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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

edited by | 3.9k views

20 Answers

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int * *** ** Student s)

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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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int * * ** a){
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}
answered by (-122 points)
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Hidden content!
* ** *** ** *

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struct student



{



******* * ** **** * grade[20];



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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
** ** * ** *** * * i=0,j=0,k=0,r=0;
* * ** *** * * * *** * * ********
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}
answered by (-8 points)
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Hidden content!
* * * * *** ** * *



struct Student {
* * ******* ** * ** grade[20];
** * * ***** *** count;



};



int * *** * Student *s) {
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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


*** ** ** * ** grade[20];


* * ** ******** count;



};



int average_grade(struct Student s)

{


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{
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}
answered by (-157 points)
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Hidden content!
* *** ** **** *

* *** * ***

* *** * ** **



struct student

{

* **** *** * * * grade[20];

* * ** *** * **** **** count;

 };



int * ** * student s);



int main(void)

{

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int * ** * * * * * student s)

{

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* * * * ** * **** * * * = sum + s.grade[j];

* *** * ** **** **** ** * ** * * = sum/s.count;

* **** * *** * * ** * * * average;

}
answered by (-102 points)
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Hidden content!
* ** * * * * *
** * * ***
* ** ** **** *



struct Student

{
* * * * * * * * * *** grade[20];
* ** * **** * **** **** ** count;

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int * *** * * Student s);



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{

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}



int ** * *** Student s)

{
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* ** ** * ** * * ** * = b+s.grade[k];
** ***** **** ** * = b/s.count;
* * * * * * * ******** * * * ** *** * **

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include * ***** * ***

struct student

{
** *** ** * * * ** ** * grade[20];
*** * * ** * *** count;

}s;

int main(void)

{
* * * * * * ** ** ** student s;
**** ****** * * * grade[20];
* * *** * * * ** *** * ** count;
** * * **** * ** **** i;
* ** * * *** ****** ** * sum = 0;
**** * *** ** * ** ***** aver = 0;
* ** *** **** **** ** * **** **** **
** * **** * ****** * = 1;i <= count;i++)
* * * **** ** *
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** * ** * * *** * * * * * ** * * *** * * * += grade[i] ;
*** * **** ** * *
***** **** *** ** * * * = sum / count;
* * ** * * ** ***** ** *** * * *
* ** * * * ** ** * * 0;

}
answered by (-320 points)
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