0 like 0 dislike
1.4k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 1.4k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* *** ** * ** * ***** **** **** ** **
* * *** ** * * *** * * ** **

    {
* ** * * *** ***** *** * * * ** * * ** **
* * ** ** ***** * ** * * * * ** * * ** ** **
* *** ** ** ** * **** ** ** ** ** ***** * * * * * ** * * * *** *
** * ** * * * ** * *** ** * * *** * * ** * * *** * * ** * * *** * *** * * * *** = a[n] + b[n];
** * * * **** * ** **** * ** * *** * ** ** * * * * * ** if(a[n]+b[n]>='10')
* ** ******** ** * ** ** *** *** * ** ***** ****** * * * *
* **** * * ** **** * ***** * *** ** * * ** **** * ** **** * * * * ** ** ** * = a[n] + b[n] - '10';
* * * * ** ** * ** * * * ** **** ** **** *** * ** * * ** * * *** * *** *** ** ** * ** *** * * * *
* ************ ** * * ** * * ***** ** *** ** * **** *** ** *
* *** * **** ** ****** * * * * * * * *
* **** ** * *** * ** * * *** * **** ** *** * if(t == 1)
* * * *** ** * * ** * **** * * * *** *
* *** * ****** * ** **** * * ***** * * * **** *** ** * **** * *
**** *** * * ** * ** *** *** * * * * ****** * * ***** ***** * *** * * ** * * ** = a[n] + b[n] + '1';
* ** *** ** * * * * * * * *** * * **** ** ** *** ** * * ** * * ** if(a[n]+b[n]>='9')
** ** ** * *** ** * * ***** * ** ** * ** ** * ** * * ** *
* * * ** **** * * * ** * ******** ** * * ** *** * * ** * * * * * *** ** * * ** **** * = a[n] + b[n] - '9';
* ** *** * * * ** * * **** * ****** *** ** * * ** * ***** * ** * * ** ** * *** ** * ***
** * * **** * * *** **** *** * ** * * ***** * ** * * * ** ** *
* * ** * * *** **** * ** *** * * * * * * * **

    }
* ** * ****** ** * * * ** ** * * *

    {
* * ** * * **** * ** ** ** * * ** * * ** **** **** *** **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* * * ** ***
* ** * *** *****

int main ()

{

int **


*** ** *** * **** *** * * ******* *
* * ** *** * **


** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** ** *** * ****

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
*** ** * **** ** * * * a[100],b[100];
* * ** **** ** ****** **** * sum[200];
*** * ** * ** ** *** * la,lb,lm,i,j,k;
** *** ** * * * * * ** * * * %s",a,b);
***** * ** *** * = strlen(a);
** * * * *** * * *** * = strlen(b);
** * * * ** ** * *** * * ** * * ***
*** **** * * ** ***** ** ****** ** *** ** * * ** * * = a[i];
* * * ** * * ******* * ******* *** ** * *** * ** * *
*** **** * * * * * * ***
* ** * * * * * ** ** ***** * ** *
* * * *** ***** *** ** * * ** * ** ** * += b[i]-48;
* * *** * ** * * *** *** * * ** * **** * *** ** **** * *
*** ** * * * * *
** *** *** * * * * = strlen(sum);
*** **** **** * * * *** * * ** * ** *** * * * *
* * *** **** ** ******* ** *** * * * **** * ** * * *** ******** *
** * ** * * ***** *
***** * ** ****** ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* * ** * * *
* *** ******** **





int main ()

{
*** a , b ;
** * * * * ** * * , * ****
** ** *** * ** ** , *****
** * * * * ** * ,a+b);
** **** *** *** * * 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
** ** *** ** * * *** * * * * *** ** *
**** **** * ** * * * * * ** * ** ** *

    {
** **** **** ** * ** *** **** * * * *****
* * * * ** * * * **** * * * * *** **** * ** *
* * * * ** * * * **** ** *** *** ** * * * * * ** * *** * *** ** * *
****** * * ** * ***** ** *** ********** ** * * ** ** ** * * * * * ** *** * = a[n] + b[n];
* * ** *** * ** * **** * **** * * * * ** * * * * if(a[n]+b[n]>=10)
** * ** * ** ** **** *** **** * * * *** *** ** ** *** *
* * ** * ** * ** *** * * **** * * * * ** ** **** *** * *** * * ***** * * = a[n] + b[n] - 10;
* * *** * ** ******* * *** ** * * * * ** * ** *** ** * ** *** ** * * * *** ** ** * **** **
** * **** * **** * ** *** * ** ** ** * *** * * * *** ******** *** **
** ** **** ******* * * * ***** * * * **
*** * ***** * * *** ** *** * *** ** * ***** ** * * if(t == 1)
* **** **** **** ** * ** * ****** *
** ** ** ** ***** * * * ** ** * * * * ** *** * * * * **** **** **** * ** * *
* ****** * * *** ** ** ** * * * *** **** *** * ** * ** *** * * *** ** * *** * *** * * = a[n] + b[n] + 1;
* ****** * ** **** * ** * * * * ** ** ** ** * * ** ** * *** * **** ** if(a[n]+b[n]>=9)
* *** * ****** * ** * ** **** * * *** ** * ** * *** * ** **
* * *** * * * * *** ** * * *** ** ** ******* * ** ****** * ** *** ** *** ** * ** = a[n] + b[n] - 9;
* * * ** ***** **** * ** * ** ** ****** * *** *** * ** * *** * *** * * **** * **** ** * *
*** ** ** * **** * ** ****** * * ***** * ********* *** *** *** **
* ***** * * ** ** *** * *** **** *** * ****

    }
* * * * ** * **** * * * ** * *

    {
* ** * * ** * * ** *** *** * ***** ******* * * * * * *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
**** * * ** ** * ** data[2];
* *** * * ** ** sum;
* ** *** ** * * i;
** * *** ******* * *** * **** ** *
*** ** * ** ** * *** *
*** * *** * * * * ** * ** *** *** * ** *** **** * *** ** * * * *
* * ** * * *
* ** ****** * ** * * **** ** ***
* * * * ** ** * ***** ******* * *** * * * * **
****** * ** ** * **

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** ***
* ** * *** ** *****
*** *** ******
** * * * **







int ******

{


*** *** int ** ** **
* * * * ** **

* * * scanf ****** ****** *** *
* ** ** *

* ** **** ** while (a[i]!= ' ')

{
** * * *

** ***** i++;
* * * * *

** * * scanf * ** *** * ** * * * ** ** ** *

* ** * * **

}


* ** * *** scanf * * *** **** * * * **


* * **** while * ** ** ******** * *
** ** * * * *

* ** * {
* * * * * * * * * *

* * * * * * ** * j++;
** ** ** ** * * ****

***** **** ** * *** ** * * ** scanf ** ********* *** ** ** *

** **** * * * *

* ** * * ** }
* ** * **

}
* * ** ******

*** * * *** for (i = 0,j = 0;;i++)
* ** * *

* * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include * **** * ***

int main()

{
***** ** * *** a,b,c;
* * * ** **** * * * * * * ****** ** ***** ***
* * ** * ** ***** = a + b;
* *** * * * ** * * * * ***** ** * ** *
****** * * **** *** ** ** ** ******
* *** **** * * * * * *
* * ** * * ** **** * **
******* * * * ** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * ** ** ** *

int * *** y=999999999;

int main()

{
** * * * * ** ** **** *** * **** * **
**** * * ** * *
** ** ** * * *** ****** * *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ***** * *

int main(){
* ** * ****** ** * ** a,b,c=0;
***** ** ***** * * **** ** * ** * *** * * * ** * **
* * * * * * *** * *** ** **** ***** * * ** * * *
******* * *** ** ** ***
* * ** * *** ** * ** * * *** ** * ***** * **
** *** * * *** * ****** 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.191
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 2.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users