0 like 0 dislike
2.7k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 2.7k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
** * * **** * * ** ** * **** * *
** * ** * * * * * *** * * **** ** *

    {
* *** * **** ** **** * ***** * * * * *
* * * **** **** ** * ********** ********
*** * * * * ** * * ****** * ** * ** * ** * ***** ** * ***** ***** ** *
*** ****** * ** *** ** **** * **** * * ** ** * ** *** *** ** ** * ** * ** * * **** ** * ** * = a[n] + b[n];
**** *** * * ** * *** ** ** ** * * ** * *** **** * * * * * **** * * if(a[n]+b[n]>='10')
** ** ** * *** * * * * * *** * ** ** ** ** * **** * ** *** * ***** ** *
** * ** * ** * *** ** ** * * * ** ***** * ** ** * * * * ***** * *** * ** * * * ** = a[n] + b[n] - '10';
** * ** ** * * ** * * * ****** ** *** *** **** ** *** **** * * ** * *** * ****
* ** * *** * * ****** * * *** ** *** * * * ** *** *
* ** * ** *** * ** * ** * * * ***
** ***** * * * * * ** ******** ** * * ** ** if(t == 1)
** *** ** * * * * * * ** ********* **** *
* ** * * * * * ** **** * * ** * * ****** * * * * * * * ** * ** ** **
* ** ***** *** * * * * *** *** ** *** ** ** ** *** ** * * * * ** * * * ** ** ** * **** * *** = a[n] + b[n] + '1';
* * * * ** ** **** * * * * * * * ** ** ****** * * *** ** ** if(a[n]+b[n]>='9')
******* * * * ***** ** * * * ** * ** *** * **
*** * * * ** ** * * * * * *** * * *** * ****** ** * ** ** ** ** * ** ** ** **** ** = a[n] + b[n] - '9';
* * ****** * ****** ***** * **** **** **** *** ** ** * * ** ***** * ****** * ** * * *
* * ** * ** ** ** * * * *** * * * ** * * *** * * * * *** *** * * *
* * ** ** *** ******** * * * *** ***

    }
* *** * ***** * * * ** ** * **

    {
* * ** * ***** ** **** * *** * ** * ******** * * * * *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
*** * ** *** *
* * ** ***** *** *

int main ()

{

int * **


** * * ****** ** * ***
* * ** * * * * * * *


* ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * * * ** ***

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
*** *** *** ** * **** a[100],b[100];
* * * * * * ** ** ** ** sum[200];
* ****** **** * la,lb,lm,i,j,k;
** ** ** *** * * ** * ** * * * %s",a,b);
** ** **** ** * = strlen(a);
* *** ** ** *** * *** * = strlen(b);
* *** ****** ** ******* * * * ** **** * **** **** *
* * * * *** * * * *** * * * * ** ** * ** = a[i];
* ** ** * * * * ** *** * * ** ***** * * *** * ** *** **** *** ***
** ***** ** * * *
* * * **** * ***** ** **** * * ****** **
** ** ****** ** ** * **** * ** * ** += b[i]-48;
* ** * * ** * * *** * * * * *** * * * *** *** ** ** ****
** * ** * * ** * * * *
* ** * *** * * ** * *** * = strlen(sum);
*** * * **** ** *** * * ** *
* * ** ** * ** *** ** ***** *** ** * ** ** * *** ** * **
** ** *** * *
* * ** ** * ** * ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* * ****** * * *
* *** ** ** **





int main ()

{
a , b ;
* * * * * *** , ** * **
********** ** * ** ** , **
* * ** ** ** **** * ,a+b);
*** ** **** ** ****** 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
*** *** * * * * *** * ** *** ** * * ** *
** * * *** ***** ** * * *

    {
* ** ** ****** * * * * * * *** * * **** * *
** * * *** ** ** ** * * * ** * ** ******* ***
* * ** *** * * ** *** * * ** * ** * ** * ** ** **** ** * * *
* *** ****** *** *** * * * * * ** **** *** * * ** * * * * * ** * ***** * * *** ** * * *** * = a[n] + b[n];
* * * ** ** *** * ** * **** ***** * * * * * *** * * * ** if(a[n]+b[n]>=10)
* * * * * * *** ** ******* ** *** ** * * ** * ** * *** *** **
* * * ** * * ***** ** * * *** *** * * * * * *** * * * **** * * * * * ****** * = a[n] + b[n] - 10;
* ** *** * * * ** **** ** * * * **** *** * * ** * ******* *** * ** ** *** * *** ** **
* **** * ** * *** ***** ** *** ****** * ** * * ** ** **** ** * * * *****
* * * ***** ** * ** ** ** *** * ******** ****
*** ** * ** * *** **** *** *** ** ** ** if(t == 1)
* ** *** *** **** * ** ** * **** ** *
* ** ** ** ** * * * * * ** * ** ** * ** **** * ***** **** ** ***** * *
** ** * * ** *** * **** * * * **** ** *** * ** * * * ** * * ****** * * * * ** * = a[n] + b[n] + 1;
*** * ** * *** * *** **** *** ** * * *** * * ** ** * ** ** * *** if(a[n]+b[n]>=9)
* * * * * ** *** *** **** **** *** ** ** * *** * **** ** * ** *
** *** ** * * * *** ** ** ** *** * **** *** **** *** * * **** * ** * *** ********* * = a[n] + b[n] - 9;
* * ****** * ** ***** * ***** ******* ** * * ***** * ** * ** **** * ***** *
** *** * * * * ** * ** * * ** ******* ***** * * * ****
** * **** * * * ** * *** ** * * * * ****

    }
* * * *** * ** ********** * ** ** *

    {
* * ** *** *** *** ** * **** * * * *** * * *** ***** *** * ********

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* *** * ***** ** * ** data[2];
* ** * * *** * ** * sum;
* *** * *** *** *** ** * i;
** * ** ** * * *** *** * ** ***
*** * *** * **** * ***** *
**** *** ** * ** * * ** * * ** **** * ******** ** * * * *** *
****** ** * ** *** * *
** * ********* * * * * * ****** * ***
* *** * **** ** * ** ** * **** * ** * **
** * ******* ** ** *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * ** ** *** *
* ** * ** ** *** *
* ** * * **** *
* *** ** * ** * ***** *







int * * *

{


** *** int * * ** * *
* * *

***** ** * scanf * *** * ** *** ** * *
* ** *** *

** * * * * *** while (a[i]!= ' ')

{
*** *** * *

** * * * i++;
* ** ** ***

** ******* scanf * * * ** * * *** * * * ** * *

* * ** *

}


*** ** ** scanf ** * ** * * **


** *** ** * * while ** ** ** * * ** * * ***
* * * **

* * *** {
*** * * * * * ** *** ** ***

* * * ** *** * ****** j++;
** * * * ** **** ***

* * * **** * ** ** * * * scanf * * * * ** * ***** * **** * ***

* ***** * * **

* * ** ** }
* * * * *

}
* ****

***** * * for (i = 0,j = 0;;i++)
* * ***** *

* * * * ** return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include * * ****** * *

int main()

{
*** * ** *** ** a,b,c;
*** ** *** * **** * ** ** **** * ** * * * ****
** * * * * ** = a + b;
* *** * ****** * * * * * * *** * *** *
* ** ** * * * * * ********* * ***
* ** ** * * * * **
* *** * * ** ** **** ** *
**** **** *** *** * 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include *** ** *

int * * y=999999999;

int main()

{
******* * ** ** * * * * * ** ** * *
* * ** ** * ****** *
* *** * ** * *** * ** ** ****** * ***

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** *******

int main(){
** *** ****** * * **** a,b,c=0;
** * ****** * **** * ** * ** * ** * **
* *** * * * ** *** ****** *** * *** **** ** ***
** ** ** ** * ** * * * ***
* ** * ** * **** * ** ** * * ** * * * *
* *** **** ** * * * * * 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.192
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.9k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users