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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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}
answered by (-248 points)
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answered by (102 points)
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int ** *** * **** a){
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answered by (-122 points)
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Hidden content!
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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
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answered by (-8 points)
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Hidden content!
* ** * * *



struct Student {
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};



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


** * ** *** ** ** grade[20];


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};



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{


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}
answered by (-157 points)
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Hidden content!
*** ***** * *****

**** * * ** * * * * *

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struct student

{

** *** ***** * ** * grade[20];

* ** *** * * ** * * count;

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** * * *** *** * ** = sum/s.count;

** ** * * * * * average;

}
answered by (-102 points)
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Hidden content!
* * * * * * ** *
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struct Student

{
** * ** **** ****** grade[20];
** * ***** * * ** * * count;

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{

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}



int ** * **** * Student s)

{
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* ** *** ********* * = b+s.grade[k];
***** * ** ** **** ** = b/s.count;
* *** ****** ** ** * * ** ** **** *****

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include ** * ****

struct student

{
*** * **** ** ** *** * * grade[20];
***** * *** * *** *** * count;

}s;

int main(void)

{
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* ***** * *** **** * * * grade[20];
* * * ** * * * * count;
** * *** ** *** *** ** * i;
** ** ** *** * * * * ******* sum = 0;
** * ** ** * ** * * * * aver = 0;
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** *** * ** * * * = sum / count;
* ** *** * **** * *** ***** * *** ** **
** ** ***** * * * *** * 0;

}
answered by (-320 points)
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