0 like 0 dislike
479 views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 479 views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
**** * ** ****** * ** * ** ** *
* * * ** * *** * ***** *** **

    {
** *** ** *** **** ****** *** ** * ** ****
**** ** * **** ** ** * **** * * *** * *** *
* * * ** *** * * ** * *** * * *** ****** ** * * * ** *** * ** *** * ** *
** * *** ** ** **** * ** ** * * * * *** * * * * * **** * * ** ** * * *** *** = a[n] + b[n];
**** * *** * * * * * ** * * **** * * ** ** * * * **** ** if(a[n]+b[n]>='10')
** ** ***** * *** *** ** * * * ** * ** * ** ** ** * ***** * *** *******
* ** **** * * ***** *** **** ***** *** *** * ** ** ** * * * *** **** ***** ** * *** ** * *** = a[n] + b[n] - '10';
** * *** *** * * * * * *** **** * * *** ** * * ** * ******* *** * * **** * *
** **** * * * **** ** * * ** * ** ********* * * * **** ***
** * * *** ** ** ** * ** ** ** ** * * ***** * * * *
*** ** * * *** * ** **** * *** *** ** * * ** if(t == 1)
* ** * ** *** ***** ******* * ** * * * ** * * * ** ***
*** * *** * *** ** * ** * ***** ** * * *** * ** ** * * * ****** * * ** ** * * * * * *
* * * ** ** ** ** * ** * * *** * **** **** * ****** * **** *** * * * * ** ** *** = a[n] + b[n] + '1';
* * * * *** **** ****** * * * *** ** ** * ** * *** ****** ** *** * if(a[n]+b[n]>='9')
* ** * * *** * **** * ** ** *** ** **** * *** * * * * ** ** *
*** * * **** ** * *** **** * ** * * *** * **** *** * * ******* * ** * * * *** = a[n] + b[n] - '9';
* * ** * * * ** * * ** ** ** *** * *** ** ** * * ** ** ** ** ** * ** * *
* **** *** * * **** * * ** ** *** **** * ** ** ** *** * ** ***** * *
* * ** * * ** ** *** * * *** ** * * *

    }
* *** * * * *** ** **** **** *** *

    {
* **** *** ** * * * *** * * **** ***** ** ** *** ** * * *** * * *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
**** *** *** *
** * ** **** **

int main ()

{

int


* * * ** * * * ******* *
** * * * * * ** *


** ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * * * **

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
***** ** ** * *** ** a[100],b[100];
**** * ******** * * * ** sum[200];
** * * * * * * la,lb,lm,i,j,k;
* ** * ** * ** *** * ** %s",a,b);
** ** ** * **** **** * * = strlen(a);
*** * * ** ** * *** * * = strlen(b);
* * **** * *** * * * ** ******* * * *
** * * ** ** * * * *** * * ** **** * ** * * = a[i];
** ***** * * * * * **** *** * **** ** ** * * ** * *
** ** * ** * ** * *
** * ** * * ** * * ** *** * ** *
*** * * * * * * ** ** *** * ** * * * * += b[i]-48;
*** ** * ** * ** **** * ** ** * * ** ** ** ** * * ***** *
* * * *** **** ** *
** **** ****** * *** = strlen(sum);
** * ** * * ******* **** * * * * **
**** *** * ** **** * * *** * * * * * ** * **** * ****** *
* *** ** * ** ** *
* * * * * ** **** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
*** * **** **
** *** ** **





int main ()

{
** * a , b ;
* ******* ** *** , * *
* * ** * ** ** , * * * *
* *** * * ,a+b);
** * * ** * * *** ***** ****** 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
** ****** ** ****** ** * ** * * * ** ** **
* ****** * ** **** ** **

    {
* * ** ** * * ** * * * * ** * ** ** ****
* * * ** * ** ** * * * ** * **** * ** ** *
* ** * * **** ** ****** * * *** * *** * * ***** * ** * *** *** * ** *
* * * ** * ** ** * *** ***** * *** * *** * **** ** * * *** ** ** * ** **** ** * = a[n] + b[n];
*** * ****** *** ***** * * * ** ** *** **** **** * ** * * * * if(a[n]+b[n]>=10)
*** *** ** ** * * * * * * * ** ** ** ******* * *** * * ** ** * ** ***
* * ** ***** *** *** ** **** ** * * * * * ** ** *** **** ** * * ** * * ******** * * ** * * = a[n] + b[n] - 10;
**** * *** * ** * ******* ** * * * ** **** *** * * ** ** * ****** * * * *** * *
** * ** * * **** * **** ** * ** * ** * ** ** * *** ** ***
* **** * ** ****** ** * * * *** * ******** * **
** **** * ** * ** ** * * ** ** *** *** *** * if(t == 1)
** ** ** * ** ** * * * * * *** * **
* * **** * *** **** * ****** *** ** * ** * * **** **** * ** * *** * *******
*** ** ** * * * ** * * ** * ** * *** ** ** * ** ** * *** **** ** ** *** = a[n] + b[n] + 1;
* * * * ** ** **** *** ** * *** ** * * * *** **** if(a[n]+b[n]>=9)
* ** ***** *** **** * *** * ** * * ******* *** ** ***** **** ***
****** ** ******** * * * ** ** * ** * ** ******** * * ****** ** *** * * * * * ****** * * **** * * = a[n] + b[n] - 9;
* * * **** * ** *** * * * ** * * * * * *** * * * * * * *** * *** * * ***
* ** ** * * ***** * * ** ** * * * * * * * ** ** ***** ***
* * *** ****** ** **** * ** * *** ****** ***

    }
* *** * * ** * * ** **** * * * *** *** * *

    {
***** * * * *** ** * ** ** * *** * * *** ** ** ** * * **** *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* ** * * ***** *** * **** data[2];
*** * * * ** * * * sum;
********* ** * * ** * * i;
*** * * * * ** ***** * *** ** ***
*** *** ** * * ***
* ** * ** ** ** ** * * * *** * * * * *** ** * ** * **
* ** ** ** ** ***** *** ****
* **** **** * ** ******* * ***** *
******* * ** *** * * * ** ** ***
* ***** ** ***** *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include **** * *** ***
* *** * ** * **
** ** * *****
* * * * *** ******







int * ***

{


** * ** * ** int * * * * * *
** *** ** ***

* ** * * * * scanf **** ** * * * * * *** **
*** * * * *

***** **** while (a[i]!= ' ')

{
* ** ** ****

* * * * *** i++;
** * ** ** * *

***** ** * scanf *** * ******** ** * *** *** * ***

* ** *** * *

}


* * * ** * scanf **** **** * **** **


** ** ** while * **** ***** ** ****
* ** * * ****

* * *** {
* * * * *** * * **** * **

* * * *** * * *** * * j++;
* * ** ** * * * ** *

* * ** * ** ** *** scanf **** *** * * * * *** * * * **

** **** * ** * ***

** *** * }
* * * ** * ** *

}
*** * * * **

* ** ***** for (i = 0,j = 0;;i++)
** * ** * *

***** * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include * * **** *

int main()

{
***** * * * ******* a,b,c;
* *** *** * ** * ** * **** * * ** * * ****
* ** ** * * * ** = a + b;
* ** * * ** *** * * * ** ** ** *** ** * **** * *
*** **** ***** * * ** **** **
***** * ** ******
* ** * * * ** * *** *** ** *
* * **** * * ** **** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * ** ** *

int ***** y=999999999;

int main()

{
** * * ** * * *** * * * * * *
******* * * * ** ***
** ** * ** * * ** * * ** * ** **

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ** ** *

int main(){
** * * * ** **** a,b,c=0;
** * * *** * *** ** **** * * ** * ***** * ****
* ***** ****** ** * * ** ** * * * * * * * *
*** * ** ***** * ** ****** **
* *** * * * *** ** ** ********** * *** *****
* * * * **** * 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.228
©2016-2024

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.6k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 950 views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 499 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users