0 like 0 dislike
3.2k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 3.2k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
** *** ** ** * * **** ******* *
** ** *** *** * *** * *** ** * *

    {
* * * * **** * * ** ** * * ** ** * **** *** * * *
** * * ** * ** *** *** ** ** * ** *** **
*** **** * *** * * ** ** ** *** ** * ** **** * * **** ****** ****** * ****** *
** * ****** * * * * ** **** * * ** * ** * * * * ** * * ** * ** ** ** * ** * * *** ** * * * = a[n] + b[n];
******* *** * **** **** * ** * * ** ** * * * * * * ****** if(a[n]+b[n]>='10')
** ** ** * ****** * * * * * ** **** *** * *** ** * * * * **
*** * * * ** * * ** **** * *** * * **** * * * * ********* * * ** * * * * ** = a[n] + b[n] - '10';
* * ** * * ***** *** * * * * * ******* * * **** ** * * * * * * **** * *** * ** *
****** * ** * *** ** ** * ********* ** * **** **** * ** * ** ** ** **
* * * * * *** * ***** *** ** ** ** *
** * * *** * *** * * ** * * ** *** ** *** * if(t == 1)
** * ** * * ** *** **** ** * *** **** **
* * *** ** *** * *** * * **** *** * ** * ** ***** * ** *** ** * * * *
** * * ** ** * *** ** ** * ** * * * * * ** * * **** * * * * **** * * * * * * * * ** = a[n] + b[n] + '1';
*** * * * * *** ** ** * * ** * * * ** ****** * * * * * * * * if(a[n]+b[n]>='9')
** * ** * * ** * * ********** ** ** * * *** * * ** ** * ***
* *** ** ****** * * ** * * * * ** * ** * ** * * * *** * * * *** * * ** * * * * *** ** * = a[n] + b[n] - '9';
* * ** * *** ** * * *** **** * ****** * * *** ** * * * ** * * ** * ** * * * ******* **
** ** * *** * * * ** * **** *** ** * ** * *** * * * * *
*** * **** *** * ** * * *** *** * * * ***

    }
*** ** ** * ***** * *

    {
* * * ** ** * * **** ** ** * * ** *** * * **** * **** *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* ** **** *** * **
* * ** ** **** **

int main ()

{

int ***


* *** * ***** **** * * * *
* * *** * ********* ****


** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** * * * *******

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
*** * * * *** **** * a[100],b[100];
*** ** *** * *** *** sum[200];
* ******* *** ** * *** la,lb,lm,i,j,k;
**** * ****** * * * * * * * ** * %s",a,b);
* * **** ** *** * * * = strlen(a);
* * * ** ** * * ** * = strlen(b);
* * * * *** * * * ********* * *
** ** * ** ** * ** * * * ** * ***** *** * * ***** = a[i];
***** * ******* *** ***** *** **** ** * * * *** *** *
** * ** * ** * * * * *
*** * *** * *** * * ******* * *** * **
** ****** **** * * * * * ** ** * ***** += b[i]-48;
* ** ** ** ** ** ** * **** * ** ** * * *** * * * * ****** ***
* ** *** * * *** *** *
* * ** * **** ** ** = strlen(sum);
** * ****** * *** * * ** ** **
** ** * ** ** * *** ** ** *** *** * **** * * **** ***
***** ** ** * * ** * *** *
* ** * ** * ** * *** ** ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* *** * ** ** *
* *** * * *** ** * *





int main ()

{
* ** a , b ;
**** * * * * , *** ****
*** ** ** ** ** , ***
** **** *** ** * ** ,a+b);
** ** *** *** ** ** *** 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * **** * * *** * * *** *** *
* * **** ** ** * **** ** * **

    {
*** * *** ** **** ** * * *** * * * **
**** * * * **** * * *** * *** **** *** **
** *** * *** * ** *** ** **** * ** ** * *** ** *** * ** * * * * * *** ***** *
* ** * ********* * * * *** * * * ** ** ** * * *** ***** * ** ****** ** **** ** * = a[n] + b[n];
* ** ** ** * **** ** * ** * ** * ** * * * * ** if(a[n]+b[n]>=10)
*** * ** * ** * * ** * * * ** * *** * ***** **** * *** ** *
* ** ** ** * * ** * * * *** *** * ** ** ** * * *** ** * ** * * * ** ** * * * * ***** ** = a[n] + b[n] - 10;
* * * * *** * * * * ** ****** *** * ***** * ** *** ** *** *** ***** **** * * *
* ** * *** ********* * * * *** * ** ****** * * *** ** *
* ** ** ** * * ** * * ** * * **
* * * ** ***** * ** ** ** * ** * if(t == 1)
* * **** * * *** ** * * *** * **** ** **
*** ** ** ** **** * *** ** ** * * **** * **** * * ** * * * * * **** ** *
*** * ** * * * * * * * * * *** **** ** * **** * * * ****** * * ** * * *** ** = a[n] + b[n] + 1;
** * * **** * **** ******* ****** * * * *** *** * * * *** **** ** * * if(a[n]+b[n]>=9)
* * ** ** **** * ** ** * * * ** * * *** *** ** ** *** *** ***
* ***** * ** ** *** ********** ** ** ** * * * * ** ** ******** * * *** * * ** * = a[n] + b[n] - 9;
***** ** ** ** ** ** * ******** * * ** ** *** ** * * * * * ** *
* *** * ** ** ** *** **** * * ** *** ** ** ***** ** * ** * *
* ** * ** * *** * * ** * * *** * *****

    }
** ** ***** * * * *** ** ** *

    {
*** ** * *** * * * * * **** * ** * * * * ** * * ****** *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* *** * * ** *** ** data[2];
****** ** ** * * ** ** ** * ** * sum;
** * ** * ** * *** * i;
** * ***** ****** * * ****** * * ** **
* ** *** * * **** *
******* * * *** *** *** ** ** ** ******** * * ** ** * * * ** *
* * * * * ** *** * * * *
** ** **** * * ** ** * * ** * *** **
* ** **** * *** * * ** * **** * * ****
** * *** ********* *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * *** **
** ** *** * * ***********
* * *** ** **
* *** ** * * ** *







int ** *

{


** ** ** ** int * * *
* * ** **

* ***** * ** scanf * * *** * * *
* * * * *

** *** * while (a[i]!= ' ')

{
** ** * *

* * * * i++;
**** ***

* ** * scanf ** ** * * ** * * ** * ** ****

** * ** ****

}


* *** * * scanf * * * * * * *


* * ** ** *** while * * * * ** **** * **
****** * * *

* * * * * {
* **** * * * *** * ***

* * *** ** * ******** j++;
* ** ** ** * * *

** * * ** * ** ** * * scanf * * ** **** ** * ***** * * * * * * * *

* * * * ** * ** * ***

** ** ** *** }
** * *****

}
* * * **** *

***** * **** for (i = 0,j = 0;;i++)
* * ** ** * ***

* ** * * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include ** * * ** **

int main()

{
**** *** *** ** a,b,c;
** ****** *** **** *** *** * * * * * ***
* * *** ** * *** = a + b;
** * **** * * * * * * * ** ** * *** ** ** **
*** * *** *** * * * * * * ** * *
* * ** ** * **** *
*** ***** * **** * ** *** *** ** ** **
* * ***** ** * ** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include ***** ** *

int ***** y=999999999;

int main()

{
* * **** * *** ** * ** *
* * ** ****** ** * * *** *
***** * * * *** ** * **** * * ** ****

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** * **

int main(){
* * ** * * **** * *** a,b,c=0;
* * ***** ** *** * * *** * **** * **** * *
* * ** *** * * * * *** ** ** * * *** * **** ***
* * ** * * * ** * **
* *** * * * * * * ** ***** * * ** ** *** *** *
*** * * ***** *** ** * * 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.169
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.8k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users