * * ** * ** *
int main()
{
* ** * ****** * ** * * ** a,b;
* *** ** *** * * ** * * * ** * * * *** *** **
* *** * * **** * ** * **** *** * Ratio: * * * ** ** ***
*** * * * ** * *** ** ** ** Ratio: %g%%",100*(b/(a+b)));
* ** ** ** *** * ** ** 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * ** **
int main()
  {
*** * ** ** * ** *** *** a,b;
** * * **** ** * ***** ** *** * ** ** ** **
* ** * ** * * ** ***** ** *** Ratio: ** * * **** * ***
* * * * ******** ** * ** ** * Ratio: * **** * **
* ** ** * ** *** ** ** * 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.211.215
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users