0 like 0 dislike
4.2k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 4.2k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * ***** ** ** * * ** ** ****
* ***** *** **** * ** ** ** ** * **

    {
** * * * *** * *** * * ** ** * * ** ** *****
*** * * *** * * * **** ** *** *** * ** *
*** ***** * * * * * * *** * *** * * ***** *** ** * **** * * * * * * * ***
*** *** * *** ** * * *** ** ** ** *** *** **** * * *** ** * * * ** * ** *** ** ** * = a[n] + b[n];
***** ** ** * **** * * *** * * * ** ******* ** * * ** *** ** * if(a[n]+b[n]>='10')
** ** ***** ******* ****** *** *** * * *** *** * **** *** **** *
* *** * * ** *** * * * ** * * ** * *** *** * ** * * * * * * * * * **** ** * ** = a[n] + b[n] - '10';
***** * ** ** * * * ** * **** * * * * * * * * ** * * ** * *** * **** ** * *
* * *** * ** * * * ** * * *** * * ** * * * * * * * * * * *
** ** **** * ******** ** ** * * **
** * ** * * * *** ***** ** * ** if(t == 1)
** * ** ** ** * ** * * * * * *** **
* * ******** * ** * * **** ** * **** * * ** ** **** * ** ********* ***
** ** * * * ** ** ** **** ** ** * * ** *** ** * ** ** * * ***** * ***** *** ** *** = a[n] + b[n] + '1';
* **** ** ** *** ** * ***** ** * ** * * *** * ******** * * * if(a[n]+b[n]>='9')
* * ** * **** * ****** ** * ** ***** *** ** * * *** * *
*** *** *** ** **** * **** **** ** * *** ***** *** ** ** * * * * ** * * **** * ** ** = a[n] + b[n] - '9';
* ** * *** * * * * * ***** ***** *** * ****** ** * ** ** ** * ** * **** * * * * * **
*** * **** * * ** ** ** *** * ** * * ** * * * * ** * ** * * ** *
** * * * ** * * **** ** * * ** **** *

    }
******** ******* * * ** * ****

    {
* * * * * *** ** * * * *** * ** * ** * * * * ** ** *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
******** **** ** *
**** *** *** *** *

int main ()

{

int * *


** * * * * * * * ** ** *
* * * ** * **


* 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** ***

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
* * * **** *** ** * * * a[100],b[100];
* **** ** * * sum[200];
* **** * * ** * * ** la,lb,lm,i,j,k;
* * * * * * * *** *** * %s",a,b);
**** ******* * *** * = strlen(a);
*** ** ** ** * * = strlen(b);
** * * *** *** * **** * * ** * *
**** * * * ****** **** * * * ** * * * ** *** = a[i];
** * * ** *** * ** ** ****** * * *** ***** * **** **** ** *
* ******* ***** ** * *
* ** * ** * ** * * ** * ** **
** ** * ** * * ***** ***** *** ** ****** ** * * += b[i]-48;
*** *** * * *** ** ** ** * ** * **** **** ***** ** * *** *** *
*** * ** *** ** *
** * * ** *** * ** * * ** * = strlen(sum);
*** **** ** * * * * *** * * ** * *****
** * ** * ** * * ** * ** ** * **** * ** **** * ** ** **
* ** ******** **** *** *
*********** ** ** * * * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
** * * * **
** * * * ****** *****





int main ()

{
** a , b ;
* * * * * ** , * * *
* * *** * ** , *
*** * * *** * ,a+b);
* *** * *** * * ** * 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* ** ** * ** * * * * * *** * ** * * ** **
* * * * *** * ****** * **** ** **

    {
* * * *** * ****** ** * ** * ** ** *
* * *** * * * * * * * * *** * **** **
** * **** ** *** *** *** ** * ***** * ** *** ** * * ** ** * * * ** * *
** *** ** **** *** ** *** * ***** ** * *** * * * *** ** **** * * * *** * **** * ** = a[n] + b[n];
* * ** * * * **** * ***** * * * * **** ***** *** ** * * * * ** if(a[n]+b[n]>=10)
** * * ***** **** ** ** ***** ** * * * ** **** * ** *
* ** ** * ** *** * * * *** * * ** *** **** ******** * * ** ** * ** * ** * * * **** * ** * = a[n] + b[n] - 10;
** ** **** ******* * ******* * *** ** ** ** **** * * * * * * * ***** *** ** ** * ** ** * *** *
* ** * ** ** * * * **** * * * *** ***** ******* ****** * *** *** *** *
** * * ** * ** ** * * **** ** * ** * **
*** * * *** * ** * *** ** * * * * * * if(t == 1)
* *** * * ** **** ** *** * ** *** ** **
*** ** **** ** * ** ** * * *** ** **** **** * * *** * **** *****
** * ** *** ** **** **** *** ** *** * *** *** * * * ** * ** *** **** * * * ** ** = a[n] + b[n] + 1;
* * ** * ** * * ** **** * * *** * * ** * ** ****** ** ** * * ** if(a[n]+b[n]>=9)
* *** ** ** * * *** * ******* * ** *** *** *** * * * **** * *
******** * ****** * *** ** ** *** * * * **** * ** *** ** ** ** * ** ** * * * * *** ** ** ** **** = a[n] + b[n] - 9;
* * ** * * * ** *** ** **** * * * ** **** ** * * * * * * * * * ** * * * * * *** *** * *** **
** * ** *** * ** * * * *** **** * * * ** * * ** * **** **** * * * *
* * * * * ** ** *** * *** *** ** * * ******

    }
**** * ***** ** ***** ** * * *

    {
* ** * * ****** ** **** * * ** * * ****** ** * * * * ** * ***

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
**** * ** * ****** data[2];
* *** ** * *** * * sum;
* ** ** * * ****** * i;
* ** * ** * ** ** **** ** * **
** **** * ** * * * **
* ** * * ** ** * * ** ** * **** * * ** * * ****** ** * ** * * ** * ***
** * * ** * **** *
****** * ** * ** * * ***
* * ** ** ** ** * ** ** * * * ******
**** * * ** ** **

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * **
* * * ** ******
** * ** * * *
** * **** * * ***







int *

{


***** * **** int * * * * ** ***
** *** *

** ** * scanf ** ** ** ** ** * ***
***** * *

*** *** * * * while (a[i]!= ' ')

{
* ** * ** *

* ** i++;
* **** *****

******* ** * scanf * * **** ** * * ** *** * ** *

** * * ** **

}


*** * * * scanf * ** ** * *


** * **** * while ** * * * ** ** * *
*** **** **

*** * **** {
* ***** * *** * *

* * *** ** **** **** j++;
* *** * ** * * * ** * *** *** * ***

** * * **** * * * * *** scanf ** * * ** * **** ** **** * **

**** ** ** ** ** *

** * * ** * *** }
* * * *

}
* ** * ***

* ** * * *** for (i = 0,j = 0;;i++)
**** * *

* * * * ***** return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include * * * ***** * *

int main()

{
* ****** * * * * a,b,c;
* * * *** * * *** * *** * ** * * ** * **
*** * * * * * * = a + b;
* ** ** * * ***** *** * ** * **** * *** * ** ** * ***
** * ** ** * * * ** **** * *****
* *** *** * **
** * * * ** * ****** *** * *
** * *** ** ** *** *** ** * 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * ** * ***

int ** * y=999999999;

int main()

{
* ** * *** * * * ** ** * * * **
* *** * * * ** ** * * *
** * * ** ***** * * * *** *** *** * **

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ***** * * *

int main(){
* ** * ** ** ** * **** *** a,b,c=0;
* ***** **** *** * *** * * *** ** * * *
* ** * **** * * * * ** * *** * * *** * * ** *
** ***** * * * ** ** * ** **
* *** * ** * ** * *** * *** ** * * ** **** **
* * * * * * **** * * 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 14k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users