0 like 0 dislike
1.4k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 1.4k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* *** ** * * * *** ** * * ***** ** *** * * **
* ******** **** * **** * ** ** * ** *

    {
* * *** * * **** ** * * * ** ** ** **
* * *** * ** *** * ***** * ** **
** *** ** * ** ** ** *** * * ** *** ** *** ** ** ** ** * * * * ***
** ** ** ** *** **** * * ** * *** *** **** * **** * * ** * * *** * * ** **** * * * ** * = a[n] + b[n];
*** *** *** * *** * ** ** **** * * ** *** * ** ** * ** * *** * * *** * if(a[n]+b[n]>='10')
* * * ** * **** * * ** ** * * * **** * ** ** ** * * * ***
* * **** ** ** * * * * * *** ******** * * ** ***** * ** *** *** * ***** = a[n] + b[n] - '10';
* *** ** ***** ****** * * * ** * ** * * ***** * ****** * *** * * * **** ******
** **** ******* * * **** ** * ****** ** * *** ***** * ***** * *
* *** ** **** ** * * **** * **** *** * **
* ***** * *** ** **** * ** * * * *** * ** * if(t == 1)
* * ********** *** *** ** * ** ***** ****
* * *** * * * * **** * *** * ** ** * * ***** ** * ** ** * ** *
** ** * * **** **** ** * ** * * * ** * **** * * * ** ** * ** * ** * * * *** ** = a[n] + b[n] + '1';
** * * * * ****** ** * ** * * * ** * * * ** *** * ** * * * if(a[n]+b[n]>='9')
** * * ** *** * * * ******** ** * * *** * * ** ****** ** **** **
** * * ******* * * ** * * * ** * * ***** * *** ***** ** *** **** **** *** ** * ** = a[n] + b[n] - '9';
*** * * * * * ************* ***** * *** *** *** ** * * ***** *** * * ** * ** **
* **** *** * * * *** * * *** * ***** ** *** * * **** ******* * * * **
** * * * * * * * * ** ***** ****** * *** *

    }
** ** ** * * *** ** *** * ** * *

    {
* * ** * ** * *** ** ** * ** * * ** *** * * **** *** *** *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
** *** * * * ***
** * ***** * **** **

int main ()

{

int **


* *** ** ** * * * * * ***
* * * ** * **


* * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * ** *

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
* ***** * ***** ** **** * a[100],b[100];
** * ** **** *** * **** sum[200];
* ** * ** *** la,lb,lm,i,j,k;
* * ** *** **** ** * *** %s",a,b);
* ** * * * ** * * ** *** = strlen(a);
** ** * ** * ** * *** = strlen(b);
**** *** * ** * * ** * * ** ** *** * *** *** *
** ** * **** *** *** * * ** **** * * ** * ** = a[i];
*** * * * * *** *** *** *** * * * **** * ** ** *********
** * *** ** ** ** ****
* ** * * * * ** ** * * * ** ** * * *
* * ** * * * * * * * *** * * **** **** += b[i]-48;
* * * *** * ** * **** *** ***** ***** * * * * ** * **
* *** * * *** * * **
*** * ********* ** * * = strlen(sum);
* * **** ** **** **** ** * ** ******** *
***** ***** ** * * ** * ** ** ** * * * * ** *** ** ** * ***
* * * ** * ** * **
** ****** ** ** * * * *** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
** ** *****
* * ** * * * * **





int main ()

{
* a , b ;
* *** * *** * * , ** *
**** ** *** , * ***
* * **** * * ** ,a+b);
** ***** **** *** 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* ******* *** *** ** * ****** * ** *** *
* ** * * ** ** *** * * *** **** * *

    {
* ** * **** ** * ** * * * * *** * * * * **** * *
* * ** ** **** * **** *** * * *** * * **** **
* *** ** * * ** * ***** ** **** *** * **** * * **** * * * ** * **
*** * ****** ** * * * *** ** * * * * **** * ** *** *** ****** * * **** * ** ** **** * ** = a[n] + b[n];
* ** * ** * *** * * * * * ** * * ****** ** * * *** *** ** if(a[n]+b[n]>=10)
* **** * * * ** ** ***** *** **** * * * ** * * * * * ***
* * ** * *** * ** *** * * * ** * ** * ****** ** *** = a[n] + b[n] - 10;
* **** ** * * * * ** ****** * ** * *** **** * ** **** * ** * * ** ** *** * ** ******* * ** * *
** ** ***** *** * ** ** * * * ***** * * * * * ** ***** * *** *** * ****
* ** * *** ** * * * ** ** **** * * **** **
* * **** * ****** * ***** ** * **** ** * * if(t == 1)
** * * * * ***** * * * *** ****** * * * *
** * * * ****** *** * ** * * ****** * *** * *** ** *** *** ** * *** *
* * ** * * * ** ** * * *** *** ** * * * * * ** * * ** * *** * * *** ** * ** * * * = a[n] + b[n] + 1;
*** ** * *** ***** * * * *** ** * *** ** ** ** * **** *** if(a[n]+b[n]>=9)
** ** * * * *** ** **** ** * *** * * ** *** **** ** * *** ***
*** * * *** ** **** ***** ***** *** ****** * * * * * *** * ** ** * ** ** * * ** ******* * ** * **** * = a[n] + b[n] - 9;
** * * *** * * *** * * * ** ** ** ** *** ** * ** ** *** * * * ***** * * *** * ** *
* *** ****** * * ** ** * * ** *** ***** * ** * *** *** ** ** ** ***
** * *** * * *** ** ***** * ** ***** * * *

    }
* * * ***** * *** * * * *** * **

    {
** * * ** ** *** * ***** * * *** * * ** * * ** * * ** ***

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* *** * ** **** **** * * data[2];
* * * * **** * *** ** sum;
* * *** * ***** * i;
*** * ********* * * **** * * * *****
* *** ** * ** * **** * *
* ** * ***** * ***** * *** ** * ** ** ** * * * ******
** * *** ***** ** * ** *** *
**** * ** ** * * * * * ** ** ***
** * *** * * * * ** ** * *** ********
** * **** **** ** *** *** **

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * * * ***
** * * ** ** * ** *
***** ** *** * ***
* * * * * *







int ** * **

{


* * ***** int *** ** **** *
* ** *

* * *** * * scanf *** ** * * * * * **
* *** ***

* * ** **** while (a[i]!= ' ')

{
* *** * **

**** * * i++;
* ** *

* ** * * scanf * * ******* * *** ** ** * ** *

** * *

}


*** ** ** * * ** scanf * *** **** *** ***


* * * ** while * * ** *** * ** ** * *
** * *****

** *** ****** {
***** ** **** ** ** ** ***

** **** * * * ** * ** * j++;
* * * ** **** * *

* * * ** * * scanf *** ** * *** * **** **** **

* ** * * **** ****

*** ** * }
* ** * ** **

}
* * * ** *

** * *** * for (i = 0,j = 0;;i++)
**** ** * **

**** ** *** * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include ** ** ** ****

int main()

{
****** *** ** * a,b,c;
* * ********** * * * * **** * * **** **
** ** ** *** * * = a + b;
* ** * * ** * * ** * * ***** * * * ** ****** * *** ****
******* ** * ***** * * *** * *****
* * **** ** ** *
** * *** * ** * ** * **** * * *
* * * * * * ** * 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * ** * *

int ** y=999999999;

int main()

{
** ** **** * ** * *** * * ** *
*** *** **** * *** *
*** *** **** ** ** * *** ** *** * * *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * * ***

int main(){
****** ** * * *** a,b,c=0;
** ***** * ***** * ** *** ** * ****** **
* ** **** ** * ** * *** **** ** ** ** * ***
**** ** * ** *** * ** *
*** * ** * ** *** ** *** * * * *********
**** ** * ** ** **** ** *** 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.27
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 2.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users