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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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int **** * Student s)

{
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* ** * ** ** * *** **** ** avg; * * * record the average
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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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Hidden content!
int ** *** * * * * a){
*** ****** *** * *** = 0, total = 0;
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}
answered by (-122 points)
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Hidden content!
** * * **** * *** *

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struct student



{



** ** *** ** *** * * * grade[20];



*** * **** * * **** * count;



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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
******** * * ** ***** i=0,j=0,k=0,r=0;
*** * * **** *** *** *** *** *** **
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}
answered by (-8 points)
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Hidden content!
* * *** * ** **



struct Student {
* * *** * * * *** ** grade[20];
* *** **** * * ***** * ** count;



};



int ** ****** Student *s) {
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}



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


*** * ****** * * * grade[20];


* ** ** * * ** * *** count;



};



int average_grade(struct Student s)

{


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}



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{
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** * ** * ******* * ** * 0;
******* ** * ** ** **

}
answered by (-157 points)
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Hidden content!
* * **** * **

***** * ** * *****

** * ** * ** *



struct student

{

* * * * ** **** grade[20];

** * ** * *** count;

 };



int ** ***** * student s);



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{

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int * * student s)

{

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** * * *** ** ** *** * ** = sum + s.grade[j];

* * * * *** * * * ** = sum/s.count;

** *** ***** **** *** * average;

}
answered by (-102 points)
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Hidden content!
*** ** * * ** * * *
**** * * * *** **
* ** * ** * ***** *



struct Student

{
* *** * ** * * * grade[20];
***** **** ******** *** count;

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int * ** ** Student s);



int main(void)

{

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}



int ** * * * Student s)

{
* * * ** ** ** ** **** k,b=0;
*** * * * ******** * ** ** ** * * * *****
** * * ** ** * *** = b+s.grade[k];
** * ** * ** * * * = b/s.count;
* *** * * ** * *** ****** ***** *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include * * * **

struct student

{
**** * *** * * * * ** grade[20];
****** ********* * * * ** count;

}s;

int main(void)

{
*********** ** * * * ** student s;
**** * * ** ** ** * ** grade[20];
** *** * ** **** **** ** count;
* * ** *** *** * i;
**** * ** *** * * ****** sum = 0;
*** * ** ***** * ** * aver = 0;
** *** * * * *** * * * *** * * ** ** **
* * * ** ** ** ****** ** = 1;i <= count;i++)
***** * * * * ** * * **
* * **** * * ****** * * ** ** * ***** * ******* ** * * ***
* * * *** **** ** ** *** * * *** * ** * **** ** += grade[i] ;
* *** * * * * ****
******* ** * * * * * * ** * * = sum / count;
* *** **** * ** * * ** ** * * ** *
** * * *** * * *** ** *** 0;

}
answered by (-320 points)
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