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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

edited by | 1.3k views

20 Answers

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Hidden content!
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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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Hidden content!
int *** *** *** * a){
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answered by (-122 points)
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Hidden content!
* * **** * ***

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struct student



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* * ** * ** * ** ** * grade[20];



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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
*** * ** * *** ***** i=0,j=0,k=0,r=0;
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}
answered by (-8 points)
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Hidden content!
* * * *** *****



struct Student {
* **** * ** * * grade[20];
* * * ***** **** ****** count;



};



int **** ** ** Student *s) {
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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


**** * ** ***** **** grade[20];


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};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
** ** ** * * *

** * * * **** * *

* ** **** **** ****



struct student

{

* ** ** ** ** * * ** grade[20];

***** ***** ** * * count;

 };



int * * student s);



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{

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{

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****** ** ** * * * * * = sum + s.grade[j];

***** * ** * ** * * **** = sum/s.count;

*** ** * * * ****** * *** average;

}
answered by (-102 points)
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Hidden content!
**** * * **
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*** * * * ** * *



struct Student

{
* * * * * * ******* * grade[20];
* * ****** ***** * ** * * count;

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{

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}



int * * * ** * Student s)

{
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* * * * * ***** *** * * * ** *
* * ** * ** ** ** * * = b+s.grade[k];
*** *** * ** ** * ** * = b/s.count;
* *** * * ******* *** **

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include ** ** ** *

struct student

{
*** * ** * * grade[20];
*** * ****** *** * count;

}s;

int main(void)

{
* ** ** * ** *** * * * *** * student s;
** * * ******* *** * grade[20];
* * *** * ** * ** count;
* ** ** *** ** ******** * i;
** ** * *** * * ** * ** * sum = 0;
* ** ** ** ** * * aver = 0;
**** *** * *** ** *** **** * *** * * * * * * *
* * ** ** **** * * = 1;i <= count;i++)
** * ** * * * *** *
*** *** **** *** * *** * *** * * * * ** * * * ** * * * * * * *
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*** * * ** ****** *
* * **** ** ** ** ** * = sum / count;
* ** * ** * ** * ** * ***** * ** * * *
* * *** ** * ** * ** * 0;

}
answered by (-320 points)
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