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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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}
answered by (-248 points)
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answered by (102 points)
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int ** *** ** * * *** a){
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answered by (-122 points)
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Hidden content!
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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
*** ***** ******** * * **** i=0,j=0,k=0,r=0;
* ** * * * * ******** * *** *
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}
answered by (-8 points)
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Hidden content!
**** ** ** *



struct Student {
* ** * * *** * * * ** grade[20];
****** ** **** ** * **** count;



};



int *** * *** * * Student *s) {
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}



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


** * * * * *** *** * grade[20];


** * ** **** *** count;



};



int average_grade(struct Student s)

{


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}



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{
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** * * ** * *** * **

}
answered by (-157 points)
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Hidden content!
* ***** * ***

* ** * * * * *****

*** ** ** **** **



struct student

{

* *** * * ** *** * grade[20];

* * * * ** * ** count;

 };



int ** *** student s);



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{

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}



int * ** ** student s)

{

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** * * *** * * *** = sum + s.grade[j];

** ** * * * * * * * **** = sum/s.count;

** ** * * * * *** *** * *** average;

}
answered by (-102 points)
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Hidden content!
** * * ***** * *
*** ** * *** * **
*** * ** **



struct Student

{
* **** **** * ******* grade[20];
*** ** ***** *** * *** ** count;

 };



int * * *** ** Student s);



int main(void)

{

 int i;
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}



int * ***** Student s)

{
* * * * **** * * * ** * k,b=0;
** * *** *** * **** *** **** * ***
* ** * ** ****** ** = b+s.grade[k];
* ** **** * * *** = b/s.count;
**** * *** ** * ********** * ** ** ***

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include ** ** *

struct student

{
** *** *** * ** * * **** * grade[20];
* ** **** * * ****** * count;

}s;

int main(void)

{
* * * * * ** **** * * **** ** student s;
** *** * * * * ** * grade[20];
***** **** *** * ******* * ** count;
* ** * * * ** ** ** ** * ** i;
**** * * * * ***** ** sum = 0;
** ** * **** ****** * * * aver = 0;
* * ** ** ** ** **** *** * ***** **
* *** * * ** * *** * = 1;i <= count;i++)
** ** ** ** *** * *
** *** *** * * **** *** * * * * * * * **** * ** *** * ** * ****** * *
** * * * * * * ** *** ** ** * ** ** *** * * *** ** += grade[i] ;
* ** ** * * * * * * **
* * * *** * * ** ***** = sum / count;
** * ***** * * * * * ** * * ** * ** * *
** ** * * * * * **** ** * 0;

}
answered by (-320 points)
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