0 like 0 dislike
3.5k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 3.5k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * ** * ***** ********* * * * ** **
** ** *** **** ***** ** * * ** ***

    {
* ****** ** * ** * * *** ***** * * * ** * * *
* * *********** ***** ** * *** * * **** **
** ** ** ** * * **** * *** *** ****** ** * * *** * * *** * ** * * ** **
***** *** ****** **** * * ** * *** * * * * ** * ** * * *** * * ****** *** ******** * ** = a[n] + b[n];
** * * * ** ** * * **** * *** * ** * **** * *** **** ** ** ** if(a[n]+b[n]>='10')
* * * ** * * ** ** ** * * *** ***** * * * * ** * * * * * ** * ***
* * ** ** ******** * ** * ** * *** ** ** *** ** * * * *** * * * ** * *** ** * ** * ****** = a[n] + b[n] - '10';
* * * **** * * * * ** * * * * * * **** * ** ** * * ** ****** * **** * ** *** **** * * *** * *
* * *** * * * * ** *** ** * * * *** ** ** * * * ** ** **** * *** **
* ** ***** * **** ** **** * **** ** * ***
*** * * ***** ******* * ***** * * **** * if(t == 1)
* * *** ** ***** ** ***** ** ** * * ** *
* *** * * ****** * ** * ** * * ** * * ** * ****** ** * ** * *
* **** **** * ****** ** **** **** * * * * * ** * * * * ** * * ** * * ** * ****** = a[n] + b[n] + '1';
** *** ** * * ** * * * * * *** *** * **** *** * ** ** * *** * *** * if(a[n]+b[n]>='9')
* ** * * ** * ** *** *** * * * * * ****** ****** * * ** * * * *
*** * ** * ** * * ***** * * * * ** *** ** ** ** **** ** * * * ******** * * *** ** * ***** * = a[n] + b[n] - '9';
* *** * **** * *** * * * ** ** *** * * ** ***** **** * * ** ** ** ** ** *** * * ****
**** **** ** **** *** **** * ** * **** *** *** ** **
* ***** ** *** * * ** * *** * ***

    }
* *** ** * ** * ** ** * ** ** **

    {
* ** ** ** ** * * * **** *** * * * * ** * * **** **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
** * * ******* *
** * * * * * ** * **

int main ()

{

int ***


** ** ** ** * ** *
** **** * * *** *


* * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** ****

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
* * * *** *** *** a[100],b[100];
* * **** **** * *** * sum[200];
* * *** * * **** ** la,lb,lm,i,j,k;
***** *** * ** **** * ** ** *** * %s",a,b);
** * * *** ** * * = strlen(a);
* * * ***** * * ** * = strlen(b);
** ** * *** ** * *** * * *** * ** **
* * * * * * **** ** ** * ** ** ** * * * * = a[i];
* ** * ** * **** ****** ** *** * *** ** ** * * ** * *** **
***** ** * ****** *
** * * ***** * *** * ** ********* * ** *
* * * * * * **** *** ** * * *** * **** * * *** * += b[i]-48;
* *** ** ** ** * * * *** ******* * * * ** *** * * * ** **** ** *
* * * ** *** **** *** * *
* **** * *** ** * * = strlen(sum);
** *** * * * * * ** **** *
* * ** * ***** * * ***** ** **** ** * * *** ***** * * * * * *
**** * * ** ** *** * **
* * *** * **** ** * * * ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* **** *** *
* *** *** * ** *





int main ()

{
** a , b ;
* * ** ** * ** , * *
***** * * * , * **
* ** * * * * *** **** ,a+b);
*** *** * * * * * **** 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
** *** * ** *** *** * * * *
** ********** ** * ** * * ** ** *

    {
* * ****** ** *** ** * *** * ** ** ** ***
*** ******* * * * * **** * * * ***** * ***** *
* * *** * *** * * ****** * ** * * * ** * ***** * * *** ** ** * **
** * ** **** * ***** * * * ** ** * * ** ** * *** *** * ** ** ** **** * ** * *** * * * = a[n] + b[n];
** * * * * * * * * ******* * * * * ** * * ** * ****** * * * ** ** ** if(a[n]+b[n]>=10)
*** ** ** * ** **** *** * * ** *** * * ** * ** * **** * ** *
*** *** * ******* ** * * **** *** ******* * * ** * * **** ****** * *** * **** * * *** = a[n] + b[n] - 10;
* ** * *** * * * * ** * ** *** ** * ** * * * * *** * ** * *** * * * * ***
** * *** ** ** ** * ****** ** * *** **** * * **** ** ***** ** *
* * ** * * * **** *** *** ** *****
* * * *** * ***** * * * **** ***** **** if(t == 1)
* **** ******** * **** ** * *** * *** * * * *
*** ** * * ** ** ** * ** * ** * **** * * * ** * * ****** * * * *** * *****
***** * *** * * ** ** ** ** *** * ********* ******* *** * * ****** **** * ** * * * = a[n] + b[n] + 1;
* ** * * ** ** *** * * *** ** ****** ** * * * ** * ** ** * if(a[n]+b[n]>=9)
**** * **** ****** **** ****** * ** *** ** ** ** *** * **** *
*** * ** * ** * * * *** * *** ** * **** * * * * * ** * * *** * ** = a[n] + b[n] - 9;
** *** * * * ** * * ******* * **** ** * * ** ** ** * ** ** ******* * *** * *** *
*** * *********** * ** ** * *** *** ***** *** * *** * ** *** *
* ** *** * * **** ** *** ** ***** * *

    }
** *** * *** * * * ** * * ***** ** **

    {
** * **** * * * * * * * *** *** * * * ** * ** * * *** *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* * *** * ******* * * data[2];
** ** * ** ** ** ** * ** * sum;
* * * **** * * * ** i;
** *** * ***** ** ** ** * ** *
** *** * **** ****** ***
* * * * * ** ** * * ****** ** *** * ** * ** ** * * * *******
* * * * **** * *
* *** ** * **** * *** ** * * *
* ** ** * * * ** ** ** * * * * * **
*** ** ** ******* * * *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** * ** * ** **
** * ** * ***
** * * * * *** *
* *** * *







int **

{


*** * * int * * ** * *
* * * **

** ** *** scanf ** * * * *** * ** **
*** *****

** * *** * while (a[i]!= ' ')

{
*** * *

**** * * * i++;
* * *****

** * * scanf ** * ** * * * * *** * ** *** * *

*** * *

}


* ** * ** *** scanf * ** * ***** ** ****


** * while *** **** *** * * * ** * *
* ** * ** *

** * ** * ** * {
* * * * * ** * ** *

*** * ***** * * ** j++;
*** ***** * *** ** * **

* * * *** * * * scanf * ** ** * ** ** ** ***** *** *** ***

* * **** ** ** * * * **

* ** * * * *** }
* * * *

}
** * * * *

**** * ** * for (i = 0,j = 0;;i++)
** ** * *

** ** * * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include * * ** *

int main()

{
* ** * ** * * * a,b,c;
** ** ** * * *** * * * * * * * * ** * ** ** *
*** * ** *** * * ** = a + b;
* **** * * * * * * * * * ****** * *
*** * * ** * * * ***** * * *** *
***** * * ** * * * *
**** ******* * * * **** ** ** ** * *
* * *** * * ** ** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * * *

int ** * *** y=999999999;

int main()

{
* ** * *** * * ** * ***** **** * * ****
* ** * ********** **
* * * **** ** * * * * * ******* * *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ******* * **

int main(){
***** * ** ** * * * *** a,b,c=0;
* ** * * ** * ** ** * ** * ** * ** *
* * ** * * * ***** * * * ** ** ** ** *** *****
** * * ** *** * *** * *
* *** * **** * ** * * *** *** * * * **
***** * *** * **** * **** 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.164
©2016-2026

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.9k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users