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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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int ***** * *** Student s)

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}
answered by (-248 points)
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answered by (102 points)
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int ** * * ** a){
* * * ** * * ** = 0, total = 0;
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}
answered by (-122 points)
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Hidden content!
* *** ** * ** *

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struct student



{



*** * ** ***** * * * grade[20];



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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
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}
answered by (-8 points)
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Hidden content!
* *** ******* ** *



struct Student {
** *** ** ** ** ** * grade[20];
* * * * *** * *** * * **** count;



};



int ** ** **** Student *s) {
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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


* * ** **** * *** * * * grade[20];


* ** * * * * * count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
*** ** * ** * **

* ** ** ** *** ***** *

* ** ** ****



struct student

{

** **** *** * * grade[20];

* *** ** ***** * * ** count;

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int *** ** student s)

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**** * ** ** ** * * * = sum + s.grade[j];

* * * ** * * *** ** *** = sum/s.count;

* ** * *** * * ** ** ** * average;

}
answered by (-102 points)
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Hidden content!
**** * * * ** * * * *
* ***** * * ** * * *
* * ** * ** * **



struct Student

{
** ** * ********* ** * grade[20];
* ******* ** * *** * count;

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int main(void)

{

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int * **** * * ** Student s)

{
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** * *** * * * * * ** * * * = b+s.grade[k];
* * * * * * * ** = b/s.count;
****** * * ** * ** ** * * * *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include * ***** * * *

struct student

{
** ***** *** *** *** * * * * * grade[20];
**** ** **** **** ** * *** count;

}s;

int main(void)

{
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* * * * ***** * ** ** * grade[20];
** * ***** **** ** * ** ** * count;
* ** ** *** * ** i;
* * **** * * ** *** sum = 0;
** ** * ***** * * * * ** * * aver = 0;
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* *** * * ***** *** = 1;i <= count;i++)
* ******* *** ** * ****
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* * **** ** * * *** **
** * * *** * * *** = sum / count;
***** * * * ******** * ** * ** ** * * *
**** * *** * ** ** **** 0;

}
answered by (-320 points)
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