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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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20 Answers

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int **** ****** * Student s)

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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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Hidden content!
int * * **** ** * a){
**** *** * **** ** = 0, total = 0;
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}
answered by (-122 points)
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Hidden content!
* *** *** ***

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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
** * ** ***** * * ** i=0,j=0,k=0,r=0;
** ** ** * ** * *** ** ** ***
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}
answered by (-8 points)
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Hidden content!
** *** * *



struct Student {
* * * * ** ** ** * *** * grade[20];
* ** *** *** *** ** *** * * count;



};



int * ** ** Student *s) {
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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


** * * * **** ** * ** grade[20];


* * ***** * * * count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
* * ** * * *

* *** * * *

* * * ** * *



struct student

{

*** **** * *** ** grade[20];

* *** ** * * * *** * * count;

 };



int ** * * student s);



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{

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{

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** * * * * * ** * = sum + s.grade[j];

*** **** ** ** **** * = sum/s.count;

** **** ** ** ** *** *** average;

}
answered by (-102 points)
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Hidden content!
*** * * *** **
********** * **
***** * ** **



struct Student

{
* ****** ***** *** grade[20];
*** ** * * ** *** * count;

 };



int ** Student s);



int main(void)

{

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int * ** * Student s)

{
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* * * ** * * * **** = b+s.grade[k];
*** * * * **** * * = b/s.count;
*** ** * * * ** * * **** * ** **** * *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include ******** *

struct student

{
** ** ** * **** *** grade[20];
* * * * ** ** * count;

}s;

int main(void)

{
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* * * ***** * * **** ** count;
* * ** *** *** * ** * i;
* * * ****** * * * * ** * sum = 0;
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* * ********** *** **** * * * = 1;i <= count;i++)
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* *** ** ** ** * *** * * * * *** * **** * * * ** ****** * ** * ****
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** * ** * ********* *
* ** * * * *** ** *** * = sum / count;
** * * * * *** * * **** * * ****
*** ** * * * * ******* 0;

}
answered by (-320 points)
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