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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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20 Answers

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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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int ** ** * * ** a){
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}
answered by (-122 points)
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Hidden content!
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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
*** **** * ** * **** * ** * * i=0,j=0,k=0,r=0;
* * * ** ** * ** ** *** ***
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}
answered by (-8 points)
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Hidden content!
** * * * * *



struct Student {
** ** ********** * * ** grade[20];
** * * ****** ** ** * count;



};



int ** * * ** *** Student *s) {
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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


* *** * ** *** grade[20];


****** ** ** ** * count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
** * * *** * **

* ** * ** ** * **

*** ****



struct student

{

* * ** *** ** ** ** grade[20];

* * * * * * *** ** * * count;

 };



int ** * * * * student s);



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{

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int * ** * ** student s)

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*** ** * * * * ** * = sum + s.grade[j];

** * *** ** ** *** * * = sum/s.count;

** *** ******* * **** *** average;

}
answered by (-102 points)
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Hidden content!
** * ***** * * ** *
******** ** ** * *
* ** ** * * ***** *



struct Student

{
***** * * ** * * ** * *** grade[20];
** **** ** * * * * * count;

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int * * * * *** * Student s);



int main(void)

{

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int ** ** * * * Student s)

{
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** ** * *** * * * * *** = b+s.grade[k];
* * * *** * ******** = b/s.count;
*** * ****** ** ** * * * ** * *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include * * ***** *

struct student

{
* ***** * * * * * * * * * grade[20];
* * ***** * * **** * * count;

}s;

int main(void)

{
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***** * ** * * ** * * grade[20];
** ** * **** * ****** * * count;
****** * ** ** * * *** ** i;
* * * *** ** * * **** sum = 0;
* **** ** **** * *** *** * aver = 0;
* ** ***** ** * ******** * * ** * * *
* ** ** ***** * ** * = 1;i <= count;i++)
** ****** ** *
* * * * * ** ***** * * ** * ***** ***** * * *** * ** * ** *
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* * ** * * * *** ***** *
** ** * *** **** ********* = sum / count;
* * **** * * ** ** * * **** ** * ***
*** * **** * * * **** ** 0;

}
answered by (-320 points)
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