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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

edited by | 3.4k views

20 Answers

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int ****** * Student s)

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}
answered by (-248 points)
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answered by (102 points)
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int * * ** * * ** *** a){
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}
answered by (-122 points)
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Hidden content!
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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
* *** *** ** * * * i=0,j=0,k=0,r=0;
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}
answered by (-8 points)
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Hidden content!
* * *** * ** ***



struct Student {
* * **** ** * * grade[20];
*** ** *** ** * ****** count;



};



int * * * Student *s) {
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}



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


*** * ** ** ** grade[20];


** * * * * count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
** ** * ** *** *

*** * ** * * *

** * * * * * *** *



struct student

{

**** **** *** *** **** **** grade[20];

**** * * * * ** * * count;

 };



int * * * student s);



int main(void)

{

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int **** ****** student s)

{

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*** * * * * * **** * * *** = sum + s.grade[j];

* * *** * * * * * * * * ** = sum/s.count;

****** * ***** ** ** * * * * average;

}
answered by (-102 points)
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Hidden content!
* **** * ** * *
**** ** * **** * **
**** * * **** * ***



struct Student

{
* *** * ***** ** ** * ** grade[20];
*** ** *** *** * * count;

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int * ** * * * Student s);



int main(void)

{

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}



int * * **** Student s)

{
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* * ** ** ** * * * *** * ** * *
* ** ** * *** * *** = b+s.grade[k];
* * * * * * ** * * = b/s.count;
** ** * ** * ** * *** * * * ** *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include * * ***** *

struct student

{
* *** * *** * ***** grade[20];
** * * ** * *** * **** count;

}s;

int main(void)

{
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* * *** ** * * ** * ** * grade[20];
** *** * * ** * * * * count;
* ** * * ** * **** * * i;
*** ** * ** * *** * * sum = 0;
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** ** * *** * * *** *** ** * ***** * * ** *
* ** * *** * * * * * **** = 1;i <= count;i++)
*** ** * *** ** *** **
* * * ** *** *** * ** *** ** * * * ** * ** *** ** ** * * * *** ***
**** *** * * * * *** * *** * *** ** * ** ** * * += grade[i] ;
* ** ** * * *** * * **
* **** *** ** * ** ** * ** * = sum / count;
** * * ** ** * * *** ** ** * * * ***
* * ** *** * * ** * * * 0;

}
answered by (-320 points)
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